Answer:
V = 146.87 L
Explanation:
Given data:
Mass of sample = 14.0 g
Pressure of sample = 120 kpa
Volume of gas = ?
Temperature of gas = 30°C
Solution:
Number of moles of gas:
Number of moles = mass/molar mass
Number of moles = 14.0 g/ 2 g/mol
Number of moles = 7 mol
Pressure of gas:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 8.31 KPa.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
by putting values,
120 KPa × V = 7 mol × 8.31 KPa.L/ mol.K × 303 K
V = 17625.51 KPa .L/ 120 KPa
V = 146.87 L
73 gram of HCl was filluted by adding 144gram of water.how many gram atom of hydrogen are present in the dilute acid?
Mass of Hydrogen atoms : 18 g
Further explanationGiven
73 gram of HCl
144gram of H₂O
Required
Mass (gram) atom of Hydrogen
Solution
H atoms are in 2 compounds, H₂O and HCl, so we calculate their mass in each compound
mass H in H₂O :[tex]\tt \dfrac{1}{36.5}\times 73=2~g[/tex]
mass H in HCl :
[tex]\tt \dfrac{2}{18}\times 144=16~g[/tex]
total mass = 2 g+ 16 g = 18 g
54:63 ratio simplest form?
Answer:
The fraction is 6/7
Explanation:
6/7 is the simplified fraction for 54/63 by using the GCD or HCF method. Thus, 6/7 is the simplified fraction for 54/63 by using the prime factorization method.
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