13.How many grams of phosphorus (P4) are needed to completely consume 79.2 L of chlorine gas according to the following reaction at 25 °C and 1 atm?

phosphorus (P4) ( s ) + chlorine ( g ) -----> phosphorus trichloride ( l )

A scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

Creativity is a mental cognitive ability that involves the creation and/or discovery of a hidden process.

In science, creativity refers to the application of mental skills to create new experimental designs and extrapolate findings.

In conclusion, a scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

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Answer:

Matter can be broken down into two categories: pure substances and mixtures Pure substances are more broken down into elements and compounds Mixtures are physically combined structures that can be separated into their original components

Explanation:

hope it helps

Answer:

This is not accurate we dont know what your asking us?

Explanation:

Answer:

i need help to on this one 2

Explanation:

Answer:Actinide Group

Explanation:Plutonium is a member of the actinide group in the periodic table. Plutonium atoms have 94 electrons and 94 protons with 2 valence electrons in the outer shell. There are 150 neutrons in the most abundant isotope.

Answer:

28

Explanation:

electron = atomic number - charge(if the charge is positive and addition if the charge is negative)

electron = 30 - 2

electron = 28

x CO₂  = 0.236

x H₂  = 0.764

Given

P CO₂ = 217 mmHg

P H₂ = 703 mmHg

Required

The mole fraction

Solution

Dalton's law :

The total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

P tot for the mixture :

= 217 mmHg + 703 mmHg

= 920 mmHg

Mole fraction of each gas :

x CO₂ = 217 mmHg/920 mmHg = 0.236

x H₂ = 703 mmHg/920 mmHg = 0.764

Balanced equation

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

Given

Word equation

Required

Chemical equation

Solution

Chemical equations can be expressed in

Aluminum chlorate = Al(ClO₃)₃

Barium sulfate = BaSO₄

Aluminum sulfate = Al₂(SO₄)₃

Barium chlorate = Ba(ClO₃)₂

Al(ClO₃)₃ + BaSO₄⇒ Al₂(SO₄)₃ + Ba(ClO₃)₂

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

The balanced equation of the given equation would be:

[tex]2Al(ClO_{3} )_{3} + 3BaSO_{4}[/tex] ⇒ [tex]Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}[/tex]

Given that,

Aluminum Chlorate  +  Barium Sulfate → Aluminum Sulfate + Barium Chlorate

In chemical form, it would be written as:

[tex]Al(ClO_{3} )_{3} + BaSO_{4}[/tex] ⇒ [tex]Al_{2}(SO_{4})_{3} + Ba(ClO_{3})_{3}[/tex]

After balancing the two sides, the equation will read as:

[tex]2Al(ClO_{3} )_{3} + 3BaSO_{4}[/tex] ⇒ [tex]Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}[/tex]

Thus, [tex]2Al(ClO_{3} )_{3} + 3BaSO_{4}[/tex] ⇒ [tex]Al_{2}(SO4)_{3} + 3Ba(ClO_{3})_{2}[/tex] is the correct answer.

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Answer:

u didnt give a worksheet

Explanation:

Explanation:

I think the correct answer is B

Hope this helped u

Answer:

the image won't load so maybe upload it again please

Answer:

6.4 moles of  KClO₃ are decomposed

Explanation:

Given data:

Number of moles of O₂ produced = 9.6 mol

Number of moles of KClO₃ decomposed = ?

Solution:

Chemical equation:

2KClO₃       →     2KCl + 3O₂

now we will compare the moles of oxygen and KClO₃.

                 O₂           :           KClO₃

                   3           :               2

                9.6           :           2/3×9.6 = 6.4 mol

Thus, 6.4 moles of  KClO₃ are decomposed.

Answer:

communicable and non-communicable?

Answer: Each p orbital can hold 6 electrons.

Explanation: The p sublevel has 3 orbitals, so it can contain a maximum of 6 electrons.

Answer:

The frequency of coral diseases has increased significantly over the last 10 years, causing widespread mortality among reef-building corals. Many scientists believe the increase is related to deteriorating water quality associated with human-made pollutants and increased sea surface temperatures.

Explanation:

(NH₄)₂S

%N=  41.18%

%H =11.76%

%S=47.06%

Mg(NO₃)₂

%Mg=32.43%

%N=18.92%

%O=(64.86%

Given

(NH₄)₂S

Mg(NO₃)₂

Required

The percent composition

Solution

(NH₄)₂S MW=68 g/mol

%N=2. Ar N  / MW (NH₄)₂S x 100%

%N= (2.14/68) x 100% = 41.18%

%H =(8.1/68) x 100%=11.76%

%S=(32/68)x 100%=47.06%

Mg(NO₃)₂ MW=148 g/mol

%Mg=(2.24/148)x100%=32.43%

%N=(2.14/148)x100%=18.92%

%O=(6.16/148)x100%=64.86%

Answer:

1eV

Explanation:

Answer:

1ev

Explanation:

Answer:

Heated water begins circulating in a fish tank.

Explanation:

Answer:

Heated water begins circulating in a fish tank.

1.63 M

Math

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Chemistry

Unit 0

Aqueous Solutions

Step 1: Define

1.43 mol NaCl (sodium chloride)

0.875 L solution

Step 2: Find M

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.63429 M ≈ 1.63 M

Answer:

2KOH + 3co2 ------->2ксоз + 2Н20

Answer:

5 g of H₂ are contained in the vessel

Explanation:

A typical excersise of conversion:

We determine molar mass of H₂.

This is a dyatomic molecule, as molar mass of H is 1g/mol, molar mass of H₂ will be 2g/mol.

Let's make the conversion of units:

2.5 mol . 2g/mol = 5 g

5 g of H₂ are contained in the vessel

Mass of hydrogen in the vessel = 5 grams

The number of moles is defined as the given mass over molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given:

Number of moles= 2.5 mol

To find:

Mass of hydrogen=?

Molar mass of hydrogen =2g/mol

On substituting the values in the given formula we will get:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}=2.5 mol* 2g/mol\\\\\text{Given mass}=5 g[/tex]

Thus, mass of hydrogen in the vessel is 5 grams.

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Answer:

When one object is rubbed against another, static electricity can be created. This is because the rubbing creates a negative charge that is carried by electrons. The electrons can build up to produce static electricity. For example, when you shuffle your feet across a carpet, you are creating many surface contacts between your feet and the carpet, allowing electrons to transfer to you, thereby building up a static charge on your skin. When you touch another person or an object, you can suddenly discharge the static as an electrical shock.

Similarly, when you rub a balloon on your head it causes opposite static charges to build up both on your hair and the balloon. Consequently, when you pull the balloon slowly away from your head, you can see these two opposite static charges attracting one another and making your hair stand up.

Materials

• Balloon

• An object made out of wool (such as a sweater, scarf, blanket or ball of yarn)

• Stopwatch

• A wall

• A partner (optional)

Preparation

• Blow up the balloon and tie off the end.

• Have your partner prepare to use the stopwatch.

Procedure

• Hold the balloon in a way that your hand covers as little of its surface area as possible, such as by using only your thumb and pointer finger or by gripping the balloon by its neck where it is tied off.

• Rub the balloon on the woolly object once, in one direction.

• Hold the balloon up on the wall with the side that was rubbed against the wool facing the wall, then release it. Does the balloon stay stuck on the wall? If the balloon stays stuck, have your partner immediately start the stopwatch to time how long the balloon remains bound to the wall. If the balloon does not stick, move to the next step.

• Touch the balloon to a metal object. Why do you think this is important to do?

• Repeat the above process but each time increase the number of times you rub the balloon on the woolly object. Rub the balloon in the same direction each time. (Do not rub the balloon back and forth.)

Observations and results

In general, did the balloon stick to the wall for a longer amount of time as you increased the number of times you rubbed the balloon on the woolly object?

Wool is a conductive material, which means it readily gives away its electrons. Consequently, when you rub a balloon on wool, this causes the electrons to move from the wool to the balloon's surface. The rubbed part of the balloon now has a negative charge. Objects made of rubber, such as the balloon, are electrical insulators, meaning that they resist electric charges flowing through them. This is why only part of the balloon may have a negative charge (where the wool rubbed it) and the rest may remain neutral.

When the balloon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall. Although the wall should normally have a neutral charge, the charges within it can rearrange so that a positively charged area attracts the negatively charged balloon. Because the wall is also an electrical insulator, the charge is not immediately discharged. However, because metal is an electrical conductor, when you rub the balloon against metal the extra electrons in the balloon quickly leave the balloon and move into the metal so the balloon is no longer attracted and does not adhere.

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PLEASE MARK ME BRAINLIEST

The test variables and the control variable and the outcome variables are Balloons, the electrical insulators, and resist electric charges flowing through them.

When we brush a balloon against our head, the hair and balloon both develop opposing static charges. We can see how these two opposing static charges attract one another and make our hair stand up as the balloon is gently dragged away from our head.

When a balloon is rubbed to the wall, it will be attracted to the wall. Because the wall is an electrical insulator, the charge is not quickly discharged.

The excess electrons in the balloon immediately leave the balloon and go into the metal when it is rubbed against metal. As a result, the balloon is no longer attracted to the metal and does not adhere.

Therefore, Balloons, which act as electrical insulators and prevent the flow of electric charges, serve as the test, control, and outcome variables.

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Solution :

Given :

length of silver cube = 2.28 cm

length of gold cube = 2.75 cm

Initial temperature = 82.8°C

Volume of silver cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.28)^3$[/tex]

                [tex]$= 11.8 \ cm^3$[/tex]

mass of silver cube

Mass, [tex]$m_s = \text{density} \times \text{volume} $[/tex]

                = 10.5 x 11.8

                = 123.9 g

Similarly, the volume of gold cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.75)^3$[/tex]

                [tex]$= 20.79 \ cm^3$[/tex]

mass of gold cube

Mass, [tex]$m_g = \text{density} \times \text{volume}$[/tex]

                = 19.3 x 20.79

                = 401.247 g

Now

heat lost by silver and gold cube = heat gained by water

∴[tex]$m_g .c_g \Delta T + m_s .c_s \Delta T = m_w.c_w \Delta T$[/tex]

[tex]$m_g .c_g (82.8- T) + m_s .c_s (82.8- T) = m_w.c_w (T - 20.2)$[/tex]

[tex]$401.247 \times 0.1264 (82.8- T) + 123.9 \times 0.2386 (82.8- T) = 111.5 \times 4.184 (T - 20.2)$[/tex]

Now solving the equation

[tex]$50.71 (82.8- T) + 29.56 (82.8- T) = 466.51 (T - 20.2)$[/tex]

Final temperature, T = 31.27°C

Answer:

1. They can tell that a reaction has taken place if there is formation of gas bubbles in the test tube as well as if the metal dissolves in the acid solution

2. To determine which metal is more reactive, they would compare how fast each reaction occurs. The most reactive metal would have the fastest rate of reaction with a vigorous formation of bubbles, whereas the least reactive metal will have the slowest rate of reaction.

Explanation:

1. Metal which are more electropositive than hydrogen displace hydrogen from dilute acids with the formation of the salt of the metal and evolution of hydrogen gas. Therefore, the formation of gas bubbles in the test tube indicates that a reaction is taking place.

2. The rate of formation of the gas bubbles as well as the time taken for the reaction to come to a completion by the dissolution of the metal in the acid indicates which metal is more reactive. The most reactive metal would have the fastest rate of reaction with a vigorous formation of bubbles, whereas the least reactive metal will have the slowest rate of reaction.

However, the rate of the reaction is also affected by the concentration of the acid used. The higher the concentration of the acid, the faster the reaction rate.

Answer: The pancreas is a gland organ located in the abdomen. ... The end of this duct is connected to a similar duct that comes from the liver, which delivers bile to the duodenum. ... A person can usually treat minor chest injuries at home with rest and ...

Answer:

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + 3 H₂(g)

Explanation:

Let's consider the unbalanced equation for the single replacement reaction between Al and H₂SO₄.

Al(s) + H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

We will begin balancing S atoms by multiplying H₂SO₄ by 3.

Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

Then, we balance Al atoms by multiplying Al by 2.

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

Finally, we get the balanced equation by multiplying H₂ by 3.

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + 3 H₂(g)

Answer:

They are different because one is someone who studies volcanoes and the other is someone who studies weather

Explanation:

Answertrickinic

Explanation:

Answer:

P(O₂) = 287.41 mmHg

P(O₂) = 413.59 mmHg

Explanation:

Given data:

Total pressure = 701 mmHg

Mass of methane = 2.75 g

Mass of oxygen = 3.45 g

Partial pressure of each gas = ?

Solution:

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 2.75 g/ 16 g/mol

Number of moles = 0.17 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 3.45 g/ 32 g/mol

Number of moles = 0.12 mol

Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol

Partial pressure of oxygen:

P(O₂)  = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.12  / 0.29 ] × 701 mmHg

P(O₂) = 0.41 × 701 mmHg

P(O₂) = 287.41 mmHg

Partial pressure of methane:

P(O₂)  = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.17  / 0.29 ] × 701 mmHg

P(O₂) = 0.59 × 701 mmHg

P(O₂) = 413.59 mmHg