Answer: The pressure exerted on a surface by an object increases as the surface area of contact decreases.
Explanation:
Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.
As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!
Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has a mass of 25 kg and a KE of 450 J.
How fast is the first kid running?
I really need help
Answer:
1mph
Explanation:
A force of 10N is making an angle of 300 with the horizontal. Its horizontal components will be
Answer: 5N
Explanation:
Horizontal component is the force that is applied as a result of the diagonal application of force.
here in this case,
given diagonal force =10N.
angle= 30°
horizontal component is found using trigonometry..
so,
A vector of magnitude 10 N is provided.
It is at an angle of 30° to the + x axis.
To find:
The components along the x and y axis.
Calculation:
Along x axis:
F(x) = F cos(θ)
=> F(x) = 10 × cos(30)
=> F(x) = 10 (√3/2) = 5√3N
Along y axis:
F(y) = F sin(θ)
=> F(y) = 10 sin(30°)
=> F(y) = 10 × ½
=> F(y) = 5 N.
Additional information:
1. A vector is a quantity that can be defined with both magnitude and direction.
2. Since force is a vector, we are able to break it down into components along chosen axis.
You apply a 325 N force to a heavy crate with a rope that makes a 29.0° angle with the horizontal, if you pull the crate a distance of 5.37 m, how much work was done by you?
Answer:
W = 1526.43 J
Explanation:
Given that,
Force acting on a heavy crate, F = 325 N
The rope will make 29.0° angle with the horizontal
The distance covered by the crate, d = 5.37 m
We need to find the work done by the crate. The work done by an object is given by :
[tex]W=Fd\cos\theta\\\\=325 \times 5.37\times \cos29\\\\=1526.43\ J[/tex]
So, the required work done is 1526.43 J.
Cuál es la diferencia entre fricción beneficiosa y perjudicial? Pon 5 ejemplos de cada uno.
Answer:
Difference is given below.
Explanation:
The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.
An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's velocity when it hits the ground? (Show your work and do not forget units)
Answer :
556.59 m/s.
Explanation:
Given that,
An airplane is traveling at an altitude of 15,490 meters.
A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.
The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :
[tex]v^2-u^2=2as[/tex]
Put u = 0 and a = g
[tex]v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s[/tex]
So, when it hits the ground its velocity is 556.59 m/s.
In uniform circular motion, the factor that remains constant is.............
Answer:
When a body is in uniform circular motion, its speed remains constant but its velocity, angular acceleration, angular velocity changes due to change in its direction.