Answer: B) 46.7% Si and 53.3% O
Explanation:
To calculate the mass percent of element in a given compound, we use the formula:
[tex]\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{total mass}}\times 100\%[/tex]
Mass of quartz [tex](SiO_2)[/tex] = 5.05 g
Mass of silicon = 2.36 g
Mass of oxygen = Mass of quartz [tex](SiO_2)[/tex] - mass of silicon = 5.05g - 2.36 g = 2.69 g
[tex]\text{Mass percent of silicon}=\frac{\text{Mass of silicon}}{\text{total mass of quartz}}\times 100=\frac{2.36}{5.05}\times 100=46.7\%[/tex]
[tex]\text{Mass percent of oxygen}=\frac{\text{Mass of oxygen}}{\text{total mass of quartz}}\times 100=\frac{2.69}{5.05}\times 100=53.3\%[/tex]
Thus the percentages of silicon and oxygen in quartz are B) 46.7% Si and 53.3% O
The mass percent of silicon in quartz has been 46.7%, and the mass percent of oxygen has been 53.3%. Thus, option B is correct.
Mass percent can be described as the percent composition of an element in a chemical compound. Percent of element can be given as:
Percent mass = [tex]\rm \dfrac{Mass\;of\;element}{Mass\;of\;sample}\;\times\;100[/tex]
The mass of silicon in the sample has been = 2.36 grams
The total mass of sample = 5.05 grams.
The percent mass of silicon can be given as:
Percent mass of silicon = [tex]\rm \dfrac{2.36}{5.05}\;\times\;100[/tex]
Percent mass of silicon = 46.7%
The compound has been composed of silicon and oxygen. Thus, the mass percent of quartz can be given as:
100% Quartz = %Silicon + % Oxygen
100% Quartz = 46.7% + % Oxygen
The mass % of oxygen = 100 - 46.7%
The mass % of oxygen = 53.3%
The mass percent of silicon in quartz has been 46.7%, and the mass percent of oxygen has been 53.3%. Thus, option B is correct.
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How does the carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere?
Answer:
The calculator add the CO2 released from the use of electricity, released from driving and the CO2 from the waste that we disposed.
Explanation:
The carbon dioxide, CO2 is what the human body does not need, therefore, we breathe it out, hence taking in oxygen(respiration process). The plants need oxygen for the production of their own food.
The carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere through the consideration of several factors such as the kind of food that we eat.
Therefore, if we are to use the carbon calculator to determine the amount of CO2 that each individual releases into the atmosphere we will have:
The amount of CO2 that each individual releases into the atmosphere =( CO2 released from the use of electricity) + (CO2 released from driving) + (the CO2 from the waste that we disposed).
Chemistry question. Image attached.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Explanation:
If a neutral acid donates a proton, the conjugate base will have a charge of _______. - Type both an integer and a sign for your answer.
Answer:
-1
Explanation:
If you donate a proton (positive charge) then the result will leave a negative charge. (a negative and positive charge result In a neutral charge)
The answer is -1
Now if i have an acid such as H2SO4. Recall that the neutral acid is dibasic as you cam see from the formula of the acid, the acid can give out a proton as follows;
[tex]H2SO4 ------> H^+ + HSO4^-[/tex]
We can see that the conjugate base (HSO4-) has a charge of -1 as written in the answer.
The same also happens for a monobasic acid and so on.
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Calculate the combustion of gaseous dimethyl ether CH 3 OCH 3 (g)+3O 2 (g) 2CO 2 (g)+3H 2 O(l) using standard molar enthalpies of formation Molecule AH H l ^ 0 (k)/mol) CH 3 OCH 3 (g) - 184.1
Answer:
[tex]\Delta _cH=-1328.3kJ/mol[/tex]
Explanation:
Helllo,
In this case, for the given chemical reaction in gaseous state:
[tex]CH_3OCH_3+3O_2\rightarrow 2CO_2+3H_2O[/tex]
We comoute the combustion enthalpy as the reaction enthalpy for one mole of fuel (dimethyl ether) considering the formation enthalpy of each given substance and whether they are reactants (subtracting) or products (adding), therefore we write:
[tex]\Delta _cH=2*\Delta _fH_{CO_2}+3*\Delta _fH_{H_2O}-\Delta _fH_{CH_3OCH_3}-3*\Delta _fH_{O_2}[/tex]
Whereas the formation enthalpies for carbon dioxide, water, dimethyl ether and oxygen are -393.5, -241.8, -184.1 and 0 kJ/mol respectively, thereby, the combustion enthalpy turns out:
[tex]\Delta _cH=2(-393.5)+3*(-241.8)-(-184.1)-3(0)\\\\\Delta _cH=-1328.3kJ/mol[/tex]
Notice that enthalpy of formation of oxygen is zero since forming an element has no chemical sense, it just exists as it has been early demonstrated.
Regards.
1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n):_______.
2. Glyceraldehyde is an example of a(n):_____, because it has three carbon atoms.
3. A monosaccharide is a(n):_______ if the carbonyl group is on the end of the carbon chain.
4. Any carbohydrate with the carbonyl group on the second carbon is a(n):_______.
5. The most common carbohydrate, , has six carbon atoms.
6. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n):_________.
Answer:
Following are the answer to this question:
Explanation:
The answer are:
1) ketopentose
2) Triose
3) Aldose
4) Ketose
5) Glucose
6) Aldohexose
The pentose has 2-position contain a personal ketone group. The triose is a monosaccharide or simple sugar that contains three atoms of carbon. The Aldose and ketose are simple carbohydrates, both also called monosaccharides. In aldose, it has a functional group of aldehydes within its structure. The ketose sugars have workable ketone groups. Stereoisomerism has been found in aldose sugars that contain more than three carbon atoms. Glucose is also one of the main molecules which function as plant and animal energy sources. It's also derived from plant sap and seems to be present in the bloodstream of humans, that's why it is called "blood sugar." The aldohexose is a hexose is a group of aldehydes on one end, it has a total of 16 possible aldohexose stereoisomers in four chiral centers.The molecular weight of table salt, NaCl, is 58.5 g/mol. A tablespoon of salt weighs 6.37 grams. Calculate the number of moles of salt in one tablespoon.
Finally, solve (remember significant figures):
Answer:
0.109 mol/tablespoon
Explanation:
6.37 g/ 58.5 mol = 0.10888888 mol (0.109 significantly)
Answer:
A: 0.109
Explanation:
Edge 2020
The thermochemical equation is for the reaction of hydrogen bromide gas to form hydrogen gas and bromine liquid. 2HBr(g) = H 2 (g)+ Br 2 (l) 72.6 kJ How many grams of HBr (g) would be made to react if 11.4 energy were provided?
Answer:
the mass of HBr that would react is 25.41 g of HBr
Explanation:
attached is the calculations.
What is the shape of a molecule that has 4 atoms bonded to a central atom
and no lone pairs of electrons?
A. Octahedral
B. Cubic
C. Tetrahedral
D. Trigonal-pyramidal
Answer:
C. Tetrahedral
Explanation:
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.
Tetrahedral is the shape of a molecule that has 4 atoms bonded to a central atom and no lone pairs of electrons. Hence, option C is correct.
What is an atom?An atom consists of a central nucleus that is usually surrounded by one or more electrons.
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which mean it has tetra (which translates to four) domains hence tetrahedral.
Hence, option C is correct.
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The compound barium nitrate is a strong electrolyte. Write the transformation that occurs when solid barium nitrate dissolves in water.
Answer:
Ba(NO₃)₂(s) → Ba²⁺ + 2NO₃⁻
Explanation:
A strong electrolyte is a salt (A compound that has an anion and a cation and are neutral) that, in water, dissociates completely in its ions.
In Barium nitrate, Ba(NO₃)₂, the cation is Ba²⁺ (Alkaline earth metal), and the anion is the nitrate ion, NO₃⁻.
Thus, when Ba(NO₃)₂ (s) is dissolved in water, its transformation is:
Ba(NO₃)₂(s) → Ba²⁺ + 2NO₃⁻When solid barium nitrate (Ba(NO₃)₂) dissolves in water, it undergoes a dissociation process where the compound breaks apart into its constituent ions.
Dissociation refers to the process in which a compound breaks apart into its constituent ions when dissolved in a solvent, typically water. In this process, the chemical bonds within the compound are disrupted, resulting in the separation of positive and negative ions.
The dissociation occurs due to the interaction between the solute particles and the solvent molecules, leading to the formation of hydrated ions.
The transformation can be represented as follows:
Ba(NO₃)₂(s) → Ba²⁺(aq) + 2NO₃⁻(aq)
In this process, the barium nitrate compound dissociates into barium ions (Ba²⁺) and nitrate ions (NO₃⁻) in the aqueous solution. The resulting ions are free to move and conduct electricity, indicating that barium nitrate is a strong electrolyte when dissolved in water.
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Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory.
Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),
Answer and Explanation:
1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)
on the other hand
Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.
2. The Chemical name and nature of acid is shown below:-
Nature Chemical Name
a. HCl Acidic Hydrochloric Acid
b. KOH Basic Potassium hydroxide
c. HNO Acidic Nitric Acid
d. Mg(OH)2 Basic Magnesium hydroxide
A transition in the balmer series for hydrogen has an observed wavelength of 434 nm. Use the Rydberg equation below to find the energy level that the transition originated. Transitions in the Balmer series all terminate n=2.
Delta E= -2.178 x10-18J ( 1/n2Final - 1/n2Initial )
The number is 5.
What is the energy of this transition in units of kJ/mole? ( hint: the anser is NOT 4.58x10-22kJ/mole or -4.58x10-22kJ/mole)
Answer:
i. n = 5
ii. ΔE = 7.61 × [tex]10^{-46}[/tex] KJ/mole
Explanation:
1. ΔE = (1/λ) = -2.178 × [tex]10^{-18}[/tex]([tex]\frac{1}{n^{2}_{final} }[/tex] - [tex]\frac{1}{n^{2}_{initial} }[/tex])
(1/434 × [tex]10^{-9}[/tex]) = -2.178 × [tex]10^{-18}[/tex] ([tex]\frac{n^{2}_{initial} - n^{2}_{final} }{n^{2}_{final} n^{2}_{initial} }[/tex])
⇒ 434 × [tex]10^{-9}[/tex] = (1/-2.178 × [tex]10^{-18}[/tex])[tex]\frac{n^{2}_{final} *n^{2}_{initial} }{n^{2}_{initial} - n^{2}_{final} }[/tex]
But, [tex]n_{final}[/tex] = 2
434 × [tex]10^{-9}[/tex] = (1/2.178 × [tex]10^{-18}[/tex])[tex]\frac{2^{2} n^{2}_{initial} }{n^{2}_{initial} - 2^{2} }[/tex]
434 × [tex]10^{-9}[/tex] × 2.178 × [tex]10^{-18}[/tex] = [tex](\frac{4n^{2}_{initial} }{n^{2}_{initial} - 4 })[/tex]
⇒ [tex]n_{initial}[/tex] = 5
Therefore, the initial energy level where transition occurred is from 5.
2. ΔE = hf
= (hc) ÷ λ
= (6.626 × 10−34 × 3.0 × [tex]10^{8}[/tex] ) ÷ (434 × [tex]10^{-9}[/tex])
= (1.9878 × [tex]10^{-25}[/tex]) ÷ (434 × [tex]10^{-9}[/tex])
= 4.58 × [tex]10^{-19}[/tex] J
= 4.58 × [tex]10^{-22}[/tex] KJ
But 1 mole = 6.02×[tex]10^{23}[/tex], then;
energy in KJ/mole = (4.58 × [tex]10^{-22}[/tex] KJ) ÷ (6.02×[tex]10^{23}[/tex])
= 7.61 × [tex]10^{-46}[/tex] KJ/mole
The initial energy level is 5 and the energy of this transition in units of kJ/mole is 7.57 * 10^-43 kJ/mole
We must first calculate ΔE as follows;
ΔE = hc/λ
h = Plank's constant = 6.6 * 10^-34 Js
c = speed of light = 3 * 10^8 m/s
λ = wavelength = 434 * 10^-9
ΔE = 6.6 * 10^-34 * 3 * 10^8/434 * 10^-9
ΔE = 0.0456 * 10^-17 J
ΔE = [tex]ΔE = -2.178 x10^-18 (\frac{1}{n^2final} - \frac{1}{n^2initial}) \\ΔE = -2.178 x10^-18 (\frac{1}{2^2} - \frac{1}{n^2initial} )\\\\4.56 * 10^-19/2.178 x10^-18 = (\frac{1}{2^2} - \frac{1}{n^2initial})\\0.210 = (\frac{1}{2^2} - \frac{1}{n^2initial})\\\frac{1}{n^2initial} = 0.25 - 0.210\\\frac{1}{n^2final} = 0.04\\n = (\sqrt{(0.04)^-1} \\n = 5[/tex]
Energy of this transition in units of kJ/mole = 4.56 * 10^-19/ 6.02 * 10^23
= 7.57 * 10^-43 kJ/mole
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Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without re-arrangement give 2-butanol as the major product.
Answer:
See explanation
Explanation:
Hydration of alkenes is a common reaction in organic chemistry. Hydration is simply the addition of water to an alkene. This is an acid catalysed reaction as we can see from the mechanism attached.
Recall that our task is to carry out the synthesis of 2-butanol using an alkene starting material in which there will be no rearrangement of the intermediate carbocation. If we start with the compound shown in the image (but-2-ene), the first step is the formation of the secondary carbocation. This is followed by the addition of water. Subsequently, the added water is deprotonated by another water molecule to yield 2-butanol and the acid catalyst. All these steps have been clearly outlined in the image attached.
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
[Afus H° = 6.01 kJ/mol H2O(s)]
Answer:
[tex]m=33.9g[/tex]
Explanation:
Hello,
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J[/tex]
Afterwards, the mass of ice that can be melted is computed by:
[tex]Q=n \Delta _{fus}H[/tex]
So we solve for moles with the proper units handling:
[tex]n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol[/tex]
Finally, with the molar mass of water we compute the mass:
[tex]m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g[/tex]
Best regards.
mass=33.9g
Given:
n= 3.00 mol
Δfus H° = 6.01 kJ/mol H₂O(s)
Enthalpy of fusion is the change in its enthalpy resulting from providing energy, typically heat, to a specific quantity of the substance to change its state from a solid to a liquid, at constant pressure.
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nC_P[/tex]ΔT
[tex]Q=3.00\text{mol}*75.38\frac{J}{mol^oC} *50.0^oC\\\\Q=11307J[/tex]
Now, the mass of ice that can be melted is given by:
Q=nΔfus H°
So we solve for moles with the proper units handling:
n= Q/ Δfus H°
[tex]n=\frac{11307 J}{6010\frac{J}{mol} } =1.88 mol[/tex]
On substituting the moles with the molar mass of water we get:
[tex]m=1.88 mol*\frac{18 g}{1mol}\\\\m=33.9g[/tex]
The mass of ice is 33.9g.
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How many valence electrons are in the electron dot structures for the elements in group 3A(13)?
Answer:
here, as we have known the elements of group 3A(13) such as aluminium , boron has three valance electron and in perodic table the elements are kept with similar proterties in same place so, their valance electron is 3.
hope it helps...
The number of valence electrons are in the electron dot structures for the elements in group 3A(13) is three.
What are Groups in the Periodic Table?The periodic table is organized into groups (vertical columns), periods (horizontal rows), and families (groups of elements that are similar). Elements in the same group have the same number of valence electrons.
Groups are the columns of the periodic table, and periods are the rows. There are 18 groups, and there are 7 periods plus the lanthanides and actinides.
There are two different numbering systems that are commonly used to designate groups, and you should be familiar with both.
The traditional system used in the United States involves the use of the letters A and B. The first two groups are 1A and 2A, while the last six groups are 3A through 8A. The middle groups use B in their titles.
Therefore, The number of valence electrons are in the electron dot structures for the elements in group 3A(13) is three.
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Which of the following describes green design?
A. Materials that will fail in a predictable and safe way
B. The use of new engineering technologies in building construction
c. Building structures made of composite materials to make them
safer
D. Materials and design techniques that reduce the negative
environmental impact of a structure
Answer: materials and design Techniques that reduce the negative environmental impact of a structure
Explanation:
Calculate the number of moles of C2H6 in 3.97×1023 molecules of C2H6.
3.97×1023 molecules C2H6 1 mol C2H6
------------------------------------------ x ------------------------------------ = 0.66 mol C2H6
6.022 x 1023 molec. C2H6
If the reaction starts with a mixture of PCl5, PCl3 and Cl2 at pressures of 0.820 atm, 1.322 atm and 0.911 atm respectively, is the reaction at equilibrium
Answer:
The reaction is not in equilibrium
Explanation:
For the reaction:
PCl₅ ⇄ PCl₃ + Cl₂
Equilibrium constant, Kp, is defined as:
[tex]Kp = \frac{P_{PCl_3}P_{Cl_2}}{P_{PCl_5}} = 0.497[/tex]
When this ratio is = 0.497, the reaction is in equilibrium. Replacing the pressures of the problem, reaction quotient, Q, is:
[tex]Q =\frac{1.322atm*0.911atm}{0.820atm} = 1.469[/tex]
As Q ≠ Kp, the reaction is not in equilibrium
To reach the equilibrium, the reaction will shift to the left producing more reactant and decreasing amount of products.
Using the thermodynamic information , calculate the standard reaction entropy of the following chemical reaction: Round your answer to zero decimal places.
2Al(s)+ Fe2O3(s) → Al2O3(s)+ 2Fe(s)
Answer:
The answer is "−847 J/K".
Explanation:
The given expression is:
2Al(s)+ Fe2O3(s) → Al2O3(s)+ 2Fe(s)
Δ[tex]H^{\circ}_{rxn}=[/tex] ∑(Δ[tex]H^{\circ}_{products}-H^{\circ}_{reactants}[/tex])
by the above definition Δ[tex]H^{\circ}_{element}= 0\cdot KJ \cdot Mol^{-1}[/tex] For Such a Component under standard conditions from its standard state, that also applies here. But, we start taking the overview and follow the conventions of signing:
[tex]\to (-1669)-(-822) \frac{KJ}{mol}\\\\\to (-1669+822) \frac{KJ}{mol}\\\\\to -847\frac{KJ}{mol}\\\\[/tex]
Δ[tex]H^{\circ}_{rxn}=[/tex] -847 [tex]\frac{KJ}{mol} \ mol^{-1} \texttt{ we mean \mole of Reaction as written....}\\[/tex]
What is the electron geometry and molecular geometry of:
A. H2O
B. CH2CL2
C. OPCL3
D. CO3^2-
E. ALCL6^3-
F. SO2
G. PCL5
Answer:
H2O
Electron geometry-tetrahedral
Molecular geometry bent
CH2Cl2
Electron geometry- tetrahedral
Molecular geometry-tetrahedral
OPCL3
Electron geometry- tetrahedral
Molecular geometry- tetrahedral
CO3^2-
Electron geometry- trigonal planar
Molecular geometry- trigonal planar
ALCL6^3-
Electron geometry-octahedral
Molecular geometry- octahedral
SO2
Electron geometry-tetrahedral
Molecular geometry-bent
PCL5
Electron geometry-trigonal bipyramidal
Molecular geometry- trigonal bipyramidal
Explanation:
Water contains four electron domains this corresponds to a tetrahedral electron geometry. How ever, there are two lone pairs in the molecule hence it is bent.
CH2Cl2 is shows a tetrahedral molecular geometry and a tetrahedral electron geometry. This can only be observed from the structure of the compound.
OPCL3 is bonded to four groups making it a tetrahedral molecule. There are non lone pairs on phosphorus so the molecule is not bent.
CO3^2- is bonded to three groups which leads to a trigonal planar geometry.
ALCL6^3- contains six bonding groups which arrange themselves at the corners of a regular octahedron at a bond angle of 90°.
SO2 has four electron domains leading to a tetrahedral electron domain geometry according to valence shell electron pair repulsion theory. However, the lone pairs on the central atom in the molecule leads to a bent molecular geometry.
PCL5 has five electron domains without lone pairs of electrons on its central atom. Hence the molecule possess a trigonal bipyramidal geometry.
The electron geometry and molecular geometry of the molecule are as follows:
A. H₂O: The electron geometry is tetrahedral because it has four electron domains (two bonding pairs and two lone pairs). However, due to the presence of two lone pairs, the molecular geometry is bent or V-shaped.
B. CH2Cl₂: The electron geometry is tetrahedral. However, the molecular geometry is trigonal planar because two of the electron domains are occupied by chlorine atoms, resulting in a bent shape.
C. OPCl₃: The electron geometry is tetrahedral. However, the molecular geometry is trigonal pyramidal because one of the electron domains is occupied by a lone pair on phosphorus.
D. CO3⁻²: The electron geometry is trigonal planar because it has three electron domains (three single bonds). The molecular geometry is also trigonal planar.
E. AlCl6⁻³: The electron geometry is octahedral because it has six electron domains. The molecular geometry is also octahedral.
F. SO₂: The electron geometry is trigonal planar because it has three electron domains (two single bonds and one lone pair). The molecular geometry is bent or V-shaped due to the presence of a lone pair on sulfur.
G. PCl₅: The electron geometry is trigonal bipyramidal because it has five electron domains. The molecular geometry is also trigonal bipyramidal.
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Write a balanced half-reaction for the reduction of aqueous arsenic acid H3AsO4 to gaseous arsine AsH3 in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Answer:
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Explanation:
Let's consider the half-reaction for the reduction of aqueous arsenic acid to gaseous arsine in a basic aqueous solution.
H₃AsO₄(aq) ⇒ AsH₃(g)
We see that there is an excess of 4 oxygen atoms on the left side. So, we add 4 molecules of water to the left side and 8 hydroxyl ions to the right side.
H₃AsO₄(aq) + 4 H₂O(l) ⇒ AsH₃(g) + 8 OH⁻(aq)
We need to add 8 electrons to the left side to balance the reaction electrically.
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Answer:
[tex]H_3AsO_4(aq)+8H^+(aq)+8e^-=AsH_3(g)+4H_2O(l)[/tex]
Explanation:
Calculate the weight of solid NaOH required to prepare (a) 5 liters of a 2 M solution, (b) 2 liters of a solution of pH 11.5?
i need full solution not just result please
Answer:
A. 400g of NaOH.
B. 0.253g of NaOH.
Explanation:
A. The following data were obtained from the question:
Volume = 5 L
Molarity = 2 M
Mass =..?
Next, we shall determine the number of mole of NaOH. This can be obtain as follow:
Molarity = mole /Volume
2 = mole/5
Cross multiply
Mole = 2 x 5
Mole of NaOH = 10 moles
Finally, we shall convert 10 moles of NaOH to grams. This is illustrated below:
Mole of NaOH = 10 moles
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH =?
Mole = mass /molar mass
10 = mass of NaOH /40
Cross multiply
Mass of NaOH = 10 x 40
Mass of NaOH = 400g
Therefore, 400g of NaOH is needed to prepare the solution.
B. The following data were obtained from the question:
pH = 11.5
Volume = 2 L
Next, we shall determine the pOH of the solution. This can be obtain as shown below:
pH + pOH = 14
pH = 11.5
11.5 + pOH = 14
Collect like terms
pOH = 14 – 11.5
pOH = 2.5
Next, we shall determine the concentration of the hydroxide ion, [OH-] in the solution.
This is illustrated below:
pOH = - Log [OH-]
pOH = 2.5
2.5 = - Log [OH-]
-2.5 = Log [OH-]
Take the antilog of both side
[OH-] = antilog (-2.5)
[OH-] = 3.16×10¯³ M
Next, we shall determine the concentration of NaOH. This is illustrated below:
NaOH —> Na+ + OH-
From the balanced equation above,
1 mole of NaOH produced 1 mole of OH-.
Therefore, 3.16×10¯³ M NaOH will also produce 3.16×10¯³ M OH-.
Therefore, the concentration of NaOH is 3.16×10¯³ M
Next, we shall determine the number of mole of NaOH in the solution. This can be obtain as follow:
Molarity = 3.16×10¯³ M
Volume = 2 L
Mole of NaOH =?
Molarity = mole /Volume
3.16×10¯³ = mole of NaOH / 2
Cross multiply
Mole of NaOH = 3.16×10¯³ x 2
Mole of NaOH = 6.32×10¯³ mole
Finally, we shall convert 6.32×10¯³ mole of NaOH to grams
Mole of NaOH = 6.32×10¯³ mole
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH =?
Mole = mass /molar mass
6.32×10¯³ = mass of NaOH /40
Cross multiply
Mass of NaOH = 6.32×10¯³ x 40
Mass of NaOH =0.253 g
Therefore, 0.253g of NaOH is needed to prepare the solution.
Which of the following atoms would have the longest de Broglie wavelength, if all have the same velocity?
A) Li
B) Na
C) Fe
D) Pb
E) Not possible to tell with given information
Answer:
Li
Explanation:
The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;
λ= h/mv
Where;
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength
The atom that have the longest de Broglie wavelength is ; ( A ) Li
Wave particle duality is a phenomenon by de Broglie. that shows that The wavelength associated with matter waves is related to its mass and velocity .
Wave particle duality is represented as ; λ = h / mv
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
Given that the elements have the same velocity the atom that would have the longest de Broglie wavelength is Li
Learn more : https://brainly.com/question/21537274
What is the atomic mass of OsO4
Answer:
254.23 g/mol
Explanation:
Atomic mass for Osmium tetroxide would be 254.23 g/ml
Answer:254.2276
Explanation:
Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?
boiling
freezing
chromatography
sorting
Answer:
a. boiling
Explanation:
Read the following passage and find the two errors. Then, choose the answer that corrects the errors.
pH is a measure of the concentration of OH ions in a solution of an acid or base. The pH scale plots the concentration of solutions in a range from 0-16.
O pH is a measure of the concentration of Hions in a solution of an acid or base. The pH plots the concentration of solutions in a range from 0-14.
O pH is a measure of the concentration of H* ions in a solution of an acid or base. The basic scale plots the concentration of solutions in a range from 0-16.
O pH is a measure of the concentration of OH" ions in a solution of water. The pH scale plots the concentration of solutions in a range from 0-12
O pH is a measure of the concentration of OH" ions in a solution of an acid or base. The acid scale plots the concentration of solutions in a range from 0-
16
Answer:
pH is a measure of the concentration of H+ ions in a solution of an acid or base. The pH plots the concentration of solutions in a range from 0–14.
Explanation:
The pH is a measure of the hydrogen ion(H^+) concentration in an acid or base. It can be obtained mathematically by the formula:
pH = —Log [H^+]
The pH scale ranges from 0 to 14
Answer:
it really is A
Explanation:
just got wrong answer because i put 16 and clearly b and c makes no sence : )
what phrase best describes the arrangement of these electron groups around the central nitrogen atom
Answer:
the electron groups around the central nitrogen atom is trigonal planar
Explanation:
An electron group is defined as a bond (single or multiple) or/and a non-bonding electron pair around the central atom. The central nitrogen (N) atom in NO3- has three (3) electron groups (three bonds to three oxygen, O atoms).
Three electron groups around a central atom are best arranged in a trigonal planer arrangement to minimize repulsions between the bonding and/or non-bonding electrons. Therefore, the arrangement of the electron groups is trigonal planer or planer trigonal.
Which substance is the oxidizing agent in the following reaction? 2H2 + O2 -> 2H2O
Answer:
O₂
Explanation:
When we create H₂O, the electrons tend to be shared by oxygen. The hydrogen bonds with the oxygen covalently, but the electrons tend to stay with the oxygen longer rather than near the hydrogens.
: Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050-L flask at 668 K, how many moles of Cl2(g) will be present at equilibrium
Answer:
The number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
Explanation:
The reaction is:
CO(g) + Cl₂(g) ⇄ COCl₂(g)
The equilibrium constant of the above reaction is:
K = 1.2x10³
To find the moles of Cl₂ present at equilibrium, let's evaluate the reverse reaction:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
The equilibrium constant for the reverse reaction is:
[tex] K_{r} = \frac{1}{1.2 \cdot 10^{3}} = 8.3 \cdot 10^{-4} [/tex]
Now, we need to calculate the concentration of CO and COCl₂:
[tex] C_{CO} = \frac{\eta_{CO}}{V} = \frac{0.3500 moles}{3.050 L} = 0.115 M [/tex]
[tex] C_{COCl_{2}} = \frac{\eta_{COCl_{2}}}{V} = \frac{0.05500 moles}{3.050 L} = 0.018 M [/tex]
Now, from the reaction we have:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
0.018 - x 0.115+x x
The concentration of Cl₂ is:
[tex] K_{r} = \frac{[CO][Cl_{2}]}{[COCl_{2}]} [/tex]
[tex] 8.3 \cdot 10^{-4} = \frac{(0.115 + x)(x)}{0.018 - x} [/tex]
[tex] 8.3 \cdot 10^{-4}*(0.018 - x) - (0.115 + x)(x) = 0 [/tex]
By solving the above equation for x we have:
x = 1.29x10⁻⁴ M = [Cl₂]
Finally, the number of moles of Cl₂ present at equilibrium is:
[tex] \eta_{Cl_{2}} = C_{Cl_{2}}*V = 1.29 \cdot 10^{-4} mol/L*3.050 L = 3.94 \cdot 10^{-4} moles [/tex]
Therefore, the number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
I hope it helps you!
A constant volume and mass of helium gas at 77°C is heated so that the pressure of the gas doubles. What is the new temperature of the gas in Celsius degrees?
Answer:
427°C .
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial temperature (T1) = 77°C
Initial pressure (P1) = P
Final pressure (P2) = 2P
Final temperature (T2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T (°C) + 273
Initial temperature (T1) = 77°C
Initial temperature (T1) = 77°C+ 273 = 350K
Step 3:
Determination of the new temperature. The new temperature can be obtained as follow:
P1/T1 = P2/T2
P/350 = 2P/T2
Cross multiply
P x T2 = 350 x 2P
Divide both side by P
T2 = (350 x 2P ) / P
T2 = 700K
Step 4:
Conversion of Kelvin temperature to celsius temperature.
This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 700K
T(°C) = 700 – 273
T(°C) = 427°C
Therefore, the new temperature of the gas is 427°C
Calculate the mass of a body
Whose volume is
Is 2cm3 and
density is 520cm3
Answer:
The answer is
1040gExplanation:
Density = mass / volume
mass = density × volume
volume = 2cm³
density = 520g/cm³
mass = 2 × 520
= 1040g
Hope this helps you