(C)
Explanation:
[tex]t = 2\pi \sqrt{ \frac{l}{g} } [/tex]
If g is only 1/6 on another planet, then
[tex]t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } = 2\pi \sqrt{ \frac{6l}{g} } [/tex]
[tex] = \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4 \times t(on \: earth)[/tex]
1 point
4. When mass is in kilograms and velocity is in meters per second then
momentum is in kilograms-meters per second.
True
Ο Ο
False
Answer:
true
Explanation:
momentum = kg (m/s)
momentum = mass × velocity
In a double-slit experiment, the third-order maximum for light of wavelength 510 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 670 nm is then projected through the same slits. Part A How far from the central bright spot will the second-order maximum of this light be located
Answer:
14.9 mm
Explanation:
We know dsinθ = mλ where d = separating of slit, m = order of maximum = 3 and λ = wavelength = 510nm = 510 × 10⁻⁹ m
Also tanθ = L/D where L = distance of m order fringe from central bright spot = 17 mm = 0.017 m and D = distance of screen from slit = 1.6 m
So, sinθ = mλ/d
Since θ is small, sinθ ≅ tanθ
So,
mλ/d = L/D
d = mλD/L
Substituting the values of the variables into the equation, we have
d = 3 × 510 × 10⁻⁹ m × 1.6 m/0.017 m
d = 2448 × 10⁻⁹ m²/0.017 m
d = 144000 × 10⁻⁹ m
d = 1.44 × 10⁻⁴ m
d = 0.144 × 10⁻³ m
d = 0.144 mm
Now, for the second-order maximum, m' of the 670 nm wavelength of light,
m'λ'/d = L'/D where m' = order of maximum = 2, λ' = wavelength of light = 670 nm = 670 × 10⁻⁹ m, d = slit separation = 0.144 mm = 0.144 × 10⁻³ m, L' = distance of second order maximum from central bright spot and D = distance of screen from slit = 1.6m
So, L' = m'λ'D/d
So, substituting the values of the variables into the equation, we have
L' = 2 × 670 × 10⁻⁹ m × 1.6 m/0.144 × 10⁻³ m
L' = 2144 × 10⁻⁹ m²/0.144 × 10⁻³ m
L' = 14888.89 × 10⁻⁶ m
L' = 0.01488 m
L' ≅ 0.0149 m
L' = 14.9 mm
A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds. What is the average linear velocity (inches/second) of the golf club
Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;
[tex]\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s[/tex]
The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
a spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?
a. 0.0014 meters
b. 0.45 meters
c. 2.2 meters
d. 5.0 meters
show your work
Answer:
I think its B
Explanation:
whats is the purpose of the
(1) Armature winding
(2) the commutator
(3) the fan
here's your correct answer.. please copy it..
using the image provided, which moon phase is next?
Answer:
Waning Crescent
Answer: waxing crescent
Explanation:
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardless of the order in which each object was plotted. True False
Answer:
True
Explanation:
It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different
what is the value of 3 in
24.635
Answer:
3 tens
Explanation:
The value
of 3 in 24.635 is at 3 tens place as the place is two to the left.
The correct answer to the given is question is "0.03".
What is Place Value?The value of each digit in a number is known as place value.For example the 2 in 125 represent 2 tens or 20, however the 2 in 2103 represent 2 thousands or 2000.Frequently, they will only include the letters like Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, tenths, hundredths, and so on to denote each place. How to solve this question?Let's display the number 24.635 using a place value chart.
Tens -> 2 Ones -> 4 Tenth -> 6 Hundredths -> 3 Thousandths -> 5
The 3 is in Hundredths Place or the value of 3 in 24.635 is 0.03.
Thus, we can conclude that the value of 3 in 24.635 is 0.03 after solving the question.
Learn more about Place Value here:
https://brainly.com/question/569339
#SPJ2
Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24 m away, adjacent bright fringes are separated by 2.88 mm.What is the wavelength of the light that falls on the slits
Answer: 655.7 nm
Explanation:
Given
The slits are separated by [tex]d=0.510\ mm[/tex]
Distance between slits and screen is [tex]D=2.24\ m[/tex]
Adjacent bright fringes are [tex]\beta =2.88\ mm[/tex] apart
Also, the distance between bright fringes is given by
[tex]\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm[/tex]
If the string connecting the puck to the center is cut, there will be no net force on the puck. (The force of gravity is offset by the turntable.) The puck will not accelerate or change direction, so it will move at a constant speed in the direction it was moving at the time the string was cut. How does this relate to the boy whirling a yo-yo given at the start of this Exploration sheet
Solution :
In the context, it is given that a boy is whirling a yo-yo in the counter clockwise direction above his head.
Similarly when a pink puck is floating above the circular table in uniform circular motion. Now when the string connecting the pink puck is cu at the center, no net force will be acting on the puck and it will not change its direction nor accelerate. But the puck will move at a constant speed.
Both the scenarios are same . But incase of the boy playing with the yo-yo, we consider the gravity force.
Question 15 of 25
You feel warm sitting next to a bright light. Which type of heat transfer are
Experiencing?
Answer:
radiation
Explanation:
Describe each of the FITT training principles. (Site 1
Answer:
The FITT principles are an exercise prescription to help participants understand how long and how hard they should exercise. FITT is acronym that stands for Frequency, Intensity, Time, and Type. FITT can be applied to exercise in general or specific components of exercise.
Explanation:
Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit
Answer:
Explanation:
screen distance D = 6 m .
wavelength of light λ = 633 nm.
slit width = d .
Distance between first minima on either side is width of central maxima
= 2 x λD /d
Given
32 x 10⁻³ = 2 x λD /d
d = 2 x λD /32 x 10⁻³
= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³
= 237.37 x 10⁻⁶ m
= .23737 x 10⁻³ m
= .24 mm .
g A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth's (where Earth's radius is approximately 6370 km ). What is the gravitational acceleration of the meteoroid
Answer:
Explanation:
gravitational acceleration of meteoroid
= GM / R²
M is mass of planet , R is radius of orbit of meteoroid from the Centre of the planet .
R = (.9 x 6370 + 600 )x 10³ m
= 6333 x 10³ m
M , mass of the planet = 5.97 x 10²⁴ kg .
gravitational acceleration of meteoroid
= GM / R²
= (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ kg / (6333 x 10³ m)²
9.92m/s²
Select the correct answer. A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds? A. 2 meters/second B. 3 meters/second C. 4 meters/second D. 5 meters/second E. 6 meters/second
Answer:
2 m/s
Explanation:
...........................
Answer:
A:2 m/s
Explanation:
Plato
please help, im having trouble can you please explain how to do it
Answer:
independent and the second one with the (-8, 1, -3)
A Piatma is a very hot gas comprised of freely moving positive and negative suale particles that are in random motion. Which of the following microscopic properties, together alwama held to have an observable macroscopic effect on the plasma when the plan is placed in the region that contains the magnetic field?
A. The particles have subatomically mal dimensions
B. The particles are charged
C. The particles are not all classified as fundamental particles
D. The particles are in random motion
Answer:
B. The particles are charged
Explanation:
We know that a moving charge particle in magnetic field experiences a magnetic force given by :
[tex]$\vec F = q (\vec v \times \vec B)$[/tex]
In the context, a very hot gas of piatma consists of freely moving positive particles as well as negative particles. Now when the plasma is placed in the region of a magnetic field, then it experiences a force and thus it shows that the particles are charged particles.
Hence , option (B) is correct.
g PRACTICE ANOTHER Two trains approach each other on separate but adjacent tracks. Train 1 is traveling at a speed of 30.3 m/s and train 2 at a speed of 22.5 m/s. If the engineer of train 1 sounds his horn which has a frequency of 520 Hz, determine the frequency of the sound heard by the engineer of train 2. (Use 343 m/s as the speed of sound. Enter your answer to the nearest Hz.)
Answer:
f'= 607.8 Hz
Explanation:
This is a Doppler effect exercise due to the relative velocity of the sound source and the observer.
By the time the source and the observer are getting closer the expression is
f ’=[tex]f_o \ \frac{ v+ v_o}{v - v_s}[/tex]
where vs is the speed of the source, vo is the speed of the observer, if the bodies move away the signs are exchanged
in this case, train 1 emits sound, so its speed is v_s = 30.3 m / s and train 2 is the receiver of the sound v₀ = 22.5 m / s
let's calculate
f ’= [tex]520 \ ( \frac{343 + 22.5}{343 - 30.3} )[/tex]520 (343+ 22.5 / 343 - 30.3)
f'= 607.8 Hz
What forces are acting on the race car while it is in motion? (hint: there are 3
forces)
Answer:
the forces acting on the car while moving are - frictional force, applied force , air resistance and gravity.:
g Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzzer over the side while the balloon is rising at constant speed, what can you conclude about the sound you hear as the buzzer falls toward the ground
Answer:
the observed frequency will reduce but the wavelength will increase
Explanation:
As we know
fo = fs (v/(v-vs))
fo = observed frequency
vs = velocity of source
As per this equation,
When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.
Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase
Please help... I'm confused on what I represents in terms of solving the total current. Would variable would I be singling out?
Answer:
the researcher say hi for us the best pa the best of us are going out to eat that I can get my money toward a little bit but the best of luck to be at work by then and we will see what the status
Explain the relationship between physics and mathematics.
Answer:
The relationship between Physics and Mathematics is that both are of 1 family.Se infla hasta 3dm3 un globo de goma a una temperatura de 20ºC y se lo lleva a una temperatura de
30ºC. Calcular su nuevo volumen
Answer:
V2 = 4.5 dm³
Explanation:
Dados los siguientes datos;
Volumen inicial = 3 dm³
Temperatura inicial = 20°C Temperatura final = 30°C
Para encontrar el nuevo volumen V2, usaríamos la ley de Charles.
Charles afirma que cuando la presión de un gas ideal se mantiene constante, el volumen del gas es directamente proporcional a la temperatura absoluta del gas.
Matemáticamente, Charles está dado por;
[tex] VT = K[/tex]
[tex] \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Dónde;
V1 y V2 representan los volúmenes inicial y final respectivamente.
T1 y T2 representan las temperaturas inicial y final, respectivamente.
Haciendo V2 como la fórmula del sujeto, tenemos;
[tex] V_{2}= \frac{V1}{T1} * T_{2}[/tex]
[tex] V_{2}= \frac{3}{20} * 30 [/tex]
[tex] V_{2}= 0.15 * 30 [/tex]
V2 = 4.5 dm³
how is intera in baseball
Answer:
Ok I guess
Explanation:
Answer:
what is intera basketball?
A skydiver weighing 200 lbs with clothes that have a drag coefficient of .325 is falling in an area that has an atmospheric density of 1.225 kg/m2 (and assuming that altitude has a negligible effect on atmospheric density). The skydiver can change the body orientation from straight-erect with a cross-sectional area of 6 sqft to a belly-flat cross-sectional area of 24 sqft. Calculate the terminal velocity of the person when the body has straight and when the body has belly-flat orientations. Calculate the terminal velocity on these two different orientations.
Answer:
The right solution is:
(a) 89.455 m/s
(b) 44.73 m/s
Explanation:
The given values are:
Mass,
m = 200 lbs
or,
= [tex]\frac{200}{2.205} \ kg[/tex]
= [tex]90.7 \ kg[/tex]
Air's density,
[tex]\delta = 1.225 \ kg/m^3[/tex]
Drag coefficient,
[tex]C_d=0.325[/tex]
When body is straight, area,
[tex]A_1=6 \ ft^2[/tex]
As we know,
Terminal velocity,
⇒ [tex]V_t=\sqrt{\frac{2W}{C_d \delta A} }[/tex]
or,
⇒ [tex]=\sqrt{\frac{2mg}{C_d \delta A} }[/tex]
At straight orientation,
⇒ [tex]V_t'=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.223}}[/tex]
⇒ [tex]=89.455 \ m/s[/tex]
When belly flat,
⇒ [tex]V_t''=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558\times 4} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.889} }[/tex]
⇒ [tex]=44.73 \ m/s[/tex]
b. Why are the resources listed in part (a) considered "renewable"?
Answer:
I would need to see the part a to be more specific but this may help:
resources like solar, water, wind are considered renewable because they will never run out, they can be replenished over and over again. There will always be a sun (and if there wasn't then we'd have bigger conserns than renewable energy) and the wind will always blow. It can never run out because you use too much unlike coal and fossil fuels.
Hope this helps!
Solve the following problem. A force of 5N is being applied to the right, and a force of
3N is being applied to the left. What is the net force?
A- 15 N
B- 8 N
C- 7N
D- 2N
Answer:
D 2N
Explanation:
these are opposite forces so one becomes negative and the other positive that is
-3+5=2 or 5-3=2
Which nucleus completes the following equation?
Answer:
b
Explanation:
b
Answer: c
Explanation:
A p e x
12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
a)3:4
c)27:64
b)9:16
d)81:256
Answer:
[tex]81:256[/tex].
Explanation:
Let [tex]T[/tex] denote the absolute temperature of this object.
Calculate the value of [tex]T[/tex] before and after heating:
[tex]T(\text{before}) = 27 + 273 = 300\; \rm K[/tex].
[tex]T(\text{after}) = 127 + 273 = 400\; \rm K[/tex].
By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to [tex]T^4[/tex].
Ratio between the absolute temperature of this object before and after heating:
[tex]\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}[/tex].
Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:
[tex]\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}[/tex].