6x - 4 -2x + 5 = 13 answer this question

Answer:

D. 264π units³

Step-by-step explanation:

1/3(πr²h)

1/3(π•6²•22)

1/3(π•36•22)

1/3(π•792)

264π

Answer:

i would like to have the pic of the graph and ill help asap

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

[tex]\frac{2\sqrt{3} + 6}{12}[/tex]

Step-by-step explanation:

Simplify the denominator of [tex]\frac{1 + \sqrt{3} }{\sqrt{12} }[/tex] completely.

[tex]=> \frac{1 + \sqrt{3} }{ \sqrt{(4 \times 3)} } = \frac{1 + \sqrt{3} }{\sqrt{4} \times \sqrt{3} } = \frac{1 + \sqrt{3} }{2\sqrt{3} }[/tex]

Now, to rationalise it you need to make the denominator rational.

[tex]=> \frac{1 + \sqrt{3} }{2\sqrt{3} } \times \frac{2\sqrt{3} }{2\sqrt{3} }[/tex]

[tex]=> \frac{(1 + \sqrt{3})\times 2\sqrt{3} }{2\sqrt{3} \times 2\sqrt{3} }[/tex]

[tex]=> \frac{2\sqrt{3} + 6 }{12}[/tex]

Answer:

144

I hope that helped!

Answer:

26

Step-by-step explanation:

Answer:

∠1 = ∠8

Step-by-step explanation:

Because they are ALTERNATE EXTERIOR ANGLE

Answer:

∠1 = ∠8

Step-by-step explanation:

Because alternate exterior angles are equal.

Also there is no angle given so you cant work them out.

simply put:

∠1 = ∠8

∠1 = ∠4

∠3 = ∠2

∠1 = ∠5

∠2 = ∠6

∠2 = ∠7

∠5 = ∠8

∠4 = ∠8

∠7 = ∠6

∠7 = ∠3

Let me know if I missed out on anymore! It was long that's why.

Hope this kind of explained it :)

Answer:

D. divide by 12​

Step-by-step explanation:

→ When you :

- Multiply, the inverse is divide

- Divide, the inverse is multiply

- Add, the inverse is minus

- Minus, the inverse is add

Answer:

The answer for this question is 240 yd

Answer:

I din nosjwjfkwifowockwofkwkfkekfkamcqkkr1o4k30rjdogiq

Answer:

Smallest Number = 35

Other Number  = 42

Step-by-step explanation:

Let the smaller number be x.

Let the other number be y.

Given:

x : y = 5 : 6

That is,

          [tex]\frac{x}{y} = \frac{5}{6}[/tex]

             [tex]=> 5y = 6x\\\\=>x = \frac{5y}{6}[/tex]

Next: Let the smaller number be reduced by 5, x - 5

        Let the other number be increased by 3, y + 3

Given : (x - 5) : (y + 3) = 2 : 3

That is,

        [tex]\frac{x-5}{y+3} = \frac{2}{3}\\[/tex]

[tex](x-5) \times 3 = (y+3)\times 2\\\\substitute \ x = \frac{5y}{6}\\\\3(\frac{5y}{6} -5) = 2y + 6\\\\\frac{5y}{2} - 15 = 2y + 6\\\\\frac{5y}{2} - 2y = 6 + 15\\\\\frac{5y-4y}{2} = 21\\\\y = 21 \times 2 = 42\\\\Substitute \ y \ in \ x = \frac{5y}{6} \\\\x = \frac{5 \times 42}{6} = 35[/tex]

Answer:

10x

Step-by-step explanation:

10x times itself is 100x^2

Hope this helps!

Answer:

Is can

Is can

1 is the answer

Step-by-step explanation:

But what’s the name of that topic?

Answer:

Is can

Is can

1 is the answer

Step-by-step explanation:

Answer:

[tex]\begin{array}{cc}{Stem} & {Leaves} & {4} & {7} & {5} & {2, 7, 8, 8} & {6} & {1, 6, 6, 8, 8} & {7} & {0, 2, 2, 3, 3, 5, 6, 7} & {8} & {4, 4, 4, 5, 6, 6, 7, 9} & {9} & {0, 1, 1, 2, 3, 7} \ \end{array}[/tex]

Step-by-step explanation:

Given

See comment for complete part of the question

Required

Make a stem and leaf plot

We have:

[tex]58, 52, 68, 86, 72, 66, 97, 89, 84, 91[/tex]

[tex]91, 92, 66, 68, 87, 86, 73, 61, 70, 75, 72, 73[/tex]

[tex]85, 84, 90, 57, 77, 76, 84, 93, 58, 47[/tex]

Categorize the dataset according to tens

[tex]47[/tex]

[tex]52, 57, 58, 58[/tex]

[tex]61, 66, 66, 68, 68[/tex]

[tex]70, 72, 72, 73, 73, 75, 76, 77[/tex]

[tex]84, 84, 84, 85, 86, 86, 87, 89[/tex]

[tex]90, 91, 91, 92, 93, 97[/tex]

So, the stem and leaf plot is:

[tex]\begin{array}{cc}{Stem} & {Leaves} & {4} & {7} & {5} & {2, 7, 8, 8} & {6} & {1, 6, 6, 8, 8} & {7} & {0, 2, 2, 3, 3, 5, 6, 7} & {8} & {4, 4, 4, 5, 6, 6, 7, 9} & {9} & {0, 1, 1, 2, 3, 7} \ \end{array}[/tex]

Answer:

c = 10*b

Step-by-step explanation:

We know that in each bag, we have exactly 10 sliced carrots.

so if b represents the number of bags, and c the number of sliced carrots, for each one of the b bags we will have 10 sliced carrots, then for b bags, we have b times 10 carrots:

c = 10*b

So for example, if we have one bag, b = 1

c = 10*1 = 10

So in one bag, there are 10 carrots.

if instead, we have 3 bags, b = 3

c = 10*3 = 30

in 3 bags we have 30 carrots.

Then the equation that represents the relationship between b and c is:

c = 10*b

or

b = c/10

Answer:

7.5 hours

Step-by-step explanation:

The key here is to find out how much can be done in the same amount ot time

the least common multiple of 5 hrs and 3 hrs is 15hrs

In 15 hours:

- At 5 hours per lawn Norton could mow 15/5 = 3 lawns

- At 3 hours per lawn together thay could mow 15/3 = 5 lawns

In 15 hours Jesse would mow 5 - 3 = 2 lawns

15 hours/ 2 lawns = 7.5 hours per lawn

7.5 hours

--------------------

Here's the math

1 lawn/5hrs + x = 1 lawn / 3hrs

1/5 + x = 1/3

Subtract 1/5 from both sides

x = 1/3 - 1/5

x = 5/15 - 3/15

x = 2/15

x = 2lawns/15 hrs

15hrs/2lawns = 7.5 hrs per lawn

7.5 hours

Answer:

14 questions correct

Step-by-step explanation:

x/20 *100 = 70

so x/ 20 = 70/100(0.7)

x/20 = 0.7

x = 0.7*20

x =14

Answer:

There is significant difference in difference in the amount of food ferns eat ; and the preferred is TAB-a-cat.

(0.216, 5.984)

Step-by-step explanation:

This is a 2 sample t test test problem :

The hypothesis :

H0 : μ1 = μ2

H1 : μ1 ≠ μ2

x1 = 85.2 ; x2 = 82.1 ; n1 = 31 ; n2 = 30 ; s1 = 3.45 ; s2 = 4.62

The test statistic :

T = (x1 - x2) / √(s1²/n1 + s2²/n2)

T = (85.2 - 82.1) / √(3.45²/31 + 4.62²/30)

T = 3.1 / 1.0466

T = 2.96

Using the Pvalue from Tstatistic calculator :

df = smaller n - 1 = 30 - 1 = 29

Pvalue(2.96, 29) = 0.006075

α = 0.05

Pvalue < α ; We reject the Null and conclude that there is significant difference in difference in the amount of food ferns eat.

99% Confidence interval :

The test statistic :

(x1 - x2) ± Tcritical *√(s1²/n1 + s2²/n2)

Tcritical at 99% = Tcritical(0.01, 29) = 2.756

(85.2 - 82.1) / 2.756*√(3.45²/31 + 4.62²/30)

3.1 ± 2.8844296

Lower boundary = (3.1 - 2.8844296) = 0.216

Upper boundary = (3.1 + 2.8844296) = 5.984

(0.216, 5.984)

Since interval does not contain 0, then, we reject the Null.

Answer:

After the extended period of time, Pete would have typed 6400  words.

Step-by-step explanation:

Given the data in the question;

In the same time;

number typed word of Pete = 80

type word of Ralph = 50

After a period time;

number of typed word of Pete = ?

number of typed word of Ralph = 4000

so, let x represent the number of typed word by Pete after an extended period.

so

80 words = 50 words

x words =    4000 words

we cross multiply

x × 50 = 4000 × 80

x = ( 4000 × 80 ) / 50

x = 320000 / 80

x = 6400

Therefore, After the extended period of time, Pete would have typed 6400  words.

Answer:

30 and 50

Step-by-step explanation:

its simple if you cant figure it out then drop out

Answer:

length = 5

width = 9

Step-by-step explanation:

V = lwh

let 'x' = length

let '4+x' = width

9 = height

405 = 9x(4+x)

405 = 36x + 9x²

this is a quadratic equation:  9x² + 36x - 405 = 0

factor out a 9 to get:

9(x² + 4x - 45) = 0

9(x-5)(x+9) = 0

one root is 5 and the other is -9

since distance cannot be negative we use 5 as the length and 9 is the width

Answer:

0.4364 = 43.64% probability that the disposal of such capacitors will be regulated.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 48.3 ppm and a standard deviation of 8 ppm.

This means that [tex]\mu = 48.3, \sigma = 8[/tex]

Sample of 40:

This means that [tex]n = 40, s = \frac{8}{\sqrt{40}}[/tex]

Find the probability that the disposal of such capacitors will be regulated.

Sample mean above 48.5, which is 1 subtracted by the p-value of Z when X = 48.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{48.5 - 48.3}{\frac{8}{\sqrt{40}}}[/tex]

[tex]Z = 0.16[/tex]

[tex]Z = 0.16[/tex] has a p-value of 0.5636.

1 - 0.5636 = 0.4364

0.4364 = 43.64% probability that the disposal of such capacitors will be regulated.

Answer:

i know there's a lot of explanation. but it helps u for sure :)

Step-by-step explanation:

1)

[tex]-7 \ and \ \frac{1}{3} = \frac{-7}{1} \ and \ \frac{1}{3}\\\\LCM \ of \ 1 \ and\ 3 = 3\\\\\frac{-21}{3} \ and \ \frac{1}{3}\\\\To \ find \ rational \ numbers \ between \ \frac{-21}{3} \ and \ \frac{1}{3} \ write \ any \ number \ between \ -21 \ and \ 1 \ with \ denominator \ 3. \\\\That \ is, \ \frac{-20}{3}, \frac{-19}{3}, \frac{-18}{3}.....[/tex]

2)

[tex]\frac{5}{9} \ and \ \frac{2}{3}\\\\Similarly \ take \ LCM \ of \ 9 \ and \ 3 = 9\\\\Since \ it \ is \ still \ complicated \ to \ find \ rational \ number \ between \ \frac{5}{9} \ and \ \frac{6}{9},[/tex]

[tex]because \ there \ exists \ no\ natural \ number \ between \ 5 \ and \ 6.[/tex]

[tex]We \ will \ multiply \ numerator \ and \ denominator\ by\ 10. \\\\Therefore\ \frac{5}{9} \ and \ \frac{6}{9} \ becomes \ \frac{50}{90} \ and \ \frac{60}{90}.[/tex]

[tex]Keeping \ denominator \ 90 \ write \ numbers \ from \ 50 \ to \ 60 \ in \ the\ numerator.\\\\That \ is , \frac{51}{90}, \frac{52}{90}, \frac{53}{90}, \frac{54}{90}, .\ .\ .[/tex]

3)

[tex]LCM \ of \ 5 \ and \ 7 = 35\\\\\frac{-2}{5} \ and \ \frac{-3}{7}\ becomes \ \frac{-14}{35} \ and \ \frac{-15}{35}\\\\Now \ multiply \ denominator \ and \ numerator \ by \ 10\\\\\frac{-140}{350} \ and \ \frac{-150}{350}.\\\\Rational \ numbers \ are \frac{-141}{350}, \frac{-142}{350}, \frac{-143}{350}, . \ . \ . \[/tex]

Tip :

1. Make the denominator same.

2. Multiply numerator and denominator by 10 , 100 or 1000

3. Just write the natural numbers between the 2 numerators keeping denominator same.

Answer:

here summation x = sum of all number

Answer:

34

Step-by-step explanation:

Hypotenuse is the longest side

I hope this helped have a great day

Answer:

Perimeter = 33.4 units.

Step-by-step explanation:

The 2 horizontal lines are 10 and 3 units long.

The vertical line is 9 units long.

By Pythagoras the length of the sloping line

= sqrt(9^2 + 7^2)

= sqrt(130)

= 11.4017.

Perimeter = 10 + 3 + 9 + 11.4

= 33.4 units.

Answer:

Step-by-step explanation:

Always work from the inside out. That means we will deal with the parenthesis first: (4 - 1)

That gives us

2[32 - (3)³]. Next deal with the exponents. That gives us

2[32 - 27]. Next, the last set of parenthesis, which are actually brackets:

2[5] which then, finally, becomes 10

Order of operations...PEMDAS

A because they are preserving? I guess that's the best way for me

Answer:

angle y = 49°

Step-by-step explanation:

If AB = AD and BC = DC, then the two triangles are isosceles triangles. The altitude from the top to the base divides the top angle into two equal angles, with 90° angles at the base. If angle C is divided into two equal angles (41°) and at the base is a 90° angle, that makes angle CBD 49°. On an isosceles triangle, the two angles opposite to the equal sides are identical. So angle y is identical to angle CBD.

Answer:

[tex]C=252.2ft[/tex]

Step-by-step explanation:

From the question we are told that:

First Kite Distance [tex]A=450ft[/tex]

Second Kite Distance [tex]B=390ft[/tex]

Angle [tex]\theta=34\textdegree[/tex]

Generally the equation for Distance X between the kites is mathematically given by

Using Cosine Rule

 [tex]C^2=A^2+B^2-2abCos \theta[/tex]

Therefore

 [tex]C^2=(450)^2+(390)^2-2(450)(390)Cos 34[/tex]

 [tex]C^2=63607.81[/tex]

 [tex]C=\sqrt(63607.81)[/tex]

 [tex]C=252.2ft[/tex]

Answer:

9.42m

Step-by-step explanation:

I took this on a test. Was extremely difficult, but I remembered the answer after my 4th retake