1 poin 4. If the same strength force is exerted on two objects but the objects have different masses, the object with mass will have a greater change in velocity. O more O less O greater O the same​

Answer:

4) Object in motion

5) Velocity

6) 0 m/s²

7) non - uniform acceleration

8) 0 m/s

9) Equal

10) distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.

Explanation:

4) Object in motion

5) Ratio between displacement and time is velocity. Displacement is in metres(m) and time is in seconds(s). Thus, displacement/time is in m/s which is velocity.

6) Acceleration = 0 m/s² since it loves with uniform velocity and therefore doesn't accelerate.

7) Since the object changes its velocity with unequal amounts in equal time, the acceleration is called non - uniform acceleration since the acceleration will differ at different points.

8) Initial velocity of an object that starts motion from rest is zero.

9) They are equal since velocity is uniform.

10) The horizontal range will be distance covered by the object along the horizontal plane before it reaches the same vertical position from which it started.

Answer:

Your answer is A) 3.33ft/min E

Explanation:

i know this because i know to find the velocity you have to divide distance and time. So for this question your distance=10 and your time=3.

poste en français s’il vous plaît

Answer:

the reading on the scale is 158.5 mm.

Explanation:

Given;

upper fixed point of the temperature scale, x₁ = 260 mm

lower  fixed point of the temperature scale, x₂ = 50 mm

upper temperature scale, T₁ = 212 °F

lower temperature scale, T₂ = 32 °F

thermometer reading, t = 125 °F, let the reading on the scale = x

Interpolate as follows to determine the value of "x"

[tex]\frac{X_1 - X}{X_1-X_2} = \frac{T_1-t}{T_1-T_2} \\\\\frac{260-X}{260-50} = \frac{212-125}{212-32} \\\\\frac{260 -X}{210} =\frac{87}{180} \\\\180(260-X) = 87(210)\\\\46800 -180 X = 18270 \\\\180X = 46800-18270\\\\180X = 28530\\\\X = \frac{28530}{180} \\\\X = 158.5 \ mm[/tex]

Therefore, the reading on the scale is 158.5 mm.

Answer:

0.89 g/cm^3 = 890 kg/m^3

Explanation:

Cross sectional area of U-tube ( A ) = 1.00 cm^2

volume of oil ( V )  = 5.00 cm^3

change between top surface = 0.550 cm

height of oil = 5 cm  ( volume / area )

height of water = 5 - 0.550 = 4.45 cm

pressure at the oil-water junction = Pressure on the second side of the U-tube at same level

Po * g * Hoil = Pw * g * Hwater

Po * 5 = 1 * 4.45

∴ Density of oil ( Po ) = 4.45 / 5  g/cm^3 = 0.89 g/cm^3

Answer:

The amount of thermal energy needed is 15167500 joules.

Explanation:

By First Law of Thermodynamics, we see that amount of thermal energy ([tex]Q[/tex]), in joules, is equal to the change in internal energy. From statement we understand that change in internal energy consisting in two latent components ([tex]U_{l,ice}[/tex], [tex]U_{l,steam}[/tex]), in joules, and two sensible component ([tex]U_{s,w}[/tex]), in joules, that is:

[tex]Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam}[/tex] (1)

By definitions of Sensible and Latent Heat, we expanded the formula:

[tex]Q = m\cdot (h_{f,w}+h_{v,w}+c_{ice}\cdot \Delta T_{ice}+c_{w}\cdot \Delta T_{w})[/tex] (2)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]h_{f,w}[/tex] - Latent heat of fussion of water, in joules per kilogram.

[tex]h_{v,w}[/tex] - Latent heat of vaporization of water, in joules per kilogram.

[tex]c_{ice}[/tex] - Specific heat of ice, in joules per kilogram per degree Celsius.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram per degree Celsius.

[tex]\Delta T_{ice}[/tex] - Change in temperature of ice, measured in degrees Celsius.

[tex]\Delta T_{w}[/tex] - Change in temperature of water, measured in degrees Celsius.

If we know that [tex]m = 5\,kg[/tex], [tex]h_{f,w} = 3.34\times 10^{5}\,\frac{J}{kg}[/tex], [tex]h_{v,w} = 2.26\times 10^{6}\,\frac{J}{kg}[/tex], [tex]c_{ice} = 2.090\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]c_{w} = 4.186\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]\Delta T_{ice} = 10\,^{\circ}C[/tex] and [tex]\Delta T_{w} = 100\,^{\circ}C[/tex], then the amount of thermal energy is:

[tex]Q = 15167500\,J[/tex]

The amount of thermal energy needed is 15167500 joules.

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

[tex]W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J[/tex]

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

Answer:

a) 2.8 m/s2

b) 2.2 m/s2

Explanation:

       [tex]F_{n1} = m * (g +a_{1}) = 227 lb (2)[/tex]

      [tex]F_{n2} = m * (g +a_{2}) = 138 lb (3)[/tex]

       [tex]a_{1} = (\frac{227lb}{177lb} *g) - g = 0.28*g = 0.28*9.8m/s2 = 2.8 m/s2 (4)[/tex]

       [tex]a_{2} = (\frac{138lb}{177lb} *g) - g = -0.22*g =- 0.22*9.8m/s2 = -2.2 m/s2 (5)[/tex]

Answer:

[tex]\mu=1[/tex]

Explanation:

Given that,

Mass of a rubber mat, m = 105 kg

We need to find the coefficient of static friction, if the force required to start the mat sliding is 1030 N.

The applied force is given by :

[tex]F=\mu mg\\\\\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{1030}{105\times 9.8}\\\\\mu=1[/tex]

So, the required coefficient of static friction is equal to 1.

Answer:

500uF

Explanation:

On the graph C (Charge/Coulomb) increases by .005 each measurement and the Voltage by 10. Capacitance= Charge/Potential difference. .005/10 =.0005 which is written as 500uF. This works since if u simply work it backwards, 1uF is 1 millionth of a Coulomb times that by 500 which gives .0005 then by 10 for Voltage and then u get the original charge.

So the answer is 500uF.

Answer:

The answer should be D..

Explanation:

Answer:

P = 5880 J

Explanation:

Given that,

The mass of a person, m = 60 kg

The height of the stairs, h = 10 m

We need to find the gravitational potential energy of the person. The formula is as follows :

[tex]P=mgh[/tex]

Substitute all the values,

[tex]P=60\times 9.8\times 10\\\\P=5880\ J[/tex]

So, the required gravitational potential energy is equal to 5880 J.

Answer:

These are called molecular compounds. ex. organic compounds like lipids or proteins.

Answer:

Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat.

Answer:

Explanation:

Radiant energy is a type of kinetic energy, referring to energy that travels by waves or particles. The energy is created through electromagnetic waves and is most commonly experienced by humans in the form of heat. Radio signals: Similar to x-rays, radio waves also travel in the form of waves.

Answer:

A.Radio waves

Explanation:

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

44e

Answer:

= weather

Explanation:

Answer:

The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.

Explanation:

A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.

Let us find the drag force which is proportional to the velocity of two conducting plates.

The EMF that is induced in the eddy currents are : [tex]$E=v(B \times L)$[/tex]

The force which is due to the induced magnetic field is, [tex]$F=l(L \times B)$[/tex]

Therefore, [tex]$F=\frac{E}{R} \times (L \times B)$[/tex]

                 [tex]$F=\frac{v(B \times L)}{R} \times (L \times B)$[/tex]

Here, force is directly proportional to the velocity of the two conducting plates.

Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.  

Answer:

C .energy from the sun, carbon dioxide in the air, water

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Answer:

the average acceleration is 8.8 m/s^2

Explanation:

The computation of the average acceleration is shown below;

As we know that

a = (v − u) ÷ t

where

a denotes average acceleration

v denotes the speed at the bottom of the slope

u denotes the speed at down the slop

t denotes time

= (25 - 3) ÷ 2.5

= 8.8 m/s^2

hence, the average acceleration is 8.8 m/s^2

Could you please provide the options? :)

Answer:1.. true 2 false

Explanation:

The sound of heavy street traffic is 100 times louder than the sound of normal conversation.

Street traffic is the movement of vehicles and pedestrians in a designated public space, such as a street or alley. Traffic is generally regulated by signs, signals, and lane markings. It is important to obey these rules, as they are intended to keep pedestrians and drivers safe. Street traffic can involve many types of vehicles, including cars, buses, motorcycles, bicycles, and trucks.

The sound of heavy street traffic is 60dB, while the sound of normal conversation is 40dB. This means the sound of the heavy street traffic is 20dB louder than the sound of a normal conversation. To calculate the difference in loudness, we need to take the difference in decibels and raise it to the power 10. This means that the sound of heavy street traffic is 100 times louder than the sound of normal conversation.

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decreased 5 times

Explanation: if the force increases 5 times between them would decrease 5 times

Convection is the primary mode of heat transfer in liquids and gases.

The correct answer is option C.

Convection is a process of heat transfer that occurs in fluids (liquids and gases) due to the movement of the fluid itself. It involves the transfer of heat energy through the bulk movement of the fluid particles. This mechanism is different from conduction, which is the direct transfer of heat through molecular collisions, and radiation, which is the transfer of heat through electromagnetic waves.

In the case of liquids and gases, convection occurs when a temperature difference exists within the fluid. The heated regions of the fluid become less dense and rise, while the cooler regions sink. This creates a continuous circulation of the fluid, known as convection currents, which transfer heat from one location to another.

Option A, Gas and vacuum, does not involve the presence of a fluid medium, so convection cannot occur. In a vacuum, heat transfer primarily occurs through radiation. Option B, Solid and liquid, includes the possibility of conduction in solids but not convection. Option D, Solid and vacuum, does not involve any fluid medium, so convection is not applicable.

Therefore, option C, Liquid and gas, is the correct choice where convection is the main type of heat transfer. In liquids and gases, convection plays a significant role in heat transfer processes, such as the movement of heat in boiling water, air currents in a room, and oceanic circulation patterns.

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Answer:

the object absorbs all light except for red. the red light is reflected back into your eyes, which is why it looks red.