2 HCl + Na2SO4 > 2 NaCl + H2SO4
If you start with 20 grams of hydrochloric acid, how many grams of sulfuric acid will be produced?

Answers

Answer 1

Answer:

15

Explanation:


Related Questions

To prepare 250mL of calcium chloride solution with a molar concentration of 1.20mol/L, what mass of calcium chloride would be required?

Answers

Answer:

33.30 grams of CaCl2 will be required

Explanation:

Given,

Volume of solution, V= 250 ml

Molarity of solution, M= 1.20 mol/L

Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111

We know,

Required mass, W= SVM/1000

Now,

W = (111 X 250 X 1.20)/1000

    = 33300/1000

    = 33.30

Therefore, 33.30 grams of Calcium Chloride will be required.

Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.

Answers

Answer:

HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER

A flask contains 85.5 grams C12H2011 (sucrose) in 1.00 L of solution. What is the molarit
Your answer.
3.8 M
25 M
10M
1.2M

Answers

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Molar Mass of C₁₂H₂₂O₁₁ = (Molar Mass of C)*12 + (Molar Mass of H)*22 + (Molar Mass of O)*11Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol85.5 g ÷ 342.3 g/mol = 0.25 mol

Then we divide the number of moles by the number of liters to calculate the molarity:

0.25 mol / 1.00 L = 0.25 M

What is the hydrogen ion concentration of a solution with a pH of 2.0?

Answers

Answer:

[H+] = 10^-2

Explanation:

pH = -log[H+]

2 = -log[H+]

[H+] = 10^-2

What are the characteristics of acids and bases, and some examples of each?

Answers

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

Heat is added to two identical samples of a monatomic ideal gas. In the first sample, the heat is added while the volume of the gas is kept constant, and the heat causes the temperature to rise by 80 K. In the second sample, an identical amount of heat is added while the pressure (but not the volume) of the gas is kept constant. By how much does the temperature of this sample increase

Answers

Answer:

The temperature of the sample increase by 48 Kelvin

Explanation:

The sample is identical.

Hence the heat at constant pressure is equal to the heat at the constant Volume

Q1 = Q2

Q 1 = heat at constant pressure

Q2 = heat at the constant Volume

Substituting the given values, we get -

[tex]\frac{3}{2} nRT_1 = \frac{5}{2} nRT_2\\3 * 80 = 5 * T_2\\T_2 = 48[/tex]

The temperature of the sample increase by 48 Kelvin

What is the percent yield when 1.72 g of H2O2 decomposes and produces 375 mL of O2 gas measured at 42 oC and 1.52 atm

Answers

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

Theoretical yield of oxygen

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂O₂: 2 moleH₂O: 2 mole O₂: 1 moles

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

Real yield of oxygen

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

P= 1.52 atmV= 375 mL= 0.375 L (being 1000 mL= 1 L)n= ?R= 0.082 [tex]\frac{atmL}{molK}[/tex]T= 42 °C= 315 °K (being 0°C= 273°K)

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

Percent yield of oxygen

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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the reaction stoichiometry: brainly.com/question/16487206?referrer=searchResults brainly.com/question/14446695?referrer=searchResults brainly.com/question/11564309?referrer=searchResults brainly.com/question/4025026?referrer=searchResults brainly.com/question/18650135?referrer=searchResultsideal gas lawhttps://brainly.com/question/4147359?referrer=searchResults

Two iron-clad characteristics of matter
are that it has mass and also exhibits
which of the following?
A. It flows from hot to cold.
B. It can do work,
C. It has volume (takes up space).
D. It is a solid.

Answers

Answer:

it has volume( takes up space).

Explanation:

The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

What is Matter ?

A physical substance in general, that which occupies space and possesses rest mass, especially as distinct from energy.

Matter is important because it makes up everything around us and matter can not be created or destroyed but instead, they just transformed into a different form.

Any characteristic that can be measured, such as an object's density, colour, mass, volume, length, malleability, melting point, hardness, odour, temperature, and more, are considered properties of matter.

Therefore, The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

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Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to four significant figures. View Available Hint(s)

Answers

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

Oh no! I dash (lose) my purse

Answers

Answer:

Ok

Explanation:

Is nuclear energy good or bad?

Answers

Answer:

It is bad

Explanation:

Is nuclear energy good or bad?

Bad it’s bad bad baddddddddddddddd

What is the mass in grams of 5.50 moles of Copper, Cu?

Answers

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

What is a mole ?

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

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The total number of sodium atoms in 46.0 grams of sodium
is

Answers

The answer is 2.0, and it is because

help please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?

A 201kpa
B 200kpa
C 400kpa
D 78kpa​

Answers

Answer:

A. 201 kPa

Explanation:

We can solve this problem by using Boyle's law, which states:

P₁T₂ = P₂T₁

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 K

We input the data:

125 kPa * 487 K = P₂ * 303 K

And solve for P₂:

P₂ = 201 kPa

Water potential is the potential energy for water to move from one area to another. Water
always moves from a high water potential area to a lower water potential area. According
to the water potential formula, which factors affect the water potential?
a) Pressure and the amount of solute
b) Volume and temperature
c) Surface area and depth
d) Speed and concentration

Answers

Answer:

A

Explanation:

The water potential depends upon the pressure and amount of solute according to the water potential formula.

The following points can be considered:

The water potential formula defines as the summation of the solute potential, pressure component, gravimetric component, potential due to humidity, potential due to matrix effects, and the reference correction. The water potential does not depend on the volume and temperature of the system. The water potential does not depend on the surface area and depth of the system. The water potential does not depend on the speed and concentration of the system.

Therefore, the correct answer is a) pressure and the amount of solute.

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Which best compares kinetic energy and temperaturo?
A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.
B. Temperature is energy of motion, whilo kinetic energy is a measure of that energy in substances,
C.Kinetic energy is internal transferable energy, while temperature is a measure of that energy in substances,
D.Temperature is internal transferable energy, while kinetic energy is a measure of that energy in substances.

Answers

Which best compares kinetic energy and temperature?

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A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

got it right on edge 2021

28. If the total pressure of a mixture of four gases (neon, carbon dioxide, oxygen and hydrogen) is 1245 mm
Hg, what is the pressure of neon gas if the pressure of carbon dioxide is 145 mm Hg, the pressure of hydrogen is
499 mm Hg and the pressure of oxygen is 228 mm Hg?
A) 601 mm Hg
B) 746 mm Hg
C) 872 mm Hg
D) 373 mm Hg

Answers

Answer:

D) 373 mm Hg.

Explanation:

We can solve this problem by keeping in mind Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:

Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm HgNe Pressure = 373 mm Hg

The answer is option D) 373 mm Hg.

One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/Kg.K.

Answers

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

The change in entropy = [tex]-1083.534 J/k[/tex]

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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1. How many moles of hydrogen are needed to completely react with two moles of nitrogen?
_N2 + _H2 -->_NH3
Please hurry it is for a big assignment

Answers

N2 + 3H2  -->  2NH3

Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.

Explanation:

21. A piece of metal with a a mass of 15.2 g is heated from 17°C to 42°C. In the process it absorbs 1362 J of
energy as heat. What is the specific heat of the metal?

Answers

Answer:

3584.21 J/kg.K

Explanation:

Applying

Q = cm(t₂-t₁)........... equation 1

Where Q = Quantity of heat absorb, c = specific heat capacity of the metal, m = mass of the metal, t₁ = intial temperature, t₂ = Final temperature.

make c the subject of the equation

c = Q/(m(t₂-t₁)........... Equation 2

From the question,

Given: Q = 1362 J, m = 15.2 g = 0.0152 kg, t₁ = 17°C, t₂ = 42°C

Substitute these values into equation 2

c = 1362/0.0152(42-17)

c = 1362/0.38

c = 3584.21 J/kg.K

What is the [OH-] of a solution with a pH of 1.4?

Answers

Answer:

If a solution has pH=8 , then its pOH is 14−8=6 and the corresponding concentration of hydroxyl OH− ions is 10−6 mol per litre.

Explanation:

True or False
Low temperatures lead to faster dissolution rates compared to high temperatures

Answers

Answer:

false

Explanation:

this is because , high temperature speeds up the the random motion of particles which leads to high dissolution

what is a saturated organic compound and unsaturated organic compound?​

Answers

Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

As the temperature increases from 0°C to 25°C the amount of NH3 that can be dissolved in 100 grams of water.

A) decreases by 10 grams
B) decreases by 40 grams
C) increases by 10 grams
D) increases by 40 grams​

Answers

Answer:

decreases by 10 gram

Explanation:

b. Calculate the empirical formula of a formula unit with the following percent compositions: 59.7%
lithium (Li) and 40.3% nitrogen (N). Complete the table to help with the calculations. (5 points)

Answers

Given

Li - 59.7 %

N - 40.3 %

Solution,

First get the molar mass of each Atom,

Li- 6.941

N- 14.00

Second find the moles of both atom,

moles of Li = 59.7/6.941 = 8.60

Moles of N = 40.3/14 = 2.87

Third devide both the moles with smaller mole,

first- 8.6÷2.87 = 2.99 ~ 3

second 2.87÷2.87 = 1

Ratio of Li to N is 3:1

The compound is Li3N.

Using what you know about the structures of the amino acid side chains and the mechanisms presented in this chapter, which of the following amino acid side chain may play the following roles in an enzymatic mechanism: a. participate in proton transfer, b. act as a nucleophile

Answers

Answer:

a. participate in proton transfer - His

b. acts as a nucleophile - Ser

Explanation:

Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.

WILL GIVE BRAINLIEST!!!
Which of the following conditions remain constant in Boyle's law?

Volume and pressure
Density and temperature
Pressure and number of moles
Temperature and number of moles

Answers

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

[tex]P \propto \frac{1}{V}[/tex]

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

Answer:

Temperature and number of moles

Explanation:

Benzaldehyde and benzyl alcohol can be distinguished by NMR. The proton on the aldehyde group will appear at approximately _____ ppm; the methylene peak on the alcohol is the only peak ______ ppm for either compound.

Answers

Answer:

9-10 ppm.

0.2-0.4 ppm.

Explanation:

The proton on the aldehyde group will appear at approximately 9-10 ppm whereas the methylene peak on the alcohol is the only peak 0.2-0.4 ppm for either compound. Aldehydes and aromatics are quite distinctive in the Nuclear magnetic resonance (NMR). Aldehydes show up from 9-10 ppm, usually as a small singlet; aromatic protons show up from 6.5-8.5 ppm. NMR spectroscopy is the use of NMR to study the physical, chemical, and biological properties of matter.

Select all of the abiotic factors in an ecosystem.

Plants

Sunlight

Soil

Animals

Rocks

Dead deer in the forest

Temperature

Answers

Answer:

Sunlight, Soil, Rocks, Temperature and dead deer

Explanation:

You could say the dead tree is now an abiotic factor because biotic factors refer to living things

A 10.00 mL sample of a solution containing formic acid (a weak acid) was placed in a 25 mL volumetric flask and diluted to the mark with water. A 10.00 mL sample of the diluted formic acid solution was then titrated with 0.1322 M sodium hydroxide. The titration required 15.80 mL of sodium hydroxide to reach the equivalence point. Calculate the molarity and the percentage (by mass) formic acid in the original solution. The density of the formic acid solution was found to be 1.02 g/mL.

Answers

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

Moles NaOH = Moles HCOOH:

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

Moles in the original solution:

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

Molarity of the solution:

0.005222 moles HCOOH / 0.01000L =

0.522M

Mass HCOOH in 1L -Molar mass: 46.03g/mol-

0.522moles * (46.03g / mol) = 24.04g HCOOH

Mass solution:

1L = 1000mL * (1.02g / mL) = 1020g solution

Mass percent:

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

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