15. The primitive data types in JavaScript are:​

Answer:

The program written in Python is as follows

nums = []

for i in range(0,68):

-->nums.append(i)

print(nums)

Explanation:

Please note that --> is used to denote indentation

The first line creates an empty list

nums = []

This line creates an iteration from 0 to 67, using iterating variable i

for i in range(0,68):

This line saves the current value of variable i into the empty list

nums.append(i)

At this point, the list has been completely filled with 0 to 67

This line prints the list

print(nums)

Answer:

Here is the C++ program for Employee class with fields id,name and sal.

#include <iostream>  // to use input output functions

#include <string>  //to manipulate and use strings

using namespace std;   // to access objects like cin cout

class Employee {  //class Employee

private:  

/* the following data members are declared as private which means they can only be accessed by the functions within Employee class */

  string name;  //name field

  int id; //id field

  double sal;   //salary field

public:    

  Employee();  // constructor that initializes an object when it is created

/* setName, setID and setSalary are the mutators which are the methods used to change data members. This means they set the values of a private fields i.e. name, id and sal */

  void setName(string n)  //mutator for name field

     { name = n; }        

  void setId(int i)  //mutator for id field

     { id = i; }        

  void setSalary(double d)  //mutator for sal field

     { sal = d; }  

/* getName, getID and getSalary are the accessors which are the methods used to read data members. This means they get or access the values of a private fields i.e. name, id and sal */

  string getName()  //accessor for name field

     { return name; }        

  int getId()  //accessor for id field

     { return id; }        

  double getSalary()  //accessor for sal field

     { return sal; }  };  

Employee::Employee() {  //default constructor where the fields are initialized

  name = "";  // name field initialized

  id = 0;  // id field initialized to 0

  sal = 0;   }   // sal field initialized to 0

void display(Employee);  

// prototype of the method display() to display the data of Employee

int main() {  //start of the main() function body

  Employee emp;  //creates an object emp of Employee class

/*set the name field to Abc Xyz which means set the value of Employee class name field to Abc Xyz  through setName() method and object emp */

  emp.setName("Abc Xyz");  

/*set the id field to 1234 which means set the value of Employee class id field to 1234  through setId() method and object emp */

  emp.setId(1234);

/*set the sal field to 1000 which means set the value of Employee class sal field to 1000  through setSalary() method and object emp */

  emp.setSalary(1000);    

  display(emp);  }   //calls display() method to display the Employee data

void display(Employee e) {  // this method displays the data in the Employee //class object passed as a parameter.

/*displays the name of the Employee . This name is read or accessed through accessor method getName() and object e of Employee class */

  cout << "Name: " << e.getName() << endl;  

/*displays the id of the Employee . This id is read or accessed by accessor method getId() and object e */

  cout << "ID: " << e.getId() << endl;

/*displays the salary of the Employee . This sal field is read or accessed by accessor method getSalary() and object e */

  cout << "Salary: " << e.getSalary() << endl;  }

Explanation:

The program is well explained in the comments mentioned with each statement of the program.

The program has a class Employee which has private data members id, name and sal, a simple default constructor Employee(), mutatator methods setName, setId and setSalary to set the fields, acccessor method getName, getId and getSalary to get the fields values.

A function display( ) is used to display the Employee data i.e. name id and salary of Employee.

main() has an object emp of Employee class in order to use data fields and access functions defined in Employee class.

The output of the program is:

Name: Abc Xyz                                                                                                      

ID: 1234                                                                                                                  

Salary: 1000

The program and its output are attached.

Answer:

Both manual and digital editing are concepts used in proofreading.

Manual editing is also called "hard proofreading" (or "hard proofing" for short). It is the process of proofreading, modifying or revising printed documents. In this type of proofreading, one would normally manually mark parts of the printed documents with editing materials such as ink, pen, marker e.t.c

Digital editing is also called "soft proofing". In contrast to manual editing, this type is done on digital documents. These documents include, but not limited to, DOC, txt, PDF, image, audio and video files.

Tools for editing manually are;

i. pen

ii. ink

iii. tipex

Tools for editing digitally are;

i. Photoshop application

ii. Text editors such as notepad++, Microsoft word

Proofreading has evolved in recent times as a result of advancements in technology. Now, manual proofreading has paved way for digital proofreading, which allows revising of PDF and  DOC files. The difference in both forms is as follows:

Manual Editing: In the process of revising or proofing printed documents, one would manually apply standard proofreading marks. Manual editing is also known as "Hard proofing", as the process requires proofreaders to mark the hard copies.

Digital Editing: In the process of revising or proofing digital documents i.e. PDF and DOC files, one would digitally apply the proofreading marks. Thus, corrections and edits are transferred electronically among authors, proofreaders. Digital editing is also known as "Soft proofing", as the process requires proofreaders to mark the soft copies i.e. without using any paper or pen.

There are a number of electronic tools and marks available for both techniques of

proofreading. Some tools used for manual proofreading include- deletion, capitalization, and  insertion, close-up, transpose.

Tools used in digital proofreading include- spell check, readability levels, trite expressions,  and comment, track changes.

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Answer:

Bulk Ethernet Cable - Category 5e or CAT5e

Bulk RJ45 Crimpable Connectors for CAT-5e

Explanation:

If my computer has 4 gigabytes of ram memory then I have 4e+9 bytes of memory.  I think-

Answer: That isn't a software problem, its a hardware problem. There is a difference between 12gb of ram versus 100 gb of HDD. Ram is temporary storage, you can not turn SSD or HDD storage into RAM. If you are a gamer, STEER AWAY FROM LAPTOPS, DO NOT BUY A GAMING LAPTOP. Either buy a DESKTOP (or build) or a console. They give more performance for the price and they are easily upgradable. Not many people can open up a laptop and put in more RAM because the hardware is incredibly small.

Answer:

D.  A maximum RPO of 60 minutes

Explanation:

Note that an option is not included in this list of options.

The complete list of options is:

A. A maximum MTTR of 30 minutes

B. A maximum MTBF of 30 minutes

C. A maximum RTO of 60 minutes

D.  A maximum RPO of 60 minutes

E. An SLA guarantee of 60 minutes

The Recovery Point Objective tells how old a backup file must be before it can be  recovered by a system after failure.

Since the data in the failover systems described in this question must be backup and recovered after the failure, it will be important to include the Recovery Point Objective (RPO) in the Business Continuity Plan.

Since the failover systems must use back up data that is no older than one hour, the backup of the system data must be done at intervals of 60 minutes or less. Meaning that the maximum RPO is 60 minutes.

Note that RPO is more critical than RTO in data backup

Answer:

Linked lists and arrays are both linear data structures but while an array is a collection of items that can be accessed randomly, a linked list can be accessed sequentially.

A sparse matrix contains very few non-zero elements. For example;

_                        _

|  0   0   3  0  6    |

|   0   5   0  0  4   |

|   2   0   0  0  0   |

|_ 0   0   0  0  0 _|

In the implementation of a sparse matrix, the following are some of the pros and cons of using a linked list over an array;

PROS

i.  Linked lists are dynamic in nature and are readily flexible - they can expand and contract without having to allocate and/or de-allocated memory compared to an array where an initial size might need to be set and controlled almost manually. This makes it easy to store and remove elements from the sparse matrix.

ii. No memory wastage. Since the size of a linked list can grow or shrink at run time, there's no memory wastage as it adjusts depending on the number of items it wants to store. This is in contrast with arrays where you might have unallocated slots. Also, because the zeros of the sparse matrix need not be stored when using linked lists, memory is greatly conserved.

CONS

i. One of the biggest cons of linked lists is the difficulty in traversing items. With arrays, this is just of an order of 0(1) since the only requirement is the index of the item. With linked lists, traversal is sequential which means slow access time.

ii. Storage is another bottle neck when using linked lists in sparse matrix implementation. Each node item in a linked list contains other information that needs to be stored alongside the value such as the pointer to the next or previous item.

Answer:

Security controls are those measures taken to prevent, identify, counteract, and reduce security risks to computer systems, whereas, Security Requirements are guidelines or frameworks that stipulates measures to ensure security control.

Explanation:

Security controls encompass all the proactive measures taken to prevent a breach of the computer system by attackers. Security requirements are those security principles that need to be attained by a system before it can be certified as safe to use.

Security controls are of three types namely, management, operational, and technical controls. Examples of technical controls are firewalls and user authentication systems. A statement like 'The system shall apply load balancing', is a security requirement with an emphasis on availability.

(ESFs) is correct: ESFs are not exclusively federal coordinating mechanism.

It is not okay to just paste the URLs of the items you used for references at the end of a paper therefore the answer is False

For better understanding, lets explain why the answer is false



From the above, we can therefore say that the answer is It is not okay to just paste the URLs of the items you used for references at the end of a paper therefore the answer is False, is correct.

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Answer:

double ComputeGasVolume(double pressure, double temperature, double moles){

   double volume = moles*GAS_CONST*temperature/pressure;

    return volume;        

}

Explanation:

You may insert this function just before your main function.

Create a function called ComputeGasVolume that takes three parameters, pressure, temperature, and moles

Using the given formula, PV = nRT, calculate the volume (V = nRT/P), and return it.

Answer:

PAN

Explanation:

PAN, short form of Personal Area Network, is a type of computer network built for personal use typically within a building. This could be inside a small office or a bedroom in a residence. This type of network basically consists of one or more personal computers, digital camera, printer, Tv, scanner, telephones, peripheral devices, video games console, and other similar devices.

It is pretty much simple to set up and allow for great flexibility. In this network, a single modem can be set up to enable both wired and wireless connections for multiple devices within the building.

Answer:

true

Explanation:

Answer:

Internet backbone

Explanation:

The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.

Answer:

1 (true)

Explanation:

10 == 10 is valid=> 10 >= 10 is valid => 10 >=(5*2) is valid

10 == 10 is valid=> 10 <= 10 is valid => 10 <=(5*2) is valid

=>  ((10 >= 5*2) and (10 <= 5*2)) is valid => Return 1 or True

Answer: D) Sharing best practices, lessons learned and other topics in a central place where the team can collaborate

Explanation: Knowledge sharing within a team is usually an important aspect of building a strong and efficient team. Acquiring knowledge usually comes from the experience gathered from previous projects, learning, or tips learned from various sources. Therefore, sharing knowledge is always a good way to ensure that what is gained is sustained by letting others know. Sharing and sustaining knowledge is most effective when transmitted or aired to a group of people usually a team gathered in an interactive setting which allows members to freely share experience and get feedback, views, or thoughts from other collaborators.

Answer:

Following are the description of the given points:

Explanation:

A) The Multiple greedy approaches could exist, which could be to reach for the closest emergency diamond, and yet clearly we are going to miss some very essential routes in that case. So, it can make every argument quickly, and seek to demonstrate a reference case for that.

B) An approach to the evolutionary algorithm and its users are going to just have states M x N. But each state (i, j) indicates the absolute difference between the amount of the selected diamond and the amounts of the costs incurred.

DP(i, j) = DimondVal(i, j) + max ((DP(i, j-1)-2), (DP(i-1,j-1)-3))

DP(i, j) is a description of the state.

DimondVal(i, j) is the diamond value at (i j), 0 if there is no diamond available.

This states must calculate the states of M N  and it involves continuous-time for each State to determine. Therefore the amount of time of such an algo is going to be O(MN).

Answer:

packet filtering

Explanation:

We can use a packet filtering firewall, for something like this, reasons because when visiting a site these types of firewalls should block all incoming traffic and analyze each packet, before sending it to the user. So if the packet is coming from a malicious origin, we can then drop that packet and be on our day ;D

Answer:

Following are the code to this question:

#include <stdio.h> //defining header file

#include <string.h>//defining header file

int main()//defining main method

{

char name[50]; //defining character variable

int A=0,E=0,I=0,O=0,U=0,value=0,i,l; //defining integer variables

printf("Enter string value: ");//print message

gets(name);//input value by gets method

l=strlen(name);//defining l variable to store string length

for(i=0; i<50; i++) //defining loop to count vowels value

{

if(name[i] == 'A' || name[i] == 'a') //defining if condition count A value A++;//increment value by 1

else if(name[i] == 'E' || name[i] == 'e')//defining else if condition count E value

E++;//increment value by 1

else if(name[i] == 'I' || name[i] == 'i') //defining else if condition count I value

I++;//increment value by 1

else if(name[i] == 'O' || name[i]== 'o') //defining else if condition count O value

O++;//increment value by 1

else if(name[i] == 'U' || name[i] == 'u')//defining else if condition count U value

U++;//increment value by 1

else if(name[i]>= '0' && name[i] <= '9')//defining else if condition count digits value

value++;//increment value by 1 }

printf("A: %d\n",A);//print A value

printf("E: %d\n",E); //print E value

printf("I: %d\n",I);//print I value

printf("O: %d\n",O);//print O value

printf("U: %d\n",U);//print U value

printf("value: %d",value);//print digits value

return 0;

}

Output:

please find the attachment.

Explanation:

Answer:

Adobe Photoshop To Manipulate The Photo.

Explanation:

BLACKPINKS new album is amazing OMG I LOVE Lovesick Girls!!!

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

Answer:

The function can return multiple values and the function can return an object

Explanation:

The advantage of returning a structure type from a function when compared to returning a fundamental type is that the function can return multiple values and also the function can return an object

A function in a structure can be passed to a function from any other function or from the main function itself and the definition of a structure can be seen in the function where it is found

Answer:

def random_marks(apostrophe, quotation, apostrophe_quotation):

   return "'"*apostrophe + "\""*quotation + "'\""*apostrophe_quotation

print(random_marks(3, 2, 3))

Explanation:

Create a function called random_marks that takes apostrophe, quotation, and apostrophe_quotation as parameters. Inside the function, return apostrophe sign times apostrophe plus quotation mark times quotation plus apostrophe sign quotation mark times apostrophe_quotation.

Note that plus sign (+) is used to concatenate strings. Also, if you multiply a string with a number, you get that number of strings ("#"*3 gives ###).

Then, call the function with given parameters and print

Answer:

#This is in Python

number1 = raw_input("Enter a number: ")

number2 = raw_input("Enter another number: ")

sum = float(number1) + float(number2)

print(sum)

Explanation:

Answer:

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets. It might go a week or longer between charges if you only use the tablet once or twice each day.

Many people find that charging merely 80% is ineffective. Your phone won't function if you fully charge it and then use it in a single day. The 40-80% rule applies if, like me, your daily usage is limited to 25–50%.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.                          

Therefore, In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

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#SPJ2

Answer:

1. Divide each bonus by regular bonus apply this to all the data

2. In cell C11 write, "Average" press tab key on the keyboard and then select the range of the cells either by typing "C7:C10" or by selecting it through the mouse.

Explanation:

The average bonus multiplier can be found by dividing each bonus with the regular bonus applying this to all the data and then putting the average formula and applying it to the cells C7:C10.  

After dividing the bonus with regular bonus, in cell C11 write, "Average" press tab key on the keyboard and then select the range of the cells either by typing "C7:C10" or by selecting it through the mouse.

Answer:

I believe it is A

Explanation:

Question:

1. Open a command prompt window, type ipconfig/ all and press Enter.

2. Write down the information for your system’s active network connection(most likely either Ethernet or Wi-Fi).

* Physical address in paired hexadecimal form.

* Physical address expressed in binary form.

Answer:

00000000 11111111 00000011 10111110 10001100 11011010

Explanation:

(i)First, open a command prompt window by using the shortcut: Windows key + X then select command prompt in the list.

(ii)Now type ipconfig/ all and press Enter. This will return a few information

(a) To get the Physical address in paired hexadecimal form, copy any of the Physical Addresses shown. E.g

00-FF-03-BE-8C-DA

This is the hexadecimal form of the physical address.

(b) Now let's convert the physical address into its binary form as follows;

To convert to binary from hexadecimal, we can use the following table;

Hex                 |         Decimal                |           Binary

0                      |          0                           |           0000

1                       |          1                            |           0001

2                      |          2                           |           0010

3                      |          3                           |           0011

4                      |          4                           |           0100

5                      |          5                           |           0101

6                      |          6                           |           0110

7                      |          7                           |           0111

8                      |          8                           |           1000

9                      |          9                           |           1001

A                     |          10                           |           1010

B                      |          11                           |           1011

C                      |          12                           |           1100

D                      |          13                           |           1101

E                      |          14                           |           1110

F                      |          15                           |           1111

Now, from the table;

0 = 0000

0 = 0000

F = 1111

F = 1111

0 = 0000

3 = 0011

B = 1011

E = 1110

8 = 1000

C = 1100

D = 1101

A = 1010

Put together, 00-FF-03-BE-8C-DA becomes;

00000000 11111111 00000011 10111110 10001100 11011010

PS: Please make sure there is a space between ipconfig/ and all

Answer:

(b) is used in Traceroute

(d) is used by Ping

Explanation:

ICMP is the short form of Internet Control Message Protocol. It is a protocol used by networking devices such as routers to perform network diagnostics and management. Since it is a messaging protocol, it is used for sending network error messages and operations information. A typical message could be;

i. Requested service is not available

ii. Host could not be reached

ICMP does not use ports. Rather it uses types and codes. Some of the most common types are echo request and echo reply.

Traceroute - which is a diagnostic tool - uses some messages available in ICMP (such as Time Exceeded) to trace a network route.

Ping - which is an administrative tool for identifying whether a host is reachable or not - also uses ICMP. The ping sends ICMP echo request packets to the host and then waits for an ICMP echo reply from the host.

ICMP is not required to solve NAT traversal problem neither does it have a new version in IPV6.

Explanation:

A website is a group of globally accessible into linked pages which have a single domain name. A web application is a software or program is is accessible using any web browser.

Answer:

Explanation:

A website shows static or dynamic data that is predominantly sent from the server to the user only, whereas a web application serves dynamic data with full two way interaction.