5. Infer if a water molecule (H20) has two hydrogen atoms and one oxygen atom, how would you describe the make- up of a carbon dioxide molecule (CO2)?

(please help)​

Answer:

Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.

Explanation:

Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.

The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.

Answer:See explanation

Explanation:

MOLECULAR REACTION EQUATION;

Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)

complete ionic equation:

Al^3+(aq) + 3NO3^-(aq)  + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)

Net ionic reaction equation;

Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]

Thus, the price is:

[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]

Best regards!

Answer:

168.56

Explanation:

Answer:

48 grams

Explanation:

If p and V are already given, calculate m by multiplying those two values.

m = pV

m = 4/5 * 60/1

m = 240/5

m = 48 grams

The mass of that substance is 48 grams.

Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 12.55 g/ 180.156 g/mol

Number of moles = 0.069 mol

Volume in L:

500 mL × 1 L /1000 mL

0.5 L

Molarity:

M = 0.069 mol / 0.5 L

M = 0.138 M

The mass of the acid : 75.64 g

Given

volume = 48.8 ml

density = 1.55 g/ml

Required

the mass

Solution

Further explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

 Density formula:

[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]

Input the value :

mass = ρ x V

mass = 1.55 g/ml x 48.8 ml

mass = 75.64 g

Answer:it has one proton,

and one electron

Explanation:

It has one neutron and It has one nucleon

Answer:

32.76mole of P

Explanation:

The reaction expression is given as;

          P₄O₁₀  →    4P  +  5O₂

Given parameters:

Number of moles of   P₄O₁₀  = 8.19mol

Unknown:

Number of moles of P produced = ?

Solution:

From the balanced reaction expression;

             1 mole of P₄O₁₀  will produce 4 mole of P

         8.19mole of P₄O₁₀  will therefore produce 4 x 8.19  = 32.76mole of P

Answer:

True

Explanation:

When ice is heated, the ice gains heat.

This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.

Answer:

We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.

Explanation:

Details:

Density of Copper= 8.96 g/ml

Volume of Copper=141 ml

mass of Gold = mass of Copper

Density of Gold=19.3 g/ml

In order to solve for the mass of copper, we need to use the density formula

Density= mass/volume

Since we are to solve for the mass of copper

mass of copper= Density of Copper * Volume of Copper

mass of copper= 8.96 g/ml* 141 ml= 1263.36 g

Thus,

mass of gold=mass of copper=1263.36 g

Hence,

Using still the density formula to solve for the volume of gold,

Volume of gold=mass of gold/ Density of gold

Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL

Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper

Answer:

Mole fraction for benzene is 0.683

Explanation:

We need to determine the colligative property about vapour pressure which formula is:

ΔP = P° . Xm

where P° is vapour pressure of pure solvent.

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.

P° of benzene at 20°C is 74.7 Torr

Xm is the value for the mole fraction of solute.

Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm

Xm = 0.317 → That's the mole fraction for toluene.

Then, mole fraction for benzene will be: 1 - 0.317 → 0.683

Answer:

electron and ignore this woejdnks

Answer:

Some places have more earthquakes than others because they sit on the edges of tectonic plates.

Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol

Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]

[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol

Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol

Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]

[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]

[tex]2\Delta H=17.2-364.64[/tex]

[tex]\Delta H=-173.72[/tex]

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

Answer:

The Aluminium sample

Explanation:

From the question,

ΔQ of the iron = Cm(t₂-t₁)........................ Equation 1

Given: C = specific heat capacity of iron, m = mass of iron, t₁ and t₂ = initial and final temperature respectively.

Given: m = 175 g = 0.175 kg, t₂ = 21.5°C, t₁ = 99.7°C

Constant: C = 444 J/kgK.

Substitute into equation 1

ΔQ = 0.175(444)(21.5-99.7)

ΔQ = -6076.14 J

Similarly, for aluminium,

ΔQ' = c'm'(t₂-t₁)...................... Equation 2

Given: m' = 175 g = 0.175 kg,

Constant: 900 J/kgK

ΔQ' = 0.175(900)(21.5-99.7)

ΔQ' = -12316.5 J

Hence the aluminium sample undergoes the greater heat change

Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure

Explanation:

Answer:

12.49 ml

Explanation:

Density = mass / volume

Volume = mass / density

Volume of zinc = 2.54/7.14

Volume of zinc = 0.3557

Initial volume = 12.13 ml

Total volume = initial volume+ volume of zinc

Total volume = 12.13 + 0.3557

Total volume = 12.4857 = 12.49 ml

Answer:

d. none of the above (all have the same kinetic energy)

Explanation:

The kinetic theory of gases states that the molecules of an ideal gas experience a constant random motion.

At standard temperature and pressure (STP), the kinetic energy of an ideal gas such as hydrogen, argon, neon, sodium, oxygen, helium, magnesium, beryllium, nitrogen, carbon, fluorine, chlorine etc are all the same.

The standard temperature and pressure (STP) of an ideal gas is 273K and 100 kPa.

Hence, all of the gases have the same kinetic energy at standard temperature and pressure (STP).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where, K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Answer:Moles of Mg, Cl,  0 =  5.40, 10.80, 43.2

Explanation:

1  mole of Mg(ClO4)2  contains  1 mole of Magnesium, Mg atoms

                                                    2 Moles of Chlorine, Cl atoms

                                                    8 Molresof Oxygen atoms

Such that to find the number of moles of each element, We have that

------1 mole Magnesum  atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles

------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2   x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles

------8 moles Oxygen atoms/ 1 mol of  Mg(ClO4)2   x 5.40 moles  of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles

Answer:

Exothermic

General Formulas and Concepts:

Chemistry

Thermodynamics

Explanation:

We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.

This means that heat would be product as it is being released during the reaction.

Therefore, we have an exothermic reaction.

Answer:

[tex]20[/tex] moles of CO2 can be produced from a reaction of 10.0 moles C2H6

Explanation:

In this reaction -

2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)

So 1 mole of C₂H6 will produce [tex]\frac{4}{2} = 2[/tex] moles of Carbon dioxide (CO2)

Thus, 10 moles of C₂H6 will produce [tex]2 * 10 = 20[/tex] moles of Carbon dioxide (CO2)

Answer:

Answer:

dunno

Explanation:

sorry

Answer:

We divide our value by 1.5×10⁸

Explanation:

AU is a unit to determine distance in the space.

We know that AU means astronomic unit.

The value for conversion is 1.5×10⁸ Km

1 AU = 1.5×10⁸ Km

Let's see the example:

One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:

3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU

Answer:

Molarity =  2.02 M

Explanation:

Given data:

Molarity of solution = ?

Mass of sodium chloride = 38.5 g

Volume of solution = 325 mL (0.325 L)

Solution:

Number of moles = mass/molar mass

Number of moles = 38.5 g/ 58.44 g/mol

Number of moles = 0.658 mol

Molarity:

Molarity = number of moles / volume of solution in L

Molarity = 0.658 mol /0.325 L

Molarity =  2.02 M

Answer:

[tex]V=24.45\ \text{cm}^3[/tex]

Explanation:

Given that,

Mass of a piece of Aluminium, m = 66 grams

The density of Aluminium, d = 2.70 g/cm³

We need to find the volume of this piece in cm³.

We know that,

Density = mass per unit volume

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]

So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].

Answer:

0.321 M

Explanation:

The neutralization reaction of HCl with NaOH is the following:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:

1 equivalent HCl = 1 mol HCl

1 equivalent NaOH = 1 mol NaOH

At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:

moles HCl = moles NaOH

M(HCl) x V(HCl) = M(NaOH) x V(NaOH)

We have:

M(NaOH) = 0.150 M

V(NaOH) = 21.4 mL = 0.0214 L

V(HCl) = 10.0 mL = 0.01 L

Thus, we calculate the initial concentration HCl as follows:

M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))

            = (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

Answer:

cointreau, tequila,lime juice