12. A baseball player throws a ball. While the 700.0-g ball is in the pitcher’s hand, there is a force of 125 N on it. What is the acceleration of the ball?

Answers

Answer 1

Answer:

F=ma

125N=.7*a solve for a.

Explanation:


Related Questions

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?

Answers

Answer:

either its 12 or 0.402

Explanation:

A fish swimming at a rate of .6 m/s notices a huge shark. Three seconds later, the fish is swimming at a speed of 3 m/s. What is the fish's acceleration?

0.8 m/s/s
-0.8 m/s/s
12.5 m/s/s
-12.5 m/s/s

Answers

Answer:

C

Explanation:

???

i think

Can u anser 5,6 on the picture

Answers

Answer: Number 6 is Periods

Explanation:

A 0.15 kg ball is moving with a velocity of
35 m/s. Find the momentum of the ball.

Answers

Answer:

5.25 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

5.25 kg.m/s

Hope this helps you

Using Velocity vs Time Graphs to Find Acceleration
A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line has 4 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 15 meters per second. Then segment B runs to 2 seconds 20 meters per second. Then segment C runs to 4 seconds 20 meters per second. Then segment D runs to 5 seconds 0 meters per second.

The acceleration of segment D is m/s2.



Rank segments A, B, and C from least acceleration to greatest acceleration.

Least:








Greatest:

Answers

The acceleration at segment D is -20m/s²

The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)

Acceleration is the change in velocity with respect to time.

a = v-u/t

Acceleration at segment A:

Aa = 15-0/1-0

Aa = 15m/s²

Acceleration at segment B:

Ab = 20-15/2-1

Ab = 5m/s²

Acceleration at segment C:

Aa = 0-0/4-2

Aa = 0m/s²

Acceleration at segment D:

Ac = 0-20/5-4

Ac = -20m/s²

Hence the acceleration at segment D is -20m/s²

The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)

Learn more here: https://brainly.com/question/18398656

A 75kg bicyclist (including the bicycle), initially at rest at the top of a hill, coasts down the hill, reaching a speed of 14.6m/s at the bottom of the hill. The distance and height of the hill are shown. Neglect any friction impeding the motion and the rotational energy of the wheels. List the energy types at the initial and final time and whether work and loss (due to non-conservative forces) occur as well as the corresponding amounts of energy.

Answers

The energy type at the initial time is potential energy and the energy at the final time or position is kinetic energy.

What is the law of conservation of energy?

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

Based on the law of conservation of mechanical energy, the formula for the change in the kinetic energy and the potential energy of the bicyclist is given as;

K.Ei + P.Ei = K.Ef + P.Ef

where;

K.Ei is the initial kinetic energy of the bicyclistK.Ef is the final kinetic energy of the bicyclistP.Ei is the initial potential energy of the bicyclistP.Ef is the final potential energy of the bicyclist

The kinetic energy of the bicyclist increases with increase in the velocity of the bicyclist while the potential energy increases with increase in the height of the bicyclist.

At the initial position when the bicyclist is at rest, the kinetic energy is zero, so the only energy at the initial position is potential energy because the height is maximum.

In addition, at the final position, the velocity of the bicyclist is maximum and the height is zero, so the only energy at the final position is kinetic energy.

Learn more about conservation of energy here: https://brainly.com/question/166559

#SPJ1

how many teeth shows signs of decay?​

Answers

Answer:

what do you mean

Explanation:

If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?

A. Iron
B. Carbon
C. Rubber
D. Air

Answers

Answer:

iron

Explanation:

(HELP PLEASE)What are some reasons people produce synthetic materials?

Answers

Answer:

Explanation:

Synthetic fabrics, such as nylon and polyester, are produced entirely from chemicals. Natural fabrics, such as cotton, silk, and wool are made of fibres from plants and animals. Synthetic fabrics are useful because they have very different or enhanced (improved) properties in comparison to natural materials.

Physical values in the real world have two components: magnitude and

Answers

Answer:

Dimension.

Explanation:

13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters​

Answers

Answer:

B. 1200

Explanation:

60 sec in one min in 2 min there will be 120 sec. 10x120=1200

help me with this please :((

Answers

Answer:

huh?

Explanation:

Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f​

Answers

Answer: true

Explanation:

You bought a helium balloon for a friend’s winter birthday. The outside temperature was -34 degrees C. The store was at a comfortable 298K. The volume of the balloon immediately after the store clerk filled it was 6 liters. What was the volume after you brought it outside? Show your work. Make sure to include units.

Answers

Answer:

4.81 L

Explanation:

From the question given above, we obtained the following information:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = – 34 °C

Final Volume (V₂) =?

Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = – 34 °C

T(K) = – 34 + 273

T(K) = 239 K

Thus, –34 °C is equivalent to 239 K

Finally, we shall determine the final volume of the balloon as follow:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = 239 K

Final Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

6 / 298 = V₂ / 239

Cross multiply

298 × V₂ = 6 × 239

298 × V₂ = 1434

Divide both side by 298

V₂ = 1434 / 298

V₂ = 4.81 L

Thus, the volume of the balloon when it was brought outside the store was 4.81 L.

A sound wave passes from air into water and then into steel. With each change in medium, the velocity of this wave will a(increase,then decrease b(decrease c(increase d( decrease,then increase ?

Answers

Answer:

a

Explanation:

because it can increase anything

Describe the last three years of your life. Include positive and negative experiences.
For a middle school girl

Answers

Answer:

my middle school life was horrible and still is sadly ); could you please do my recent brainless <333

Explanation:

My middle school life was eh.i allways got assumed that i was a elementry kid when i was and 6 and 7 grade.until 8th when i hit my grow spurt.my voice end up getting really deep in 8th grade too.tho in 8th i got sent to a certain  type of scholl for kids who did bad because of some dum teacher who lied that i hit her when i actually just went to her desk to get my phone sence she saw it in my pocket and took it away.i got sent there for 3 months and was worst thing ever.the treated us like prisoners in that school and made us tacky uniforms that i refused to where.i believe it was a school for 7th-12th.after my expierence at that school my expierence in 8th grade was almost done.i end up being popular at school for being that kid who hit the teacher.ofc that was like 2 years ago im 10th now.i dont really remember my 6th and 7th grade year.only thing i rember is i was a trouble maker and still am a trouble maker.

hope that helped you:)

please make my answer brainiest as im trying get 4 brainiest answers

Shows a car travelling around a bend in the road. The car is travelling at a constant speed. There is a resultant force acting on the car. This resultant force is called the centripetal force. (i) In which direction, A, B, C or D, does the centripetal force act on the car? Tick ( ) one box. A B C D (1) (ii) State the name of the force that provides the centripetal force.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but the missing figure is in the attachment below.

When an object is travelling around a circular path, there is a force that tends to draw that object towards the center of the circular path and keep the object moving in the curved path, that force is called the centripetal force. From this description, it can be deduced that the direction of the centripetal force that acts on the car (in the attachment below) is D.

The name of the force that provides this centripetal force is frictional force. This is the force that prevents the car from slipping off the road; keeping it moving in the curved path.

a metallic cube whose each side is 10 cm is subjected to a shearing force of 100 kg. The top force is displaced through 0.25 cm with respect to the bottom. calculate the shearing stress strain and modulus​

Answers

Answer:

9.8×104Nm−2,0.025,3.92×106Nm−2

Solution :

Here, L=10cm=10×10−2m

F=100kgf=100×9.8N

ΔL=0.25cm=0.25×10−2m,

Shearing stress =FL2=100×9.8(10×10−2) Sheraing strain =ΔLL=0.25×10−210×10−2 = 0.025 Shear Modulus of elasticity, G=Shearing stressShearing strain=9.8×1040.025

=3.92×106Nm−2

Explanation:

An object at rest has no net force acting on it.
True or False​

Answers

That’s True bc an unbalanced force would need to keep and object in motion at a constant velocity.

Answer:

True

Explanation:

The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.

WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?

Answers

Answer:                                                                              

372                              

Explanation:(40.0)×(9.8)=392

764N-392=372

a squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy

What is the squirrels mass

Answers

Answer:

yeet yeet yeet yeet

Explanation:

Kinetic energy (K.E):-

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

Two soccer players run toward each other. One player has a mass of 85 kg
and runs west with a speed of 8 m/s, while the other has a mass of 105 kg
and runs east with a speed of 7 m/s. What is the total momentum of the
system made up of the two players?

Answers

Answer:

Total momentum, p = 55 kg-m/s

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

Speed of player 1, v₁ = -8 m/s (west)

Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

p=m_1v_1+m_2v_2p=m

1

v

1

+m

2

v

2

p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s

p = 55 kg-m/s

The total momentum of the system made up of the two players is 55 kg-m/s.

Answer:

p = 55 kg * m/s east

Explanation:

The answer above explains it neatly, but leaves the direction out of the answer. The player heading east has more momentum, so the net momentum of the system is east.

If you run North for 5 meters and then East for 15 meters and then
South for 2 meters all in 22 seconds. What was your speed?
0 points

Answers

Answer:

1m/s

Explanation:

D = 22m

T = 22s

S = 22÷22

= 1 m/s

WRITE A PARAGRAPH ABOUT PRESSURE

Answers

Answer:

pressure is a horrible thing to go through, it can lead to many bad side effects, like burn out and it can also lead to high blood pressure, head aches, heart problems, depression, anxiety, and many more damaging effects. Pressure can destroy someones mental health if not dealed worth properly

I hope this is okay! I'm not sure what pressure you meant

Which type of pressure are you referring to ?

A merry go round exerts a force of 1000 N on a rider on the
outer ring of animals when it takes 15 seconds to make a
complete revolution. If the person weighs 750 N, the radius
of the circle he is making is m. Round your answer to
the nearest tenth.

Answers

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

[tex]F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r[/tex]

Where;

m = The mass of the person

v = The velocity of the person

[tex]F_c[/tex] = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

[tex]F_c[/tex] = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

26. For this table of data, which column is the independent variable?
radius of circle (m) area of circle (m2)
3.4
36.317
4.5
63.617
4.6
66.476
6.2
120.763
7.6
181.458
7.7
186.265
8.6
232.352
9.7
295.592
area of circle
o
radius of circle
O
None of these is correct.

Answers

Answer:

radius of a circle is measured by an instrument, so it is the independent variable

Explanation:

The independent variable corresponds to the magnitude controlled by the experimenter and in general can be measured by an instrument.

The dependent variable is the variable used to perform the calculations, obtained from a mathematical transformation of the independent variable.

The radius of a circle is measured by an instrument, so it is the independent variable and the area is calculated by

         A = π r²

Therefore the area corresponds to the dependent variable

Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero

Answers

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

Alex wants to learn how to surf, but he is not a strong swimmer. He knows he needs to increase his ability to paddle out in order to catch the best waves. Which piece of advice would you give to help him get started on reaching his goal? He should swim at least three times a week at the community pool to build stamina. He should tread water every day to get more comfortable in the water. He should purchase the best surfboard he can afford because it will help him paddle faster. He should watch your friend who is a competitive surfer practice to learn her technique.

Answers

Answer:

He should swim at least three times a week at the community pool to build stamina.

Explanation:

If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?

Answers

3 meters per second squared (3 m/s2)

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

                                   

                                           

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