1. Correct to the nearest millimetre, the length of a side of a regular hexagon is 3.6 cm. Calculate the upper bound for the perimeter of the regular hexagon.

2. Kelly runs a distance of 100 metres in a time of 10.52 seconds.
The distance of 100 metres was measured to the nearest metre.

The time of 10.52 seconds was measured to the nearest hundredth of a second.

(d) Calculate the lower bound for Kelly’s average speed. Write down all the figures on your calculator display.

3. Steve measured the length and the width of a rectangle.
He measured the length to be 645 mm correct to the nearest 5 mm.
He measured the width to be 400 mm correct to the nearest 5 mm.

Calculate the lower bound for the area of this rectangle.
Give your answer correct to 3 significant figures.

4. The length of the rectangle is 35 cm correct to the nearest cm.
The width of the rectangle is 26 cm correct to the nearest cm.

Calculate the upper bound for the area of the rectangle.
Write down all the figures on your calculator display.​

Answers

Answer 1

1. The upper bound for the perimeter of the regular hexagon is 21.9 cm.

2. All figures on the calculator display for the calculation of Kelly's average speed is: 99.5 / 10.51 = 9.46717412

3. the lower bound for the area of the rectangle is 2.55 × 10⁵ mm²

4. Upper bound for area = 937.6525 cm²

How to calculate the perimeter of the hexagon

1. The upper bound for the perimeter of the regular hexagon can be calculated by multiplying the length of one side by 6 (the number of sides in a hexagon):

Upper bound for perimeter = 6 × (3.6 + 0.05) = 21.9 cm (rounded to one decimal place)

2. Kelly's average speed can be calculated by dividing the distance she ran by the time she took:

Average speed = distance / time

The lower bound for the distance is 99.5 m (since 100 m was measured to the nearest meter, the actual distance could be as low as 99.5 m).

The lower bound for the time is 10.51 s (since 10.52 s was measured to the nearest hundredth of a second, the actual time could be as low as 10.51 s).

Therefore, the lower bound for Kelly's average speed is:

Average speed = 99.5 / 10.51 = 9.4617 m/s (rounded to 4 decimal places)

3. The length of the rectangle is 645 mm correct to the nearest 5 mm, which means it could be as small as 642.5 mm or as large as 647.5 mm. We can express this as:

645 mm ± 2.5 mm, similarly

400 mm ± 2.5 mm

Lower bound for length = 645 - 2.5 = 642.5 mm

Lower bound for width = 400 - 2.5 = 397.5 mm

Lower bound for area = 642.5 × 397.5 = 255393.75 mm²

Rounded to 3 significant figures, the lower bound for the area of the rectangle is 2.55 × 10⁵ mm².

4. To calculate the upper bound for the area of the rectangle, we need to multiply the upper bounds for the length and width of the rectangle:

Upper bound for length = 35 + 0.45 = 35.45 cm

Upper bound for width = 26 + 0.45 = 26.45 cm

Upper bound for area = 35.45 × 26.45 = 937.6525 cm²

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Related Questions

Line A (y= 2x+4) is transformed into Line B(y=x-9) Which best describes the new slope and y-intercept?


The slope is __ and the line is shifted ___

complete the blanks

Answers

The line is 13 units to the right (or shifted by -13 units).

What is an equation?

A mathematical statement known as an equation consists of two algebraic expressions separated by equal signs (=) on either side.

It demonstrates the equality of the relationship between the printed statements on the left and right.

Left side equals right side in all formulas.

To find the values of unknowable variables, which stand in for unknowable quantities, you can solve equations.

A statement is not an equation if it lacks the equals sign.

When two expressions have the same value, a mathematical statement known as an equation will include the symbol "equal to" between them.

According to our question-

The ratio of y to x, which indicates how many units change in y when a specific number of units change in x, is used to express a line's slope.

A has a slope of 2 (x factor) = 2/1.

and as a result, y moves 2 units while x moves 1 unit.

B has a slope of 1 = 1/1.

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2. A boat traveling at 30 miles per hour with a tow line of 400 feet will give a parasail rider a height of 300 feet.
a) Draw and label a diagram to represent this situation. (2 points)
b) What is the angle of elevation from the boat to the parasail rider? (5 points)
c) What is the horizontal distance from the parasail rider to the boat? (5 points)
d) What do you notice about the angle of elevation of this flight compared to the. anale of elevation of the flight described in Exercise 1? Use trigonometric functions to explain wny this is true. (10 points)
e) What conclusion can you draw about angles of elevation for parasailing boats traveling at the same speed? (10 points)2. A boat traveling at 30 miles per hour with a tow line of 400 feet will give a parasail rider a height of 300 feet.
a) Draw and label a diagram to represent this situation. (2 points)
b) What is the angle of elevation from the boat to the parasail rider? (5 points)
c) What is the horizontal distance from the parasail rider to the boat? (5 points)
d) What do you notice about the angle of elevation of this flight compared to the. anale of elevation of the flight described in Exercise 1? Use trigonometric functions to explain wny this is true. (10 points)
e) What conclusion can you draw about angles of elevation for parasailing boats traveling at the same speed? (10 points)

Answers

The angle of elevation is approximately 36.87 degrees and the horizontal distance is 264.6 feet

What is the angle of elevation from the boat to the parasail rider

a.

The diagram is attached below;

b. We can use the tangent function to find the angle of elevation:

tan(θ) = opposite / adjacent

tan(θ) = 300 / 400

tan(θ) = 0.75

θ = tan^(-1)(0.75)

θ ≈ 36.87 degrees

So the angle of elevation from the boat to the parasail rider is approximately 36.87 degrees.

c. We can use the Pythagorean theorem to find the horizontal distance from the parasail rider to the boat:

d = √(400^2 - 300^2)

d ≈ 264.6 feet

So the horizontal distance from the parasail rider to the boat is approximately 265 feet.

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Which algebraic expression is equivalent to the expression below? 6(9 + 5x) + 14 A. 30x - 68 B. 30x + 68 C. 30x + 40 D. 5x + 68

Answers

Answer:

[tex]30x +68[/tex]

Step-by-step explanation:

[tex]6(9+5x)+14[/tex]

[tex]\text{Distribute the 6}[/tex]

[tex]30x +68[/tex]

4x+3y=21 and 4x+2y=16

Solve the simentaneous equations

Answers

the solution (x = 3/2, y = 5) satisfies both equations, and therefore it is the correct solution.

We can solve this system of equations using either substitution or elimination method.

Using substitution method:

From the second equation, we can solve for x in terms of y:

4x + 2y = 16

4x = 16 - 2y

x = 4 - (1/2)y

Substitute this expression for x into the first equation:

4x + 3y = 21

4(4 - (1/2)y) + 3y = 21

16 - 2y + 3y = 21

y = 5

Now, substitute y = 5 into either of the original equations to solve for x:

4x + 2y = 16

4x + 2(5) = 16

4x + 10 = 16

4x = 6

x = 3/2

Therefore, the solution to is x = 3/2 and y = 5.

We can check this solution by substituting x = 3/2 and y = 5 into both equations:

4x + 3y = 21

4(3/2) + 3(5) = 6 + 15 = 21

and 4x + 2y = 16

4(3/2) + 2(5) = 6 + 10 = 16

So the solution (x = 3/2, y = 5) satisfies both equations, and therefore it is the correct solution.

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Helen is about to ride a straight water slide. The launching platform is at the top of a tower that is 21 feet tall. The splash pool at the end of the slide is 72 feet from the base of the tower. How long is the water slide itself?
feet=​

Answers

The length of the slide itself in feet would be = 75 ft.

How to calculate the length of the water slide?

To calculate the length of the water slide the Pythagorean formula should be used which is written as follows;

C² = a² + b²

a = length of the tower = 21 ft

b = distance from the base of the tower = 72ft

C = length of the water slide = ?

c² = 21²+72²

C² = 441 + 5184

c² = 5625

C = √5625

C = 75 ft

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face A
2cm
20%
face B
2cm
Both watch faces are circular with radius 2cm.
The materials used to make both watch faces have the same thickness.
A is made entirely of plastic.
B has a 20° sector of metal and à 340° sector of plastic.
The ratio of the cost per cm² of the metal to the cost per cm² of the plastic is 3:2
Work out the ratio of the cost of the materials for A to the cost of the materials for B.
Give your answer in its simplest form.
You must show all your working.

Answers

Therefore , the solution of the given problem of ratio comes out to be  8:17 .

Describe ratio.

The simple formula "a / b," where "b" may be greater than zero, can be used to determine a group of integers "a" and "b" that appear to be equal. Two ratios are combined to form a ratio. If there were only one man and three ladies, the fraction would be 1:1. In the group, there are 3/4 women and 1/4 males. Parts can be a division between things, a figure, or a particular percentage of a component's volume.

Here,

Let x be the price of plastic per square centimetre used to create visage A.

Consequently, the price of the components for aspect A is:

=> 4πx

The metal sector's size on face B is:

=>  (20/360)π(2cm)² = (1/9)π cm²

The plastic sector's size on face B is:

=>  (340/360)π(2cm)² = (17/9)π cm²

Face B's entire surface size is:

=>  (1/9)π + (17/9)π = 2π cm²

Let y be the plastic's expense per square centimetre used to create face B.

Consequently, the price per cm2 of the metal used to create face B is three and a half times the price per cm2 of the plastic, leading to:

=> (3/2)y = (3/2)(2x) = 3x

The material cost for the metal section on face B is inversely correlated with its area, so:

=>  (1/9)π(3x)

The price of the plastic used in the section on face B is inversely proportional to its area, so:

=>  (17/9)πy

=> 8πx : 17πy = 8 : 17

The response is 8:17,

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In a school of 145 students, each was asked to choose one or more activities from sport, music and drama. 76 students choosr sport, 64 chose music and 40 students chose drama. 12 students chose both music and sport, 7 chose both sport and drama, and 21 chose both music and drama. How many students chose all three activities?​

Answers

7 number of  students chose all three activities.

To find out how many students chose all three activities, we need to subtract the number of students who chose two activities from the total number of students. There are 76 students who chose sport, 64 students who chose music, and 40 students who chose drama. 12 students chose both music and sport, 7 chose both sport and drama, and 21 chose both music and drama. We can subtract these two-activity choosers from the total number of students to find out how many chose all three activities: 145 - (12 + 7 + 21) = 105. Therefore, 7 students chose all three activities.

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Last night, while on patrol, Agent 008 came upon a spaceship! He hid behind a tree and watched a group of little space
creatures carry all sorts of equipment out of the ship. But suddenly, he sneezed. The creatures jumped back into their
ship and sped off into the night. 008 noticed that they had dropped something, so he went to pick it up. It was a
calculator! What a great find. He noticed that it had a LOG button, but he noticed something interesting: log 10 did
not equal 1! With this calculator, log 10≈ 0.926628408. He tried some more: log 100≈ 1.853256816 and
log 1000 2.779885224.

a. What base do the space creatures work in? Explain how you can tell.

b. How many fingers do you think the space creatures have?

Answers

(A) The basis in which the space work is done is around 2. The powers of 10's logarithmic values can be used to determine this. (b) They could have two fingers for each hand, giving infants a total of five fingers.

What is the purpose of logarithmic?

a. The space creatures are most likely employed in a base other than base 10. The values of log 10, log 100, and log 1000 do not match the expected values for base 10, which should be 1, 2, and 3, respectively. Instead, the values given indicate that the base is slightly less than ten, because log 10 is less than one, log 100 is less than two, and log 1000 is less than three.

To be more specific, using the calculator's approximation, we can use the change of base formula to find the value of log base b for each of these numbers:

log base b of 10 = log 10 / log b ≈ 0.926628408

log base b of 100 = log 100 / log b ≈ 1.853256816

log base b of 1000 = log 1000 / log b ≈ 2.779885224

By dividing the known values of log 10, log 100, and log 1000, we can find log b:

0.473606797 log b = log 1000 / log 100

As a result, the space creatures are most likely based on 9.526.

b. It is impossible to determine how many fingers the space creatures have based solely on the calculator information and logarithm values. The space creatures' base could be related to the number of fingers they have, but we don't have enough information to tell.

The inverses of exponential functions, or those that "undo," the exponential functions, are the logarithmic functions.

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Premise: All multiples of 9 are multiples of 3. Premise: 57 is a multiple of 3. Conclusion: 57 is a multiple of 9.

Answers

Answer:

The conclusion is false.

Step-by-step explanation:

[tex]\frac{57}{3} = 19\\\\\frac{9}{3} = 3[/tex]

Although 3 and 9 do share some multiples, they must be divisible by 3. For example. 36/3 = 12, and 12 is divisible by 3. However, 57/3 = 19, which is not divisible by 3.

Please helppp!!!!!!!!!!!!

Answers

The length of the arc of the sector is approximately 34.6 millimeters when rounded to one decimal place.

What is angle ?

An angle is a geometric figure formed by two rays that share a common endpoint, called the vertex of the angle. The rays are often referred to as the sides of the angle. Angles are typically measured in degrees or radians and are used to describe the amount of turn between two lines or surfaces.

In a circle, the measure of the arc of a sector is proportional to the measure of the central angle that it subtends. Therefore, to find the length of the arc of the sector in this problem, we need to first find the measure of the central angle that corresponds to the inscribed angle of 312 degrees.

The measure of the central angle is equal to twice the measure of the inscribed angle, which is 312/2 = 156 degrees. This is because the inscribed angle subtends an arc that is half as long as the arc subtended by the central angle.

The length of the arc of the sector can be calculated using the formula:

arc length = (central angle / 360 degrees) x (2 x pi x radius)

Plugging in the values we have:

arc length = (156/360) x (2 x pi x 4mm)

arc length = (13/30) x (8pi)

arc length = (104/30) x pi

arc length ≈ 34.557mm

Therefore, the length of the arc of the sector is approximately 34.6 millimeters when rounded to one decimal place.

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(-2,-9), m= -7/5 write an equation in point slope form for the line that passes through each point with the given slope, then graph the equation.

Answers

The line passes through the two points (-2,-9) and (3,-16).

We can write an equation in point-slope form using the following formula for the line passing through the point (-2,-9) and having a slope of m = -7/5:

y - y1 = m(x - x1)

where m is the slope of the line and (x1,y1) is the line's point.

Inputting the values provided yields:

y - (-9) = (-7/5)(x - (-2))

Simplifying:

y + 9 = (-7/5)(x + 2)

To get rid of the fraction, multiply both sides by 5. This gives us:

5y + 45 = -7(x + 2)

As we enlarge and rearrange, we obtain:

7x + 5y + 59 = 0

This is the line's standard form equation.

We can locate two points on the line and plot them to create a graph of the line. We can utilise the y-intercept, which is obtained by solving for y while setting x=0 in the equation:

7(0) + 5y + 59 = 0

5y = -59

y = -59/5

The y-intercept is therefore (0,-59/5). Using the slope, we may also locate a different point on the line:

m = -7/5

Beginning at (-2,-9), we can travel 7 units left and 5 units right to reach a different point:

(-2+5, -9-7) = (3, -16) (3, -16)

Hence, the line traverses both of the following two points: (3,-16).

Here is the line's graph:

     |

     |

*    |

 \   |

  \  |

   \ |

    \|

-------*-----------------

     |

    3|

     |

    2|

     |

    1|

     |

     |

     |

     |

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The answer is:

[tex]\sf{y+9=-\dfrac{7}{5}(x+2)}[/tex]

Work/explanation:

We need to determine the line's equation.  I will begin by writing the equation in point slope form:

[tex]\mapsto\phantom{333}\sf{y-y_1=m(x-x_1)}[/tex]

where m = slope and (x₁,y₁) is the point

Plug in the data:

[tex]\sf{y-(-9)=-\dfrac{7}{5}(x-(-2)}[/tex]

Simplify

[tex]\sf{y+9=-\dfrac{7}{5}(x+2)}[/tex]

Hence, this is the equation.

try
(x
-2y = 16)
(- 6x +5y =-26)
x
-2y = 16
-6x +5y = -26
=
0 |xo|y=

Answers

Answer: I belive the answer is 0lxoly+39.56

Step-by-step explanation:

SIKE

Which value represents a percentage between 11% and 17%?

F. 0.159
G. 0.013
H. 11/1,000
J. 6/100

Answers

Therefore , the solution of the given problem of percentage comes out to be F. 0.159.

Percentage : What is it?

A% is a figure or integer that in statistics is shown as a percentage of 100. Additionally, the words "pct.," "pct.," and "pc" are rarely used. But even so, the "%" indicator is commonly used to denote it. There are no dimensions; the percentage total is flat. Percentages are really just numbers because the numerator is always 100. To indicate that a number is a percentage, either the percent mark (%) or the phrase "percent" must appear before the number.

Here,

Divide by 100 to transform a percentage to a decimal. Therefore, we must locate a decimal between 0.11 and 0.17 in order to determine the figure that corresponds to a percentage between 11% and 17%.

The choices are as follows:

=> F. 0.159

=> G. 0.013

=> H. 11/1,000

=> J. 6/100

The decimal 0.159 falls within this range (0.11 to 0.17), so the solution is F. 0.159.

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Painters painted half of a wall yellow, their boss told them it was supposed to be painted red, they waited for it to dry and then started covering the yellow with red. At the end of the day, 5/6 of the yellow was painted red, how much of the whole wall had been painted red. ​

Answers

Answer: 1/6

Step-by-step explanation:

1/1 - 5/6

2    6-5/6

2    1/6

if anyone could help, would be much appreciated

Answers

[tex]g( \sqrt{55} ) = ( \sqrt{55} ) {}^{2} + 11 = 55 + 11 = 66[/tex]

[tex]f(g(55)) = f(66) = \sqrt{66 - 2} = \sqrt{64} = 8[/tex]

The value of the function f(g(√55)) is 3√7.

What is Function?

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).

We have the function:

f(x) = √ (x - 2)

and, g(x) = x² + 11.

As, g(√55)

= (√55)² + 11

= 55 + 11

= 66

So, f(g(√55))

= √ (65 - 2)

= √63

= 3√7

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(7.2 x 1017) x (7.5 x 10-9 X (3.6 x 10-8) x (2.5 x 1010) X

Answers

Answer:

Step-by-step explanation:

483278.4

On a scale drawing of a dock for a marina, 1 inch equals 18 feet. The dock is 250 feet long. What is the length of the dock on the scale drawing?

Answers

The length of the dock on the scale drawing would be 13.89 inches (250/18 = 13.89).

On a scale drawing of a dock for a marina, 1 inch equals 18 feet. This means that for every inch on the scale drawing, it represents 18 feet in reality. The dock is 250 feet long. To calculate the length of the dock on the scale drawing, divide 250 by 18. This gives the result of 13.89. This means that the length of the dock on the scale drawing is 13.89 inches. This is because for every inch on the scale drawing, it represents 18 feet in reality. Therefore, the length of the dock on the scale drawing is 13.89 inches (250/18 = 13.89). To ensure accuracy, the calculation should be double checked. This can be done by multiplying 13.89 by 18 which should give the result of 250. This confirms that the length of the dock on the scale drawing is 13.89 inches.

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Write a standard form quadratic equation with -2 and 3 as solutions

Answers

x² - x - 6 = 0 is the standard form quadratic equation with solutions of -2 and 3.

A quadratic equation with two solutions is what?

There are two roots—or solutions—to a quadratic equation with real or complex coefficients. These two possibilities may or may not be distinct, and they may or may not be true. The standard quadratic equation, Y=x2x6, can be solved using the set of solutions 2, 3, which are given.

The elements of a quadratic equation whose solutions are -2 and 3 are (x + 2) and (3, respectively) (x - 3).

The total value of the quadratic equation is 0.

We can add the two elements together to obtain the quadratic equation in standard form:

(x + 2) (x - 3) = x²-3x+2x-6

Simplifying this expression, we get:

x²- x - 6 = 0

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lighthouse sits at the edge of a cliff, as shown. A ship at sea level is 825 meters from the base of the cliff. The angle of elevation from sea level to the base of
he lighthouse is 37.2". The angle of elevation from sea level to the top of the lighthouse is 38.3°. Find the height of the lighthouse from the top of the cliff.
Do not round any intermediate computations. Round your answer to the nearest tenth.
Note that the figure below is not drawn to scale.

Answers

The height of the lighthouse from the top of the cliff is given as 25.3 cm

How to solve for the height

tan 37.2 = h / 825

h = 825 * 0.7590

h = 626.209

tan 38.3 = 626.209 + a / 825

825 tan 38.3 = 626.209 + a

651.55 = 626.209 + a

a = 651.55 - 626.209

a = 25 . 33 meters

Hence we can say that the height of the  lighthouse from the top of the cliff is given as 25 . 33 meters

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Simplify this expression
Show you work using the CER strategy.

4(8x + 1)-6(1-8x)

Answers

I do believe this is the CER strategy, but if not, I’m sorry.

1. Multiply the numbers outside the parentheses with the numbers inside the parentheses. That would give you 32x+4-6+48x.

2. Merge like terms, which would give you 80x-2.

3. Unless your given the value for X, the answer is 80x-2.

A 3-gallon container of laundry detergent costs $53.76. What is the price per cup?

Answers

There are 16 cups in 1 gallon
53.76 / 16 = $3.36

Given:

AC‾ \overline{AC}

AC


and

BD‾\overline{BD}

BD


bisect each other.


Prove:

△BEC≅△DEA\triangle BEC \cong \triangle DEA

△BEC≅△DEA.

Answers

As a result of angle-angle-side (AAS) alignment, we have ABO, DBO, and AEO, CEO.

To prove △BEC≅△DEA:

First, we can see that segment AC and segment BD intersect at point O, which is the point of intersection of the angle bisectors of △BED.

Since AC and BD are angle bisectors, they are perpendicular bisectors of each other, so they divide the angles of △BED into congruent angles.

This means that angle ABO is congruent to angle DBO, and angle AEO is congruent to angle CEO.

Since angle ABO and angle AEO are vertical angles, they are congruent.

Similarly, angle DBO and angle CEO are vertical angles, so they are congruent.

Therefore, we have △ABO≅△DBO and △AEO≅△CEO by angle-angle-side (AAS) congruence.

Since BE is common to both triangles, we can conclude that △BEC≅△DEA by side-angle-side (SAS) congruence.

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I need to know how to find the x,y, and z

Answers

Answer:

x =~ 31.2

y =~ 18

z =~ 9

Step-by-step explanation:

cos 30º = 27 / x

0.8660 = 27 / x

x = 27 / 0.8660

x =~ 31.18

w = height (smaller trinagle w, y, z)

tg 30º = w / 27

0.5774 = w / 27

w = 27 * 0.5774

w = 15.5898

tg 30º = z / 15.5898

0.5774 = z / 15.5898

z = 0.5774 * 15.5898

z = 9.00155052

cos 30º = 15.5898 / y

0.8660 = 15.5898 / y

y = 15.5898 / 0.8660

y =~ 18

Error Analysis Adding and subtracting fractions

Answers

In addition of fractions together student added the denominators together, which is the error in solution. You must have like denominators in order to add fractions together is the strategy for solution. Haley bought 7/8 pound of cheese.

We have a incorrect solution of problem consists addition and subtraction fractions. We have to identify error and solve problem correctly and also share a strategy for solution. Now the problem is defined as : Quantity of mozzarella cheese bought by Haley = [tex] \frac{3}{8} [/tex] pound

Quantity of parmesan cheese bought by Haley = [tex] \frac{1}{2} [/tex] pound

Total pound of cheese that she did bought = sum of parmesan cheese and mozzarella cheese

= [tex] \frac{3}{8} + \frac{1}{2} [/tex]

Incorrect work:

[tex] \frac{3}{8} + \frac{1}{2} = \frac{4}{10}[/tex] [tex]= \frac{2}{5} [/tex]

Identification and Explain the Error :

In the problem student correctly identified that this was addition of fractions however he was incorrect in solving. When adding fractions together you do not add denominators together.

He also forgot that you must have "like" denominators.

Correct Solution:

[tex] \frac{3}{8} + \frac{1}{2} [/tex]

For addition of fractions, make the same denominator in both of fractions. So, multiply the denominator and numentor in fraction 1/2 by 4.

[tex] = \frac{3}{8} + \frac{1 \times 4}{2\times 4} = \frac{3}{8} + \frac{4}{8} [/tex][tex] =\frac{7}{8} [/tex], which is the required solution.

Strategy: We do not add denominator together ever. You must have like denominators in order to add them together. Hence, Haley bought 7/8 pound of cheese.

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Complete question:

Error Analysis Adding and subtracting fractions :

Read the word problem. Look at the students work and solution. Identify the error and describe it. Solve the problem correctly. Then share a strategy this student could use to prevent the same error in the future. Haley bought 3/8 pound of mozzarella cheese and 1/2 pound of parmesan cheese. How many pound of cheese did she buy?

Incorrect work or solution : 3/8 + 1/2

= 4/10 = 2/5

Haley bought 2/5 pound of cheese.

Is this relationship a direct variation X -3 2 1 y -4 6 4

Answers

the relationship between x and y given by the values (-3, -4), (2, 6), and (1, 4) is not a direct variation.

To determine whether the relationship between x and y is a direct variation, we need to check if y is directly proportional to x. In other words, we need to check if there is a constant of proportionality that relates the two variables.

To do this, we can calculate the ratio of y to x for each pair of corresponding values:

y/x = (-4)/(-3) = 4/2 = 2

y/x = 6/2 = 3

y/x = 4/1 = 4

If y is directly proportional to x, then the ratio of y to x should be the same for all pairs of corresponding values. However, in this case, the ratios are not equal. Therefore, the relationship between x and y is not a direct variation.

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Suppose a normal distribution has a mean of 62 and a standard deviation of
4. What is the probability that a data value is between 55 and 63? Round your
answer to the nearest tenth of a percent.
O A. 55.9%
O B. 56.9%
O C. 53.9%
O D. 54.9%

Answers

Answer:To solve this problem, we need to standardize the values of 55 and 63 to z-scores and then use the standard normal distribution table to find the area between those two z-scores.

The z-score for a value of 55 is:

z = (55 - 62) / 4 = -1.75

The z-score for a value of 63 is:

z = (63 - 62) / 4 = 0.25

Using a standard normal distribution table, we can find that the area to the left of z = -1.75 is 0.0401 and the area to the left of z = 0.25 is 0.5987. Therefore, the area between z = -1.75 and z = 0.25 is:

0.5987 - 0.0401 = 0.5586

To convert this area back to a percentage, we multiply by 100:

0.5586 * 100 ≈ 55.9%

Therefore, the answer is A. 55.9%.

Step-by-step explanation:

PLEASE HELP!! I NEED HELP

Answers

The interval at which he was most likely driving in the city is from point D to point E, due to the lower average velocity.In the interval from point B to point C, the position remained constant, hence he may have stopped for lunch.The average velocity for the whole trip is of 32.86 miles per hour.

What is the relation between velocity, distance and time?

Velocity is given by the change in the distance divided by the change in the time, hence the following equation is built to model the relationship between these three variables:

v = d/t.

The parameters for the trip are given as follows:

Distance of 230 miles.Time of 7 hours.

Hence the velocity is obtained as follows:

230/7 = 32.86 miles per hour.

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The lateral area of the smaller cylinder is 25pi and the lateral area of the larger cylinder is 64pi. If the volume of the smaller cylinder is 150pi, what is the volume of the larger cylinder?

Answers

The volume of the larger cylinder is (25/8)πR³.

What is volume?

Volume is a measure of the amount of space occupied by a three-dimensional object. It is typically measured in units of cubic meters, cubic centimeters, cubic feet.

According to question:

Let's denote the radius and height of the smaller cylinder as r and h, respectively, and the radius and height of the larger cylinder as R and H, respectively.

We know that the lateral area of a cylinder is given by the formula:

Lateral area = 2πrh

Using this formula for the smaller and larger cylinders, we get:

25π = 2πrh

64π = 2πRH

Dividing both sides of the first equation by 2π, we get:

rh = 25/2π

We also know that the following formula determines a cylinder's volume:

Volume = πr²h

Using this formula for the smaller cylinder, we get:

150π = πr²h

Substituting rh = 25/2π from above, we get:

150π = πr²(25/2π)

r² = 12

Taking the square root of both sides, we get:

r = √12 = 2√3

Substituting this value into rh = 25/2π, we get:

h = 25/(2πr) = 25/(4π√3)

Now, we can use the ratio of the lateral areas to find the ratio of the heights:

25π/64π = (2πrh)/(2πRH)

25/64 = rh/RH

25/64 = (2√3)(25)/(4πR)(H)

H = 2hR/r

Finally, we can use the formula for the volume of the larger cylinder to find its volume:

Volume = πR²H

Volume = πR²(2hR/r)

Volume = 2πR³h/r

Substituting the values we found for r, h, and H, we get:

Volume = 2π(R³)(25/(4π√3))/(2√3)

Volume = (25/8)πR³

Therefore, the volume of the larger cylinder is (25/8)πR³.

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in a class of 40 students,18 passed maths,19passed account,16 passed economics,5 passed math and accounts only,6maths only,9accounts only,2account and economics only,if each students offered at least one of the subjects:how many failed in all the subjects. (b) find the percentage number who failed in at least one of economics and mathematics. (c). calculate the probability that a student at random failed?​

Answers

a. The number of students that failed in all subject is 4

b. The percentage of students who failed one of economic and mathematics is 5.2%

c. The probability that a student at random failed is 1/10

What is set?

A set is defined as the collect of item with similarities.

n( of student that passed math only) = 6

n( of students that passed account only) = 9

n( of students that passed economics only) = 16-(4+3+2)

= 16-9 = 7

n ( of student that passed math and account only) = 5

n( of student that passed account and economics only) = 2

n ( of student that passed math and economics only) = 18-(5+3+y) = 6

= 18-8-y = 6

= 10-y = 6

y = 4

n( of students that passed all the three subjects) =19-( 5+2+x) = 9

= 19-7-x = 9

= 12 -x = 9

-x = -3

x = 3

a. Therefore no of student that failed all subject =

6+9+7+5+2+4+3+z = 40

36+z = 40

z = 40-36 = 4

b. Student that failed at least math and economics = 4+9 = 13

= 13/40 × 100 = 5.2%

c. probability that a student at random failed = 4/40 = 1/10

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4)
A basket contains four types of fruits. Cherries, Bananas, Green apples and water melons.
What is the proportion of
a) Cherries? b) green apples?
b) Ratio of water melons to bananas?

Answers

The proportion of green apples can be estimated in the same way: expressions  Green apple proportion = (number of green apples) / (Total number of fruits)

what is expression ?

In mathematics, you can multiply, divide, add, or subtract. An expression is formed as follows: Expression, number, and math operator Numbers, parameters, and functions make up a mathematical expression. It is possible to contrast phrases and expressions. Every mathematical statement that contains variables, numbers, and a mathematical action between them is referred to as an expression. For example, the phrase 4m + 5 is made up of the phrases 4m and 5, as well as the variable m from the provided equation, all separated by the mathematical sign +.

a) Because the basket contains four different types of fruits, the proportion of cherries can be computed as follows:

Cherry proportion = (number of cherries) / (Total number of fruits)

We can't compute the proportion of cherries without knowing how many fruits are in the basket.

b) The proportion of green apples can be estimated in the same way:

Green apple proportion = (number of green apples) / (Total number of fruits)

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