Answer:
-2
Step-by-step explanation:
-5-7 = -12
6x = -12
x = -2
What is the common factor in the expression 5ײ+20×+30?
Answer:
2t-6
Step-by-step explanation:
The radius of a circle is 11 ft. Find the circumference of the circle.
34.54 ft
69.08 ft
17.27 ft
25.14 ft
Answer:
69.12 ft
Step-by-step explanation:
The formula for circumference of a circle is 2πr
= 2 × 3.142× 11
= 69.12
Hence the circumference of the circle is 69.12 ft
algebra what is 6a6 over 2a2=
Answer:
3a^4
Step-by-step explanation:
Simplify the expression.
Which point is a solution to the equation 2x - y = 4?
Answer:
2x= 1 /2 y+ 2
Step-by-step explanation:
Solve for x.
2x−y=4
Add y to both sides.
2x−y+y=4+y
2x=y+4
Divide both sides by 2.
2x /2 = y+4 /2
x= 1/ 2 y+2
The required point that is the solution to the equation 2x - y = 4 is at (2, -4)
In order to get the solution to the equation, we will need to get its x and y-intercept.
x- intercept is the point where y is zero.
Given the equation 2x - y = 4
If y = 0
2x - 0 = 4
2x = 4
x = 4/2
x = 2
Get the y-intercept
y intercept is the point where x = 0
if x = 0
2(0) - y = 4
-y = 4
y = -4
Hence the y-intercept is -4
The required point that is the solution to the equation is at (2, -4)
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The city of Gainesville is trying to determine the average price for a gallon of gas. They randomly sampled 28 gas stations and found the sample mean to be $2.58 with a standard deviation of $0.09. Assume that all of the assumptions are met. Calculate a 95% confidence interval for the population mean gas price in Gainesville.
Answer:
The 95% confidence interval for the population mean gas price in Gainesville is between $2.54 and $2.62.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 28 - 1 = 27
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 27 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0.52
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.052\frac{0.09}{\sqrt{27}} = 0.04[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is $2.58 - $0.04 = $2.54
The upper end of the interval is the sample mean added to M. So it is $2.58 + $0.04 = $2.62.
The 95% confidence interval for the population mean gas price in Gainesville is between $2.54 and $2.62.
solve for da x in 2x+3=7 :>
Answer:
x = 2Step-by-step explanation:
Given
2x+3=7Solve for x
2x = 7 - 32x = 4x = 4/2x = 2Answer:
2
Step-by-step explanation:
first answer deleted by moderator... even when it was correct... i did more explaining on that one, but they kindly deleted my answer and didn't even show my full answer after they had deleted it like some other moderators do which i always appreciate.
Please help! Just Answer if you know how to do it please . No wrong answers . Thank you.
Answer:
42
Step-by-step explanation:
Suppose a car travels 174 miles in 3 ours. How far will it travel in 6 hours?
Answer: 348 miles
Step-by-step explanation:
The car will travel 174 miles in 3 hours, if you multiply 174 x 2, the car will travel 348 miles in 6 hours.
1 and 1/2 divided by 4 and 2/8
Answer:
1.375
Step-by-step explanation:
Answer: 11/2
Step-by-step explanation:
Combine the like terms to create an equivalent expression. \large{7k-k+19}7k−k+19
Answer:
The simplified expression is 6k+19 .
Step-by-step explanation:
Need help please and thank you
Answer:
Step-by-step explanation:
-2 2
3(2) -3(2)
What is 3/5 times 6/5
Answer is 0:72
hope it is helpful
Answer:
18/25
Step-by-step explanation:
If line q has a slope of -3/8, what is the slope of any line perpendicular to to q?
Answer:
The slope of line perpendicular to line q is 8/3.
Step-by-step explanation:
Given that:
Slope of a line q is -3/8
Slope is the steepness of any line.
Let,
x be the slope of line perpendicular to line q.
The product of slopes of two perpendicular lines is equal to -1.
[tex]\frac{-3}{8}x = -1[/tex]
Multiplying both sides -8/3
[tex]\frac{-8}{3}*\frac{-3}{8}x=-1*\frac{-8}{3}[/tex]
x = 8/3
Hence,
The slope of line perpendicular to line q is 8/3.
A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those dates, finds a variance of 34.34 and a standard deviation of 5.86 rooms rented. If the number of rooms rented is normally distributed, find the 95% confidence interval for the population standard deviation of the number of rooms rented. Interpret your interval in context.
Answer:
Confidence interval variance [21.297 ; 64.493]
Confidence interval standard deviation;
4.615, 8.031
Step-by-step explanation:
Given :
Variance, s² = 34.34
Standard deviation, s = 5.86
Sample size, n = 27
Degree of freedom, df = 27 - 1 = 26
Using the relation for the confidence interval :
[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]
From the chi distribition table :
X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844
Hence,
[34.34*26 / 41.923] ; [34.34*26 / 13.844]
[21.297 ; 64.493]
The 95% confidence interval for the population variance is :
21.297 < σ² < 64.493
Standard deviation is the square root of variance, hence,
The 95% confidence interval for the population standard deviation is :
4.615 < σ < 8.031
The population variance of 95% confidence interval is [tex]4.615<\sigma<8.031[/tex] and this can be determined by using the given data.
Given :
Variance = 34.34Standard Deviation = 5.86Sample Size = 2795% confidence intervalFirst, determine the degree of freedom.
[tex]df = 27-1=26[/tex]
The determine the confidence interval using the below formula:
[tex]\left(\dfrac{s^2(n-1)}{X^2_{\alpha/2,(n-1) }}\right);\left(\dfrac{s^2(n-1)}{X^2_{(1-\alpha)/2,(n-1) }}\right)[/tex]
Now, using the chi distribution the above expression becomes:
[tex]\left(\dfrac{34.34\times 26}{41.923 }}\right);\left(\dfrac{34.34\times 26}{13.844 }}\right)[/tex]
Simplify the above expression.
(21.297 ) ; (64.493)
So, the population variance of 95% confidence interval is:
[tex]\begin{aligned}\\21.297&<\sigma^2<64.493\\4.615&<\sigma<8.031\\\end{alingned}[/tex]
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pls help solve question 3
Answer:
If m is the midpoint of ab it means am is equal to mb
am = 3x + 8 and mb = 6x-4
and ab = am + mb
first find the value of x by using am = mb
3x + 8 = 6x - 4
8 + 4 = 6x - 3x
12 = 3x
x = 4
ab = 3 (4) + 8
= 12 + 8 = 20 = mb
ab = am + mb
= 20 + 20
40
so, the value of ab is 40
Olive weights are classified according to a unique set of adjectives implying great size. For example, the mean weight of olives classified as "Colossal" is 7.7 grams. Suppose a particular company’s crop of "Colossal" olives is approximately Normally distributed with a mean of 7.7 grams and a standard deviation of 0.2 grams. Which of the following represents the probability that the mean weight of a random sample of 3 olives from this population is greater than 8 grams?
a. 0.0970
b. 0.9953
c. 0.0668
d. 0.0047
e. 0.1932
Answer:
d. 0.0047
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Population:
We have that [tex]\mu = 7.7, \sigma = 0.2[/tex]
Sample of 3:
[tex]n = 3, s = \frac{0.2}{\sqrt{3}} = 0.1155[/tex]
Which of the following represents the probability that the mean weight of a random sample of 3 olives from this population is greater than 8 grams?
This is 1 subtracted by the pvalue of Z when X = 8. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{8 - 7.7}{0.1155}[/tex]
[tex]Z = 2.6[/tex]
[tex]Z = 2.6[/tex] has a pvalue of 0.9953
1 - 0.9953 = 0.0047
The probability is given by option d.
You can calculate the z score for the specified sample and then use the z tables to find the p value(probability) needed.
The probability that the mean weight of a random sample of 3 olives from this population is greater than 8 grams is given by
Option d : 0.0047
How to find the z score for a sample taken from a normal distribution holding random variate?Suppose that the sample is of size 'n', then we have the z score(we are converting random variable X to standard random variable Z) as:
[tex]Z = \dfrac{X - \overline{x}}{s} = \dfrac{X - \mu}{\sigma/\sqrt{n}}[/tex]
where [tex]\overline{x}[/tex] is mean of the sample
s is the standard deviation of the sample,
and we used the central limit theorem which says that a sample from a normally distributed population with [tex]mean = \mu[/tex] and standard deviation = [tex]\sigma[/tex] can have its mean approximated by population mean and its standard deviation approximated by [tex]s = \dfrac{\sigma}{\sqrt{n}}[/tex]
Using the data given to find the intended probabilityLet the weight of the the olives for the given crop of olives of a particular company for taken random sample is given by X (a random variable)
Then, we have:
[tex]X \sim N(7.7, 0.2)[/tex]
where
[tex]\mu = 7.7, \sigma = 0.2[/tex]
Thus, we have:
[tex]\overline{x} = \mu, s = \sigma/\sqrt{n} = 0.2/\sqrt{3}[/tex]
Using the given facts, we get the needed probability as:
[tex]P( X> 8)[/tex] sample size n = 3)
Then, using the z score, we get):
[tex]P(X > 8) = 1 - P(X \leq 8) = 1 - P(Z \leq \dfrac{8 - 7.7}{0.2/\sqrt{3}})\\\\P(X > 8)=1- P(Z \leq \dfrac{0.3\sqrt{3}}{0.2}) = 1- P(Z \leq 1.5 \times \sqrt{3} )\\\\P(X > 8) = 1 - P(Z \leq 2.59) = 1- 0.9952 \approx 0.0047[/tex]
Thus,
The probability that the mean weight of a random sample of 3 olives from this population is greater than 8 grams is given by
Option d : 0.0047
Learn more about standard normal distribution here:
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4x – 3y = 18
Determine the missing coordinate in the ordered pair (5, ?) so that it will satisfy the given equation.
Answer:
Step-by-step explanation:
when x=5, 4(5)-3y=18
3y=2
y=2/3
The coordinate would be(5,2/3)
please help me
thank
Answer:B,C and E
Step-by-step explanation:
A car that has a wheel radius of 1.5 feet travels 30 miles in 45 minutes. How fast are the wheels spinning? Give your answer in revolutions per minute.
Answer:
373.43 rev/min
Step-by-step explanation:
Given data
r= 1.5ft
v=30 miles per 45 minutes
convert miles per hour to ft per minute
=30miles/45 minutes* 5280ft/1 mile
=158400/45 minutes
v=3520 feet per minute
so
v=wr
substitute
3520= w*1.5
w= 3520/1.5
w=2346.66 rad/min
Convert to rev/min
=2346.66 rad/min*1rev/2*π rad
=2346.66/2*3.142
=2346.66/6.284
=373.43 rev/min
Hence the answer is 373.43 rev/min
Consider the system of equations.
x-3y = 9
1/5 x - 2y = -1
Which number can be multiplied by the second equation to eliminate the x-variable when the equations are added
together?
Given:
The system of equations:
[tex]x-3y=9[/tex]
[tex]\dfrac{1}{5}x-2y=-1[/tex]
To find:
The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.
Solution:
We have,
[tex]x-3y=9[/tex] ...(i)
[tex]\dfrac{1}{5}x-2y=-1[/tex] ...(ii)
The coefficient of x in (i) and (ii) are 1 and [tex]\dfrac{1}{5}[/tex] respectively.
To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.
It means, we have to convert [tex]\dfrac{1}{5}[/tex] into -1. It is possible if we multiply the equation (ii) by -5.
On multiplying equation (ii) by -5, we get
[tex]-x+10y=5[/tex] ...(iii)
On adding (i) and (iii), we get
[tex]7y=14[/tex]
Here, x is eliminated.
Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.
A Cub with 40members elects a finance committee having 3members. How many committees
are possible?
Answer:
9880
Step-by-step explanation:
[tex]C^3_{40}=\frac{40!}{3!(40-3)!} =\frac{40!}{3!*37!}=13*19*40=9880.[/tex]
Enter the number that belongs in the green box
PLEASE HELP FAST
what does the following quotient 2-√18/4+√12
Which expression means the same as "25 less that 5y"
Answer:5y-25
Step-by-step explanation:
Answer:
5y - 25
Step-by-step explanation:
that expression shown 25 less than 5y
hope this helps...
can someone show me the problems to 4/3 x 2/5 and 2/5 divided by 4/3
Answer:
8/15 and 3/10
The area of a rectangle is 2- 3/4 inch. ^2 If the length of the rectangle is 1/2 inch, what is the measurement of the width?
Answer:
The width of the rectangle = 1.15 inches
Step-by-step explanation:
Explanation:-
Given that the length of the rectangle = [tex]\frac{1}{2} inch[/tex]
The area of the rectangle = [tex]\frac{2.3}{4}[/tex] inch²
We have to find the width of the rectangle
The area of the rectangle = length × width
[tex]\frac{2.3}{4} = \frac{1}{2} X width[/tex]
⇒ 2 × 2.3 = 4× width
⇒ 4.6 = 4 w
⇒ w = 1.15 inches
Final answer:-
The width of the rectangle = 1.15 inches
How many different 3-digit numbers can be made using each of these digits shown below only once?
3,6,9
OA 3
O B. 6
Oc. 8
OD 10
O E more than 12
Here are the first four terms of a number sequence.
8
14
20
26
Write down the next term of the number sequence and explain how you found your answer
Isabella is making a display board for the school trip. The display board is 2.50m by 2m rectangle. She needs to cover the entire display board with card. How much card would she needs?
Answer:
5m^2
Step-by-step explanation:
Given data
Length of board= 2.50m
Width of board= 2m
The cover need should have the same area as the board
Area= Length*Width
Area= 2.5*2
Area=5m^2
Hence the area of the cover is 5m^2
If you invested $250 at 16% interest, how much would you have after 18 years?
Answer:
4,000
Step-by-step explanation: