20. Evaluate:

(55.5 x 2) = 5 + 13-7​

Answer:

x is 64 and y is 16 but if you can't comprehend thats 64/16 = 4

Step-by-step explanation:the power is the number multiplied by it self so 8 to the power if 2 is 8 x 8 and 2 to the power of four is 2 x 2 x 2 x 2= 16

Answer:

P10 = 27.4

P90 = 22.0

It helps the producer to know the higher (P10) and lower estimates (P90) for the amount of chocolate chips per cookie.

Step-by-step explanation:

In P10 and P90 the P stands for "percentile".

In the case of P10, indicates the value X of the random variable for which 10% of the observed values will be above this value X.

In the case of P90, this percentage is 90%.

In this case, we can calculate from the z-values for each of the percentiles in the standard normal distribution.

For P10 we have:

[tex]P(z>z_{P10})=0.1\\\\z_{P10}=1.2816[/tex]

For P90 we have:

[tex]P(z>z_{P90})=0.9\\\\z_{P90}=-1.2816[/tex]

Then, we can convert this values to our normal distribution as:

[tex]P10=\mu+z\cdot\sigma=24.7+1.2816\cdot 2.1=24.7+2.7=27.4 \\\\P90=\mu+z\cdot\sigma=24.7-1.2816\cdot 2.1=24.7-2.7=22.0[/tex]

===================================================

Explanation:

Let's say the lawn is 120 square feet. I picked 120 as it is the LCM (lowest common multiple) of 60 and 40.

Since Wilma can mow the lawn in 60 minutes, her rate is 120/60 = 2 sq ft per minute. In other words, each minute means she gets 2 more square feet mowed. Rocky can do the full job on his own in 40 minutes, so his rate is 120/40 = 3 sq ft per minute.

Their combined rate, if they worked together (without slowing each other down), would be the sum of the two rates. So we get 2+3 = 5 sq ft per minute as the combined rate. The total time it would take for this 120 sq ft lawn is 120/5 = 24 minutes.

--------------------------

Another approach

Wilma takes 60 minutes to do the full job, so her rate is 1/60 of a lawn per minute. Rocky's rate is 1/40 of a lawn per minute. Their combined rate is

1/60 + 1/40 = 2/120 + 3/120 = 5/120 = 1/24 of a lawn per minute

x = number of minutes

(combined rate)*(time) = number of jobs done

(1/24)*x = 1

x = 1*24

x = 24 is the time it takes if they worked together without getting in each other's way.

Effectively, we are solving the equation

1/A + 1/B = 1/C

with

A = time it takes Wilma to do the job on her own

B = time it takes Rocky to do the job on his own

C = time it takes the two working together to get the job done

The equation above is equivalent to C*(1/A + 1/B) = 1 or (1/A + 1/B)*C = 1.

So basically you find the value of 1/A + 1/B, then find the reciprocal of this to get the value of C.

Together they can mow the lawn in 24 minutes.

Time and efficiency are inversely proportional to each other.

Time and work are directly proportional to each other.

Given, Wilma can mow a lawn in 60 minutes. Rocky can mow the same lawn in 40 minutes.

Assuming total work to be 120 as it is the LCM of 40 and 60.

So, The efficiency of Wilma is (120/60) = 2 and the efficiency of Rocky is

(120/40) = 3.

Now together their efficiency is (2 + 3) = 5.

∴ Together they can complete the work in (120/5) = 24 minutes.

learn more about time and work here :

https://brainly.com/question/3854047

#SPJ2

Answer:

The equation is:

[tex]L=3\,\,d^2\\[/tex]

and a beam with 10 in diagonal will support 300 lb

Step-by-step explanation:

The mathematical expression that represents the statement:

"The maximum load a beam will support varies directly with the square of the diagonal of the beam’s cross-section. "

can be written as:

[tex]L=k\,\,d^2[/tex]

where k is the constant of proportionality

To find the constant we use the data they provide: "A beam with diagonal 6 in will support a maximum load of 108 lb.":

[tex]L=k\,\,d^2\\108 = k\,\,(6)^2\\k=\frac{108}{36} \,\,\frac{lb}{in^2}\\ k = 3\,\,\frac{lb}{in^2}[/tex]

Now we can use the proportionality found above to find the maximum load for a 10 in diagonal beam:

[tex]L=3\,\,d^2\\L=3\,\,(10)^2\\L=300 \,\,lb[/tex]

Answer:

L=3d^2 the beam will support 300 pounds

Step-by-step explanation:

108=k x 6^2

Dividing by 6^2=36 gives k=3, so an equation that relates L and d is

L=3d^2 d=10 yields

3(10)^2=300

So a beam with a 10in diagonal will support a 300lb load.

Answer:

16x^2 + 8x.

Step-by-step explanation:

To find the area of the walkway, you need to do the area of the whole thing minus the area of the pool.

The area of the whole thing is (8x - 3)(2x + 7) = 16x^2 - 6x + 56x - 21 = 16x^2 + 50x - 21.

The area of the pool is (8x - 3 - x - x)(2x + 7 - x - x) = (6x - 3)(7) = 42x - 21.

So, the area of the walkway is 16x^2 + 50x - 21 - (42x - 21) = 16x^2 + 50x - 21 - 42x + 21 = 16x^2 + 8x.

If you want, you can factor that and make it 8x(2x + 1).

Hope this helps!

Answer:

Lower Quartile: 62

Upper Quartile: 81

Interquartile Range: 19

Step-by-step explanation:

To find the lower quartile, you want to find the median from the minimum to the median.

49, 55, 62, 64, 67

The median of this is 62. Therefore, 62 is the lower quartile.

To find the upper quartile, you want to find the median from the median to the maximum.

76, 79, 81, 82, 83

The median of this is 81. Therefore, 81 is the upper quartile.

To find the interquartile range, you subtract the upper and lower quartile.

81-62=19

The difference is 19. Therefore, the interquartile range is 19.

Answer:

Pr(Three 2's) = 1/27

Step-by-step explanation:

Let's assume the die is a fair die, on the first roll of the die, the child has a 1/6 chance of getting any number, including 6.

Second roll, the child has a 1/36 chance of getting any two numbers, including two 6's.

And on the third roll, the child has a 1/36×1/6=1/216 chance of getting any three numbers, including three 6's. And this is due to the fact that the rolls are independent, so the total possible outcomes multiply each roll with each roll's probability. Since each roll's probability is 1/6.

The probability of the child rolling no more than three twos will be =2/6×2/6×2/6

=1/3×1/3×1/3

=1/27

Therefore, the chances of three twos will be 1/27

Answer:

Step-by-step explanation:

The complete statement would be "if a line is perpendicular to one of two parallel lines, then it is also perpendicular to the other".

The reason for this is because parallel lines have the same slope, that's the condition. On the other hand, parallel lines have opposite and reciprocal slopes.

So, if you think this through, if a line is perpendicular to another, then it's going to be perpendicular to all different lines which are parallel to the first one, because all their slopes are equivalent, and they will fulfill the perpendicularity condition.

Answer:

Parallel line

Step-by-step explanation:

Hope It Helps

Answer:

To construct a confidence interval, Normal distribution should be used since the sample size is quite large (n > 30)

From the z-table, at α = 0.025 the critical value is

[tex]z_{\alpha/2} = 1.96[/tex]

Step-by-step explanation:

We are given the following information:

The sample size is

[tex]n = 235[/tex]

The mean weight is

[tex]\bar{x}= 33.7 \: hg[/tex]

The standard deviation is

[tex]s = 7.3 \: hg[/tex]

Since the sample size is quite large (n > 30) then according to the central limit theorem the sampling distribution of the sample mean will be approximately normal, therefore, we can use the Normal distribution for this problem.

The correct option is (b)

The critical value corresponding to 95% confidence level is given by

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

From the z-table, at α = 0.025 the critical value is

[tex]z_{\alpha/2} = 1.96[/tex]

What is Normal Distribution?

A Normal Distribution is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.

Answer:

m^4+(1/m^4)= 123.4641 or 118.6

Step-by-step explanation:

m-(1/m)=3

m² - 1= 3m

m² -3m -1= 0

m = (3-√13)/2 = -0.3

Or

m =( 3+√13)/2= 3.3

m^4+(1/m^4) for m = -0.3

= (-0.3)^4 + (1/(0.3)^4)

= 0.0081 + 123.456

= 123.4641

m^4+(1/m^4) for m = 3.3

= (3.3)^4 + (1/(3.3)^4)

= 118.5921 + 0.008432

= 118.6

Answer:

a. In the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. The correct option is zero.

c. See the attached excel file for the new supply schedule.

d. The monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Step-by-step explanation:

Note: This question is not complete. A complete question is therefore provided in the attached Microsoft word file.

a. In the butter market, the monthly equilibrium quantity is million pounds and the equilibrium price is $ per pound.

At equilibrium, quantity demanded must be equal with the quantity supplied.

In this question, equilibrium occurs at the price of $1.20 per pound and quantity of 95 million pounds.

Therefore, in the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. What is the monthly surplus created in the wholesale butter market due to the price support (price floor) program?

Price floor refers to a government price control on the lowest price that can be charged for a commodity.

It should be noted that for a price floor to be binding, it has to be fixed above the equilibrium price.

Since the price floor of $1 per pound is lower than the equilibrium price of $1.2 per pound, the price floor will therefore not be binding. As a result, the market will still be at the equilibrium point and the monthly surplus created in the wholesale butter market due to the price support (price floor) program will be zero.

Therefore, the correct option is zero.

c. Fill in the new supply schedule given the change in the cost of feeding cows.

Since a decrease in the cost of feeding cows shifts the supply schedule to the right by 40 million pounds at every price, this implies that there will be an increase in supply by 40 million at each price.

Note: Find attached the excel file for the new supply schedule.

d. Given the new supply of butter, what is the monthly surplus of butter created by the price support program?

Since the price floor has been fixed at $1 per pound by the price support program, we can observe that the quantity demanded is 101 million pounds and quantity supplied is 119 million pounds at this price floor of $1. The surplus created is then the difference between the quantity demanded and quantity supplied as follows:

Surplus created = Quantity supplied - Quantity demanded = 119 - 101 = 18 million pounds

Therefore, the monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Answer:

Step-by-step explanation:

Answer:

56% shaded

Step-by-step explanation:

if there are 100 boxes, then every box it 1%

5 rows (50%) + 6 extra boxes (6%) = 56%

Answer:

81

Step-by-step explanation:

Let's do this systematically:

Four numbers: a, b, c, d

Whose mean is 85: [tex]\frac{a + b + c + d}{4} = 85[/tex]

Whose largest number is 97: [tex]\frac{a + b + c + 97}{4} = 85[/tex]

Lets solve for the other numbers:

a+b+c+97 = 85*4 = 340

340 - 97 = 243

a+b+c = 243

at this point it doesn't matter what the numbers are, they just need to add up to 243.

We can do 243÷3=81, which is our answer

Answer: k = 4, k = -4 and k = 0.

Step-by-step explanation:

If we have y = sin(kt)

then:

y' = k*cos(kt)

y'' = -k^2*son(x).

then, if we have the relation:

y'' - y = 0

we can replace it by the things we derivated previously and get:

-k^2*sin(kt) + 16*sin(kt) = 0

we can divide by sin in both sides (for t ≠0 and k ≠0 because we can not divide by zero)

-k^2 + 16 = 0

the solutions are k = 4 and k = -4.

Now, we have another solution, but it is a trivial one that actually does not give any information, but for the diff equation:

-k^2*sin(kt) + 16*sin(kt) = 0

if we take k = 0, we have:

-0 + 0 = 0.

So the solutions are k = 4, k = -4 and k = 0.

Answer:

7+c or 6

Step-by-step explanation:

Answer:

-89+c

Step-by-step explanation:

I'm assuming

"(7-6)(-1)

-7 +0

-7-

7-6

7+ c"

Is the whole equation.

(7-6)(-1) -7+0 -7- 7-6 7+c=

(1)(-1)-7+0-7-7-67+c=

-1-7+0-7-7-67+c=

-8+0-7-7-67+c=

-8-7-7-67+c=

-15-7-67+c=

-22-67+c=

-89+c

Answer:

SOLUTION SET={x/x>-1} and SOLUTION SET={x/x<-1}

Step-by-step explanation:

1)4x-39>-43

evaluating the inequality

adding 39 on both sides

4x-39+39>-43+39

4x>-4

dividing 4 on both sides

4x/4>-4/4

x>-1

SOLUTION SET={x/x>-1}

2)8x+31<23

evaluating the inequality

subtracting 31 on both sides

8x+31-31<23-31

8x<-8

dividing 8 on both sides

8x/8<-8/8

x<-1

SOLUTION SET={x/x<-1}

i hope this will help you :)

Answer: There are no solutions

Step-by-step explanation:Khan Academy

Answer:

A

Step-by-step explanation:

9-2x≤3x+24

-15≤5x

-3≤x

so it's:

[-3,∞)

The symbol [tex]\ge[/tex] can be thought of a greater than sign over top an equal sign, like this [tex]\stackrel{>}{=}[/tex] though the second horizontal line is erased to keep things relatively more simple (in terms of having to write it out).

Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

[tex]P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,3,......[/tex]

where, n = number of trials (samples) taken = 30

           r = number of success = at least 60%

           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = [tex]\frac{1}{4}[/tex] = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

(a) The probability you pass the exam is given by = P(X [tex]\geq[/tex] 18)

Because 60% of 30 = 18

P(X [tex]\geq[/tex] 18) = P(X = 18) + P(X = 19) +...........+ P(X = 29) + P(X = 30)

= [tex]\binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}[/tex]

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  [tex]n \times p[/tex]

                                                                =  [tex]30 \times 0.25[/tex] = 7.5

(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  [tex]\sqrt{n \times p \times (1-p)}[/tex]

                    =  [tex]\sqrt{30 \times 0.25 \times (1-0.25)}[/tex]

                    =  [tex]\sqrt{5.625}[/tex]  =  2.372                

Answer: 484m²

Step-by-step explanation: This is a question on solid shape.

The surface area of a cone is the same thing as the perimeter of the cone ie, the materials required to construct the cone.

Formula for the surface area of the cone = πrl + πr², ( the circular base )

From.the diagram,

r = 7.1m , l = 14.6m, π = 3.142

Now substitute for those values in.the formula above

SA = πrl + πr²

= 3.142 × 7.1 × 14.6 + 3.142 × 7.1²

= 325.6997 + 158.388

= 484.09

Now to the nearest tenth meter,

SA = 484m²

Answer:

Correct option: C.

Step-by-step explanation:

(Assuming the correct function is R(x) = 2x^2 + 3x + 5)

To find the input value that gives the value of R(x) = 19, we just need to use this output value (R(x) = 19) in the equation and then find the value of x:

[tex]R(x) = 2x^2 + 3x + 5[/tex]

[tex]19 = 2x^2 + 3x + 5[/tex]

[tex]2x^2 + 3x -14 = 0[/tex]

Solving this quadratic function using the Bhaskara's formula (a = 2, b = 3 and c = -14), we have:

[tex]\Delta = b^2 - 4ac = 9 + 112 = 121[/tex]

[tex]x_1 = (-b + \sqrt{\Delta})/2a = (-3 + 11)/4 = 2[/tex]

[tex]x_2 = (-b - \sqrt{\Delta})/2a = (-3 - 11)/4 = -3.5[/tex]

So looking at the options, the input to the function is x = 2

Correct option: C.

Answer:

-72

Step-by-step explanation:

We just have to plug in -2 for x so the answer is 12 * 3 * (-2) = -72.

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 60, \sigma = 16[/tex]

P(X < 80)

This is the pvalue of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 60}{16}[/tex]

[tex]Z = 1.25[/tex]

[tex]Z = 1.25[/tex] has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

Answer:

Alice

Step-by-step explanation:

5 feet is approximately 1.5 meters so we can say Alice is taller than Mary by 10cm

Answer:

Mary, by 3 inches.

Step-by-step explanation:

Convert the unit to inches.

5 feet = 60 inches

1.6 meters = 63 inches

63 - 60 = 3

Mary is taller than Alice by 3 inches.

Answer:

1) 2/9

2)3/9

Step-by-step explanation:

sorry,thats what i know so far

Answer:

Step-by-step explanation:

No, it is not an even function.  The graph is not symmetric about the y-axis.

Answer:

1) [tex]h(x) = \frac{f(x)}{g(x)}[/tex], 2) [tex]h(x) = \frac{g(x)}{f(x)}[/tex], 3) [tex]h(x) = f(x) + g(x)[/tex], 4) [tex]h (x) = f [g (x)][/tex], 5) [tex]h(x) = f(x) - g(x)[/tex]

Step-by-step explanation:

1) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h (x) = \frac{x+4}{2\cdot x + 1}[/tex], then:

[tex]h(x) = \frac{f(x)}{g(x)}[/tex]

2) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = \frac{2\cdot x + 1}{x+4}[/tex], then:

[tex]h(x) = \frac{g(x)}{f(x)}[/tex]

3) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = 3\cdot x + 5[/tex], then:

[tex]h(x) = 3\cdot x + 5[/tex]

[tex]h (x) = (1 + 2)\cdot x + (4+1)[/tex]

[tex]h(x) = x + 2\cdot x + 4 +1[/tex]

[tex]h(x) = (x+4) + (2\cdot x + 1)[/tex]

[tex]h(x) = f(x) + g(x)[/tex]

4) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = 2\cdot x + 5[/tex], then:

[tex]h(x) = 2\cdot x + 5[/tex]

[tex]h(x) = 2\cdot x + 1 + 4[/tex]

[tex]h(x) = (2\cdot x +1)+4[/tex]

[tex]h (x) = f [g (x)][/tex]

5) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = -x + 3[/tex], then:

[tex]h(x) = -x + 3[/tex]

[tex]h(x) = (1 - 2)\cdot x + 4 - 1[/tex]

[tex]h(x) = x - 2\cdot x + 4 - 1[/tex]

[tex]h(x) = x + 4 - (2\cdot x + 1)[/tex]

[tex]h(x) = f(x) - g(x)[/tex]