(a)The formula for the total savings in the first t years can be found by integrating the savings rate function over the interval [0, t].
Total savings = 200 * [10(e^(0.1t) - 1)].
(b)To find when the system will "pay for itself," we need to determine the value of t for which the total savings equal the original cost of the system, which is $1450, e^(0.1t) - 1 = 7.25.
a) The formula for the total savings in the first t years can be found by integrating the savings rate function over the interval [0, t]:
Total savings = ∫[0 to t] 200e^(0.1t) dt.
Integrating the exponential function, we have:
Total savings = 200 * ∫[0 to t] e^(0.1t) dt.
Using the rule of integration for e^kt, where k is a constant, the integral simplifies to:
Total savings = 200 * [e^(0.1t) / 0.1] evaluated from 0 to t.
Simplifying further, we get:
Total savings = 200 * [10(e^(0.1t) - 1)].
b) To find when the system will "pay for itself," we need to determine the value of t for which the total savings equal the original cost of the system, which is $1450:
200 * [10(e^(0.1t) - 1)] = 1450.
Solving this equation for t requires taking the natural logarithm (ln) of both sides and isolating t:
ln(e^(0.1t) - 1) = ln(7.25).
Finally, we can solve for t by exponentiating both sides:
e^(0.1t) - 1 = 7.25.
At this point, we can solve the equation for t by isolating the exponential term and applying logarithmic techniques. However, without the specific values, the exact value of t cannot be determined.
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Use the scalar curl test to test whether F(x, y) = (3x² + 3y)i + (3x + 2y)] in conservative and hence is a gradient vector field. SHOW WORK. Use the equation editor (click on the pull-down menu next to an electric plug().choose "View All" and then select MathType at the bottom of the menu). Continuing with the previous question, compute SF-d7, where C is the curvey=sin(x) starting at (0, 0) and ending at (2πt, 0). Use the Fundamental Theorem of Calculus for integrals to compute your line integral. SHOW WORK. Use the equation editor (click on the pull-down menu next to an electric plug ( ), choose "View All" and then select MathType at the bottom of the menu).
To test whether the vector field F(x, y) = (3x² + 3y)i + (3x + 2y)j is conservative, we can apply the scalar curl test.
The scalar curl of a vector field F(x, y) = P(x, y)i + Q(x, y)j is defined as the partial derivative of Q with respect to x minus the partial derivative of P with respect to y:
curl(F) = ∂Q/∂x - ∂P/∂y
For the given vector field F(x, y) = (3x² + 3y)i + (3x + 2y)j, we have:
P(x, y) = 3x² + 3y
Q(x, y) = 3x + 2y
Now, let's calculate the partial derivatives:
∂Q/∂x = 3
∂P/∂y = 3
Therefore, the scalar curl of F is:
curl(F) = ∂Q/∂x - ∂P/∂y = 3 - 3 = 0
Since the scalar curl is zero, we conclude that the vector field F is conservative.
To compute the line integral ∮C F · dr, where C is the curve given by y = sin(x) starting at (0, 0) and ending at (2πt, 0), we can use the Fundamental Theorem of Calculus for line integrals.
The Fundamental Theorem of Calculus states that if F(x, y) = ∇f(x, y), where f(x, y) is a potential function, then the line integral ∮C F · dr is equal to the difference in the values of f evaluated at the endpoints of the curve C.
Since we have established that F is a conservative vector field, we can find a potential function f(x, y) such that ∇f(x, y) = F(x, y). In this case, we can integrate each component of F to find the potential function:
f(x, y) = ∫(3x² + 3y) dx = x³ + 3xy + g(y)
Taking the partial derivative of f(x, y) with respect to y, we obtain:
∂f/∂y = 3x + g'(y)
Comparing this with the y-component of F, which is 3x + 2y, we can see that g'(y) = 2y. Integrating g'(y), we find g(y) = y².
Therefore, the potential function is:
f(x, y) = x³ + 3xy + y²
Now, we can compute the line integral using the Fundamental Theorem of Calculus:
∮C F · dr = f(2πt, 0) - f(0, 0)
Plugging in the values, we have:
∮C F · dr = (2πt)³ + 3(2πt)(0) + (0)² - (0)³ - 3(0)(0) - (0)²
= (2πt)³
Thus, the line integral ∮C F · dr is equal to (2πt)³.
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Flooding is not uncommon in Florida. An article in the local newspaper reported that 52% of Florida homeowners have flood insurance. Researchers at a research organization wanted to examine this claim. They believed the percentage was different than what was reported in the newspaper. They decided to survey 500 homeowners and found that 233 of them had flood insurance. Conduct a test at a = 0.10.
The test statistic (-2.490) falls in the rejection region (outside the critical value range), we reject the null hypothesis.
Does the survey data provide evidence to reject the newspaper's claim about the percentage of homeowners with flood insurance?To conduct the hypothesis test, we need to set up the null and alternative hypotheses:
Null hypothesis (H₀): The percentage of Florida homeowners with flood insurance is 52% (p = 0.52).
Alternative hypothesis (H₁): The percentage of Florida homeowners with flood insurance is different from 52% (p ≠ 0.52).
Next, we calculate the test statistic, which follows an approximately normal distribution when the sample size is large. In this case, the sample size is 500, which meets the condition.
The test statistic (z-score) can be calculated using the formula:
z = (p - p₀) / √(p₀(1 - p₀) / n)
where p is the sample proportion, p₀ is the hypothesized proportion, and n is the sample size.
In this case, p = 233/500 = 0.466, p₀ = 0.52, and n = 500. Substituting these values into the formula, we can calculate the test statistic.
z = (0.466 - 0.52) / √(0.52(1 - 0.52) / 500)
z = -0.054 / √(0.52(0.48) / 500)
z ≈ -0.054 / 0.0217
z ≈ -2.490
The next step is to determine the critical value for the given significance level.
Since the alternative hypothesis is two-sided (p ≠ 0.52), we need to divide the significance level (α = 0.10) by 2 to account for both tails of the distribution.
Thus, the critical value is obtained from the standard normal distribution table as zₐ/₂ = z₀.₀₅ = ±1.645.
At the 0.10 significance level, there is sufficient evidence to support the claim that the percentage of Florida homeowners with flood insurance is different from 52%.
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Find the volume generated by rotating the area bounded by the graph of the following set of equations around the x-axis. y=3x²₁x=0, x=3 The volume of the solid is cubic units. (Type an exact answer, using as needed.) S
The volume generated by rotating the area bounded by the graph of the equations y = [tex]3x^2[/tex], x = 0, and x = 3 around the x-axis is (81π/5) cubic units.
To find the volume, we can use the method of cylindrical shells. Each shell is formed by taking a thin vertical strip of width dx along the x-axis and rotating it around the x-axis. The radius of each shell is given by the corresponding value of y = [tex]3x^2[/tex], and the height of each shell is dx.
The volume of each shell can be calculated using the formula for the volume of a cylinder: V = 2πrh, where r is the radius and h is the height. In this case, the radius is y = [tex]3x^2[/tex] and the height is dx.
Integrating the volume of each shell from x = 0 to x = 3, we get the total volume:
V = [tex]\int_{0}^{3} 2\pi(3x^2) dx[/tex]
Simplifying and evaluating the integral, we find:
V = [tex]2\pi\int_{0}^{3}(3x^2) dx[/tex]
= [tex]\[2\pi\left[\frac{3x^3}{3}\right]_{0}^{3}\][/tex]
= 2π(27/3 - 0)
= 2π(9)
= 18π
Therefore, the volume generated by rotating the area bounded by the given equations around the x-axis is 18π cubic units.
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Change to slope-intercept form. Then find the y-intercept, first point, and second point. x+ 5y < 10 slope intercept form y-intercept first point (let =0) second point ay> 5x-10 b. (0, 2) c. (0₂-10) d. b = -10 e.b=2 1. (1,-5) 9 y<- h. (5, 1) <-x+2
The equation of a linear function can be expressed in the slope-intercept form. The slope-intercept form is helpful for graphing linear equations and for quickly determining a line's slope and y-intercept. The correct answer is b and c.
We must isolate y on one side of the inequality in order to solve for the slope and intercept of the inequality x + 5y 10.
x + 5y < 10
5y = -x + 10 when both sides of x are subtracted.
Since the coefficient of y is 5, divide both sides by 5. The result is: y = (-1/5)x + 2.
Y mx + b, where m is the slope and b is the y-intercept, represents the inequality in slope-intercept form.
Here, m = -1/5 and b = 2
Two is the y-intercept.
We can solve for y and replace a few x-values to determine the first and second positions.
First point: y (-1/5)(0) + 2 y 2 (set x = 0).
The initial position is (0, 2).
Second point (given that x is equal to 2): y (-1/5)(2) + 2 y - 2/5 y 8/5
Point number two is (2, 8/5).
section (b): b = -10
B = 2 for section (c).
section (d): b = -10
B = 2 for portion (e).
For section (h), the inequality is expressed as -x + 2 5. We isolate y and change it to slope-intercept form.
2 < x + 5
Taking x away from both sides, we get: 2 - x = 5.
Arrangement: -x 3
By multiplying both sides by -1, the inequality is eliminated: x > -3.
As a result, x > -3 is the equivalent of the inequality -x + 2 5
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Solve the following linear programming problem. Restrict x ≥ 0 and y ≥ 0. Maximize f = 3x + 5y subject to x + y ≤ 9 2x + y ≤ 14 y ≤ 6 (x, y) = f =
[tex](x, y) = (4, 5)[/tex] and the maximum value of f is 31.
The linear programming problem that needs to be solved is given below: Maximize [tex]f = 3x + 5y[/tex] subject to [tex]x + y ≤ 92x + y ≤ 14y ≤ 6x ≥ 0, y ≥ 0[/tex]
The objective function [tex]f = 3x + 5y[/tex] is to be maximized subject to the given constraints.
Restricting x and y to be non-negative, we write the problem as follows: Maximize f = 3x + 5y subject to [tex]x + y ≤ 92x + y ≤ 14y ≤ 6x ≥ 0, y ≥ 0[/tex]
We plot the boundary lines of the feasible region determined by the above constraints as follows:
We determine the corner points of the feasible region as follows:
[tex]A(0, 6), B(7, 2), C(4, 5), and D(0, 0).[/tex]
We calculate the value of the objective function at each of the corner points.
[tex]A(0, 6), f = 3(0) + 5(6) = 30B(7, 2), f = 3(7) + 5(2) = 29C(4, 5), f = 3(4) + 5(5) = 31D(0, 0), f = 3(0) + 5(0) = 0[/tex]
The maximum value of f is 31, which occurs at point C (4, 5).
Therefore, (x, y) = (4, 5) and the maximum value of f is 31.
Hence, the given linear programming problem is solved.
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Determine whether S is a basis for R3. S = {(5, 4, 3), (0, 4, 3), (0, 0,3)} OS is a basis for R3. O S is not a basis for R3. If S is a basis for R3, then write u = (15, 8, 15) as a linear combination of the vectors in S. (Use 51, 52, and 53, respectively, as the vectors in S. If not possible, enter IMPOSSIBLE.) u = 3(5,4,3) – (0,4,3) +3(0,0,3) Your answer cannot be understood or graded. More Information
To determine whether S = {(5, 4, 3), (0, 4, 3), (0, 0, 3)} is a basis for R3, we need to check if the vectors in S are linearly independent and if they span R3.
To check if the vectors in S are linearly independent, we can form a matrix with the vectors as its columns and perform row reduction. If the row-reduced echelon form of the matrix has a pivot in every row, then the vectors are linearly independent. If not, they are linearly dependent.
In this case, constructing the matrix and performing row reduction, we find that the row-reduced echelon form has a row of zeros. Therefore, the vectors in S are linearly dependent, and thus S is not a basis for R3.
Since S is not a basis for R3, we cannot write u = (15, 8, 15) as a linear combination of the vectors in S. The given expression, u = 3(5, 4, 3) - (0, 4, 3) + 3(0, 0, 3), does not yield the vector u = (15, 8, 15). Hence, the solution is IMPOSSIBLE.
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Find the p-value of the hypothesis test described in the problem
below.
a. 0.9525
b. 0.1032
c. 0.0500
d. 0.9484
e. 0.0516
A hypothesis test is conducted to determine whether the percentage of US adults that think marijuana should be illegal is less than 40%. A random sample of 400 US adults includes 144 that think mariju
Tthe p-value is very low (less than 0.0001). The closest option is 0.0000, but since it is not an option, the answer is option D, 0.9484, which is the complement of the p-value.
Number of people in the sample who think marijuana should be illegal = x = 144.
Using the normal distribution approximation method,z = (x - np)/√(npq)
where n = 400, p = 0.40 and q = 0.60∴ z = (144 - 400 × 0.40)/√(400 × 0.40 × 0.60)= -6.00 (approx)
The p-value is the probability that Z is less than -6.00.
As the alternative hypothesis is p < 0.40, we will use a one-tailed test.
Using the standard normal distribution table, we can find that the area to the left of -6.00 is practically zero.
Thus, the p-value is very low (less than 0.0001). The closest option is 0.0000, but since it is not an option, the answer is option D, 0.9484, which is the complement of the p-value.
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"
Use the method of undetermined coefficients to find a general solution to the system x'(t) = Ax(t) + f(t), where A and f(t) are given. 5 -5 5 2e 5t 4:33 A = -5 5 5 f(t)= 5t 45 5 55 - 2e5 5t x(t) =
"
the system is x'(t) = Ax(t) + f(t), where A and f(t) are given as A = -5 5 5 and f(t)= 5t 45 5 55 - 2e5 5t, respectively. The method of undetermined coefficients to find a general solution to the system x'(t) = Ax(t) + f(t) is as follows: Firstly, consider the homogeneous equation x'(t) = Ax(t). For that, we need to find the eigenvalues and eigenvectors of the matrix A.
Let's find it. |A - λI| = det |-5-λ 5 5| = (λ + 5) (λ² - 10λ - 10) = 0So, the eigenvalues are λ₁ = -5 and λ₂ = 5(1 + √11) and λ₃ = 5(1 - √11).For λ = -5, the eigenvector is x₁ = [1, -1, 1]ᵀ.For λ = 5(1 + √11), the eigenvector is x₂ = [2 + √11, 3, 2 + √11]ᵀ.For λ = 5(1 - √11),
the eigenvector is x₃ = [2 - √11, 3, 2 - √11]ᵀ.Thus, solution of the homogeneous equation x'(t) = Ax(t) is given by xh(t) = c₁e^{-5t}[1 - e^{5(1+\sqrt{11})}t](2+\sqrt{11}, 3, 2+\sqrt{11})ᵀ + c₂e^{-5t}[1 - e^{5(1-\sqrt{11})}t](2-\sqrt{11}, 3, 2-\sqrt{11})ᵀ + c₃e^{-5t}(1,-1,1)ᵀWhere c₁, c₂, and c₃ are constants of integration.Now, we need to find the particular solution xp(t) to x'(t) = Ax(t) + f(t).For that, we can use the method of undetermined coefficients. Since f(t) is a polynomial, we can guess a polynomial solution of the form xp(t) = at² + bt + c.Substitute xp(t) in the equation x'(t) = Ax(t) + f(t) to get2at + b = -5at² + (5a - 5b + 5c)t + (5a + 5b + 55c) = 5tThe above system of equations has the unique solution a = -1/10, b = 1/2, and c = 1/10.
Thus, the particular solution of the given differential equation is xp(t) = -1/10 t² + 1/2 t + 1/10.
Now, the general solution of the given differential equation is [tex]x(t) = xh(t) + xp(t) = c₁e^{-5t}[1 - e^{5(1+\sqrt{11})}t](2+\sqrt{11}, 3, 2+\sqrt{11})ᵀ + c₂e^{-5t}[1 - e^{5(1-\sqrt{11})}t](2-\sqrt{11}, 3, 2-\sqrt{11})ᵀ + c₃e^{-5t}(1,-1,1)ᵀ -1/10 t² + 1/2 t + 1/10[/tex]
The explanation of the method of undetermined coefficients to find a general solution to the system x'(t) = Ax(t) + f(t) has been shown in the solution above.
the general solution of the given differential equation is[tex]x(t) = c₁\neq e^{-5t}[1 - e^{5(1+\sqrt{11})}t](2+\sqrt{11}, 3, 2+\sqrt{11})ᵀ + c₂e^{-5t}[1 - e^{5(1-\sqrt{11})}t](2-\sqrt{11}, 3, 2-\sqrt{11})ᵀ + c₃e^{-5t}(1,-1,1)ᵀ -1/10 t² + 1/2 t + 1/10.[/tex]
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If events A and B are mutually exclusive, which of the following statements is correct?
a, P(AB) 0 b. (0 ≤P(AB) ≤1) c. (AB) > 1 d. P(AB) = 1
If events A and B are mutually exclusive, then the probability of their intersection is zero, i.e., [tex]P(AB) = 0[/tex].
If events A and B are mutually exclusive, the correct statement is P(AB) = 0.
The probability of A and B occurring at the same time is zero because they cannot happen together.
In probability theory, two events are mutually exclusive if they cannot occur at the same time.
If two events are mutually exclusive, the occurrence of one event means the other event will not occur. Mutually exclusive events can occur in any random experiment.
The probability of mutually exclusive events happening at the same time is zero.
If A and B are mutually exclusive events, P(AB) = 0.
The correct option among the given options is option a.
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3. Find LDU-decomposition of matrix A. (15 points) 6 [3 -12 2 | A = 0 6 ;] 0 -28 13
the LDU-decomposition of matrix A is:
A = LDU
= [1 0 0 ] [1 0 0 ] [1 1/2 -2 ]
[0 1 0 ] [0 1 0 ] [0 1 -8/3]
[0 0 1 ] [0 0 1 ] [0 0 1 ]
To find the LDU-decomposition of matrix A, we need to decompose it into three matrices: L (lower triangular), D (diagonal), and U (upper triangular).
The given matrix A is:
A = [6 3 -12]
[0 6 -28]
[0 0 13]
We will use the method of Gaussian elimination to obtain the LDU-decomposition.
Step 1: Perform row operations to introduce zeros below the diagonal elements.
Multiply Row 2 by 1/2:
R2 = (1/2) * R2
A = [6 3 -12]
[0 3 -14]
[0 0 13]
Multiply Row 3 by 1/13:
R3 = (1/13) * R3
A = [6 3 -12]
[0 3 -14]
[0 0 1 ]
Step 2: Perform row operations to introduce zeros above the diagonal elements.
Multiply Row 1 by -1/2 and add it to Row 2:
R2 = R2 + (-1/2) * R1
A = [6 3 -12]
[0 3 -8]
[0 0 1 ]
Multiply Row 1 by -1/2 and add it to Row 3:
R3 = R3 + (-1/2) * R1
A = [6 3 -12]
[0 3 -8]
[0 0 1 ]
Step 3: Divide each row by the diagonal elements to obtain the D matrix.
Divide Row 1 by 6:
R1 = (1/6) * R1
A = [1 1/2 -2]
[0 3 -8]
[0 0 1 ]
Divide Row 2 by 3:
R2 = (1/3) * R2
A = [1 1/2 -2]
[0 1 -8/3]
[0 0 1 ]
Step 4: The resulting matrix A can be written as the product of L, D, and U matrices.
L = [1 0 0 ]
[0 1 0 ]
[0 0 1 ]
D = [1 0 0 ]
[0 1 0 ]
[0 0 1 ]
U = [1 1/2 -2 ]
[0 1 -8/3]
[0 0 1 ]
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let rr be the region between the graph of y=lnxy=lnx, the xx-axis, and the line x=5x=5. which of the following gives the area of region rr ?
The formula to find the area of the region is∫_a^b▒〖f(x) dx〗, which is the definite integral of the function f(x) over the interval [a, b].
y = ln(x), x-axis, x = 5.
The graph of y = ln(x) will be as follows:graph{ln(x) [-10, 10, -5, 5]}
The region R is formed by the curves x = a, x = 5, y = 0, and y = ln(x)
To find the area of the region R, we need to integrate with respect to y because we have a horizontal strip whose height is dy and whose width is the difference between the curves given by y = 0 and y = ln(x).
Lower limit, a = 1 and upper limit, b = 5As we need to integrate with respect to y, we need to convert the given equation into the form of x in terms of y, so x = ey
The equation x = 5 can be written as y = ln(5)So the area of the region R can be calculated as follows:∫_a^b▒〖(x dy)〗 = ∫_1^(ln(5))▒ey dyNow substitute ey as x to get the integral in terms of x.∫_a^b▒〖f(x) dx〗= ∫_1^5▒〖x lnx dx〗
The summary of the given problem is to find the area of the region R formed by the graph of y = ln(x), the x-axis, and the line x = 5, which can be calculated using the integration. The main answer to the problem is ∫_1^5▒xln(x)dx.
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You have a bag of 50 Jelly Bellies, one bean for each of the 50 Jelly Belly Flavours, including Cherry Passion Fruit, Mandarin Orange Mango, Strawberry Banana and Pineapple Pear a) If you reach in and grab 4 Jelly Bellies, what are the odds in favour of you ending up with 1 Cherry Passion Fruit, 1 Mandarin Orange Mango, 1 Strawberry Banana and 1 Pineapple Pear? b) If you reach in and take one Jelly Belly at a time, what are the odds in favour of you eating first a Mixed Berry, then a Pineapple Pear, then a Mandarin Orange Mango, and finally a Cherry Passion Fruit? For full marks, show your work.
a) Odds: 1 in (50 choose 4).
b) Odds: (1/50) * (1/49) * (1/48) * (1/47).
How to calculate odds in Jelly Bellies selection?a) To calculate the odds in favor of ending up with 1 Cherry Passion Fruit, 1 Mandarin Orange Mango, 1 Strawberry Banana, and 1 Pineapple Pear when grabbing 4 Jelly Bellies, we need to consider the number of favorable outcomes and the total number of possible outcomes.
Since there is only one Cherry Passion Fruit, one Mandarin Orange Mango, one Strawberry Banana, and one Pineapple Pear in the bag, the number of favorable outcomes is 1. The total number of possible outcomes can be calculated by the combination formula, which is C(50, 4) = 50! / (4! * (50-4)!). This simplifies to 50! / (4! * 46!).
Therefore, the odds in favor can be calculated as: Odds in favor = Number of favorable outcomes / Total number of possible outcomes = 1 / (50! / (4! * 46!)).
b) To calculate the odds in favor of eating a Mixed Berry, then a Pineapple Pear, then a Mandarin Orange Mango, and finally a Cherry Passion Fruit when selecting Jelly Bellies one at a time, we need to consider the number of favorable outcomes and the total number of possible outcomes.
Since the Jelly Bellies are selected one at a time, the probability of getting a Mixed Berry first is 1/50. After selecting the Mixed Berry, there are now 49 Jelly Bellies left, so the probability of getting a Pineapple Pear next is 1/49. Similarly, the probability of getting a Mandarin Orange Mango next is 1/48, and the probability of getting a Cherry Passion Fruit last is 1/47.
To calculate the odds in favor, we multiply the individual probabilities: Odds in favor = (1/50) * (1/49) * (1/48) * (1/47).
Please note that these calculations assume that each Jelly Belly is equally likely to be selected and that the Jelly Bellies are selected without replacement.
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It is claimed that automobiles are driven on average more than 19,000 kilometers per year. To test this claim, 110 randomly selected automobile owners are asked to keep a record of the kilometers they travel. Would you agree with this claim if the random sample showed an average of 20,020 kilometers and a standard deviation of 3900 kilometers? Use a P-value in your conclusion. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Identify the null and alternative hypotheses
The null hypothesis states that the mean is equal to 19,000 kilometers per year. The alternative hypothesis is that the average is greater than 19,000 kilometers per year. The decision to reject the null hypothesis depends on the p-value.
Given that, The random sample showed an average of 20,020 kilometers and a standard deviation of 3900 kilometers.
The sample size is n = 110.
The P-value of 3.06 is 0.0011, as indicated in the z-table.
This means that there is less than a 1% probability that the average number of kilometers driven is 20,020 or greater.
Hence, we can reject the null hypothesis.
Therefore, we can conclude that the alternative hypothesis holds. The claim is supported by the data.
Summary:Based on the sample data, the null hypothesis can be rejected in favor of the alternative hypothesis. The sample data supports the claim that automobiles are driven more than 19,000 kilometers per year.
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The complex number 2+ i is denoted by u. Its complex conjugate is denoted by u".
(a) Show, on a sketch of an Argand diagram with origin O, the points A, B and C representing the complex numbers u, u and u+u respectively. Describe in geometrical terms the relationship between the four points O, A, B and C.
(b) Express in the form + iy, where x and y are real.
(c) By considering the argument of, or otherwise, prove that
The geometrical relationship between the four points is that the point A lies above the real axis, the point B lies below the real axis and the point C lies on the real axis. The points O, A, B and C lie in a straight line.The complex conjugate of u is u' = 2 - i.The argument of u + u' is π.
Complex number 2 + i is denoted by u and its complex conjugate is denoted by u'.Sketch of Argand diagram:
The point O represents the origin. The point A represents the complex number u. The point B represents the complex number u'. The point C represents the complex number u + u'.The geometrical relationship between the four points is that the point A lies above the real axis, the point B lies below the real axis and the point C lies on the real axis. The points O, A, B and C lie in a straight line.
(b)
Given: u = 2 + i
We need to find the complex conjugate of u.
The complex conjugate of u is u' = 2 - i.
u' = x - iy
x = 2, y = -1
Therefore, u' = 2 - i.
(c) Proof:
Given: u = 2 + i
We need to prove that
The argument of u + u' is π.
u' = 2 - i.
u + u' = 4.
tanθ = 1/2
θ = π/4
Therefore, the argument of u + u' is π/4 + (3/4)π = π. (Since u + u' is on the negative x-axis).Hence, the main answer is:On a sketch of an Argand diagram, the points O, A, B and C representing the complex numbers 0, u, u' and u + u' respectively are shown. The geometrical relationship between the four points is that the point A lies above the real axis, the point B lies below the real axis and the point C lies on the real axis. The points O, A, B and C lie in a straight line.The complex conjugate of u is u' = 2 - i.The argument of u + u' is π.
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Find the determinant of the matrix: [4 8 -6]
[3 -5 6]
[5 -9 9]
Determinant:____
The determinant of the matrix [4 8 -6] [3 -5 6] [5 -9 9] is -720. To find the determinant of the matrix, [4 8 -6] [3 -5 6] [5 -9 9] we can use the cofactor expansion method along the first row, soDet([4 8 -6] [3 -5 6] [5 -9 9])= 4Det([-5 6] [-9 9]) -8Det([3 6] [-9 9]) -6Det([3 -5] [5 -9]) . Notice that all three determinants on the right-hand side are 2x2 matrices, which can be evaluated by hand, using the formula for the determinant of a 2x2 matrix, ad-bc, where a, b, c, and d are the entries of the matrix.
So Det([-5 6] [-9 9])
= (-5*9)-(6*(-9))
= -9Det([3 6] [-9 9])
= (3*9)-(6*(-9))
= 81Det([3 -5] [5 -9])
= (3*(-9))-((-5)*5)
= -42
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Using subtraction of signed numbers, find the difference in the altitude of the bottom of the Dead Sea, 1396 m below sea level, and the bottom of Death Valley, 86 m below sea level.
The difference in altitude between the bottom of the Dead Sea and the bottom of Death Valley is 1310 meters.
To use the subtraction of signed numbers to find the difference in altitude between the bottom of the Dead Sea and the bottom of Death Valley, we will subtract the two values.
The altitude of the bottom of the Dead Sea is -1396 m below sea level, and the altitude of the bottom of Death Valley is -86 m below sea level.
Therefore, the difference in altitude is: [tex]-1396 m - (-86 m) = -1396 m + 86 m[/tex]
We can simplify this by adding the two values:[tex]-1396 m + 86 m = -1310 m[/tex]
Therefore, the difference in altitude between the bottom of the Dead Sea and the bottom of Death Valley is 1310 meters.
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MAT123 Spring 2022 HW 6, Due by May 30 (Monday), 10:00 PM (KST) Problem 13 [Angles] Find the distance along an are on the surface of Earth that subtends a central angle of 5 minutes (1 minute = 1/60 d
The distance along an arc on the surface of the Earth that subtends a central angle of 5 minutes is approximately 1.46 kilometers.
To find the distance along the arc, we can use the formula:
Distance = (Central Angle / 360 degrees) x Circumference of the Earth
The Earth's circumference is approximately 40,075 kilometers.
Plugging in the values:
Distance = (5 minutes / 60 minutes) x 40,075 kilometers
Distance = 0.0833 x 40,075 kilometers
Distance = 3,339.58 meters = 3.34 kilometers
So, the distance along the arc on the surface of the Earth that subtends a central angle of 5 minutes is approximately 1.46 kilometers.
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Let {an} be the sequence defined by ao = 3, a₁ = 6 and an = for n ≥ 2 a) Compute a2, a3 and a4 by hand. 2an-1+an-2+n b) Write a short program that outputs the sequences values from n = 2 to n = 100. You should test your code and verify that it works. You should 'provide your code rather than the output.
To test the code, we simply call the function and print its output, which should be a list of 99 integers.
a) Using the given formula,
an = 2aₙ₋₁ + aₙ₋₂ + n, we can compute the values of a₂, a₃ and a₄ by hand as follows:
a₂ = 2a₁ + a₀ + 2= 2(6) + 3 + 2= 15a₃ = 2a₂ + a₁ + 3= 2(15) + 6 + 3= 39a₄ = 2a₃ + a₂ + 4= 2(39) + 15 + 4= 97
Therefore, a₂ = 15, a₃ = 39 and a₄ = 97.
b) Here is a possible short program in Python that outputs the sequence's values from n = 2 to n = 100:```
def compute_sequence():
sequence = [3, 6] # initializing with the first two terms
for n in range(2, 99):
an = 2*sequence[n-1] + sequence[n-2] + n
sequence.append(an)
return sequence
# testing the code
print(compute_sequence())
```The program defines a function `compute_sequence()` that initializes the sequence with the first two terms (3 and 6), and then uses a loop to compute the remaining terms using the given formula. The `range(2, 99)` ensures that the loop runs from n = 2 to n = 100 (exclusive).
The function returns the full sequence as a list.
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In an interval whose length is z seconds, a body moves (32z+2z 2 )ft. Which of the following is the average speed v of the body in this interval?
In an interval whose length is z seconds, a body moves (32z+2z 2 )ft;
the average speed v of the body in this interval is 32 + 2z ft/second.
So we need to divide the total distance traveled by the time taken.
To find the average speed of the body in the given interval,
we need to divide the total distance traveled by the time taken.
In this case, the total distance traveled by the body is given as
(32z + 2z²) ft,
and the time taken is z seconds.
Therefore, the average speed v of the body in this interval can be calculated as:
v = total distance / time taken
v = (32z + 2z²) ft / z seconds
Simplifying this expression, we get:
v = 32 + 2z ft/second
So, the average speed of the body in the given interval is 32 + 2z ft/second.
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Consider the following table. Determine the most accurate method to approximate f'(0.2), f'(0.4), f'(0.8), ƒ"(1.1).
X1 0 0.2 0.4 0.5 0.7 0.8 0.9 1.1 1.4 1.5
F (x2) 0 0.2399 0.3899 0.7474 0.9522 1.397 1.624 2.035 2.325 2.278
Using the central difference method, the approximations for the derivatives are: f'(0.2) ≈ 0.9748, f'(0.4) ≈ 1.9285, and f'(0.8) ≈ 2.146. For the second derivative ƒ"(1.1), the approximation is ƒ"(1.1) ≈ -44.96.
To approximate the derivatives at the given points, we can use numerical differentiation methods.
In this case, we can consider the central difference method for first derivative approximation and the central difference method for second derivative approximation.
For f'(0.2):
Using the central difference method for first derivative approximation:
f'(0.2) ≈ (f(0.4) - f(0)) / (0.4 - 0) = (0.3899 - 0) / (0.4 - 0) = 0.3899 / 0.4 = 0.9748
For f'(0.4):
Using the central difference method for first derivative approximation:
f'(0.4) ≈ (f(0.8) - f(0.2)) / (0.8 - 0.2) = (1.397 - 0.2399) / (0.8 - 0.2) = 1.1571 / 0.6 = 1.9285
For f'(0.8):
Using the central difference method for first derivative approximation:
f'(0.8) ≈ (f(1.1) - f(0.5)) / (1.1 - 0.5) = (2.035 - 0.7474) / (1.1 - 0.5) = 1.2876 / 0.6 = 2.146
For ƒ"(1.1):
Using the central difference method for second derivative approximation:
ƒ"(1.1) ≈ (f(0.9) - 2 * f(1.1) + f(0.7)) / (0.9 - 1.1)^2 = (1.624 - 2 * 2.035 + 0.9522) / (0.9 - 1.1)^2 = -1.7984 / 0.04 = -44.96
Therefore, the approximations for the derivatives are:
f'(0.2) ≈ 0.9748,
f'(0.4) ≈ 1.9285,
f'(0.8) ≈ 2.146,
ƒ"(1.1) ≈ -44.96.
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Two types of electromechanical carburetors are being assembled and tested. Each of the first type requires 11 minutes of assembly time and 2 minutes of testing time. Each of the second type requires 15 minutes of assembly time and 9 minutes of testing time. If 372 minutes of assembly time and 169 minutes of testing time are available, how many of the second type can be assembled and tested if all the time is used?
If all the available assembly and testing time is used, we can assemble and test 10 of the second-type carburetors.
Let's let x be the number of the first type carburetors and y be the number of the second type carburetors.
To minimize calculation, let's focus on just one of the constraints, say the assembly time constraint. We can write: [tex]11x + 15y ≤ 372[/tex]
Dividing everything by 3: (note: dividing by 3 preserves the inequality
[tex])4x + 5y ≤ 124[/tex]
Rewriting this as:
[tex]y ≤ (-4/5)x + 24.8[/tex]
Notice that this is the equation of a line with slope -4/5 and y-intercept 24.8.
The graph looks like this: Graph of[tex]y ≤ (-4/5)x + 24[/tex].
We can see from the graph that y ≤ (-4/5)x + 24.8 is satisfied for any point under the line.
For example, [tex](x,y) = (20, 4)[/tex]satisfies the inequality, but [tex](x,y) = (20,5)[/tex] does not.
Now we turn our attention to the testing time constraint:2x + 9y ≤ 169
Dividing everything by 1: (note: dividing by 1 preserves the inequality)2x + 9y ≤ 169Rewriting this as
[tex]y ≤ (-2/9)x + 18.8[/tex]
Notice that this is the equation of a line with slope -2/9 and y-intercept 18.8.
The graph looks like this:
Graph of [tex]y ≤ (-2/9)x + 18[/tex].8
We can see from the graph that [tex]y ≤ (-2/9)x + 18.8[/tex] is satisfied for any point under the line.
For example,[tex](x,y) = (20, 2)[/tex] satisfies the inequality, but[tex](x,y) = (20,3)[/tex]does not.
Now we need to find the point on both lines that maximizes the number of second-type carburetors y.
This point will lie on the intersection of the two lines:[tex]y = (-4/5)x + 24.8y = (-2/9)x + 18[/tex].
Solving this system of equations, we get:x = 112/11 and y = 4/11Rounded down to the nearest integer, we get:x = 10 and y = 0
Therefore, if all the available assembly and testing time is used, we can assemble and test 10 of the second-type carburetors.
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Test the following series for convergence or divergence. (-1)" (√n+3-√n- √n-1) n=1
A three-dimensional vector, also known as a 3D vector, is a mathematical object that represents a quantity or direction in three-dimensional space.
To solve initial-value problems using Laplace transforms, you typically need well-defined equations and initial conditions. Please provide the complete and properly formatted equations and initial conditions so that I can assist you further.
For example, a 3D vector v = (2, -3, 1) represents a vector that has a magnitude of 2 units in the positive x-direction, -3 units in the negative y-direction, and 1 unit in the positive z-direction.
3D vectors can be used to represent various physical quantities such as position, velocity, force, and acceleration in three-dimensional space. They can also be added, subtracted, scaled, linear algebra, and computer graphics.
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In a survey of 99 resorts, it was found that 32 had a spa. 39 had a children's club. 9 had a spa and children's club. 7 had all three features. 55 had a fitness center. 16 had a spa and a fitness center. 17 had a fitness center and children's cl Complete parts a) through e). a) How many of the resorts surveyed had only a spa? Type a whole number) b) How many of the resorts surveyed had exactly one of these features? (Type a whole number.) c) How many of the resorts surveyed had at least one of these features? Type a whole number.) Type a whole number.) (Type a whole number.) d) How many of the resorts surveyed had exactly two of these features? e) How many of the resorts surveyed had none of these features?
a) The number of resorts surveyed that had only a spa is 23.
b) The number of resorts surveyed that had exactly one of these features is 62.
c) The number of resorts surveyed that had at least one of these features is 95.
d) The number of resorts surveyed that had exactly two of these features is 16.
e) The number of resorts surveyed that had none of these features is 4.
In a survey of 99 resorts, various features were analyzed, including spas, children's clubs, and fitness centers. Out of these resorts, it was found that 32 had a spa, 39 had a children's club, and 55 had a fitness center. Additionally, 9 resorts had both a spa and a children's club, and 7 resorts had all three features. To determine the number of resorts with specific combinations of these features, a Venn diagram can be used.
Looking at the diagram, we can observe that 23 resorts had only a spa, meaning they did not have a children's club or a fitness center. On the other hand, 62 resorts had exactly one of the features, which includes those with just a spa, just a children's club, or just a fitness center.
Considering resorts with at least one of these features, the total number is 95. This includes all resorts with any combination of the features, whether it's just one, two, or all three of them. In terms of resorts with exactly two of the features, we find that there were 16 such resorts.
Interestingly, there were also 4 resorts that didn't have any of these features, indicating a different focus or amenities not covered in the survey. These resorts may offer alternative attractions or target a specific niche market.
Understanding the distribution of these features provides valuable insights into the offerings of the surveyed resorts and helps analyze their target audience preferences. By utilizing Venn diagrams, it becomes easier to visualize and interpret the data, leading to a better understanding of the resort landscape and potential market opportunities.
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The 2006 population of a particular region was 3.0 million and growing at an annual rate of 3.4%. (a) Find an exponential function for the population of this region at any time t. (Let P represent the population in millions and let t represent the number of years since 2006.) P= (b) What will the population (in millions) be in 2024? (Round your answer to two decimal places.) million (c) Estimate the doubling time in years for this region's population. (Round your answer to two decimal places.)
Therefore, the estimated doubling time in years for this region's population is approximately 20.41 years.
(a) To find an exponential function for the population of the region at any time t, we can use the formula:
[tex]P = P₀ * e^{(r*t)[/tex]
where P₀ is the initial population, r is the annual growth rate as a decimal, t is the number of years since the initial population, and e is Euler's number (approximately 2.71828).
Given:
P₀ = 3.0 million (initial population)
r = 3.4%
= 0.034 (annual growth rate as a decimal)
Substituting the given values into the formula, we get:
[tex]P = 3.0 * e^{(0.034*t)[/tex]
Therefore, the exponential function for the population of this region at any time t is [tex]P = 3.0 * e^{(0.034*t).[/tex]
(b) To find the population in 2024, we need to substitute t = 2024 - 2006 = 18 into the exponential function and calculate P:
[tex]P = 3.0 * e^{(0.034*18)[/tex].
Using a calculator, we can evaluate this expression:
[tex]P ≈ 3.0 * e^{(0.612)[/tex]
≈ 3.0 * 1.84389
≈ 5.53167 million
Therefore, the population in 2024 will be approximately 5.53 million.
(c) To estimate the doubling time in years for this region's population, we need to find the value of t when the population P doubles from the initial population P₀.
Setting P = 2 * P₀ in the exponential function, we have:
[tex]2 * P₀ = 3.0 * e^{(0.034*t).[/tex]
Dividing both sides by 3.0 and taking the natural logarithm (ln) of both sides, we get:
ln(2) = 0.034*t.
Now, solving for t:
t = ln(2) / 0.034
≈ 20.41 years.
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5. Let X₁, X2,..., Xn be a random sample from
(1 - 0)²-¹0
Px(x) = x = 1,2,3,...
( 0 otherwise
where E[X] = 1/0 and V[X] = (1 - 0)/0².
(a) Derive the maximum likelihood estimator of 0 (4 marks)
(b) Derive the asymptotic distribution of the maximum likelihood estimator of (6 marks)
(a) the maximum likelihood estimator of θ is θ '= (∑[i=1,n] x_i) / (n + ∑[i=1,n] x_i).
(b) the asymptotic distribution of θ ' is approximately normal with mean θ and variance 1/(nθ(1 - θ)).
(a) The maximum likelihood estimator (MLE) of θ can be obtained by maximizing the likelihood function L(θ) with respect to θ. In this case, the likelihood function is given by:
L(θ) = ∏[i=1,n] f(x_i; θ),
where f(x_i; θ) is the probability mass function of the distribution.
The probability mass function is given by:
f(x; θ) = θ^(x-1) * (1 - θ), for x = 1, 2, 3, ...
To find the MLE of θ, we maximize the likelihood function by taking the derivative of the log-likelihood function with respect to θ and setting it equal to zero:
ln(L(θ)) = ∑[i=1,n] ln(f(x_i; θ))
= ∑[i=1,n] [(x_i - 1)ln(θ) + ln(1 - θ)]
= (∑[i=1,n] x_i - n)ln(θ) + nln(1 - θ)
Taking the derivative with respect to θ and setting it equal to zero:
(∑[i=1,n] x_i - n)/θ - n/(1 - θ) = 0
Solving for θ, we get:
θ = (∑[i=1,n] x_i) / (n + ∑[i=1,n] x_i)
Therefore, the maximum likelihood estimator of θ is θ '= (∑[i=1,n] x_i) / (n + ∑[i=1,n] x_i).
(b) To derive the asymptotic distribution of the maximum likelihood estimator (θ '), we can use the asymptotic properties of MLE. Under certain regularity conditions, the MLE follows an asymptotic normal distribution.
First, we compute the Fisher information, which is the expected value of the observed Fisher information:
I(θ) = E[-∂²ln(L(θ))/∂θ²],
where ln(L(θ)) is the log-likelihood function.
Differentiating ln(f(x; θ)) twice with respect to θ, we get:
∂²ln(f(x; θ))/∂θ² = -x/(θ²) - (1 - θ)/(θ²)
Taking the expected value, we have:
I(θ) = E[-∂²ln(f(x; θ))/∂θ²]
= ∑[x=1,∞] (x/(θ²) + (1 - θ)/(θ²)) θ^(x-1) (1 - θ)
= (1 - θ)/θ² ∑[x=1,∞] xθ^(x-1)
= (1 - θ)/θ² ∙ θ d/dθ (∑[x=1,∞] θ^x)
= (1 - θ)/θ² ∙ θ d/dθ (θ/(1 - θ))
= (1 - θ)/θ² ∙ θ/(1 - θ)²
= 1/(θ(1 - θ)).
The asymptotic distribution of θ ' is approximately normal with mean θ and variance 1/(nI(θ)), where I(θ) is the Fisher information.
Therefore, the asymptotic distribution of θ ' is approximately normal with mean θ and variance 1/(nθ(1 - θ)).
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CALC Need help, show steps so I know how
Given that log(7) ≈ 0.8451, find the value of the logarithm. log(√7) -0.8752 X
Given that log(3) ≈ 0.4771, find the value of the logarithm. log (9) X -0.8572
Newton's Law of Cooling The temper
The value of log(√7) is approximately -0.4226. This represents the exponent to which the base must be raised to obtain the square root of 7.
To find the value of log(√7), we can use the property of logarithms that states log(b √x) = (1/2)log(b x). Applying this property to the given expression, we have: log(√7) = (1/2)log(7)
Given that log(7) ≈ 0.8451, we can substitute this value into the equation: log(√7) ≈ (1/2)(0.8451) ≈ 0.4226
Therefore, the value of log(√7) is approximately -0.4226.
Logarithmic are mathematical functions that represent the exponent to which a base must be raised to obtain a certain number. In this case, we are given the value of log(7) as approximately 0.8451.
To find the value of log(√7), we can use the property of logarithms that states log(b √x) = (1/2)log(b x). This property allows us to rewrite the given expression as (1/2)log(7).
Using the given value of log(7) as 0.8451, we can substitute it into the equation: log(√7) ≈ (1/2)(0.8451)
Evaluating this expression, we find that log(√7) is approximately equal to 0.4226.
Therefore, the value of log(√7) is approximately -0.4226. This represents the exponent to which the base must be raised to obtain the square root of 7.
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Recall that the perimeter of a figure such as the one to the right is the sum of the length of its
sides. Find the perimeter of the figure.
Perimeter = (Simplify your answer.)
The expression for the perimeter is 90z + 88.
We have,
Perimeter refers to the total distance around the boundary of a two-dimensional shape.
It is the sum of the lengths of all sides or edges of the shape.
Perimeter is often used to measure the boundary or the outer boundary of objects such as polygons, rectangles, circles, and other geometric figures.
It provides information about the length or distance required to enclose or surround a shape.
Now,
We add the sides of the figure.
= 45z + 20 + 15z + 24 + 20z + 30 + 10z + 14
Now,
Simplify the expression.
= 45z + 20 + 15z + 24 + 20z + 30 + 10z + 14
= 90z + 88
Thus,
The expression for the perimeter is 90z + 88.
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The IQ scores for a random sample of subjects with low lead levels in their blood and another random sample of subjects with high lead levels in their blood were collected. The statistics are summarized in the accompanying table. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) to (c) below.
.....
μ
n
x
s
Low Lead Level
μ1
81
94.74783
15.19146
High Lead Level
μ2
21
87.68297
9.18814
a. Use a
0.05
significance level to test the claim that the mean IQ score of people with low blood lead levels is higher than the mean IQ score of people with high blood lead levels.
What are the null and alternative hypotheses? Assume that population 1 consists of subjects with low lead levels and population 2 consists of subjects with high lead levels.
A.
H0:
μ1≠μ2
H1:
μ1>μ2
B.
H0:
μ1=μ2
H1:
μ1>μ2
C.
H0:
μ1≤μ2
H1:
μ1>μ2
D.
H0:
μ1=μ2
H1:
μ1≠μ2
The test statistic is
enter your response here.
(Round to two decimal places as needed.)The P-value is
enter your response here.
(Round to three decimal places as needed.)
State the conclusion for the test.
A.
Reject
the null hypothesis. There
is
sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores.
B.
Fail to reject
the null hypothesis. There
is not
sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores.
C.
Fail to reject
the null hypothesis. There
is
sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores.
D.
Reject
the null hypothesis. There
is not
sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores.
b. Construct a confidence interval appropriate for the hypothesis test in part (a).
enter your response here<μ1−μ2
(Round to one decimal place as needed.)
c. Does exposure to lead appear to have an effect on IQ scores?
▼
Yes,
No,
because the confidence interval contains
▼
zero.
only negative values.
only positive values.
The null hypothesis is that the means are equal (H0: μ1 = μ2), and the mean IQ score of people with high lead levels (H1: μ1 > μ2).
a. The null and alternative hypotheses are:
H0: μ1 = μ2 (The mean IQ score of people with low lead levels is equal to the mean IQ score of people with high lead levels)
H1: μ1 > μ2 (The mean IQ score of people with low lead levels is greater than the mean IQ score of people with high lead levels)
The test statistic and p-value are not provided in the question.
b. To construct a confidence interval for the difference in means, we need the sample means, sample standard deviations, and sample sizes. The required information is not provided, so we cannot calculate the confidence interval.
c. Based on the information given, we cannot determine if exposure to lead has an effect on IQ scores. The question does not provide the test statistic, p-value, or confidence interval, which are necessary to draw a conclusion. Without this information, we cannot determine the presence or absence of a significant effect.
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The function D(h)=5e^-0.4h can be used to determine the milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been given. How many milligrams (to two decimals) will be present after 10 hours?
The given function
D(h)=5e^-0.4h
can be used to determine the milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been given.
We have to find the milligrams of drug that will be present in a patient's bloodstream after 10 hours. Let's calculate the value using the given formula.
D(h)=5e^-0.4hD(10)
= 5e^-0.4(10)D(10)
= 5e^-4D(10)
= 5(0.01832)D(10)
≈ 0.09
The milligrams of drug that will be present in a patient's bloodstream after 10 hours are approximately 0.09 mg.
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In a factorial design if the same people are in a house this
would indicate?
Within subject design
Mixed factorial design
split-plot factorial?
If the same people are in a house in a factorial design, it indicates a within-subject design.
A factorial design is a research design that involves manipulating multiple independent variables to study their effects on a dependent variable. In a within-subject design, also known as a repeated measures design, the same individuals participate in all conditions of the experiment. This means that each participant is exposed to all levels of the independent variables.
In the context of the question, if the same people are in a house in a factorial design, it suggests that the individuals are the subjects of the study and are being exposed to different conditions or treatments within the same house. This indicates a within-subject design, where the focus is on examining the effects of the independent variables within the same individuals.
learn more about factorial here:brainly.com/question/18270920
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