02.4) Calculate the charge and give the unit when
a current of 0.15 A flows around the circuit for
20 seconds.
[3 marks)
02.5) Calculate how much energy is transferred from the
battery in 20 seconds. Use your answer from 02.4.
[2 marks]

Answer:

jejeje

Explanation:

jejejejejee

Answer:

-5.6m/s²

Explanation:

Given parameters:

Initial speed  = 11.2m/s

Time of running  = 2s

Unknown:

Acceleration of the puppy  = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

   Acceleration  = [tex]\frac{Final speed - initial speed }{time}[/tex]  

final speed  = 0m/s

 Acceleration  = [tex]\frac{0 - 11.2}{2}[/tex]    = -5.6m/s²

Answer:

The radius of the curve is 9,183.67 m.

Explanation:

Given;

velocity of the jet plane, v = 600 m/s

acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²

The radius of the curve is calculated from centripetal acceleration formula as given below;

[tex]a = \frac{v^2}{r} \\\\r = \frac{v^2}{a} \\\\r = \frac{600^2}{39.2} \\\\r = 9,183.67 \ m[/tex]

Therefore, the radius of the curve is 9,183.67 m.

Answer:

c might be right

Explanation:

c doesn't make any sense. big storms mean more water for flooding, inadequate drainage system means the water can't leave certain areas, I'm not sure what rip currents are tho

Answer:

rip currents

I live in florida, and we don't have mild storms either its big one or none :)

Explanation:

and can you help me please, its 30 points

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^^ there the same question but the first website i misspelt it but its 30 points and the 2nd website is the question written out right but its 5 point but there the same thing you need to do, you can put the same thing for both and get extra point idc, i just need help lease

Answer:

I believe that B is the right one.

Answer:

Dawg

Explanation:

Answer: : it is so because velocity and speed differ each other by direction. in a 100 m sprint race ,the person moves in a straight path without changing its direction where as in a 400 m race , the person moves in a lap around the race track and the direction changes as he turns according to the race track.

Explanation:

Answer:

When the ball falls down.

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

Answer:

To provide mathematical models for describing physical reality.

Answer:

See explanation

Explanation:

Range of a projectile is given by; U^2sin2θ/g

When θ = 45°

The maximum range is obtained as;

Rmax = U^2/g

Maximum range on earth = RME = U^2/g

Maximum range in the moon= RMM =U^2/g/6

Maximum range in Mars = RMMA = U^2/0.38g

a)

RME/RMM =  U^2/g/U^2/g/6

RME/RMM = 6

But RME = 3 m

RMM = 3 * 6 = 18 m

b)

RME/RMMA =U^2/g/U^2/0.38g

RME/RMMA = 1/0.38

But RME = 3 m

RMMA = 3/0.38

RMMA = 7.9 m

Answer:

The answer is B. Circulatory

Answer:

20N

Explanation:

newtons 3rd law every action has an equal opposite reaction

I'm not too sure

Answer:

w1:w2 = 16:1

Explanation:

As we know that ration of amplitude is equal to

[tex]\frac{a_1}{a_2} = \sqrt{\frac{w_1}{w_2} }[/tex]

here w1 and w2 are the widths of the slit.

[tex]\frac{I _{min}}{I_{max}} = \frac{(a_1-a_2)^2}{(a_1+a_2)^2} \\\frac{9}{25} = \frac{(1-\frac{a_2}{a_1} )^2}{(1+\frac{a_2}{a_1} )^2} \\\frac{3}{5} = \frac{(1-\frac{a_2}{a_1} )}{(1+\frac{a_2}{a_1} )}\\8 \frac{a_2}{a_1} = 2\\\frac{a_1}{a_2} = 4[/tex]

Again

[tex]\frac{a_1}{a_2} = \sqrt{\frac{w_1}{w_2} }[/tex]

[tex]4 = \sqrt{\frac{w_1}{w_2} }\\\frac{w_1}{w_2} = 16[/tex]

w1:w2 = 16:1

Answer:

Explanation:

hope this helps!

thermal,true the explanation is because the other guy said so

Answer:

cause by imbalances between stroms cloud and grounds , or within the cloud themselves.

Explanation:

Lightning is an electrical discharge caused by imbalances between storm clouds and the ground, or within the clouds themselves. Most lightning occurs within the clouds. ... This heat causes surrounding air to rapidly expand and vibrate, which creates the pealing thunder we hear a short time after seeing a lightning flash.

The positive and negative charges grow large enough, a giant spark lightning, occurs between the two charges within the cloud.

The naturally occurring electrostatic discharge with high voltage for short duration from the cloud to the ground or within the cloud. The lightning can be seen by a flash of light that could be followed by the strong sound. Lightning happens when the negative charges (electrons) in the bottom of the cloud are attracted to the positive charges (protons) in the ground or within the clouds. In the starting stages air acts as an insulator, but after the  charges build up with the charges in the ground and cloud there will be the rapid form of electricity causes lightning. These lightning were in the color of bluish white.

Thus, the charges discharging naturally causes  lightning.

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Answer:

29 m/s.

Explanation:

Hope this helps.

Answer:

The weight of an object at the poles is more than the weight of the object at the equator

Explanation:

The shape of the Earth is an ellipsoid such that the distance from the North and South poles to the Earth's center, R₁, is less than the distance from the Equator to the center of the Earth, R₂

The weight of an object is given by the universal gravitational law as follows;

[tex]Weight = F_{gravity} =G\times \dfrac{M \cdot m}{R^{2}}[/tex]

Where;

[tex]F_{gravity}[/tex] = The force of gravity = The weight of an object

G = The universal gravitational constant

M = The mass of the Earth

m = The mass of the object

R = The radius of the Earth

Where R₁ < R₂, we have;

The weight at the Poles, W₁ = [tex]G\times \dfrac{M \cdot m}{R_1^{2}}[/tex]

The weight at the Equator, W₂ = [tex]G\times \dfrac{M \cdot m}{R_2^{2}}[/tex]

We have;

[tex]\left(G\times \dfrac{M \cdot m}{R_1^{2}} \right) > \left(G\times \dfrac{M \cdot m}{R_2^{2}} \right) \because R_1 < R_2[/tex]

Therefore, the weight of an object at the poles, W₁, is more than the weight of the object at the equator, W₂

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

Hence, the smallest radius of the circular path is 8.1 km

Answer:

They affect by switch by the conductors

Explanation:

sana makatulong

Answer:

A. (Buoyancy) and D. (Temperature)

Explanation:

I took itttttttttttttttt

The physical properties of matter are A and D.

Among the following the properties of matter are:-

A. Whether a substance floats or sinks in water.

D. The temperature at which a substance boils.

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Answer:

(a) if she increases the tension in the string is increased by 15%, the fundamental frequency will be increased to 740.6 Hz

(b) If she decrease the length of the the string by one-third the fundamental frequency will be increased to 840 Hz

Explanation:

(a) The fundamental, f₁, frequency is given as follows;

[tex]f_1 = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L}[/tex]

Where;

T = The tension in the string

μ = The linear density of the string

L = The length of the string

f₁ = The fundamental frequency = 560 Hz

If the tension in the string is increased by 15%, we will have;

[tex]f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T\times 1.15}{\mu}} }{2 \cdot L} = 1.3225 \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = 1.3225 \times f_1[/tex]

[tex]f_{(1 \, new)} = 1.3225 \times f_1 = (1 + 0.3225) \times f_1[/tex]

[tex]f_{(1 \, new)} = 1.3225 \times f_1 =\dfrac{132.25}{100} \times 560 \ Hz = 740.6 \ Hz[/tex]

Therefore, if the tension in the string is increased by 15%, the fundamental frequency will be increased by a fraction of 0.3225 or 32.25% to 740.6 Hz

(b) When the string length is decreased by one-third, we have;

The new length of the string, [tex]L_{new}[/tex] = 2/3·L

The value of the fundamental frequency will then be given as follows;

[tex]f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \times \dfrac{2 \times L}{3} } =\dfrac{3}{2} \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = \dfrac{3}{2} \times 560 \ Hz = 840 \ Hz[/tex]

When the string length is reduced by one-third, the fundamental frequency increases to one-half or 50% to 840 Hz.

Answer:

Option d (108,000 J) is the correct answer.

Explanation:

The given values are:

Power,

P = 120 Watts

Time,

t = 15 min.

i.e.,

 = 900 sec

As we know,

⇒ [tex]P=\frac{W}{t}[/tex]

So,

⇒ [tex]W=P\times t[/tex]

On substituting the given values, we get

⇒      [tex]=120\times 900[/tex]

⇒      [tex]=108,000 \ J[/tex]

Answer:

the twenty-fourth, and last, letter of the Greek alphabet (Ω, ω), transliterated as ‘o’ or ‘ō.’.

Explanation:

Answer: 2 i think

Explanation:

Answer:Im pretty sure its the second one because sound sometimes bounces back and that causes echo and it doesnt travel in one line or direction

Explanation:

Answer:

The angle of incidence is the angle between this normal and the incident ray; the angle of reflection is the angle between this normal and the reflected ray. According to the law of reflection, the angle of incidence equals the angle of reflection.

Explanation:

:)

Answer:

hope my answer helps

Explanation:

second law of reflection states that the angle of incidence equals to the angle of reflection,

this is the basic relationship,

so the angle of incidence is also equals to angle of reflection

hope this helps, if not please report it so that someone else gets to try it out

please mark it brainliest

you are so wise how do you do it?

Answer:

D

Explanation:

The relationship between bond strength and the melting and boiling points can be explained as the force between the particles increases, and the melting and boiling points also increase.​Therefore the correct option is D.

It is a temperature at which the pressure exerted by the external atmosphere is equal to the vapor pressure of the substance.

The boiling point depends on atmospheric pressure, temperature, bond strength, and vapor pressure of the liquid.

The bond strength between different atoms of the substance greatly influences the boiling point and melting point.

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