power is reffering to force
what makes up a atom
Answer:
They're typically made up of three main parts: protons, neutrons and electrons. Think of the protons and neutrons as together forming a “sun”, or nucleus, at the centre of the system. The electrons orbit this nucleus, like planets. If atoms are impossibly small, these subatomic particles are even more so.
Explanation:
hope i helped.
Answer:
Atoms consist of a nucleus made of protons and neutrons orbited by electrons. ... We now know that atoms are made up of three particles: protons, neutrons and electrons — which are composed of even smaller particles, such as quarks.
Explanation:
A jet aircraft is traveling at 214 m/s in hor-
izontal flight. The engine takes in air at a
rate of 115 kg/s and burns fuel at a rate of
2.53 kg/s. The exhaust gases are ejected at
276 m/s relative to the aircraft.
Find the thrust of the jet engine.
Answer in units of N.
Answer:
The thrust is [tex]F = 7828.3 \ N [/tex]
Explanation:
From the question we are told that
The speed of the jet aircraft is [tex]v = 214 \ m/s[/tex]
The rate at which the engine takes in air is [tex]\^ Q = 115 \ kg/s[/tex]
The rate at which the engine burns fuel is [tex]\r m = 2.53 \ kg/s[/tex]
The speed of the exhaust gases is [tex]u = 276 \ m/s[/tex]
Generally the thrust of the engine is mathematically represented as
[tex]F =[ \^ Q * ( u - v )] + (\r m * u)[/tex]
=> [tex]F =[ 115 * ( 276 - 214 )] + (2.53 * 276)[/tex]
=> [tex]F = 7828.3 \ N [/tex]
Matt is driving his car around a curve that has a radius of 40 m. If his speed is 25 m/s as he negotiates the curve, find the centripetal acceleration for the curve.
A- 13.9 m/s2
B- 24.6 m/s2
C- 15.6 m/s2
D- 7.25 m/s2
Answer:
[tex]\huge\boxed{\sf a_{c} = 15.6\ m/s^2}[/tex]
Explanation:
Given Data:
Radius = r = 40 m
Speed = v = 25 m/s
Required:
Centripetal Acceleration = [tex]\sf a_{c}[/tex] = ?
Formula:
[tex]\sf a_{c} = \frac{v^2 }{r}[/tex]
Solution:
[tex]\sf a_{c} = \frac{v^2}{r} \\\\a_{c} = \frac{(25)^2}{40} \\\\a_{c} = \frac{625}{40} \\\\a_{c} = 15.6 m/s^2\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Which type of energies make up the mechanical energy of a roller coaster moving along a track?
Answer:
gravitational potential energy and kinetic energy
Explanation:
In its American colonies, Spain helped the Catholic Church meet its goal of
finding gold.
gaining territory.
converting people.
achieving glory.
This is from ed please help thank you
Answer: Converting people
Explanation: In Spanish colonies such as Florida, Spanish moved up into the other states to spread their christianity and were successful with doing so.
Which source of energy causes most of the water evaporation on Earth’s surface?
A.
wind
B.
solar
C.
gravity
D.
electrical
Answer:
I think it will be b. solar
Hope I can help.
Answer:
Explanation:
its b
A stretched spring attached to two fixed points is compressed on one end and released, as shown. The resulting wave travels back and forth between the two fixed ends of the spring until it comes to a stop. This is an example of _____ .
a Transverse wave
b
longitudinal wave
c
surface wave
d
electromagnetic wave
Answer:
B. Longitudinal wave
Explanation:
It's the only option that makes sense. Hope this helped :)
Which of the following is true about particles of matter?
Answer:
Matter is a substance which has mass and takes up space by volume the properties of matter are,
States of matter (solid,liquid,gas)are inter convertable.
Force of attraction varies from one kind of matter to another.
States of matter can be varied by varying temperature and pressure.
Explanation:
As we know, the moon is a satellite of our earth, what is the
theoretical period of the moon? The average radius of the
moon's orbit is 3.84 108 m and the mass of the earth is 5.97 x
1024 kg (in hours, G = 6.67 x 10-9 N (m/kg) 3).
Answer:c
Explanation:c
This question involves the concepts of the time period, orbital radius, and gravitational constant.
The theoretical period of the moon is "658 hr".
The theoretical time period of the moon around the earth can be found using the following formula:
[tex]\frac{T^2}{R^3}=\frac{4\pi^2}{GM}[/tex]
where,
T = Time Period of Moon = ?
R = Orbital Radius = 3.84 x 10⁸ m
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
Therefore,
[tex]\frac{T^2}{(3.84\ x\ 10^8\ m)^3}=\frac{4\pi^2}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}\\\\T^2=(9.91\ x\ 10^{-14}\ s^2/m^3)(56.62\ x\ 10^{24}\ m^3)\\\\T=\sqrt{561.34\ x\ 10^{10}\ s^2}[/tex]
T = 2.37 x 10⁶ s[tex](\frac{1\ h}{3600\ s})[/tex]
T = 658 hr
Learn more about the orbital time period here:
https://brainly.com/question/14494804?referrer=searchResults
The attached picture shows the derivation of the formula for orbital speed.
How do you compare the mass of proton, neutron, and
electron?
Answer:Explanation:
Protons and neutrons have very similar mass, while electrons are far lighter, approximately 11800 times the mass. Protons are positively charged, neutrons have no electric charge, electrons are negatively charged. The size of the charges is the same, the sign is opposite.
Earthquakes
Shaking of the ground
Seismographs
Scientific method
Answer:
C. seismographs
Explanation:
Theirs another name for seismographs but c is correct
when it comes to graphs I am no genius lol
Answer:
Option B
Explanation:
Displacement = Area under the velocity-time graph
So to find the displacement of a particle from 7 to 8 seconds we take the triangle and calculate its area.
[tex]Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(base)*(height) \\\\Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(1)*(3) \\\\Area\ of\ a\ right\ angled\ triangle = 1.5[/tex]
So the displacement is 1.5 meters
I have an uploaded image so you can understand it better hope it helps
What 2 factors affect the impulse on an object in a collision?
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour.
Answer:
first one 31
second one 23
Explanation:
on edge ;))
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10s. If the airplane is putting out an average force of 5.8810x10^4 N during this time, what is the average friction force exerted on the airplane by the air?
Given :
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.
If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].
To Find :
The average friction force exerted on the airplane by the air.
Solution :
Acceleration is given by :
[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]
Now, force equation is given by :
[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]
Therefore, frictional force exerted in the airplane by the air is 9810 N.
When velocity is graphed with respect to time, what does the area under
the line represent?
A) velocity
B) distance
C) acceleration
D) displacement
Answer:
the answer is D
Explanation:
Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.
How much power is used if a force of 35 newtons is used to push a box a distance of 10 meters in 5 seconds?w=350j
Answer:
How much power is used if 350J of work is done when pushing a box for 5 seconds.
Explanation:
the answer is 70watts
A car traveling at 50 m/s comes to a stop in 5 seconds. What is the
acceleration of this?
Answer:
10
Explanation:
10 is the answer because you divide 50 and 5 and your answer is 10.
Hope this helps:)
Pls mark brainlist
Answer:
a = -10m/s²
Explanation:
Givens:
Vf = 0m/s
Vi = 50m/s
t = 5s
Use the following kinematic equation:
Vf = Vi+at
Rearrange
a = (Vf-Vi)/t
a = -10m/s²
What year was the RoboSapien toy robot released?
a) 2007
b) 2004
c) 2020
d) dunno
option b )2004........
4) Choose Yes or No next to the descriptions to indicate whether or not an object
is accelerating,
A car slows down,
A car stays the same speed,
A car goes faster,
Luke walks at a constant speed of 4 mph,
Luke walks north at a constant speed of 4 mph,
Luke walks north at a constant speed of 4 mph, turns right, and walks
Type here to search
Charles, the 75 kg trampoline artist, lands on a trampoline with a speed of 9.0 m/s.
If the trampoline behaves like a spring with a spring constant of 52,000 N/m, what maximum distance will Charles push down the trampoline before bouncing back up? (Hint: at maximum compression, Charles is not moving.)
Answer:
The maximum distance Charles will push down the trampoline ≈ 0.342 m
Explanation:
The given parameters are;
The mass of the trampoline artist, m = 75 kg
The speed with which the trampoline artist lands, v = 9.0 m/s
The value of the spring constant of the trampoline, k = 52,000 N/m
Let x represents the maximum distance Charles will push down the trampoline
Therefore, we have;
Kinetic energy = 1/2·m·v²
The kinetic energy with which the trampoline artist lands = 1/2 × 75 × 9.0² = 3037.5
The kinetic energy with which the trampoline artist lands = 3037.5 J
The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands
∴ 1/2 × 52,000 × x² = 3037.5
∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342
The maximum distance Charles will push down the trampoline = x ≈ 0.342 m
Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
Answer:
See the answer below
Explanation:
If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.
If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.
which one?? please someone quick!
Answer:
i think its second law of motion.
Explanation:
Answer:
it’s the second law
Explanation:
A substance will take on the shape of an open container if it is a
liquid.
plasma.
gas.
solid.
Answer:
liquid
Explanation:
What makes the yardstick test a direct measurement of reaction time?
A.
The further the yardstick falls, the slower the reaction time.
B.
Yardsticks have numerical markings for length.
C.
Yardsticks are designed to measure reaction time.
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
Answer:
A. the further the yardsticks falls, the slower the reaction time.
Answer:
The further the yardstick falls, the slower the reaction time.
Explanation:
its A
A red 120 kg bumper car moving at 4 m/s collides with a green 100 kg bumper car moving at 3 m/s. The red bumper car bounces off at 2 m/s. What is the green car's final velocity?
The temperature of a substance is 45 C. Convert this to Kelvin.
Answer:
it will be 318.5 Kelvin
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap around the 80.00 m radius circular track. What is the frequency of the race car's circular motion?
Answer:
The value is [tex]f = 0.05 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 615 \ kg[/tex]
The period of the circular motion is [tex]T = 20 \ s[/tex]
The radius is [tex]r = 80 \ m/s[/tex]
Generally the frequency of the circular motion is
[tex]f = \frac{1}{T }[/tex]
=> [tex]f = \frac{1}{ 20 }[/tex]
=> [tex]f = 0.05 \ Hz[/tex]
Where are alkaline earth metals found on the periodic table?
Group 1
Group 2
Groups 3–12
Group 17
Answer:
B
Explanation:
Answer:
B
Explanation:
I had a feeling
Can someone help me in this please any one good in science.
Let's calculate the equivalent resistances on both circuits.
On Diagram A we have a series connection of the resistors. The equivalent resistance will be the sum of all resistances:
[tex]R_{eq}=1+1+1\\\\\boxed{R_{eq}=3\Omega}[/tex]
On diagram B we have a parallel connection of the resistors. The reciprocal of the equivalent resistance will be the sum of the reciprocals of all the resistances:
[tex]\frac{1}{R_{eq}} = \frac{1}{1} +\frac{1}{1} +\frac{1}{1} \\\frac{1}{R_{eq}}=3\\\\\boxed{R_{eq}=\frac{1}{3}}[/tex]
Therefore, the larger resistance occurs on diagram A.
For the current, recall
[tex]V=IR[/tex]
Where [tex]I[/tex] stands for current [tex]R[/tex] is the resistance and [tex]V[/tex] is the voltage. Rearranging the equation we have
[tex]I = \frac{V}{R}[/tex]
We can see that the larger the resistance, the smaller the current gets. So the larger current must happen in the diagram with smaller resistance. Therefore, the larger current occurs on diagram B.
Glad to help, wish you great studies ;)
Mark brainliest if you deem the answer worthy