15 points AND BRAINLIEST!!
At what Celsius temperature will Neon have a mass of 0.02 kg and a pressure of 6.43 atm in 2.5 L
container

Answers

Answer 1

Answer:

[tex]T=-75.59\°C[/tex]

Explanation:

Hello!

In this case, since we can treat neon as an ideal gas, it is possible for us to use the following equation:

[tex]PV=nRT[/tex]

Whereas the temperature is out unknown, so we proceed as follows:

[tex]T=\frac{PV}{nR}[/tex]

However, we need the moles of neon in 0.02 kg as shown below:

[tex]n=0.02kg*\frac{1000g}{1kg}*\frac{1mol}{20.17g} =0.992mol[/tex]

Thus, we obtain the following temperature in Kelvins:

[tex]T=\frac{6.43atm*2.5L}{0.992mol*0.08206\frac{atm*L}{mol*K}} \\\\T=197.56K[/tex]

Therefore, in degree Celsius it is:

[tex]T=197.56-273.15\\\\T=-75.59\°C[/tex]

Best regards!


Related Questions

what process formed slate

Answers

Answer:

Explanation:

Slate is a fine-grained, foliated metamorphic rock that is created by the alteration of shale or mudstone by low-grade regional metamorphism. It is popular for a wide variety of uses such as roofing, flooring, and flagging because of its durability and attractive appearance.

Answer:

Deep within the Earth's crust rocks can be put under huge pressures and temperatures are very high. These conditions can cause the minerals in the rock to change. This process is called metamorphism. Limestone can change into marble, shale and mudstones into slate, and igneous rocks like granite can turn into gneiss.

Explanation:

Slate is a fine-grained, foliated metamorphic rock that is created by the alteration of shale or mudstone by low-grade regional metamorphism. It is popular for a wide variety of uses such as roofing, flooring, and flagging because of its durability and attractive appearance.

What group of elements on the periodic table is not usually found in nature?

Answers

Answer:

Halogens

Explanation:

they they are never found free in nature.

How many formula units of CuCl2 are present in 18.42 g?

Answers

Answer:

Think 12 units

Explanation:

Because it represents the hands of the clock

Can some one help I'm lost iam being timed:( Show using two conversion factors how you would convert from 0.020 kg into mg

Answers

Answer:

20000 Mg

Explanation:

10-kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answers

Answer:

Temperature = 0.605°C

Total enthalpy at 300kpa = 545.2 kJ

Total enthalpy at 600kpa = 846.45 kJ.

Explanation:

Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.

Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.

The first thing to do is to determine the value for the specific volume of saturated liquid.

At 300 kpa, the specific volume of saturated liquid,n is given below as;

300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.

Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.

300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).

n = 0.0679 m^3/kg.

The second thing to do is to determine the value of the specific volume.

Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.

Determine the enthalpy of the mixture,b(I). This is given below as;

300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).

b(I) = 198.125 kJ/Kg.

Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.

b = 54.517 KJ/Kg.

Total enthalpy = 10 × 54.517 = 545.17 kJ.

Temperature can be Determine as below;

300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.

Temperature = 0.605°C.

Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10

Total enthalpy at 600kpa = 846.45 kJ.

Ice floats on the surface of water because ice is less dense than liquid water
true or false?

Answers

Answer:

yes it is true.

Ice floats on the surface of water because ice is less dense than liquid water

Explanation:

True because ice is not as dense as water

Richard sketched models of two different neutral isotopes of oxygen. If the
isotope models are accurate, which statement might be true? (Refer to the
periodic table if necessary.)
A. One shows 7 protons, and one shows 9.
B. One shows 8 neutrons, and one shows 9.
C. One shows 8 electrons, and one shows 9.
D. One shows 8 protons, and one shows 7.

Answers

Answer:

its b

Explanation:

just did the test on A P E X

If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.

What is isotope?

A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.

The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

To know more about isotope, here:

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What two methods are used for determining the age of rocks and fossils?

Relative and Absolute Dating

Carbon and Water Dating

Absolute and Resolute Dating

Relative and Absent Dating

Answers

Explanation:

first one because absolute dating is a thing for rock layers

How many significant figures are in the following measurement? 433.8 liters

Answers

4 significant figures
There are four significant figures in this measurement

How many grams of silver nitrate are needed to prepare 0.125 M solution in 250.0 mL of water?*
(1 Point)
AgNO₃
Ag
= 107.868 8
mol
N = 14.0078
mol
8
0 = 15.999
mol
0.313 g
169.872 g
0.0849 g
5.31 g
O 31.3 g

Answers

Answer:5.3 grams AgNO3

Explanation:

To solve your problem, take a look at the definition of molality (m):

moles of solute/kg of solvent

You are given the grams of solvent (water) to find the grams of silver nitrate.

First, convert 250 grams to kg:

250 g * 1 kg / 1000g = 0.250 kg

Now that you have the kg of solvent, you can solve for the moles of solute:

kg of solvent * molality = moles of solute

0.250 kg * 0.125 m = 0.03125 mol AgNO3

You can convert the number of moles to grams using the molar mass of AgNO3, which is 169.872 g/mol:

moles of solute * molar mass of solute = grams of solute

0.03125 mol AgNO3 * 169.872 g/mol = 5.3085 g

Because your question provides two significant digits, you must round this number to get the final answer:

5.3 grams AgNO3

I hope this helps!

What happens when a base dissolves?
A. It increases the concentration of OH in solution.
B. It increases the concentration of H+ in solution.
C. It adds oxygen to the solution.
D. It is no longer dangerous.

Answers

Answer:

A. It increase the concentration of OH in solutions.

Explanation:

Bases are substances that react with and neutralise acids, producing water. When dissolved, bases release hydroxide ions, OH-(aq) into solution.

When a base dissolves, it increases the concentration of OH⁻ ions in the solution. Therefore, option A is correct.

What are acids and bases?

An acid can be described as a substance that is capable of donating a hydrogen ion to another substance.  A base can be described as a molecule or ion that is able to have a hydrogen ion from an acid.

Acidic materials are commonly identified by sour taste. An acid can be considered commonly a molecule that can donate an H⁺ ion and can be energetically favorable after a loss of H⁺ ion. Acids increase the concentration of H⁺ ions in solution.

Bases are described by a bitter taste and a slippery nature. A base or alkali increases the concentration of OH⁻ ions in the solution. When bases react with acids, they give salts and water as products.

The pH range on the pH scale of the acids lies between 0 to 7 and the pH range of the bases lies between 7 to 14.

Learn more about acids and bases, here:

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9. The times of first sprinkler activation (in seconds) for a series of tests of fire-prevention sprinkler systems that use aqueous film-forming foam is as follows. The system has been designed so that the true average activation time is supposed to be at most 25 seconds. Does the data indicate the design specifications have not been met

Answers

This question is incomplete, the complete question is;

The times of first sprinkler activation (in seconds) for a series of tests of fire-prevention sprinkler systems that use aqueous film-forming foam is as follows; 27 41 22 27 23 35 30 33 24 27 28 22 24

( see " use of AFFF in sprinkler systems," Fire technology, 1975: 5)

The system has been designed so that the true average activation time is supposed to be at most 25 seconds.

Does the data indicate the design specifications have not been met?

Test the relevant hypothesis at significance level 0.05 using the P-value approach  

     

Answer:

since p-value (0.042299) is lesser than the level of significance ( 0.05)

We Reject Null Hypothesis

Hence, There is no sufficient evidence that the true average activation time is at most 25 seconds

Explanation:

Given the data in the question;

lets consider Null and Alternative hypothesis;

Null hypothesis H₀ : There is sufficient evidence that the true average activation time is at most 25 seconds

Alternative hypothesis H₁ : There is no sufficient evidence that the true average activation time is at most 25 seconds

i.e

Null hypothesis H₀ : μ ≤ 25

Alternative hypothesis H₁ :  μ > 25

level of significance σ = 0.05

first we determine the sample mean;

[tex]x^{bar}[/tex] = [tex]\frac{1}{n}[/tex]∑[tex]x_{i}[/tex]

where n is sample size and ∑[tex]x_{i}[/tex] is summation of all the sample;

=  [tex]\frac{1}{13}[/tex]( 27 + 41 + 22 + 27 + 23 + 35 + 30 + 33 + 24 + 27 + 28 + 22 + 24 )

=   [tex]\frac{1}{13}[/tex]( 363

sample mean [tex]x^{bar}[/tex] = 27.9231

next we find the standard deviation

s = √( [tex]\frac{1}{n-1}[/tex]∑([tex]x_{i}-x^{bar}[/tex])²

x                    ([tex]x_{i}-x^{bar}[/tex])                       ([tex]x_{i}-x^{bar}[/tex])²

27                   -0.9231                          0.8521

41                    13.0769                        171.0053

22                  -5.9231                          35.0831  

27                  -0.9231                          0.8521

23                  -4.9231                          24.2369

35                  7.0769                          50.0825

30                  2.0769                          4.3135

33                  5.0769                          25.7749

24                  -3.9231                          15.3907

27                  -0.9231                          0.8521

28                  0.0769                          0.0059

22                 -5.9231                          35.0831  

24                 -3.9231                          15.3907

sum                                                    378.9229

so ∑([tex]x_{i}-x^{bar}[/tex])² = 378.9229

s = √( [tex]\frac{1}{13-1}[/tex] ×378.9229 )

s = √31.5769

standard deviation s = 5.6193

now, the Test statistics

t = ( [tex]x^{bar}[/tex] - μ ) / [tex]\frac{s}{\sqrt{n} }[/tex]

we substitute

t = ( 27.9231 - 25 ) / [tex]\frac{5.6193}{\sqrt{13} }[/tex]

t = 2.9231 / 1.5585

t = 1.88

now degree of freedom df = n - 1 = 13 - 1 = 12

next we calculate p-value

p-value = 0.042299 ( using Execl's ( = TDIST(1.88,12,1)))

Here x=1.88, df=12, one tail

now we compare the p-value with the level of significance

since p-value (0.042299) is lesser than the level of significance ( 0.05)

We Reject Null Hypothesis

Hence, There is no sufficient evidence that the true average activation time is at most 25 seconds

Why does adding lemon juice to a blueberry smoothie
make it change color from purple to pink.

Answers

Answer:

Acidity

Explanation:

Classity the following of matter
under the
three basic particles
Oxygen, soduim, water, hydrogen, iron,
potassuim.

chlorine
magnesuimion



Answers

Answer:

Oxygen sodium hydrogen iron potassium chlorine are elements

Water is a compound

And magnesium ion is cation.

Morever oxygen hydrogen and chlorine are gases

Water and magnesium ion are liquid

And sodium iron potassium are solids

Explanation:

1. How would you describe what red cabbage juice is?*
(1 Point)
Acid
Neutral
Alkali
Indicator
Salt​

Answers

Red cabbage juice is a pH indicator.

How many O atoms are in 7.39 g CO2?

Answers

Answer:

2 O atoms

hope it helps....

Answer:

2O is the correct answer


You have a shirt. If you shine a red light on it, it looks red. If you shine a blue light on it, it looks
blue. If you shine a green light on it, it looks green. What color is the shirt?

Answers

Answer: White or Black

Explanation: White is a blank color used for coloring so if you shine a certain color on it it'll show and along goes with black. :)

Calcium and titanium atoms have the same mass

Answers

Answer:

these elements do not have the same masses.

How is the waste in your body similar to the waste in your home or community

Answers

Answer:

Your body naturally gets rid of its waste and in your community/home also has sewers and gutters to also get rid of waste.

How many moles of "02" are in a 192g sample of O2? *
1
2
3
4
5
6
7

Answers

Answer: The number of moles of [tex]O_2[/tex] are 6.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

Given mass = 192 g

Molar mass = 32 g/mol

[tex]\text{Number of moles}=\frac{192g}{32g/mol}=6mol[/tex]

The number of moles of [tex]O_2[/tex] are 6.

What IONS are present in MgCO₃ (magnesium carbonate)? Mark
all that apply.

A Mg+
B C⁴-
C O2-
D Mg²+
E C⁴+
F CO₃²-

Answers

Answer:

Answer:

Explanation:

"Magnesium is an alkaline earth metal, and forms a Mg2+ ion. And carbonate ion, CO2−3 , has an equal an opposite charge. And thus the ionic species is MgCO3"

Ionic substances are composed of two or more ions. The compound MgCO3 is composed of  Mg²+ and CO₃²- ions.

What are ions?

The term ions refer to charged species that are present in a system. The compound MgCO₃ is an ionic substance and ionic substances are composed of ions.

As such, the compound MgCO₃ is composed of the ions  Mg²+ and CO₃²-.

Learn moer about ions: https://brainly.com/question/365923

Dilute nitric acid reacts with sodium carbonate solution. 2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + H2O (l) + CO2 (g) 25.00 cm3 of sodium carbonate solution of concentration 0.153 mol/dm3 reacts completely with 25.3 cm3 of dilute nitric acid.


a) Calculate the number of moles of sodium carbonate.

b) Use your answer to (a) and the equation for the reaction to calculate the number of moles of nitric acid that reacted.

c) Use your answer to (b) to calculate the concentration of dilute nitric acid in mol/dm3.

d) Use your answer to (a), calculate the maximum volume (at r.t.p.) of carbon dioxide gas that could be produced in this reaction.

Answers

a) Mol = Conc x Vol
=0.153 x 0.025
= 0.003825 mol

b) HNO3 : Na2CO3
2 : 1
Moles of HNO3 = 0.00385 x 2
= 0.00765 mol

c) Conc = 0.00765 / 0.0253
= 0.3023715415 mol/dm^3

d) Vol of CO2 = 0.003825 x 24
= 0.0918 dm^3

Hope this helps! Im not 100% sure about the last one thoo.

what is its molar concentration? ​

Answers

Answer:

The correct answer is - the number of moles of solute per liter of solution.

Explanation:

The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:

M = n/v

Where n is the number of moles of the solute and,

v is the volume of solution (in liters normally)

It is worldwide used measurment for the concentration.

Can someone help with these questions please???

Answers

1. B
2. A
3. C
4. C

Hope this helps!

A mass of 2000 kg is raised through a height of 20 metres in 20 seconds.
What is work done and power developed.​

Answers

Answer:

Work: 392400 J Power developer: 19620

A continuously stirred tank reactor is designed to remove the hazardous waste compound trichloroethylene (TCE) from industrial wastewater. The tank is 3250 liters. The wastewater flows into the tank at 200 L/min with a TCE concentration of 25 mg/L. The reactor decays TCE at a reaction rate of 0.20 min-1 . What is the steady-state concentration of TCE in the treated water leaving the reactor

Answers

Answer:

the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

Explanation:

Given that;

Tank volume v = 3250 liters

wastewater flows into the tank Q = 200 L/min

TCE concentration Co= 25 mg/L

reactor decays TCE at a reaction rate K = 0.20 min-1

mass balance

we know that;

Accumulation = inflow - outflow ± generation

⇒dc/dt = QCo - Qc ± rc.V

now at a steady state; dc/dt = 0

so

0 = QCo - Qc + rcV

where rc = -kc

0 = QCo - Qc - kcV

Qc + kcV = QCo

c(Q + kV) = QCo  

c = QCo / (Q + kV)

so we substitute

c = (200 × 25) / (200 + (0.2×3250))

c = 5000 / 850

c = 5.88 mg/L      

Therefore,  the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

An unknown compound contains only C , H , and O . Combustion of 5.90 g of this compound produced 11.8 g CO2 and 4.83 g H2O . What is the empirical formula of the unknown compound

Answers

Answer:

C₂H₄O

Explanation:

In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.

Moles CO₂ = Moles C:

11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =

3.216g C

Moles H₂O = 1/2 moles H:

4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =

0.537 mol H * (1g/mol) = 0.537g H

Mass O to find moles O:

5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O

Ratio of atoms -Dividing in 0.134 moles-:

C = 0.268mol C / 0.134 mol O = 2

H = 0.537mol H / 0.134 mol O = 4

O = 0.134mol O / 0.134 mol O = 1

Empirical formula is:

C₂H₄O

What is the molarity of a solution made from 325.4g of Aluminum chloride with enough water te
make 500.0 mL?*
(1 Point)
AICIAl = 26.9828 C1 = 35.45
mol
8
mol
0.488M
O 4.88M
0 2.44M
0 2.440M

Answers

Answer:

awdaef

Explanation:

Determine the mass of AgCl(s) produced when 0.91 g of AgNO3 in an aqueous solution reacts with excess NaCl aqueous solution as shown below: AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) i Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10")​

Answers

Answer:

0.77 g

Explanation:

Step 1: Write the balanced equation

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

Step 2: Calculate the moles corresponding to 0.91 g of AgNO₃

The molar mass of AgNO₃ is 169.87 g/mol.

0.91 g × 1 mol/169.87 g = 5.4 × 10⁻³ mol

Step 3: Calculate the moles of AgCl produced from 5.4 × 10⁻³ moles of AgNO₃

The molar ratio of AgNO₃ to AgCl is 1:1. The moles of AgCl produced are 1/1 × 5.4 × 10⁻³ mol = 5.4 × 10⁻³ mol.

Step 4: Calculate the mass corresponding to 5.4 × 10⁻³ moles of AgCl

The molar mass of AgCl is 143.32 g/mol.

5.4 × 10⁻³ mol × 143.32 g/mol = 0.77 g

list 5 island in the Philippines ​

Answers

Answer:

Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.

Explanation:

I hope this helps.

coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....

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