Zinc metal reacts with excess hydrochloric acid to produce hydrogen gas according to the following equation:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
The product gas, H2, is collected over water at a temperature of 20 degrees C and a pressure of 750 mm Hg. If the wet H2 gas formed occupies a volume of 9.18 L, the number of grams of H2 formed is _____ g. The vapor pressure of water is 17.5mm Hg at 20 degrees C.

Answer:

14.4g

Explanation:

Answer:

96.92 K

Explanation:

Applying,

V/T = V'/T'..................... Equation 1

Where V = Initial Volume, T = Initial Temperature, V' = Final Volume, T' = Final Temperature.

Make T the subject of the equation

T = VT'/V'................. Equation 2

From the question,

Given: V = 268 mL, V' = 824 mL, T' = 25°C = (25+273) = 298 K

Substitute these values into equation 2

T = (268×298)/824

T = 96.92 K

Hence the Initial temperature of Nitrogen gas is 96.92 K

Answer:

mass of chlorine = 10.4 grams

Explanation:

Mass of the solution = 5.20 × 10⁶ g

ppm chlorine by mass = 2.00

Recall that:

[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]

[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]

mass of chlorine = 5.20 × 2.0

mass of chlorine = 10.4 grams

Answer:

Beta emission

Explanation:

In beta emission, a neutron is converted into a proton thereby emitting an electron and a neutrino. A neutrino is a particle that serves to balance the spins.

When a nucleus undergoes beta emission, the mass number of the parent and daughter nuclei remain the same while the atomic number of the daughter nucleus is greater than that of its parent by one unit.

Hence, in beta emission, the daughter nucleus is found one pace to the right of the parent in the periodic table.

Answer:

pH = 12.58

Explanation Careful

Since NaOH is a strong bond base you have to solve for pOH and then pH

pOH= 1.42

pH= 14-pOH

14-1.42= 12.58

Answer: 114.22852 grams

HOPE THIS HELPS

Answer:  There are 0.5 grams of barium sulfate are present in 250 of 2.0 M [tex]BaSO_{4}[/tex] solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

[tex]1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L[/tex]

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given [tex]BaSO_{4}[/tex] solution is as follows.

[tex]Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g[/tex]

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M [tex]BaSO_{4}[/tex] solution.

Answer

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

(NH 4) 3P Ionic fu ammonium phosphide 3) Ca 3N 2 Ionic fu calcium nitride 4) Al( NO B) ... If there is a multi-valent metal present, write both the stock and classical name. ... 66 * 10^(23)"atoms of H" The first thing to do here is write the chemical ...

Explanation:

just follow the instructions below.

hope it helps.

#CARRYONLEARNING

Answer:

hi lol

Explanation:

rffgegerwgergergerg

Solution :

Compound                      Ksp

[tex]$PbF_2$[/tex]                               [tex]$3.3 \times 10^{-8}$[/tex]

[tex]$Ni(CN)_2$[/tex]                        [tex]$3 \times 10^{-23}$[/tex]

FeS                                [tex]$8 \times 10^{-19}$[/tex]

[tex]$CaSO_4$[/tex]                           [tex]$4.93 \times 10^{-5}$[/tex]

[tex]$Mg(OH)_2$[/tex]                      [tex]$5.61 \times 10^{-12}$[/tex]

Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]

[tex]$Mg(OH)_2$[/tex]  is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]

It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex]  is more or less soluble than [tex]$Mg(OH)_2$[/tex]  as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.

[tex]$Ni(OH)_2$[/tex]  can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]

[tex]$\text{For } \ Ni(OH)_2$[/tex]

[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]

[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]

100

1-s s 2s

Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]

[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]

1 0 0

1 - s s s

Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

Answer:

-846 kJ

Explanation:

Using Henderson Hasselbach's law,

2Al + 3/2 O2 -> Al2O3    H = -1670 kJ

-(2Fe + 3/2 O2 -> Fe2O3) = Fe2O3 -> 2Fe + 3/2 O2    H = 824 kJ

-1670 kJ + 824kJ = -846 kJ

Answer:

1) some of the gas maybe metal but non metal directly refers it self to not begin metal

2) gases are present in only air . non metals are available in solid form too

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 4.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

wavelength

Explanation:

it is the distance between two crests ot two troughs

Answer:

No

Explanation:

Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.

I know number 1 is 58.04 g/mol

Explanation:

HCL you can do it yourself .try again

Answer:

The decay takes 6min

Explanation:

The decay of an isotope as Thallium-208 follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] is amount of isotope after time t

k is decay constant = ln 2 / t(1/2)

[A]₀ is initial amount of the isotope

Replacing:

[A] = 15.0g

k = ln 2 / t(1/2) = ln 2 / 3min = 0.23105 min⁻¹

t = ?

[A]₀ = 60.0g

ln[A] = -kt + ln[A]₀

ln[15.0g] = -0.23105 min⁻¹*t + ln[60.0g]

-1.38629 = -0.23105 min⁻¹*t

6min = t

Answer:

i gotchu

Explanation:

its the 3rd raikages will eassyyy

Answer:

UK stop spending a lot on clothes if u don't wear half of them

Explanation:

Na=23

cl2=35.5×2=71

NaCl=23+35.5=58.5

2Na + Cl2== 2NaCl

2. : 1

20/23=2(x)/71

(71×20)/(23×2)=x

x=30.87g

Answer: no thank u

Explanation:

Answer: no

Explanation: