3. Waves in a lake are 6.0 m apart and pass a person on a raft every 2.0 s.
What is the speed of the waves?

Answer:

The answer should be the one on the top in the picture.

Explanation:

Friction is opposing the downward movement of the crate therefore the friction force is pointing upwards. that is why the answer should be the one on the top of the picture.

Answer: c

Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.

If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.

If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.

The not consistent with a car that is accelerating is a car is moving at a high speed.

A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).

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Answer:

c

Explanation:

Answer:

a) 2000 m

b) 1500 mm

c) 580000 cm

d) 400 mm

e) 2.7 cm

f ) 0.126 m

g) 0.012 km

Explanation:

Transform

a) 2km to m

   1 km = 1000m

hence : 2 km = 2 * 1000 =  2000 m

b) 1.5m to  mm

    1 m = 1000 mm

hence: 1.5 m = 1.5 * 1000 = 1500 mm

C) 5.8 km  to cm

     1 km = 100000 cm

hence ;5.8 km = 5.8 * 100000 = 580000 cm

D) 0.4 m   to  mm

   1 m = 1000 mm

hence; 0.4 m =  0.4 * 1000 = 400 mm

E) 27 mm to  cm

   1 mm = 0.1 cm

hence ; 27 mm = 27 * 0.1  = 2.7 cm

F) 126mm  to m

    1 mm = 0.001 m

hence ;  126 mm = 126 * 0.001 = 0.126 m

G) 12m  to Km

   1 m = 0.001 km

hence ; 12 m = 12 * 0.001 = 0.012 km

Answer:

unbalanced 1st answer

Answer:

hi, your answers are correct

Explanation:

Answer:

[tex]v = 0.25m/s[/tex]

Explanation:

Given

[tex]\lambda = 0.02m[/tex] --- Wavelength

[tex]T = 8.0 * 10^{-2}s[/tex] --- Period

Required

Determine the velocity of the wave

This is calculated using:

[tex]v = \frac{\lambda}{T}[/tex]

[tex]v = \frac{0.02m}{8.0*10^{-2}s}[/tex]

[tex]v = \frac{0.02m}{8.0*0.01s}[/tex]

[tex]v = \frac{0.02m}{0.08s}[/tex]

[tex]v = 0.25m/s[/tex]

Hence, the velocity is 0.25m/s

Answer:

Explanation:

Let lift force F be created by propellers at angle of Ф with the horizontal .

The vertical component of this force will balance the weight of helicopter and horizontal component will balance the air resistance .

F sinФ = mg = 2750 x 9.8 = 26950 N

F cosФ = 7510 N

Squaring and adding ,

F² = 26950² + 7510²

= 726302500 + 56400100

= 782702600

F = 27976.82 N .

Answer:

really fast? xP

Explanation:

Answer:

[tex] \boxed{q = 1.2 \times {10}^{ - 6} C}[/tex]

Explanation:

[tex]f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6} [/tex]

Answer:

If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.

F(1x)=F(1)=10 N

F(2x)=F(2)cos60=5•0.5=2.5 N

F(2y) =F(2)sin60 = 5•0.866= 4.33 N

F(3x) =- F(x)=- (10+2.5 )= -12.5 N

F(3y) =- F(2y)= - 4.33 N

F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N

tan φ = F(3y)/F(3x) =4.33/12.5=0.364

φ = 19.1⁰ (south-west)

Explanation:

Answer:

1. Endurance activities

Only aerobic source

2. Can contract repeatedly

Speed strength and power.

Both aerobic and anaerobic sources

3. Fast contraction speed

Only anaerobic sources

Produce most force

Fatigue quickly

Speed, strength and power

Explanation:

I hope this helps. Although, I'm about 80% sure of the answer.

Answer:

MRI and Radio telescopes

MRI and radio telescopes would be unaffected by satellites that are not working properly.

The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower. The wavelength for 300 GHz is 1 mm, which is shorter than a grain of rice, while the wavelength for 30 Hz is 10,000 km (6,200 miles) (longer than the radius of the Earth).

Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical speed in the Earth's atmosphere.

Among the given options, space communication and television broadcasting television broadcasting and GPS  and  radio telescopes and space communication​ are affected by satellites that are not working properly because they are operated by satellite technology.

Hence, only MRI and radio telescopes would be unaffected by satellites that are not working properly.

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Answer:

It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant

Explanation:

The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;

v² = u² + 2·a·s

v = u + a·t

Where;

v = The final velocity of the particle

u = The initial velocity of the particle

a = The acceleration of the particle

s = The distance through which the particle travels

t = The time of motion of the particle

By simplifying the above equation, we have;

v² - u² = 2·a·s

(v² - u²)/(2·a) = s

(v - u) × (v + u)/(2 × a) = s

((v - u)/a) × ((v + u)/2) = s

From v = u + a·t, we have;

t = (v - u)/a

∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s

∴ ((v + u)/2) = s/t

The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)

∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity

However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.

Answer:

False.

Explanation:

Potential of Hydrogen is the full form of PH.

Potential of Hydrogen tells about the acidity or basicity of the solution.

The pH of a solution is a measure of the concentration of hydrogen ions [tex](H+)[/tex] ions and hydroxide ions [tex](OH-)[/tex] in a solution.

So, the given statement is false.

Answer:

300 jules

Explanation:

Answer:1. A chair leaning on a wall

Explanation:

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Note: The question is incomplete. The complete question is as follows:

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².

Explanation:

From the given values:

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² where π = 3.142

Area of aorta = 3.142 × (1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂

Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

Answer:

Increased lean muscle tissue.

Explanation:

I hope this helps :) Tell me if I am wrong!

Answer:

Increased lean muscle tissue.

Explanation:

i took the test!

Answer:

the bonds that are formed

Explanation:

Energy is absorbed in order to break bonds.  Energy is released when new bonds are formed. Bond-making is a process of exothermic. Whether the reaction is endothermic or exothermic refers to the difference between the energy needed to break bonds and the energy released when new bonds are formed.

Answer:

8 minutes and 20 seconds

Explanation:

5000/10 to get the number of seconds, which is 500, then you convert 500 seconds to minutes and you get 8 minutes and 20 seconds

Answer:

a) The bullet will penetrate 0.375 meters into the bag of sand.

b) The average force exerted by the sand is 15 newtons.

Explanation:

The statement is incorrectly written. The correct form is presented below:

A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.

a) How far the bullet will penetrate into the bag of sand?

b) The average force exerted by the sand?

b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:

[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the bullet, measured in kilograms.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:

[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]

[tex]F = -15\,N[/tex]

The average force exerted by the sand is 15 newtons.

a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:

[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:

[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]

[tex]\Delta s = 0.375\,m[/tex]

The bullet will penetrate 0.375 meters into the bag of sand.

Answer:

C. Sources of electrical current!

Hope this helps :)

Answer:

Sources of electrical current

Explanation:

Got it right on the test.

Plot a graph, constant speed of movements represented as straight lines. Time on X axis (seconds)  and position on Y axis (metres) , calculated by moving, e.g 4metres in a second.

Distance covered = (speed) x (time)

Time = (Distance covered) / (speed)

Time = (48 km) / (32 km/hr)

Time = (48/32) hr

Time = 1.5 hrs (1 hour 30 minutes)

Answer:

I think the answer is D...

Explanation: