(5372 + 100y^2) + 5(10y^2 – 110) Add the two polynomials and write in the form ay^2 + b, where a and b are constants, What is the value of a + b?

Answer:

The value of a is 150 and b is 4822.

Explanation:

First, you have to expand to remove brackets :

[tex](5372 + 100 {y}^{2} ) + 5(10 {y}^{2} - 110)[/tex]

[tex] = 5372 + 100 {y}^{2} + 50 {y}^{2} - 550[/tex]

Next, you have to simplify :

[tex]100 {y}^{2} + 50 {y}^{2} + 5372 - 550[/tex]

[tex] = 150 {y}^{2} + 4822[/tex]

Next, you have to compare it :

[tex]a {y}^{2} + b = 150 {y}^{2} + 4822[/tex]

[tex]a = 150[/tex]

[tex]b = 4822[/tex]

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