Answer:
16 m/s
Explanation:
First, find the displacement in the east direction.
x = (15 m/s sin 45°) (3600 s) + (18 m/s cos 5°) (3600 s)
x = 102,737 m
Next, find the displacement in the north direction.
y = (15 m/s cos 45°) (3600 s) + (18 m/s sin 5°) (3600 s)
y = 43,831 m
Find the magnitude of the displacement.
d = √(x² + y²)
d = √((102,737 m)² + (43,831 m)²)
d = 111,697 m
Finally, find the resultant velocity.
v = d / t
v = (111,697 m) / (7200 s)
v = 15.5 m/s
Rounded to the nearest whole number, the resultant velocity is 16 m/s.
A speeding truck travels in the positive x direction. It hits a car traveling in the positive y direction. The vehicles are deformed and travel together at an
angle with the positive x-axis. What can you say about the kinetic energy of the system after the collision?
Kinetic energy of the system is conserved.
B.
Kinetic energy of the system is partially used up in the deformation of the vehicles
Kinetic energy of the system is unrelated to the deformation of the vehicles.
C.
D.
Kinetic energy of the system is completely transformed to heat energy
Answer:
B. Kinetic energy of the system is partially used up in the deformation of the vehicles.
Explanation:
In an inelastic collision, momentum is conserved, but kinetic energy is not. Kinetic energy is lost as heat or lost in the deformation of the objects.
The correct statement about Kinetic energy of the system after the collision is that KE of the system will be partially used up in the deformation of the vehicles. Hence, option B is correct.
What is Kinetic energy?The force that an object has because it is moving is known as kinetic energy in physics. It is defined as the quantity of effort required to accelerate anybody of a specific mass from rest to its specified velocity. The body keeps its kinetic energy after acquiring it during acceleration, barring changes in speed.
When slowing from its current pace to a condition of rest, the body expends the very same amount of energy. Any term in the Lagrangian of a system that has a derivative in regard to time is formally referred to as kinetic energy.
The momentum of an object is conserved, but kinetic energy is not in an inelastic collision. In the form of heat or by the distortion of the objects, kinetic energy is lost.
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Question: A swimmer has a swimming speed of 5.75 m/s in still water. When she
heads directly across the river, she ends up travelling downstream at an angle of 40°
(with respect to a line perpendicular to the shore).
(a) What is the speed of the current?
(b) What heading would the swimmer need to have in order to reach a point directly
across the river?
(c) If the river is 15 m wide, how long would a trip directly across the river take?
Answer:
(a) 4.82 m/s
(b) The simmer need to head 57.05° upstream of the river to reach a point directly opposite the river
(c) 4.024 seconds
Explanation:
The parameters given are;
The speed of the swimmer = 5.75 m/s
The direction of the resultant motion = 40° downstream
The speed of the current = x m/s
Therefore in a given second, we have that the swimmer moves 5.75 meters across the river while the current moves x meters downstream
Which gives;
[tex]tan(40^{\circ}) = \dfrac{x}{5.75}[/tex]
x = 5.75 × tan(40°) = 4.82 m/s
The speed of the current = 4.82 m/s
(b) If the swimmer swims at a direction θ to reach a point, p, directly opposite the river, we have;
The resultant speed across the river will be the swimmer's swimming speed which is 5.75 m/s
5.75² = y² + 4.82²
y = √(5.75² - 4.82²) = √9.78
tan(θ) = 4.82/(√9.78) = 1.54
θ = tan⁻¹(1.54) = 57.05°
The simmer need to swim 57.05° upstream to reach a point directly opposite the river
(c) If the river is 15 m wide, we have;
Time (t) = Distance/speed
The component of the swimmer's speed directly across the river = 5.75/(tan(57.05°)
The component of the swimmer's speed directly across the river = 3.73 m/s
The time, t, to cross the river is therefore;
t = 15/3.73 = 4.024 seconds
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371.2 K. What is the enthalpy of combustion of octane? The specific heat capacity of water is 4.18 J/K g.
A. -1226 kJ/mol
B. -5448 kJ/mol
C. 293.25 kJ/mol
D. 1226 kJ/mol
Answer : The correct option is, (B) -5448 kJ/mol
Explanation :
First we have to calculate the heat required by water.
[tex]q=m\times c\times (T_2-T_1)[/tex]
where,
q = heat required by water = ?
m = mass of water = 250 g
c = specific heat capacity of water = [tex]4.18J/g.K[/tex]
[tex]T_1[/tex] = initial temperature of water = 293.0 K
[tex]T_2[/tex] = final temperature of water = 371.2 K
Now put all the given values in the above formula, we get:
[tex]q=250g\times 4.18J/g.K\times (371.2-293.0)K[/tex]
[tex]q=81719J[/tex]
Now we have to calculate the enthalpy of combustion of octane.
[tex]\Delta H=\frac{q}{n}[/tex]
where,
[tex]\Delta H[/tex] = enthalpy of combustion of octane = ?
q = heat released = -81719 J
n = moles of octane = 0.015 moles
Now put all the given values in the above formula, we get:
[tex]\Delta H=\frac{-81719J}{0.015mole}[/tex]
[tex]\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol[/tex]
Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.
Answer:
B.) -5448 kJ/mol
Explanation:
I got it correct on founders edtell
define hardware.Give 2 examples
Answer:
They are the physical parts of a computer.
examples :monitor,keyboard,system unit and mouse.
Explain briefly the first aid measure that should be taken incase of poisoning
Answer:
How you treat someone who may have been poisoned depends on:
The person's symptoms
The person's age
Whether you know the type and amount of the substance that caused poisoning
If you are concerned about possible poisoning, call Poison Help at 800-222-1222 in the United States or your regional poison control center. Poison control centers are excellent resources for poisoning information and, in many situations, may advise that in-home observation is all that's needed.
A block of mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude: (A) mg tan θ (B) mg sin θ (C) mg cos θ (D) mg sec θ
Answer: mg/Cosθ
Explanation:
Taking horizontal acceleration of wedge as 'a'
FCosΘ = FsinΘ
F = mass(m) × acceleration(a) = ma
For horizontal resolution g = 0
Therefore,
Horizontal = Vertical
maCosΘ = mgSinΘ
aCosΘ = gSinΘ
a = gSinΘ/CosΘ
Recall from trigonometry :
SinΘ/Cosθ = tanΘ
Therefore,
a = gtanΘ
Normal force acing on the wedge:
mgCosΘ + maSinΘ - - - - (y)
Substitute a = gtanΘ into (y)
mgCosΘ + mgtanΘsinΘ
tanΘ = sinΘ/cosΘ
mgCosΘ + mgsinΘ/cosΘsinΘ
mgCosΘ + mgsin^2Θ/cosΘ
Factorizing
mg(Cosθ + sin^2Θ/cosΘ)
Taking the L. C. M
mg[(Cos^2θ + sin^2Θ) /Cosθ]
Recall: Cos^2θ + sin^2Θ = 1
mg[ 1 /Cosθ]
mg/Cosθ
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Explain how the diffraction of light shows that light behaves like a wave.
Explanation:
Diffraction of light involves a change in direction of waves as they pass through an opening or around an obstacle in their path. Water waves have the ability to travel around corners, around obstacles and through openings.
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If you double the amplitude of a box on a spring, how would that affect the acceleration at maximum displacement?
The acceleration would double.
The acceleration would remain the same.
The acceleration would triple.
The acceleration would be cut in 1/2.
Answer:
The acceleration would double
Explanation:
Assuming the same box and spring, the maximum acceleration is proportional to amplitude. When the amplitude doubles, the acceleration would double.
__
A spring is generally considered to have a linear force vs. distance characteristic. Hence, doubling the distance doubles the force. The acceleration is proportional to the force.
a man has a mass of 70kg. Calculate his weight on earth where the gravitational strength is 10 N/kg
Answer:
So the weight of the body is 700N
Explanation:
mass of the object=70kg
force of gravity=10N/kg
weight of the object=w-?
as we know that
weight=mass × force of gravity
weight=70kg × 10N/kg
WEIGHT OF THE BODY=700N
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The correct answer is 700 N.
Object mass = 70 kg
Gravity = 10N / kg
Weight = Mass x Gravity
Weight = 70kg x 10N / kg
Weight = 700 N
What is the gravity for a mass of 10kg?Mass is more basic because it is a unique property of the object. Weight varies from place to place depending on the acceleration of gravity. If the mass on the earth is m = 10kg, the weight is W = mg = 10 x 10 = 100N.
The strength of the Earth's gravitational field is 10 Newtons (N / kg) per kilogram. This means that there is a force of 10 Newtons per kilogram on Earth. Mass is the amount of substance that makes up an object.
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The table shows data for the planet Uranus.
A 2 column table with 4 rows. The first column is labeled Quantity with entries, Escape velocity in kilometers per second, Gravitational acceleration in meters per second squared, Orbital velocity in kilometers per second, Length of day in hours. The second column is labeled Value with entries, 21.3, 8.7, 6.8, 17.2.
To the nearest whole number, how much would a 25.0 kg rock weigh on Uranus?
170 N | 218 N | 430 N | 532 N
Answer:
218 N
Explanation:
The weight of the object on Uranus W = mg' where m = mass of the object = 25.0 kg and g' = gravitational acceleration.
Since in the table, we are given different values, we look for the value of the gravitational acceleration because, that is the only variable there that can help us calculate the weight of the object.
From the table, the gravitational acceleration g' = 8.7 m/s².
So, the weight of the object W = mg'
= 25.0 kg × 8.7 m/s²
= 217.5 N
≅ 218 N
Answer:
B. 218 N
Explanation:
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A transformer has 500 turns of the primary winding and 10 turns of the secondary winding. a) Determine the secondary voltage if the secondary circuit is open and the primary voltage is 120 V
Answer:
First we use the fact that the ratio of the voltage on the secondary and on the primary will be the same as the ratio of the number of turns of both coils,
u=u^2/U^1 = N^2/N^1
we evaluate the unkown secondary voltage
u^ 2=N^2/N^1 u1
We substitute the given values -
u^2= 10/500 * 120v = 2.4v
Hence, the answer is 2.4v.
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A 1500 kg car on flat ground is
moving 5.25 m/s. Its engine
creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?
Answer: 5.96m/s
Explanation:
Given the following :
Mass of car (m) = 1500kg
Velocity (V) = 5.25m/s
Forward force of engine = 1250N
Diatance moved = 4.8m
Final Velocity =?
Final kinetic energy = Initial kinetic energy + work done by engine
Initial kinetic energy = 0.5 × mass × velocity^2
Initial kinetic energy = 0.5 × 1500 × 5.25^2
Initial kinetic energy = 20671.875 J
Work done by engine = Force × distance
Work done by engine = 1250 × 4.8 = 6000J
Final kinetic energy = (20671.875 + 6000) J
= 26671.875 J
From kinetic energy = 0.5mv^2
26671.875 = 1/2 × 1500 × v^2
53343.75 = 1500v^2
v^2 = 35.5625
v = sqrt(35.5625)
v = 5.96m/s
2. Fill in the blanks with appropriate words.
a. The force which acts towards the centre is called .......
force.
Answer:
centripetal force
Explanation:
because this force always compels the body to move in circle
how wood helps in home insulation plz answer fast
plz answwweeeeeeerrrrrrr
Wood is a natural insulator due to air pockets within its cellular structure, which means that it is 15 times better than masonry, 400 times better than steel, and 1,770 times better than aluminum. In addition, lightweight wood framing methods allow easy installation of additional fibre or foil insulation. i hope this is better
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A 20.0 cm tall object is placed 50.0 cm in front of a convex mirror with a radius of curvature of 34.0 cm. Where will the image be located, and how tall will it be? Please show all work.
Answer:
i = -12.7 cm; h = 5.07 cm
Explanation:
1. Find the focal length
The focal length of a concave spherical mirror is half of its radius of curvature.
f = ½r = ½ × 34.0 cm = 17.0 cm
2. Find the image distance
A convex mirror produces a virtual image behind the mirror, so the image distance is negative.
[tex]\begin{array}{rcl}\dfrac{1}{o} + \dfrac{1 }{i} & = & \dfrac{1}{f}\\\\\dfrac{1}{50.0} + \dfrac{1 }{i} & = & \dfrac{1}{-17.0}\\\\\dfrac{1}{i} & = & \dfrac{1}{-17.0} - \dfrac{1}{50.0}\\\\& = & \dfrac{50.0 - (-17.0)}{500\times(-17.0)}\\\\& = & \dfrac{67.0}{-850}\\\\i & = & \dfrac{-850}{67.0}\\\\& = & \textbf{-12.7 cm}\\\end{array}[/tex]
3. Find the image size
[tex]\begin{array}{rcl}\\\\\dfrac{h_{\text{i}}}{ h_{\text{o}}} & = & -\dfrac{i}{o} \\\\\dfrac{h_{\text{i}}}{ 20.0} & = & -\dfrac{-12.7}{50.0} \\\\h_{\text{i}} & = & 20.0 \times \dfrac{12.7}{50.0}\\\\& = & \textbf{5.07 cm}\\\end{array}[/tex]
Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del suelo con un ángulo de θi = 33.0° arriba de la horizontal como se muestra en la figura siguiente. Si la rapidez del chorro cuando sale de la manguera es vi = 40.0 m/s, ¿a qué altura (en m) golpeará el edificio? m
Answer:
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Explanation:
El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:
Distancia horizontal (en metros)
[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \theta[/tex]
Donde:
[tex]x_{o}[/tex] - Posición horizontal inicial, medida en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
[tex]v_{o}[/tex] - Velocidad inicial, medida en metros por segundo.
[tex]\theta[/tex] - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.
Distancia vertical (en metros)
[tex]y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}[/tex]
Donde:
[tex]y_{o}[/tex] - Posición vertical inicial, medida en metros.
[tex]g[/tex] - Constante gravitacional, medida en metros por segundo al cuadrado.
Partiendo de la primera ecuación, se despeja el tiempo:
[tex]t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}[/tex]
Si [tex]x = 31\,m[/tex], [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 33^{\circ}[/tex], entonces:
[tex]t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}[/tex]
[tex]t = 0.924\,s[/tex]
La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]t = 0.924\,s[/tex] y [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], entonces:
[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}[/tex]
[tex]y = 15.943\,m[/tex]
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Newton’s first law of motion was a giant leap forward in scientific thought during Newton’s time. Even today, the idea is sometimes difficult at first for people to understand. Which statement is the best example of an object and motion that would make it hard for people to believe Newton’s first law? A rolling ball eventually slows down and comes to a stop. A wagon must be pushed before it begins to move. The heavier the load in a cart, the harder the cart is to turn. A box does not move when pushed equally from opposite sides.
Answer: A rolling ball eventually slows down and comes to a stop.
Explanation: Right on Edge2020, not C or B or D.
Answer:
A
Explanation:
Person above me might be right
which two elements define a story's setting?
geographical location
character description
weather conditions
plot structure
dialogue and action
Reset
Next
Answer:
Geographical location, and time and weather conditions
Answer:
Georgraphical location and weather conditions
Explanation:
Setting is where the story takes place so the location would be vital and same with weather conditions because it determines what the character(s) do
How much net force is required to keep a 3-kg object moving to the right with a constant speed of
6.0 m/s?
Answer:
Explanation:
Here,
m = 3 Kg
a = 0 m/s^2 (velocity is constant so the acceleration is zero)
We have,
F = ma
or, F = 3 x 0
or, F = 0 N
Constant velocity can always be associated with a zero net force.
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Radio waves can bend around buildings. An X-ray technician stands behind a wall during the use of her machine. What does this tell you about the relative wavelengths of these two types of invisible light?
Answer:
Radio waves have a wavelength between [tex]10^{-9}m[/tex] and [tex]10^{-12}m[/tex]
While,
X rays have a wavelength between 1m and 10km.
=> It is one of the condition of diffraction that the obstacle (coming in the way) must be comparable with the size of the wavelength.
=> This shows, that radio waves have a wavelength which is comparable with the size of buildings and can really easily diffract through it
=> While, X-rays are big enough to diffract through the wall.
So, if an X-ray technician stands behind a wall during the use of her machine, she will remain safe.
when light passess from air into glass the angle of incidence is always _______ the angle of refraction
Explanation:
The angle of incidence is always smaller than the angle of refraction
Elements in the same periodic table group have the same___
Answer:
elements in the same periodic table group have the same valence electrons
The estimated distance of the earth from the sun is 149000000km. The speed of the light is 300000km/s. What is the time taken for the light to travel from the sun to the earth
Answer:
The time taken for the light to travel from the earth to the sun = 496.67 seconds
Explanation:
Estimated distance of the earth to the sun = 149000000km
Speed of light = 300000km/s
Time taken for the light to travel from the sun to the earth = ?
Speed = Distance/time
time = Distance/speed
time = 149000000/300000
time = 496.67 s
The time taken for the light to travel from the earth to the sun = 496.67 seconds
a space shuttle travels in orbit at 21,000 km/hr. how far will it travel in 5 hr
Answer:
Explanation:
distance = speed * time
distance = 21000 * 5 = 105000 km
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A student has a 3v cell and the resistance in the circuit totals 6 ohms. How much current would flow in a series circuit?
Answer:
[tex]I=0.5 \:A[/tex] is the correct answer.
Explanation:
Using the ohm's law, we have:
[tex]V=IR\\\\I=\frac{V}{R}=\frac{3}{6}\\\\I=0.5 \:A[/tex]
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Explain how the diffraction of light shows that light behaves like a wave.
Answer:
Diffraction of light shows that light behaves like a wave. It involves the change in the direction of waves while passing through any obstacle. Diffracted light can produce fringes of light, dark or colored bands (Just like the rainbow which is also a light wave). Diffracted light has certain wavelength, amplitude , frequency and speed which are the basic characteristics of being a wave which shows that light actually behaves like a wave.
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Identify each of the following as a conductors or insulators. Explain.
-cloth
-dry wood
-tap water
-glass
Answer:
Cloth:
It is an insulator since it can't let electricity pass through
Dry Wood:
It is an insulator and can't conduct electricity.
Tap Water:
It is a good conductor as it contains dissolved salts.
Glass:
It is an insulator since it can't let electricity pass through.
An 18-kg bicycle carrying a 62-kg girl is traveling at a speed of 7 m/s. What is the kinetic energy of the girl
and bicycle combined together?
Answer:
1960 J
Explanation:
EK = (18 kg + 62 kg)[tex](7.0 m/s)^{2}[/tex]/2 = 1960 J
11. What is the wavelength of an earthquake wave if it has a speed of 5000 m/s and a frequency of 10 HZ
step#1
step#2
step#3
Answer:
500 m
Explanation:
The applicable relation is ...
wavelength = speed/frequency
wavelength = (5000 m/s)/(10 cycles/s) = 500 m/cycle
The wavelength is 500 meters.
A (an) __helps lessen the effects of thermal pollution
Answer:
Tree
Explanation:
It gets rid of the the degrading water temperature by blocking the sun's heat