Answer:
(a) 3:5
(b) 15
Step-by-step explanation:
Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.
It is asking for unshaded first so our ratio will be,
3:5
(a) 3:5
So if there is 9 unshaded how many shaded is there.
Well we can just make the following ratio 9:x
So 9/3 = 3
Meaning 3*5 = 15
So x = 15
(b) 15
Answer:
a) 3/5
b) 15
Step-by-step explanation:
(a)
unshaded: 3
shaded: 5
unshaded to shaded: 3/5
(b)
There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.
Add two more lines just like the given line.
Each new line will have 5 shaded and 3 unshaded squares.
Now you have a total of 9 unshaded and 15 shaded squares.
Which circle has a central angle that measures 40°?
Circle U is shown. Line segment Z X is a diameter. Line segment V X is a secant. Angle V X Z is 40 degrees.
Circle U is shown. Line segments U V and U Z are radii. Angle V U Z is 40 degrees.
Circle U is shown. Line segment Z V is a secant. Line segment Z X is a tangent. Angle X Z V is 40 degrees.
Circle U is shown. Line segments X V and X Z are secants. Angle V X Z is 40 degrees.
Answer:
Option B.
Step-by-step explanation:
We need to find the circle that has a central angle that measures 40°.
In all options, the center of circle is U. It means central angle must be on center, i.e., U.
In option A,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.
In option B,the angle VUZ is at point U which is the center. So, angle VUZ is a central angle with measure 40°.
In option C,the angle XZV is at point Z which is not the center. So, angle XZV is not a central angle.
In option D,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.
Therefore, the correct option is B.
Answer:
it is B
Step-by-step explanation:
We need to find the circle that has a central angle that measures 40°.
In all options, the center of circle is U. It means central angle must be on center, i.e., U.
In option A,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.
In option B,the angle VUZ is at point U which is the center. So, angle VUZ is a central angle with measure 40°.
In option C,the angle XZV is at point Z which is not the center. So, angle XZV is not a central angle.
In option D,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.
Therefore, the correct option is B.
Consider three boxes containing a brand of light bulbs. Box I contains 6 bulbs
of which 2 are defective, Box 2 has 1 defective and 3 functional bulbs and Box 3
contains 3 defective and 4 functional bulbs. A box is selected at random and a bulb
drawn from it at random is found to be defective. Find the probability that the box
selected was Box 2.
Answer:
1/6
Step-by-step explanation:
As we already know that selected bulb is defective the required probability doesn't depend on functional bulbs at all.
The probability, that selected defective bulb is from Box2 is number of defective bulbs in Box 2 divided by total number of defective bulbs.
P(defective in box 2)= N(defective in box 2)/N(defective total)
As we know there is only 1 defective lamp in box 2.
So N(defective in box 2)=1
Total number of defective bulbs is Box1- 2 defective bulbs, box2- 1 defective bulbs, box3 - 3 defective bulbs. Total are 6 defective bulbs.
So N(defective total)=6
So P(defective in box 2)=1/6
A pool that is 2.9 m tall cast a shadow that is 1.76 m long. At the Same time, a nearby building casts a shadow that is 38.25m long how tall is the building? round your answer to the nearest meter
Answer:
63m
Step-by-step explanation:
A pool that is 2.9m tall cast a shadow that is 1.76m
At the same time, a nearby building casts a shadow that is 38.25m long.
We are to find the height of the building.
If an object of length 2.9m cast an image of 1.76m ,
Then an image of 38.25m willl be cast by an object of what length?
Cross multiplying this gives:
[tex]\frac{38.25 * 2.9}{1.76}[/tex] = 63.02556818 = 63m (rounded up to nearest meter)
Multiply (2.0 ⋅ 10−4) ⋅ (3.1 ⋅ 10−20). Express the answer in scientific notation. 6.2 ⋅ 10−80 6.2 ⋅ 10−24 6.2 ⋅ 1024 6.2 ⋅ 1080
Answer:
6.2* 10 ^-24
Step-by-step explanation:
(2.0 ⋅ 10−4) ⋅ (3.1 ⋅ 10−20)
Multiply the numbers
2.0 * 3.1 =6.2
Add the exponents
10 ^-4 * 10 ^-20 = 10 ^( -4+-20) = 10 ^ -24
Put back together
6.2* 10 ^-24
The number is in scientific notation since there is one nonzero digit in front of the decimal
Answer:
B, now give the other person brainlist
The perimeter of an equilateral triangle with a side length of 12 units is:
Answer:
Hey there!
An equilateral triangle has all sides equal to each other, so the perimeter would be 3x, where x is the length of one side.
Thus, the perimeter for this equilateral triangle would be 3(12)=36
Hope this helps :)
Answer:
[tex]\boxed{Perimeter = 36 \ units}[/tex]
Step-by-step explanation:
Perimeter = sum of all sides
Perimeter = 12 +12 + 12
Perimeter = 36 units
What is the distance betweem points W and X to the nearest hundredth?
Answer:
16.97 Units
Step-by-step explanation:
From the graph
Point W is located at (-6,4)
Point X is located at (6,-8)
To determine the distance between points W and X, we use the distance formula.
[tex]\text{Distance Formula}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex](x_1,y_1)=(-6,4)\\(x_2,y_2)=(6,-8)[/tex]
So,
[tex]WX=\sqrt{(6-(-6))^2+(-8-4)^2} \\=\sqrt{(6+6)^2+(-12)^2}\\=\sqrt{(12)^2+(-12)^2}\\=\sqrt{288}\\=16.97$ units (correct to the nearest hundredth)[/tex]
The answer choices below represent different hypothesis tests. Which of the choices are one-tailed tests? Select all correct answers. Select all that apply: H0:p=0.46, Ha:p<0.46 H0:p=0.34, Ha:p≠0.34 H0:p=0.63, Ha:p≠0.63 H0:p=0.35, Ha:p≠0.35 H0:p=0.39, Ha:p<0.39
Answer:
H0:p=0.46, Ha:p<0.46
H0:p=0.39, Ha:p<0.39
Step-by-step explanation:
A one tailed test occurs in such a way that the value/results gotten is one sided and can either be lesser or greater than the particular given value but cannot be both.
Thus, in this case a one sided test includes
H0:p=0.46, Ha:p<0.46
H0:p=0.39, Ha:p<0.39
Question 6 of 10
Which equation matches the graph of the greatest integer function given
below?
Suppose taxi fares from Logan Airport to downtown Boston is known to be normally distributed and a sample of seven taxi fares produces a mean fare of $21.51 and a 95% confidence interval of [$20.52, $22.48]. Which of the following statements is a valid interpretation of the confidence interval?
a. 95% of all taxi fares are between $20.52 and $22.48.
b. We are 95% confident that a randomly selected taxi fare will be between $20.52 and $22.48.
c. We can report that the average taxi fare between Logan Airport and downtown Boston will fall between $20.52 and $22.48.
d. With 95% confidence
Answer:
The correct option is C
Step-by-step explanation:
From the question we are told that
The sample mean is [tex]\= x =[/tex]$21.51
The 95% confidence level interval is [$ 20.52 , $22.48]
Generally the 95% confidence level interval is mathematically represented as
[tex]\= x - MOE < \mu < \= x + MOE[/tex]
Where MOE is the margin of error which defines in percentage the amount by which the sample mean taxi fare(for the 7 taxi ) will differ from the average taxi fare between Logan Airport and downtown Boston will fall between
Also [tex]\mu[/tex] is the average taxi fare between Logan Airport and downtown Boston
So we see that the this 95% confidence level interval tells us that the average taxi fare between Logan Airport and downtown Boston will fall between $20.52 and $22.48.
Which expression is equivalent to x^-5/3?
Answer:
[tex]\frac{1}{(\sqrt[3]{x} )^5}[/tex]
Step-by-step explanation:
[tex]x^{-\frac{5}{3} }[/tex] = [tex](\sqrt[3]{x} )^{-5}[/tex] = [tex]\frac{1}{(\sqrt[3]{x} )^5}[/tex]
Please help with 4d.
Answer:
(Hemingway, The Old Man and the Sea)(Orwell, 1984)Step-by-step explanation:
A short web search will turn up the authors of the given titles:
The Old Man and the Sea - Hemingway
Huckleberry Finn - Twain
Moby D.ick - Melville
1984 - Orwell
Crime and Punishment - Dostoevsky
The length of a side of a square is \sqrt(x^(2)-4) If the area of the square is 12, find x. A. 16 B. 4 C. 12 D. \sqrt(148)
Answer:
B. 4
Step-by-step explanation:
Let the side of the square= a
Then the area of the square= a²
Given:
a= √x²-4 and a²=12Then:
a²= (√x²-4 )²= x²-4Considering the value of the area, 12 units
x²-4 =12x²=16x= √16x= ±4x= -4 is not considered as the length can't be negativex= 4 is the answerCorrect choice is B. 4
A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is cubic units. A cylinder with the same height and radius as the cone will have a volume of cubic units. If a sphere has the same radius as the cylinder, its volume is the volume of the cylinder.
The above question is not complete because it was not written and arranged properly
Complete Question
1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.
2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.
3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder.
Answer:
1) Volume of the cone = 134.04cubic units
2)Volume of the cylinder = 402.12cubic units
3) Volume of the sphere= 268.08 cubic units. Hence, if a sphere has the same radius as the cylinder, its volume is 2/3 times the volume of the cylinder.
Step-by-step explanation:
1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.
Volume of a cone = 1/3πr²h
h = 8 units
r = 4 units
Volume = 1/3 × π × 4² × 8
134.04cubic units
2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.
Volume of a cylinder = πr²h
Height and radius is the same as that of the cones hence,
h = 8 units
r = 4 units
= π × 4² × 8
= 402.12cubic units.
3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder.
Volume of a Sphere = 4/3πr³
r = radius of the cylinder = 4 units
Volume of a Sphere = 4/3 × π × 4³
= 268.08 cubic units.
From the above question, we are asked to compare the volume of the sphere with the volume of the cylinder
Volume of the sphere : Volume of the cylinder
268.08 cubic units : 402.12 cubic units
268.08/402.12 = 2/3
Therefore, the volume of the sphere is 2/3 times the volume of the cylinder
Please answer this correctly without making mistakes
Answer:
Step-by-step explanation:
2.8 kilometers farther. Subtract 12.1km for Winchester and 9.3 for Stamford to get 2.8 kilometers.
Find a solution to the linear equation 9x+4y=−36 by filling in the boxes with a valid value of x and y.
Answer:
Please look at the picture below!
Step-by-step explanation:
Hope this helps!
If you have any question, please feel free to ask any time.
Find the equation of the line: parallel to 3x−y=11 through (−2, 0).
Answer:
[tex]\huge\boxed{y=3x+6\to 3x-y=-6}[/tex]
Step-by-step explanation:
[tex]\text{Let}\ k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\===========================[/tex]
[tex]\text{We have the equation of a line in the standard form:}\ 3x-y=11.\\\text{Convert it to the slope-intercept form:}\ y=mx+b\\\\3x-y=11\qquad\text{subtract}\ 3x\ \text{from both sides}\\-y=-3x+11\qquad\text{change the signs}\\y=3x-11\to \boxed{m_1=3}\\\\\text{Let}\ k:y=3x-11\ \text{and}\ l:y=mx+b.\\\\l\ ||\ k\Rightarrow l:y=3x+b\\\\\text{Substitute the coordinates of the point}\ (-2;\ 0)\ \text{to the equation of}\ l:\\\\0=3(-2)+b\\0=-6+b\qquad\text{add 6 to both sides}\\6=b\to\boxed{b=6}[/tex]
[tex]\text{Finally}\ l:y=3x+6\\\\\text{Convert to the standard form:}\\\\y=3x+6\qquad\text{subtract}\ 3x\ \text{from both sides}\\-3x+y=6\qquad\text{change the signs}\\l:\ 3x-y=-6[/tex]
Identify the CONCLUSION of a hypothesis test of the following claim and sample data: Claim: "The average annual household income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.
Complete Question
The options for the above question is
a There is not sufficient evidence to warrant rejection of the claim.
b There is sufficient evidence to warrant rejection of the claim.
c There is sufficient evidence to support the claim.
d There is not sufficient evidence to support the claim.
Answer:
Option A is correct
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu =[/tex]$47,500
The sample size is [tex]n = 86[/tex]
The sample mean is [tex]\= x =[/tex]$48,061
The standard deviation is [tex]\sigma =[/tex]$2,351
The level of significance is [tex]\alpha = 0.02[/tex]
The null hypothesis is
[tex]H_o : \mu =[/tex]$47,500
The alternative hypothesis is
[tex]H_a : \mu \ne[/tex] $47,500
The critical value of [tex]\alpha[/tex] from the t-Distribution table is [tex]Z_{\frac{\alpha }{2} } = 2.326[/tex]
Now the test statistics is mathematically evaluated as
[tex]t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }[/tex]
substituting values
[tex]t = \frac{48061 - 47500 }{\frac{2351}{\sqrt{86} } }[/tex]
[tex]t = 2.21[/tex]
Now from the values obtained we can see that
[tex]Z_{\frac{\alpha }{2} } > t[/tex]
hence we fail to reject the null hypothesis
Hence there is not sufficient evidence to warrant rejection of the claim
Find the equation for the plane through the point Upper P 0equals(2 comma 5 comma 9 )and normal to the vector nequals5 Bold i plus 8 Bold j plus 2 Bold k.
Answer:
5x+8y+2z = 68
Step-by-step explanation:
Given the point P0 = (2, 5, 9), to Find an equation for a plane through that point and normal to the vector n = 5i+8j+2k the following steps must be followed:
The equation for the plane passing through the point is expressed as;
a(x-x0)+b(y-y0)+c(z-z0) = 0 where;
(x0, y0, z0) is the point on the plane and (a,b,c) is the normal vector n.
Given the point (2, 5, 9) and normal vector n =(5, 8, 2)
x0 = 2, y0 = 5, z0 = 9, a = 5, b = 8 and c= 2.
Substituting this values into the equation of the plane above will give;
5(x-2)+8(y-5)+2(z-9) = 0
On expansion:
5x-10+8y-40+2z-18 = 0
5x+8y+2z-10-40-18 = 0
5x+8y+2z-68 = 0
The required equation of the plane is 5x+8y+2z = 68
Your PI claims that the proportion of Morpho butterflies in a population that are blue is 0.3 .A sample is independently obtained from this population. Of 200 sampled Morphos, 50 turn out to be blue.Given only this information, carry out a hypothesis test to evaluate the claim. What is closest to the p-value that you obtain?
Complete Question
Your PI claims that the proportion of Morpho butterflies in a population that are blue is 0.3 .A sample is independently obtained from this population. Of 200 sampled Morphos, 50 turn out to be blue.Given only this information, carry out a hypothesis test to evaluate the claim. What is closest to the p-value that you obtain?
A 0.019
B 0.038
C 0.070
D 0.139
Answer:
The correct answer is D
Step-by-step explanation:
From the question we are told that
The population proportion of blue butterflies is [tex]p = 0.3[/tex]
The sample size is [tex]n = 200[/tex]
The sample mean is [tex]\= x = 50[/tex]
The Null Hypothesis is mathematically represented as
[tex]H_o : p = 0.3[/tex]
The Alternative Hypothesis is mathematically represented as
[tex]H_a : p \ne 0.3[/tex]
Now the sample proportion is mathematically represented as
[tex]\r p = \frac{\= x}{n}[/tex]
substituting values
[tex]\r p = \frac{50 }{200 }[/tex]
[tex]\r p = 0.25[/tex]
Generally the test statistics is mathematically represented as
[tex]z = \frac{\r p - p }{\sqrt{\frac{p(1-p)}{n } } }[/tex]
substituting values
[tex]z = \frac{ 0.25 - 0.3 }{\sqrt{\frac{0.3(1-0.3)}{200 } } }[/tex]
[tex]z = -1.54[/tex]
The p-value for a two-tailed test is mathematically represented as
for lower -tail test
[tex]p-value = P(Z \le z | H0\ is \ true) = cdf(z )[/tex]
for higher-tail test
[tex]p-value = P(Z \ge z | H0\ is \ true) = 1- cdf(z )[/tex]
for this test i assumed a 0.05 level of significance
Now
[tex]cdf(z)[/tex] is the cumulative distribution function for test statistics under the null hypothesis
Which can be calculated using MInitab (A statistics calculator )
for lower-tail test
The p-value is not significant
for higher-tail test
p-value is
[tex]1- cdf(-1.54) = 0.125[/tex]
the product of 12 and K is 84 solve for K K =
Answer: k = 7
Step-by-step explanation:
12k=84
Divide(12)
k=7
Hope it helps <3
Answer:
7Step-by-step explanation:
The product of 12 and k is 84
let's create an equation:
[tex]12k = 84[/tex]
Divide both sides of the equation by 12
[tex] \frac{12 \: k}{12} = \frac{84}{12} [/tex]
Calculate
[tex]k = 7[/tex]
Hope this helps...
Best regards!!
mark wants to invest $10,000 for his daughter’s wedding. Some will go into a short term CD that pays 12% and the rest in a money market savings account that pays 5% interest. How much should he invest at Each rate if he wants to earn $1095.00 in interest in one year.
What is the value of x?
Answer:
13=x
Step-by-step explanation:
Since BE is a bisector
ABE = EBC
2x+20 = 4x-6
Subtract 2x from each side
2x+20-2x =4x-6-2x
20 = 2x-6
Add 6 from each side
20+6 = 2x-6+6
26 = 2x
Divide each side by 2
26/2 = 2x/2
13=x
Answer:
x = 13
Step-by-step explanation:
The angle bisector theorem means that m<ABE = m<EBC. Now that we know they are equal, we can set the equations to each other and solve for x.
2x + 20 = 4x - 6
26 = 2x
13 = x
So the value of x is 13.
Cheers.
What is the value of the rate of change when we put a glass of water at room temperature in the freezer for 15 minutes, what is its temperature at 5 minutes and then at 10 minutes
Answer:
Step-by-step explanation:
I do not understand your question very well but I think that the state of the glass of the water would be liquid and solid at the same time since the water would not freeze 100% and would be with small pieces of solid and some parts liquid, in terms of temperature, I think that at 5 minutes it would be 5 ° C and at 10 it would be 3-4 ° C the longer it is in the freezer the less its temperature will be
(All of that is my point of view)
Average temperature 30 °
So :
30 ÷ 15 = 2 °
30 ÷ 10 = 3 °
30 ÷ 5 = 6 °
Use the minimum and maximum data entries and the number of classes to find the class width, the lower class limits, and the upper class limits. min = 14, max = 121, 8 classes
Answer:
The class width is [tex]C_w \approx 13[/tex]
Step-by-step explanation:
From the question we are told that
The upper class limits is [tex]max = 121[/tex]
The lower class limits is [tex]min = 14[/tex]
The number of classes is [tex]n = 8 \ classes[/tex]
The class width is mathematically represented as
[tex]C_w = \frac{max - min}{n }[/tex]
substituting values
[tex]C_w = \frac{121 - 14}{8 }[/tex]
[tex]C_w = 13.38[/tex]
[tex]C_w \approx 13[/tex]
Since
Datguy323 is going to complain again. What's the variables for: [tex]x^2+y^2=29\\x+y=7[/tex]
y<4
Answer: :o I FINALLY MADE IT
(5, 2)
x = 5
y = 2
Step-by-step explanation:
First, I graphed both equations. They meet at the points (5,2) and (2,5). Because y < 5, the solution is (5, 2)
Hope it helps <3
Answer:
[tex]x=5\\y=2[/tex]
Step-by-step explanation:
[tex]x^2 +y^2 =29[/tex]
[tex]x+y=7[/tex]
Solve for x in the second equation.
[tex]x+y=7[/tex]
[tex]x+y-y=7-y[/tex]
[tex]x=7-y[/tex]
Plug in the value for x in the first equation and solve for y.
[tex](7-y)^2 +y^2 =29[/tex]
[tex]y^2-14y+49+y^2 =29[/tex]
[tex]2y^2-14y+20=0[/tex]
[tex]2(y-2)(y-5)=0[/tex]
[tex]2(y-2)=0\\y-2=0\\y=2[/tex]
[tex]y-5=0\\y=5[/tex]
[tex]y<4[/tex]
[tex]y=2[/tex]
[tex]y\neq 5[/tex]
Plug y as 2 in the second equation and solve for x.
[tex]x+y=7[/tex]
[tex]x=7-y[/tex]
[tex]x=7-2[/tex]
[tex]x=5[/tex]
In the equation, the value of a is:
Answer:
Please check if the answer is a = 4 or not
The vertices of a triangle are given in the columns of the matrix T= [0,4,0,0,0,5] If [-1,0,0,-1] is found to preform a transformation, what are the coordinates of the transformed triangle?
Answer:
(0,0), (-4,0), (0,-5).
Step-by-step explanation:
Note: Matrices are not in proper format.
Consider the given matrix is
[tex]T=\begin{bmatrix}0&4&0\\0&0&5\end{bmatrix}[/tex]
It means vertices are (0,0), (4,0) and (0,5).
Transformation matrix is
[tex]A=\begin{bmatrix}-1&0\\0&-1\end{bmatrix}[/tex]
To find the coordinates of the transformed triangle multiply both matrices and calculate matrix AT.
[tex]AT=\begin{bmatrix}-1&0\\0&-1\end{bmatrix}\begin{bmatrix}0&4&0\\0&0&5\end{bmatrix}[/tex]
[tex]AT=\begin{bmatrix}\left(-1\right)\cdot \:0+0\cdot \:0&\left(-1\right)\cdot \:4+0\cdot \:0&\left(-1\right)\cdot \:0+0\cdot \:5\\ 0\cdot \:0+\left(-1\right)\cdot \:0&0\cdot \:4+\left(-1\right)\cdot \:0&0\cdot \:0+\left(-1\right)\cdot \:5\end{bmatrix}[/tex]
[tex]AT=\begin{bmatrix}0&-4&0\\ 0&0&-5\end{bmatrix}[/tex]
It means coordinates of the transformed triangle are (0,0), (-4,0), (0,-5).
Answer:
A
Step-by-step explanation:
E2020
Factor.
-7x2 + 49x
-7(x - 7)
01 - 7x2 + 49x)
-x(x – 7)
-7x(x – 7)
Answer:
Option 1: -7x (x - 7)
Step-by-step explanation:
Factor -7x out of -7x^2.
= -7x (x) + 49x
Factor -7x out of 49x.
= -7x (x) -7x (-7)
Factor -7x out of -7x (x) - 7x (-7).
= -7x (x - 7)
(Also I took the test and got this answer right)
Suppose the results indicate that the null hypothesis should not be rejected; thus, it is possible that a type II error has been committed. Given the type of error made in this situation, what could researchers do to reduce the risk of this error? Choose a 0.01 significance level, instead of a 0.05 significance level. Increase the sample size.
Answer:
Increase the sample size.
Step-by-step explanation:
Increasing the sample size is the best way to reduce the likelihood of a type II error.
The type II error occurs when a hypothesis test accepts a false null hypothesis. That is, it fails to reject the null hypothesis that is false.
In such a situation, to increase the power of the test, you have to increase the sample size used in the test. The sampling size has the ability to detect the differences in a hypothesis test.
We have a bigger chance of capturing the difference if the sample size is larger, and it also increases the power of the test.
Which of the following points is a solution of the inequality y <-Ixl
You did not give any options but i will try to answer.
y < -lxl basically means that the value of y is less than the absolute value of x time - 1.
So if x = 2, then y is any number less than -2.
And if x is -3. then y is any number less than -3.
Happy to help!