I'm walking 1.6m/s to 7-11 and it started to rain so I sped up to 2.7m/s in 1.2
seconds. What is my acceleration?
a=(vf-viyt
-0.92m/s2
O 01.1m/s2
0.92m/s2
1.1m/s2
1 points
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I'm Walking 1.6m/s To 7-11 And It Started To Rain So I Sped Up To 2.7m/s In 1.2seconds. What Is My Acceleration?a=(vf-viyt-0.92m/s2O

Answers

Answer 1

Answer:

Explanation:

[tex]a = \frac{v_f-v_0}{t}[/tex] which is the final velocity minus the initial velocity in the numerator, and the change in time in the denominator.  For us:

[tex]a=\frac{2.7-1.6}{1.2}[/tex] so

a = .92 m/s/s (NOT negative because you're speeding up)


Related Questions

?????? ?????help please

Answers

the answer is d. cassani

If you were capable of converting mass to energy with 100%, efficiency, how much mass would you need to produce 3.5x10^12 Joules of energy? ​

Answers

Answer:

a) 3.9 x 10⁻⁵ kg

Explanation:

The amount of mass required to produce the energy can be given by Einstein's formula:

[tex]E = mc^2\\\\m = \frac{E}{c^2}[/tex]

where,

m = mass required = ?

E = Energy produced = 3.5 x 10¹² J

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]m = \frac{3.5\ x\ 10^{12}\ J}{(3\ x\ 10^8\ m/s)^2} \\\\m = 3.9\ x\ 10^{-5}\ kg[/tex]

Hence, the correct option is:

a) 3.9 x 10⁻⁵ kg

8× +5+9×+3 how can I solve this​

Answers

Answer:

collect like terms then add

=>8x+9x+5+3

=>8x+9x+5+3=>17x+8

You have just learned that the planet core of Mars is no longer radiating heat like the core of Earth. With this information what would you communicate to building designers as the lead geologist in regards to suitable building locations on the surface of Mars? Remember your informing builders about locations that would best avoid natural disasters like marsquakes and volcanoes? What evidence or theories do you have to support your statements?

Answers

Answer:

Explanation:

That is a fun question!

Without a hot radiating core like Earth, Mars will have very different geological and seismic events. The Mars core will be relatively cold and there will not be any molten magma. So Mars will not have earthquakes or volcano activities. Both only occur when there is magma flowing or tectonic plate motion and they will not occur with a cold core.

HELP PLEASE
A virtual image is produced by a convex mirror that is 1.60 cm from the mirror. If the magnification is 0.20, how far from the mirror is the object?

Answers

1.80 If I had to guess

The distance of the object from the mirror Is = –8 cm

Calculation of the object distance of a mirror

The image distance from the mirror = –1.60cm

The magnification of the image = 0.20

The distance of the object from the mirror can be calculated using the formula below:

magnification= – image distance/ object distance

Substitute the available values into the equation above,

0.20 = – 1.60/ X

Make X the subject of formula,

X = – 1.60/0.20

X = – 8cm

The negative sign indicates that the image is virtual which is formed behind the mirror.

Therefore, the distance of the object from the mirror Is = –8 cm.

Learn more about mirror equations here:

https://brainly.com/question/26257987

La resistividad de cierto alambre es 1.72x10 -8 Ωm a 20 oC .Una batería de 6v se conecta a una bobina de 20 m de este alambre, con un diámetro de 0.8 mm. ¿Cuál es la corriente en el alambre?

Answers

Answer:

   i = 1.09 10⁴ A

Explanation:

For this exercise we will look for the resistance of the wire

          R = ρ L / a

the area of ​​the wire is

          a =ππ r² = π πd² / 4

we substitute

         R = ρ L 4 / π d²

          R = 1.72 10⁻⁸   20  4/π 8 10⁻⁴

         

         R = 5.47 10⁻⁴ Ω

to calculate the current we use ohm's law

           V = R i

            i = V / R

            i = 6 / 5.47 10⁻⁴

            i = 1.09 10⁴ A

Which object will take the most force
to accelerate? *
4 kg
6 kg
8 kg
02 kg

Answers

Answer:

I think it might be 8kg grams because it is bigger

I WILL MARK YOU THE BRAINLIEST NO LINKS
What type of friction is acting on the airplane?
sliding friction
static friction
fluid friction
rolling friction

Answers

Answer:

I believe it's sliding friction.

Explanation:

Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The length of each rod is 1.1 m, while the mass of each is 0.10 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 11 mm. Determine the current in the rods.

Answers

Answer:

220 A

Explanation:

The magnetic force on the floating rod due to the rod held close to the ground is F = BI₁L where B = magnetic field due to rod held close the ground = μ₀I₂/2πd where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, I₂ = current in rod close to ground and d = distance between both rods = 11 mm = 0.011 m. Also, I₁ = current in floating rod and L = length of rod = 1.1 m.

So, F = BI₁L

F = (μ₀I₂/2πd)I₁L

F = μ₀I₁I₂L/2πd

Given that the current in the rods are the same, I₁ = I₂ = I

So,

F = μ₀I²L/2πd

Now, the magnetic force on the floating rod equals its weight , W = mg where m = mass of rod = 0.10kg and g = acceleration due to gravity = 9.8 m/s²

So, F = W

μ₀I²L/2πd = mg

making I subject of the formula, we have

I² = 2πdmg/μ₀L

I = √(2πdmg/μ₀L)

substituting the values of the variables into the equation, we have

I = √(2π × 0.011 m × 0.1 kg × 9.8 m/s²/[4π × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2 × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2.2 × 10⁻⁷ H])

I = √(0.0049 × 10⁷kgm²/s²H)

I = √(0.049 × 10⁶kgm²/s²H)

I = 0.22 × 10³ A

I = 220 A

A charge Q acts on a point charge to create an electric field. Its strength, measured a distance of 40 cm away is 100 N/C. What is the magnitude of the electric field strength at a distance of 20 cm

Answers

Answer:

[tex]E_2=80N/C[/tex]

Explanation:

From the question we are told that:

Initial Distance [tex]d_1=40cm=>0.4m[/tex]

Initial Electric field strength [tex]E_1=100N/C[/tex]

Final Distance [tex]d_2=20cm=>0.20m[/tex]

Generally the equation for Electric field is mathematically given by.

 [tex]E=\frac{kq}{d^2}[/tex]

 [tex]q=\frac{100*(0.4)^2}{K}[/tex]

Substituting q for [tex]d=20cm[/tex]

 [tex]E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}[/tex]

 [tex]E_2=80N/C[/tex]

In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger, what happens to the magnitude of difference between the incident and scattered wavelengths

Answers

Answer:

Increases

Explanation:

In the Compton scattering experiment with x-rays,

The change in operation

[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]

Now rest being constant, as \theta increases, cos\theta decreases

Hence, The change in wavelength will increase with the increase in \theta.

Hence, wavelength increases with an increase in the angle of scatttering.

help me calculate the kinetic energy (just the middle column) ASAP! SHOW WORK! ON PAPER

Answers

Answer:

Explanation:

I can tell you what the answers for the middle column are, but if you don't know how to solve total energy problems, they won't make any sense to you at all.

First row, KE = 0

Second row, KE = 220500 J

Third row, KE = 183750 J

Fourth row, KE = 205800 J

That's also not paying any attention to significant digits because your velocity only had 1 and that's not enough to do the problem justice. I left all the digits in the answer. Round how your teacher tells you to.

If a positively charged rod is brought near the knob of a positively charged electroscope, the leaves of the electroscope will...
A) converge, only
B) diverge, only
C) first diverge, then converge
D) first converge, then diverge

Answers

I think it’s gonna be A.

Answer:

B

Explanation:

if a positively charged rod is brought near the knob of a neutral electroscope, it will attract some electrons up from the leaves onto the knob. That process causes both of the leaves to be positively charged (excess protons), and the leaves will diverge.

In what way may the turning effect of a force be increased?

By decreasing the perpendicular distance between the force and the pivot point

By lubricating the fulcrum with oil or grease.

By increasing the perpendicular distance between the force and the pivot point.

By reducing the applied force

Answers

Answer:

By increasing the perpendicular distance between the force and the pivot point

Explanation:

Due to the formula [tex]force * distance[/tex],

An increase in distance would cause the turning force to increase

Feel free to mark it as brainliest :D

What are the si units

Answers

Answer:

The uniy which is accepted all over the world is called SI unit.

Explanation:

The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.

True or false
scientific research has now proven that atoms are composed of parts that are larger than protons neutrons and electrons

Answers

Answer:

False

Explanation:

parts that are smaller than protons neutrons and electrons

False .......hope this helped you out

ACELLUS PHYSICS HELP!!

A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)​

Answers

Answer:

Potential difference, V = -0.000224 Volts

Explanation:

Given the following data;

Quantity of charge = 6.93*10-4 C

Energy = -3.09 J

To find the electric potential V at that point?

Mathematically, the energy transferred per unit of charge is given by the formula;

E = QV

Where:

E is the energy

Q is the quantity of charge

V is the potential difference.

Substituting into the formula, we have;

[tex] -3.09 = 6.93*10^{-4} * V [/tex]

[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]

Potential difference, V = -0.000224 Volts

As shown in the diagram below, a 1 kg rock tied to a rope is
swung by a boy. This rock has a constant speed of 5 m/s,
and the length of the rope is 1 m. The rock's angular
momentum is

Answers

Answer:

Explanation:

Angular momentum has a formula of L = mvr. Fillingin:

L = (1.0)(5.0)(1.0)

L = 5.0 kg*m/s

Explain how frequency and amplitude affect sound vibrations?

Answers

Answer:

The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.

Explanation:

A (200 g) of water at (80 °C) is mixed with (100 g)of water at (20 °C). What is the final temperature of the water?

Answers

Answer:

60 °C

Explanation:

From the question given above, the following data were obtained:

Mass of 1st sample (M₁) = 200 g

Temperature of 1st sample (T₁) = 80 °C

Mass of 2nd sample (M₂) = 100 g

Temperature of 2nd sample (T₂) = 20 °C

Equilibrium temperature (Tₑ) =?

NOTE: Since the sample are the same, the specific heat capacity is constant.

We can obtain the equilibrium temperature as follow:

Heat lost by 1st = heat gained by the 2nd

M₁C(T₁ – Tₑ) = M₂C(Tₑ – T₂)

Cancel out C

M₁(T₁ – Tₑ) = M₂(Tₑ – T₂)

200 (80 – Tₑ) = 100 (Tₑ – 20)

Clear bracket

16000 – 200Tₑ = 100Tₑ – 2000

Collect like terms

16000 + 2000 = 100Tₑ + 200Tₑ

18000 = 300Tₑ

Divide both side by 300

Tₑ = 18000 / 300

Tₑ = 60 °C

Therefore, the equilibrium temperature (i.e the final temperature) of the mixture is 60 °C.

Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.

Answers

Answer:

Jan Hendrik Schön I believe

Astronomical observatories have been available since ancient times, and many cultures set aside special sites for astronomical observations. The thing modern observatories have that was missing from these older observatories until about 1610 was __________________. Group of answer choices

Answers

Answer:

The answer is "telescopes".

Explanation:

Throughout ancient times, astronomical observatories have indeed been available, and so many historical locations were reserved for astronomical observations. All contemporary astronomers lacked within those older telescopes were lenses until 1610. A telescope is indeed an instrument used to view far-off objects. Telescopes often are being used to look at planets and stars.

Which of the following changes occurs during nuclear fission?
A. Energy is absorbed from the surroundings.
B. Atomic nuclei combine to form a larger nucleus.
C. Energy is converted into mass.
D.
The parent nucleus splits into lighter daughter elements.
Reset

Answers

Answer:

The parent nucleus splits into lighter daughter elements

Explanation:

Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles

a car moving with a speed of 10 metre per second is accelerator at the rate of 2 metre per second square find its velocity after 6 seconds​

Answers

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

The switch in a circuit breaker opens when which of the following in the circuit becomes too high?
A) current
B) resistance
C) static charge
D) total charge

Answers

Answer:

b) resistance

Explanation:

since resistance is responsible for heating, if it increases the circuit breaker opens breaking the flow of current to the circuit and thus preventing short circuits.

A piston is resting halfway into a cylinder containing gas in thermal equilibrium. The layer of molecules next to the closed end of the cylinder is suddenly flash-heated to a very high temperature. Which best describes what happens next

Answers

Answer: hello the options related to your question is missing attached below are the missing options

answer : The molecules with the highest temperature will bounce off their neighbors, losing energy to them and so on until the system is at a new equilibrium with the piston moved out  ( option B )

Explanation:

What best describes the situation of what will happen next as explained in the question is in Option B

Because molecules with higher temperatures will always posses higher kinetic energy and they will collide more frequently with surrounding molecules passing on their energy in the process until the energy gets to the molecules closest to the piston. The molecules closest to the piston will then hit the piston until a new equilibrium is achieved

Electronic flash units for camera contain a capacitor for storing the energy used to produce the flash. In one such unit, the flash lasts for 1675s with an average light power output of 2.70 x 105 W . (a) If the conversion of electric energy to light is 95% efficient ( the rest of the energy goes to thermal energy), how much energy must be stored in the capacitor for one flash

Answers

Answer:

420J

Explanation:

Power is the time rate of change in energy. Power is the ratio of energy to time. The S.I unit of power is in watts.

Given that the flash lasts for 1/675 s, power output is 2.7 * 10⁵ W. Hence:

Power = Energy / time

Substituting:

2.7 * 10⁵ W = Energy / (1/675)

Energy = 2.7 * 10⁵ W * 1/675 = 400J

Therefore the energy emitted as light is 400J.

Since the conversion of electric energy to light is 95% efficient, hence the energy stored as electrical energy is:

Energy(capacitor) = 5% of 400J + 400J = 0.05*400 + 400

Energy(capacitor) = 420J

An aluminum-alloy rod has a length of 10.0 cm at 20°C and a length of 10.015 cm at the boiling point of water (1000C). (a) What is the length of the rod at the freezing point of water (0 0C)? (b) What is the temperature if the length of the rod is 10.009 cm? /4mks

Answers

Answer:

a.  9.99625 cm b. 68 °C

Explanation:

(a) What is the length of the rod at the freezing point of water (0 0C)?

Before we find the length of the rod, we need to find the coefficient of linear expansion, α = (L - L₀)/[L₀(T - T₀)] where L₀ = length of rod at temperature T₀ = 10.0 cm, T₀ = 20 °C, L = length of rod at temperature T = 10.015 cm and T = 100 °C

Substituting the values of the variables into the equation, we have

α = (L - L₀)/[L₀(T - T₀)]

α = (10.015 cm - 10.0 cm)/[10.0 cm(100 °C - 20 °C)]

α = 0.015 cm/[10.0 cm × 80 °C]

α = 0.015 cm/[800.0 cm °C]

α = 0.00001875 /°C

We now find the length L₁ at T₁ = 0 °C from

L₁ = L₀(1 + α(T₁ - T₀))

So, substituting the values of the variables into the equation, we have

L₁ = L₀(1 + α(T₁ - T₀))

L₁ = 10.0 cm[1 +  0.00001875 /°C(0° C - 20 °C)]

L₁ = 10.0 cm[1 +  0.00001875 /°C × -20° C]

L₁ = 10.0 cm[1 - 0.000375]

L₁ = 10.0 cm[0.999625]

L₁ = 9.99625 cm

(b) What is the temperature if the length of the rod is 10.009 cm?

With length L₃ = 10.009 cm at temperature T₃, using

L₃ = L₀(1 + α(T₃ - T₀))

making T₃ subject of the formula, we have

L₃/L₀ = 1 + α(T₃ - T₀)

L₃/L₀ - 1 = α(T₃ - T₀)

T₃ - T₀ = (L₃/L₀ - 1)/α

T₃ = T₀ + (L₃/L₀ - 1)/α

substituting the values of the variables into the equation, we have

T₃ = 20 °C + (10.009 cm/10.0 cm - 1)/0.00001875 /°C

T₃ = 20 °C + (1.0009 - 1)/0.00001875 /°C

T₃ = 20 °C + 0.0009/0.00001875 /°C

T₃ = 20 °C + 48 °C

T₃ = 68 °C

A bird in flight pushes itself upward with
a 7.28 N force. If the bird is climbing at a
constant rate of 1 m/s (no acceleration),
what is the weight of the bird?
[?] N

Answers

Answer:

The weight of the bird is equal to 7.28 N.

Explanation:

The upward force acting on the bird = 7.28 N

The bird is climbing at a constant rate of 1 m/s.

We need to find the weight of the bird.

We know that the weight of an object is the force of gravity acting on it. It can be calculated as follows :

W = mg

In this case, 7.28 N of force is acting on the object. Hence, the weight of the bird is equal to 7.28 N.

The voltage drop across any component is
the difference in voltage referenced to
between the two terminals of
the component.

Answers

Answer:

The voltage si the nevery Hokage de Naruto y fue su amigo

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