$15.30 for 3 small pizzas

Answer:

904.32 cm^3

Step-by-step explanation:

The formula for the volume of a sphere is V=4/3πr³. Since r is given, we can plug that in for r. I'm assuming that we are using 3.14 for pi, so when we plug in all the values in the equation we get V = 4/3*3.14*6³, which solves out to 904.32.

Answer:

The answer is given below

Step-by-step explanation:

a) What is the probability that a randomly selected pregnancy lasts less than 242 days

First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,

[tex]z=\frac{x-\mu}{\sigma}=\frac{242-247}{16}=-0.31[/tex]

From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783

(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.

If a sample of 17 pregnancies is obtained, the new mean [tex]\mu_x=\mu=247,[/tex] the new standard deviation: [tex]\sigma_x=\sigma/\sqrt{n} =16/\sqrt{17} =3.88[/tex]

c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{17} }=-1.29[/tex]

From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985

d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{49} }=-2.19[/tex]

From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143

(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?

It would be unusual if it came from mean of 247 days

f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean

For x = 236 days

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{236-247}{16/\sqrt{20} }=-3.07[/tex]

For x = 258 days

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{258-247}{16/\sqrt{20} }=3.07[/tex]

From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939

Answer: A (2,5)

Step-by-step explanation: Remove Parenthesis

                                             y = 3 (2) - 1

                                             Simplify 3 (2) - 1

                                             Multiply 3 by 2

                                             y = 6 - 1

                                             Subtract 1 from 6

                                             y = 5

Use the x and y values to from the ordered pair.

(2,5)

Answer:

(2.5)

Step-by-step explanation:

Answer and Step-by-step explanation:

According to the situation, The probabilities for each one is given below:

As there are 20 families

So the probabilities for each one is

For four families have one child is

[tex]= \frac{4}{20}\\\\ = \frac{1}{5}[/tex]

For eight families have two children is

[tex]= \frac{8}{20}\\\\ = \frac{2}{5}[/tex]

For five families have three children is

[tex]= \frac{5}{20}\\\\ = \frac{1}{4}[/tex]

For two families have four children is

[tex]= \frac{2}{20}\\\\ = \frac{1}{10}[/tex]

For one family have five children is

[tex]= \frac{1}{20}[/tex]

Answer:

The data set is:

S = {4.5, 4.5, 4.5, 4.5, 6, 8, 10, 12, 13.5, 13.5, 13.5, 13.5}

Step-by-step explanation:

Consider the ordered data set:

S = {4.5, 4.5, 4.5, 4.5, 6, 8, 10, 12, 13.5, 13.5, 13.5, 13.5}

The lower extreme is: 4.5

The upper extreme is: 13.5

The median for an even number of observations is the mean of the middle two values.

[tex]\text{Median}=\frac{6^{th}+7^{th}}{2}=\frac{8+10}{2}=9[/tex]

The first quartile (Q₁) is defined as the mid-value between the minimum figure and the median of the data set.

Q₁ = 4.5

The 3rd quartile (Q₃) is the mid-value between the median and the maximum figure of the data set.

Q₃ = 13.5

A box plot that has no whiskers has, Range = Interquartile Range.

Compute the range as follows:

[tex]Rangw=Max.-Min.=13.5-4.5=9[/tex]

Compute the Interquartile Range as follows:

[tex]IQR=Q_{3}-Q_{1}=13.5-4.5=9[/tex]

Thus, the box pot for the provided data has no whiskers.

Answer:

Step-by-step explanation:

E=300.

V=200.

Answer: 20km/h

Step-by-step explanation:

20km/h.  Simply average 15 and 25 by doing (15+25)/2

Hope it helps <3

Answer:

[tex] x = 5.1 yd [/tex]

Step-by-step Explanation:

Angle of depression is congruent to angle of elevation.

Therefore, angle of elevation of the given figure, which is opposite to x is 25°.

Adjacent length = 11 yd

Opposite length = x

Trigonometric ratio formula for finding x is shown below:

[tex] tan(25) = \frac{opposite}{adjacent} [/tex]

[tex] tan(25) = \frac{x}{11} [/tex]

Multiply both sides by 11 to solve for x

[tex] 11*tan(25) = x [/tex]

[tex] 5.129 = x [/tex]

[tex] x = 5.1 yd [/tex] (to the nearest tenth)

Answer:

( x + 36 ) ( x - 2 ) = 0

Step-by-step explanation:

x^2 + 36x - 2x -72 = 0

x ( x + 36 ) - 2 ( x + 36 ) = 0

( x + 36 ) ( x - 2 ) = 0

Answer:

320793

Step-by-step explanation:

320793 / 11 = 29163

Answer:

g(x)= 5x

Step-by-step explanation:

You should go back to the graph and notice that the abscissa 1 goes with the ordinate 5.

Now ask yourself how do I get 5 using 1. There many ways but notice that the function is growing and both functions f and g geow the same way. Wich mean that g(x)= 5x is a valid option.

notice that 0 is going with o at the ordinate.  

some little calculations . m=(5-0)/(1-0)= 5

so the function is g(x)=5x+p

p is 0 since it is the first ordinate

so g(x)= 5x

Answer:

8 to the power of 1 over 3 equals 2 to the power of 3 whole to the power of 1 over 3 equals 2 to the power of 3 multiplied by 1 over 3 equals 2

Step-by-step explanation:

Options are below

8 to the power of 1 over 3 equals 4 to the power of 3 whole to the power of 1 over 3 equals 4 to the power of 3 multiplied by 1 over 3 equals 4

8 to the power of 1 over 3 equals 2 to the power of 3 whole to the power of 1 over 3 equals 2 to the power of 3 multiplied by 1 over 3 equals 2

8 to the power of 1 over 3 equals 2 to the power of 4 whole to the power of 1 over 3 equals 2 to the power of 4 multiplied by 1 over 3 equals 16

16 to the power of 1 over 4 equals 8 to the power of 2 whole to the power of 1 over 4 equals 8 to the power of 2 multiplied by 1 over 4 equals 8

Given:

8^1/3

if a power is raised to a power, we simplify it by multiplying the exponents; this will create a whole number exponent

if 8 can be rewritten as a number to the 3rd power.

We have

8 = 2*2*2 = 2³

Therefore,

8^1/3=(2^3)^1/3

=2^3×1/3

=2^3/3

=2^1

=2

Answer:

Add each given variable

(6x + 10) + (x + 2) + x = 8x + 12

The sum of all the angles equals 180ᴼ

8x + 12 = 180

Subtract 12 from both sides

8x = 168

Divide by 8 on both sides

x = 21

Now plug in 21 for each x to find the measure of each angle.

(6[21] + 10) = 126 + 10 = 136ᴼ

(21 + 2) = 23ᴼ

x = 21ᴼ

Answer:

11

Step-by-step explanation:

sub 23 with m

23 - 12 = 11

Answer:

(Factor out 2x from the expression)

2x (x +3)

Answer:

x = 50

Step-by-step explanation:

Since this is a quadrilateral, the sum is 360 degrees

2x+x+10 + 3x+x = 360

Combine like terms

7x+10 =360

Subtract 10 from each side

7x+10-10 = 360-10

7x = 350

Divide by 7

7x/7 = 350/7

x = 50

Answer:

[tex]x = 50[/tex]

Step-by-step explanation:

Sum of the interior angles in a quadrilateral

= 360°

Let's solve now

[tex]x + 10 + 3x + x + 2x = 360 \\ 7x + 10 = 360 \\ 7x = 360 - 10 \\ 7x = 350 \\ \frac{7x}{7} = \frac{350}{7} \\ x = 50[/tex]

hope this helps you.

Answer: 51,000 ; 111,000

Step-by-step explanation:

The formula to calculate the simple interest is: PRT/100

where,

P = principal = 60,000

R = rate = 8.5%

T = time = 10 years

Simple interest =(60000 × 8.5 × 10)/100

= 5100000/100

= 51,000

Total Amount Paid= Principal + Interest

= 60,000 + 51,000

= 111,000

Answer:

The answer is "120".

Step-by-step explanation:

The assuming numbers:

[tex]0, 1,2,3,4,5,6,7,8,9[/tex]

The  odd number are=[tex]1,3,5,7,9[/tex]

Now we have four places:

In the first place we have 5 option

In second place we have 4 option

In third place, we have 3 option

In fourth place, we have 2 option

So, the value is [tex]5 \times 4 \times 3\times 2 \times 1= 120[/tex]

So, we have 120 different codes, which form the code.

Answer:

1) Option 2

2) Option 1

Step-by-step explanation:

1) 3a-2b

Where a = 3, b = 2

=> 3(3)-2(2)

=> 9-4

=> 5

2) 5c+3d

Where c = 4, d = -5

=> 5(4) + 3(-5)

=> 20 - 15

=> 5

Answers:

5, 5

Step-by-step explanation:

Put a as 3 and b as 2 and evaluate:

3(3) - 2(2)

9 - 4

= 5

Put c as 4 and d as -5 and evaluate:

5(4) + 3(-5)

20 - 15

= 5

Answer:

20°

Step-by-step explanation:

A= 360°- (160°+2*90°)= 20°

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.  

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:  

[tex]P(\frac{w}{R}) = \frac{P(W\cap R)}{P(R)} \ \ \ \ \ _{Where}\\\\P(R) = P(W\cap R) + P(W'\cap R) \\[/tex]

The probability that only the transmitted chip is white is therefore [tex]P(W) = \frac{2}{3}\\[/tex], since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be: [tex]P(\frac{R}{W}) = \frac{2}{3}[/tex]

[tex]P(W\cap R) = P(W) \times P(\frac{R}{W}) \\[/tex]

                [tex]= \frac{2}{3}\times \frac{2}{4} \\\\= \frac{2}{3}\times \frac{1}{2} \\\\= \frac{2}{3}\times \frac{1}{1} \\\\=\frac{1}{3}\\\\= 0.333[/tex]

Likewise, the chip transmitted is presumably red [tex](P(W')= \frac{1}{3})[/tex]and the chip transferred is a red chip of urn II [tex](P(\frac{R}{W'})= \frac{3}{4}[/tex], and a red chip is likely to be red [tex](\frac{R}{W'})[/tex].  

Finally, [tex]P(W'\cap R) = P(W') \times P(\frac{R}{W'})\\[/tex]

                              [tex]= \frac{1}{3} \times \frac{3}{4} \\\\ = \frac{1}{1} \times \frac{1}{4} \\\\=\frac{1}{4}\\\\= 0.25[/tex]

The estimation of [tex]P(R)[/tex] and [tex]P(\frac{W }{R})[/tex] as:  

[tex]P(R) = 0.3333 + 0.25\\\\ \ \ \ \ \ \ \ \ \ = 0.5833 \\\\ P(\frac{W}{R}) = \frac{0.3333}{0.5833} \\\\\ \ \ \ \ \ \ = 0.5714[/tex]

Answer:

[tex]\boxed{Area = 3.14 ft^2}[/tex]

Step-by-step explanation:

Radius = r = 2 feet

Angle = θ = π/2 (In radians) = 1.57 radians

Area of Sector = [tex]\frac{1}{2} r^2 \theta[/tex]

Area = [tex]\frac{1}{2} (4)(1.57)[/tex]

Area = 2 * 1.57

Area = 3.14 ft²

Answer:

               [tex]\bold{2\pi\ ft^2\approx6,28\ ft^2}[/tex]

Step-by-step explanation:

360°:2 = 180° so the area of a sector bounded by a 180° arc is a half of area of a circle of the same radius.

[tex]A=\frac12\pi R^2=\frac12\pi\cdot2^2=\frac12\pi\cdot4=2\pi\ ft^2\approx2\cdot3,14=6,28\ ft^2[/tex]

Answer:

only the inverse is a function

Answer:

B. 3(4 + 5) = 3(4) + 3(5)

3 left-bracket (4) (5) right-bracket = 3 (4) + 3 (5)

3 left-bracket (4) (5) right-bracket = Left-bracket 3 (4) right-bracket + Left-bracket 3 (5) Right-bracket

Step-by-step explanation:

Distributive property of multiplication over addition:

a(b + c) = ab + ac

You have

3(4 + 5), so following the pattern above, you should get:

3(4 + 5) = 3(4) + 3(5)

Answer:

b

Step-by-step explanation:

I took the test

Answer: y = 2x+8

Check out this graph I supplied you with!

Answer:

We can prove that ΔTMB ≅ ΔTMD and ΔTMA ≅ ΔTMC by ASA. This means that BM = MD = BD / 2 = 8.5 and that AM = CM = 5 which means that CD = MD - CM = 8.5 - 5 = 3.5.

Answer:

1)2205little cherries

2)0.5.

Step-by-step explanation:

1)7little=2big

?=630big

7×630=2205little cherries

2

2)²/5x=¹/10what is the value of 10x-2

first find the value of x that is ¹/10÷²/5=¼

so x is ¼

insert the value ie 10×¼-2

=2.5-2

=0.5

Answer:

1:3

Step-by-step explanation:

Please study the diagram briefly to understand the concept.

First, we determine the height of the isosceles trapezoid using Pythagoras theorem.

[tex]4^2=2^2+h^2\\h^2=16-4\\h^2=12\\h=\sqrt{12}\\ h=2\sqrt{3}$ units[/tex]

The two parallel sides of the trapezoid are 8 Inits and 4 units respectively.

Area of a trapezoid [tex]=\dfrac12 (a+b)h[/tex]

Area of the trapezoid

[tex]=\dfrac12 (8+4)*2\sqrt{3}\\=12\sqrt{3}$ Square Units[/tex]

For an equilateral triangle of side length s.

Area  [tex]=\dfrac{\sqrt{3}}{4}s^2[/tex]

Side Length of the smaller triangle, s= 4 Units

Therefore:

Area of the smaller triangle

[tex]=\dfrac{\sqrt{3}}{4}*4^2\\=4\sqrt{3}$ Square units[/tex]

Therefore, the ratio of the area of the smaller triangle to the area of the trapezoid

[tex]=4\sqrt{3}:12\sqrt{3}\\$Divide both sides by 4\sqrt{3}\\=1:3[/tex]

Answer:

(  3x -2)

Step-by-step explanation:

6x^2 – 7x + 2

We know that the constant only has factors of 1 and 2

Since the middle term is negative we know that that we are subtracting

A negative times a negative is positive for the final term

A negative plus a negative is negative for the middle term

(   -1 ) (   -2)

We have to determine how to break up 6x^2

1x * 6x

2x*3x

3x*2x

6x*1x

We are given that one factor is 2x-1

(  2x -1 ) (   -2)

That means the other factor of 6x^2 is 3x  ( 2x*3x)

(  2x -1 ) (  3x -2)

Answer:

3x-2

Step-by-step explanation:

Factors are:

--------------

Answer:

d) Before cooling begins, the temperature of the water is 22°C

Step-by-step explanation:

Option A

If t=7 minutes

D=-7/5t+22

=-7/5(7)+22

=-49/5+22

=-49+110/5

=61/5

=12.2°C

Change in temperature=12.2°C-22°C

=-9.8°C

Option B

If t=5 minutes

D=-7/5t+22

=-7/5*5+22

=-7+22

=15°

Change in temperature=15°-22°

=-7°

Option C

The temperature of the ice must be less than 22°C

Option D

D=-7/5t+22

When ice is not placed, t=0

D=-7/5t+22

=-7/5(0)+22

=0+22

=22

Temperature of the water before cooling=22°

Answer:

D

Step-by-step explanation: