Answer:
b
Explanation:
H2(g)+I2(s)→HI(s)H2(g)+I2(s)→HI(s) balance equations
Answer:
H2(g)+I2(s)→2HI(s)
Explanation:
Hello there!
In this case, according to the given information and unbalanced chemical reaction, we infer it must be balanced in agreement with the law of conservation of mass because the reactants side has two hydrogen and iodine atoms whereas the products side has just one. In such a way, by placing a 2 on HI, we obtain the following balanced reaction:
H2(g)+I2(s)→2HI(s)
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How long will it take a 500-W heater to raise the temperature of 400 g of water from 15.0 °C to 98.0
°C?
Explanation:
E=(98-15)×400×4.2
E=139440J
t=E/P
E=139440/500=278.88s
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Lesson 17 Conservation of Momentum grade 9 I want the answer.
Answer:
1) 1.5 kg
2) 0.6 kg
Explanation:
[tex](3)(30) = 60m, m = 90/60 = 1.5[/tex] kg
[tex](0.8)(15) = 20m, m = 12/20 = 0.6[/tex] kg
A lab technician adds 3.50 mL of a 0.00450 M stock solution of barium chloride to a test tube, then adds other solutions so that the total volume is 10.00 mL.
In the absence of reactions, the molarity of barium ions is ______ M in the solution and the molarity of chloride ions is ______ M in solution.
IMPORTANT: Report each answer to 3 significant figures, I made this as a free response fill-in question and the question will be graded credit/no credit. For example, 0.0000123 or 1.23. Do NOT include units as they are already provided for you.
Answer:
[Ba²⁺] = 1.58 × 10⁻³ M
[Cl⁻] = 3.16 × 10⁻³ M.
Explanation:
Step 1: Calculate the molar concentration of BaCl₂
We have 3.50 mL (V₁) of a 0.00450 M (C₁) BaCl₂ solution and we dilute it to a final volume of 10.00 mL (V₂). We can calculate the final concentration of BaCl₂ by using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 0.00450 M × 3.50 mL / 10.00 mL = 1.58 × 10⁻³ M
Step 2: Calculate the molar concentrations of the Ba²⁺ and Cl⁻ ions
Let's consider the dissociation of BaCl₂.
BaCl₂(aq) ⇒ Ba²⁺(aq) + 2 Cl⁻(aq)
The molar ratio of BaCl₂ to Ba²⁺ is 1:1. The molar concentration of Ba²⁺ is 1/1 × 1.58 × 10⁻³ M = 1.58 × 10⁻³ M.
The molar ratio of BaCl₂ to Cl⁻ is 1:2. The molar concentration of Cl⁻ is 2/1 × 1.58 × 10⁻³ M = 3.16 × 10⁻³ M.
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
over the next few minutes?
O Molecules in both the metal and the surrounding air will start moving at lower speeds.
O Molecules in both the metal and the surrounding air will start moving at higher speeds.
O The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
O The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer: The event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.
Explanation:
A process in which heat is evolved is called an exothermic process.
When hot metal plate at [tex]150^{o}C[/tex] is placed in air at room temperature then heat is given off by the metal plate due to which there will occur a decrease in kinetic energy of its molecules.
As a result, molecules in the metal will slow down.
Whereas heat is absorbed by the air molecules from the metal due to which kinetic energy of air molecules will increase.
Thus, we can conclude that the event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.
0.350 moles of H2O is equivalent to (blank amount) molecules of water.
Answer:
is has around 1/5 lyrics of water
Answer:
[tex]1 \: mole \: = \: 6.02 \times {10}^{23} \: molecules \\ 0.350 \: moles \: = \: (0.350 \times 6.02 \times {10}^{23} ) \: molecules \\ = 2.107 \times {10}^{23} \: molecules[/tex]
A study is conducted to examine the effect of NaCl concentration on enzyme activity with the following results. Activity was tested at various salt concentrations. Negative controls were conducted without enzyme. Which of the following is the best interpretation of the 0.27 p value when comparing the activity at 0.1 M to that 1t 0.05M
NaC1 Con (M) 0 0.01 0.02 0.05 0.1 0.2
Avg. Activity (nm/mg/min) 15.5 14 35.5 175.5 195 50.5
Standard Deviation 1.5 1.5 3.6 17 20 5
T-test vs 0.1M <0.05 <0.05 <0.05 0.27 NA <0.05
T-test vs Neg. Ctrl 0.56 0.6 <0.05 <0.05 <0.05 <0.05
a. The activity at 0.1 M NaCl is statistically significantly greater than that at 0.05M NaCl
b. There is a 27% difference between the average enzyme activities at 0.1 and 0.05 M NaCl
c. The variability among the replicates at 0.1 M and 0.05 M NaCl is 27%
d. The activity at 0.1 M NaCl is not statistically significantly greater than that at 0.05M NaCl
Answer:
The answer is "Option D".
Explanation:
The behavior of 0.1M NaCl also isn't substantially larger objectively than those of 0.05M NaCl because a p-value above 0.05 (p>0.05) indicates no ability to tell differential and is a strong proof in favor of a null hypothesis.
The other wrong choices can be defined as follows:
Option A as it's just the reverse of the correct answer to the null.Options B and C because p worth tests to support nor oppose the null hypothesis.A piece of wood has a mass of 36g and measures 3cm X 6cm X 4cm. What is the density of the wood? Would the piece of wood float or sink in water?
Answer:
Explanation:
The density is
1.1 g c m 3 .
Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest: __________.
(a) 0.25 wt% C with coarse pearlite,
(b) 0.80 wt% C with spheroidite,
(c) 0 25 wt% C with spheroidite, and
(d) 0.80 wt% C with fine pearlite.
Justify this ranking.
Answer:
The Ranking from
Hardest to softest is as follows :
0.80 wt% C with fine pearlite.
0.80 wt% C with spheroidite
0.25 wt% C with coarse pearlite
0.25 wt% C with spheroidite
Explanation:
To find - Rank the following iron-carbon alloys and associated microstructures from the hardest to the softest. Justify this ranking.
Solution -
Ranking is as follows :
(d) 0.80 wt% C with fine pearlite.
(b) 0.80 wt% C with spheroidite
(a) 0.25 wt% C with coarse pearlite
(c) 0 25 wt% C with spheroidite
Justification -
For some wt% C,
Fine pearlite is stronger than spheroidite
and
Coarse pearlite is stronger than spheroidite.
Now,
Due to carbon content,
0.80 wt% C with spheroidite is stronger than 0.25 wt% C with coarse pearlite.
So,
The Ranking from
Hardest to softest is as follows :
0.80 wt% C with fine pearlite.
0.80 wt% C with spheroidite
0.25 wt% C with coarse pearlite
0.25 wt% C with spheroidite
How many molecules does 1.25 grams of C2H4 represent?
Explanation:
hope the picture above make sense:)
Three biologically important diatomic species, either because they promote or inhibit life, are
(a) CO,
(b) NO3 and
(c) CN-.
The first binds to hemoglobin, the second is a chemical messenger, and the third interrupts the respiratory electron transfer chain. Their biochemical action is a reflection of their orbital structure. Deduce their ground state electron configurations.
Answer:
See Explanation
Explanation:
We can write the molecular orbital configuration of molecules in the same way as we write the orbital electron configuration of atoms. The valence electrons in the molecule are filled into molecular orbitals of appropriate energy in accordance to the Aufbau principle.
For CO;
σ2s2, σ*2s2, Π2py2, Π2pz2, σ2px2
For NO;
σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2, Π*2px1
For CN-;
σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2
These are the ground state electron configurations of these molecules.
Why do atoms react with each other?
Answer:
Atoms react with atoms of other elements to form compounds because , every atom wants to attain noble gas configuration . Atoms interact with one another by transferring or sharing electrons that are furthest from the nucleus. These outer electrons govern the chemical properties of the element.
Explanation:
~Hope this helps
How did oxygen first enter Earth's atmosphere?
A. Meteorite impacts
B. Breakdown of Precambrian rocks
C. Biological processes
D. Volcanic outgassing
Answer:
I think c biological processes
A 24.0 gram sample of copper was
ncated from 25.0°C to 500.0°C 43783
of heat were absorbed, what is the
Specific_heat of copper?
Answer:
3.84 J/g°C
Explanation:
Using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of substance
c = specific heat of copper
∆T = change in temperature (°C).
Based on the provided information;
Q = 43783J
m = 24g
∆T = 500°C - 25°C = 475°C
c = ?
Using Q = m × c × ∆T
43783 = 24 × c × 475
43783 = 11400c
c = 43783 ÷ 11400
c = 3.84 J/g°C
A cylinder container is filled with air. Its radius is 6.00cm and its height is 3.50 cm. What is the volume of air inside in milliliters?
Answer:
Volume Cylinder = 396cm³
Explanation:
We can find the volume of a cylinder (The container is cylindric) using the general expression:
volume cylinder = π*(radius)²*height
As the container has a radius og 6.00cm and a height of 3.50cm:
volume cylinder = π*(6.00cm)²*3.50cm
Volume Cylinder = 396cm³Goodyear tires are listed with 29.72 psi pressure limits in the summer, with 10.22 L of air. In the winter, however, the volume decreases to 7.19 L because of the colder weather. What would the be the new pressure?
Answer:
42.24 psi.
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 29.72 psi
Initial volume (V₁) = 10.22 L
Final volume (V₂) = 7.19 L
Final pressure (P₂) =?
The final pressure can be obtained by applying the Boyle's law equation as follow:
P₁V₁ = P₂V₂
29.72 × 10.22 = P₂ × 7.19
303.7384 = P₂ × 7.19
Divide both side by 7.19
P₂ = 303.7384 / 7.19
P₂ = 42.24 psi
Therefore, the final pressure is 42.24 psi
Partial pressure of oxygen dissolved in blood is 50 mm Hg. That means that:
1. It exerts a force per cm^2 equal to that of a column of mercury with 1 cm^2 base and 50 mm height
2. It would be in equilibrium with gaseous oxygen that is at partial pressure of 50 mm Hg
3. Both (1) and (2)
4. Neither (2) or (2)
Answer:
The answer is "Option 2".
Explanation:
In this question, the balance with a partial 50 mm Hg pressure of gassing oxygen.In this, the base value is given in the cm that is incorrect because it is measured in mm.In this, the partial pressure of gas in the liquid is equal to the pure pressure of the gas.Calculate the approximate temperature of a 0.50 mol sample of gas at 2.7 atm and a volume of 1.20L
Answer:
79.0 K
Explanation:
Assuming the gas behaves like an ideal gas, we can solve this problem by using the following formula:
PV = nRTWhere:
P = 2.7 atmV = 1.20 Ln = 0.50 molR = 0.082 atm·L·mol⁻¹·K⁻¹ (it is a constant)T = ?We input the data:
2.7 atm * 1.20 L = 0.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * TAnd solve for T:
T = 79.0 KTrue/False: Sound waves are produced by vibrating molecules in a direction perpendicular to that of the direction the wave travels.
Answer:
true
Explanation:
HELP ME PLEASE
Which is true about the relationship between the grain size of the sediment and the permeability of the sediment?
A. As the grain size of the sediment increases, the permeability increases.
B. The size of the sediment is not responsible for the permeability of the sediment.
C. As the grain size of the sediment increases, the permeability decreases.
D. As the grain size of the sediment decreases, the permeability increases.
Answer:
i think A is the correct answer
Magnesium metal reacts with oxygen gas
What is the initial appearance of Magnesium metal?
When Magnesium comes in contact with Oxygen, it reacts with Oxygen causing a layer of Magnesium Oxide on the metal. If Magnesium is burnt, it will cause a bright white light creating Magnesium Oxide.
The initial appearance of Magnesium is a ribbon with a layer of Magnesium Oxide.
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The question is listed in the image attached.
Substance Number of Calories of Heat
1
O
2
100
The substances in the table are combined, and Substance 2 loses 50 calories of heat. How many
calories of heat will Substance 1 eventually gain?
A)
10
B)
25
50
D)
100
Answer:
C
Explanation:
the sum of calories is 100. When 50 calories are lost, 50 calories is the remainder.
80 POINTS
Batteries, motors, and generators all demonstrate what concept?
Newton's Laws
Wave Speed
Conservation of Energy
Chemical Reactions
have some points chemistry gang RISE UP
Answer:
I WILL ACHIEVE GREATNESS
Explanation:
Answer:
.
Explanation:
Find the percent composition for SF6
S =? %
F =? %
Answer:
that is answer
Explanation:
symbol - elements - mass percent
S. - sulfur. - 21.945%
F. - fluorum. - 78.047%
Which of the following substances dissolves most easily in a non polar solvent?
a. NH3
b. H2O
c. NaCl
d. O2
e. BaSO4
Answer:
its e
Explanation:
Is earth an inertial frame of reference? justify your answer
Answer:
Earth is not an inertial reference frame because the Earth rotates and is accelerated with respect to the Sun.
A gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K. If the pressure is raised to 14 atm, and the temperature is increased to 300 K. What is the new volume of the gas? (Show your work, including formula used)
Answer:
≅ 30 Liters (1 sig. fig. based on Temp values 200K & 200K)
Explanation:
P₁ = 12 atm => P₂ = 14 atm Increase P => Decrease V => (12atm/14atm)
V₁ = 23 Liters => V₂ = ?
T₁ = 200 K => T₂ = 300 K Increase T => Increase V => (300K/200K)
V₂ = V₁(P₁/P₂)(T₂/T₁) = 23L(12atm/14atm)(300K/200K) = 29.57143 L (Calc. Ans.)
≅ 30 Liters (1 sig. fig. based on Temp values 200K & 200K)
The enthalpy of solution of NaCl in water is about 3.88 kJ/mol. However, the solubility of NaCl in water is relatively high. Which statement about the entropy of the solution process explains why NaCl dissolves in water even though the process is endothermic?
a. the entropy increases when NaCl dissolves in water
b. the entropy remains the same when NaCl dissolves in water
c. the entropy decreases when NaCl dissolves in water
d. entropy has nothing to do with the solution process
We have that the statement that explains why NaCl dissolves in water even though the process is endothermic the given as,
The entropy increases when NaCl dissolves in water.Option A
HeatGenerally ,Sodium chloride is crystalline salt, when its dissolved is H20 , it dissociates its ion, the ions are scattered through out the solution which results in increased in randomness .
Therefore, the entropy increases when NaCl dissolves in water,
Option A
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