You've been hired by Maple Marvels to write a C++ console application that displays information about the number of leaves that fell in September, October, and November. Prompt for and get from the user three integer leaf counts, one for each month. If any value is less than zero, print an error message and do nothing else. The condition to test for negative values may be done with one compound condition. If all values are at least zero, calculate the total leaf drop, the average leaf drop per month, and the months with the highest and lowest drop counts. The conditions to test for high and low values may each be done with two compound conditions. Use formatted output manipulators (setw, left/right) to print the following rows:________.
September leaf drop
October leaf drop
November leaf drop
Total leaf drop
Average leaf drop per month
Month with highest leaf drop
Month with lowest leaf drop
And two columns:
A left-justified label.
A right-justified value.
Define constants for the number of months and column widths. Format all real numbers to three decimal places. The output should look like this for invalid and valid input:
Welcome to Maple Marvels
------------------------
Enter the leaf drop for September: 40
Enter the leaf drop for October: -100
Enter the leaf drop for November: 24
Error: all leaf counts must be at least zero.
End of Maple Marvels
Welcome to Maple Marvels
------------------------
Enter the leaf drop for September: 155
Enter the leaf drop for October: 290
Enter the leaf drop for November: 64
September leaf drop: 155
October leaf drop: 290
November leaf drop: 64
Total drop: 509
Average drop: 169.667
Highest drop: October
Lowest drop: November
End of Maple Marvels

Answer:

The answer is below

Explanation:

Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph

Adjacency List are most preferred to Adjacency Matrix in some cases which are:

1.  When the graph to is required to be sparsely.

2.  For iterability, Adjacent List is more preferable

Hi, your question is incomplete. Here are the options:

A. persuade the audience.

B, encourage critical thinking.

C. increase discussion.

D. relay detailed information

Answer:

D. relay detailed information

Explanation:

Indeed, slide software (like MS Powerpoint) would be an effective presentation tool, especially when the speech goal is to relay detailed information.

For example, a graph showing the exponential growth in the number of smartphone users in the United States for the last 15 years would be effectively presented using a slide that shows this data because it will allow the audience to easily see the detailed information.

Answer:

ok so u have take the 5 and put 6

Explanation:

5-5. Ethernet network design: UTP connections from client PC and server to workgroup switches, 900m fiber optic link between switches, 800 Mbps communication.

5-6. Additional client connects to the same switch, UTP connection, maintains existing fiber optic link, 800 Mbps communication with the server.

5-5. For connecting a single client PC to a single server, both located 900 meters apart and requiring communication at 800 Mbps, the following Ethernet network design can be implemented:

- Client PC and server connect to their respective workgroup switches via UTP.

- Use fiber optic cables for the 900-meter transmission link between the switches.

- Install switches at the client PC and server locations.

- Ensure that the switches support at least 1 Gbps Ethernet speeds to accommodate the required transmission speed.

5-6. In addition to the previous design, for adding another client next to the first client:

- Connect both clients to the same switch.

- Use UTP cables to connect the second client to the switch.

- Ensure the switch supports 1 Gbps Ethernet speeds.

- Maintain the existing fiber optic transmission link between the switches.

- The second client can also communicate with the server at the required 800 Mbps transmission speed.

Learn more about Network Design at:

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#SPJ2

Answer:

a task and a calendar entry

Explanation:

ITS RIGHT

Answer:

its A) a task and a calendar entry

Explanation:

correct on e2020

Answer:

B

Explanation:

Answer:

b  def drawT():

Explanation:

Answer:

7. true

8.B

Hopefully those are correct!

Explanation:

Answer: document

Explanation:

Answer:

que pinga this is a hw website not snap

Explanation:

Answer:

True

Operating System

Booting

Answer:

all of the layers

Explanation:

Answer:

a couple of the layers

Explanation: says it in the first sentence in the last paragraph of this image

Answer:

lookup value

Explanation:

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

Answer:

no

Explanation:

mabey yes

Answer:gjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

Explanation:

def something(string1, string2):

return True if string2 in string1 else False

This would be the most concise way of writing this function.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is the Bar graph.

Because we use this chart type to visually compare values across a few categories when the charts show duration or when the category text is long.

However, we can present information similarly in the bar graph and in column charts, but if you want to create a chart with the horizontal bar then you must use the Bar graph. In an Excel sheet, you can easily draw a bar graph and can format the bar graph into a 2-d bar and 3-d bar chart.

A column chart is used to compare values across a few categories. You can present values in columns and into vertical bars.

A line graph chart is used to show trends over months, years, and decades, etc.

Pie Chart is used to show a proportion of a whole. You can use the Pie chart when the total of your numbers is 100%.

Answer:

Bar graph option A

Explanation:

I did the test

Answer:

The Program written in C is as follows:

#include <stdio.h>

int main() {

   int num1, num2, num3, smallest;

   printf("Enter any three numbers: ");

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

   printf("Smallest: ");

   printf("%d", num3);

   return 0;

}

Explanation:

This line declares necessary variables

int num1, num2, num3, smallest;

This line prompts user for input of three numbers

   printf("Enter any three numbers: ");

This lines get input for the three numbers

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

The following if/else statements determine the smallest of num1, num2 and num3 and assigns to variable smallest, afterwards

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

The next two lines print the smallest value

   printf("Smallest: ");

   printf("%d", num3);

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers,  and offer real time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.

Why other options are not correct

Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement.   however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.

Answer:

C. O(n).

Explanation:

for better understanding, the os is a program that helps in telling how much resources can be used and when processor can be accessed.

to each programme data structures would load and unload every time that a programme is to be run.

while a programme is being managed there would be extra overheads and based on whatever type of os or programme that this is, it may or may not have fixed overhead

from our question overhead is fixed at 100ms

we have,

net time as: 300-100, 510-100, 905-100, 1750-100, 3305-100,

which is, 200, 410, 805, 1650, 3205

when we double 2¹⁰ to 2¹¹ to 2¹² etc, the programme ran is also doubling

this says that run time is same as size of instance n

O(n)

Answer: .\HelpdeskAdmin

Explanation:

If you wanted to log in as the local administrator then for the Username put a dot (.) and a backslash (\) in front of the Admin username.

The dot(.) will ensure that Windows knows that you are logging into a local computer as the administrator and so will grant you access. The relevant username therefore is, ''.\HelpdeskAdmin''.

I will use  .\HelpdeskAdmin as the username field.

The username-field is known to be a kind of command that is said to specifies the value for the name that shows the characteristics in the login form and it is one that identifies the username field.

Note that the use of the .\HelpdeskAdmin as the username field is the right thing to do as the dot(.) will make sure that the Windows knows that the user is logging into a computer as the administrator.

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true

Screenshots are basically snapshots of your computer screen. You can take a screenshot of almost any program, website, or open window. PowerPoint makes it easy to insert a screenshot of an entire window or a screen clipping of part of a window in your presentation.

database = ([[]])

while True:

   first_name = input("Enter the student's first name: ")

   if first_name == "0":

       while True:

           search = input("Enter a student ID number to find a specific student: ")

           if [] in database:

               database.pop(0)

           if search == "0":

               exit()

           k = 0

           for w in database:

               for i in database:

                   if i[2] == search:

                       print("ID number: {} yields student: {} {}".format(i[2], i[0], i[1]))

                       search = 0

   last_name = input("Enter the student's last name: ")

   id_number = input("Enter the student's ID number: ")

   database.append([first_name, last_name, id_number])

I hope this helps!

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //PrompT the User to enter a String

   System.out.println("Enter a sentence or phrase: ");

   //Receiving the string entered with the Scanner Object

   Scanner input = new Scanner (System.in);

   String string_input = input.nextLine();

   //Print out string entered by user

   System.out.println("You entered: "+string_input);

   //Call the first method (GetNumOfCharacters)

   System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

   //Call the second method (OutputWithoutWhitespace)

   System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

   }

 //Create the method GetNumOfCharacters

   public static int GetNumOfCharacters (String word) {

   //Variable to hold number of characters

   int noOfCharactersCount = 0;

   //Use a for loop to iterate the entire string

   for(int i = 0; i< word.length(); i++){

     //Increase th number of characters each time

     noOfCharactersCount++;

   }

   return noOfCharactersCount;

 }

 //Creating the OutputWithoutWhitespace() method

 //This method will remove all tabs and spaces from the original string

 public static String OutputWithoutWhitespace(String word){

   //Use the replaceAll all method of strings to replace all whitespaces

   String stringWithoutWhiteSpace = word.replaceAll(" ","");

   return stringWithoutWhiteSpace;

 }

}

Explanation:

question a) answer:

At the moment when it sends the package, then it has a waiting time for the acknowledgement from the receiver, however, the time will be split in two when the frameset size becomes two, meaning that two packages have been sent together, causing the receiver to acknowledge only one package.

question b) answer:

The timeout is equal to two times.

In cases when the frame size is 3, the frame will be lost since the timeout turns to be 2 times. Because the sender has to wait for the acknowledgement, therefore it will send other of the parcels.

public class Drive {

   int miles;

   int gas;

   String carType;

   public String getGas(){

       return Integer.toBinaryString(gas);

   }

   public Drive(String driveCarType){

       carType = driveCarType;

   }

   public static void main(String [] args){

       System.out.println("Hello World!");

   }

}

I'm pretty new to Java myself, but I think this is what you wanted. I hope this helps!

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The solution to this question is given in the attached word file.  

Answer:

earned = 0

total = 0

exercises = int(input("Enter the number of exercises: "))

for i in range(exercises):

   score = int(input("Enter score" + str(i+1) + ": "))

   total_score = int(input("Enter total score for exercise " + str(i+1) + ": "))

   earned += score

   total += total_score

print("The total is %" + str(earned/total * 100))

Explanation:

*The code is in Python.

Set the earned and total as 0

Ask the user to enter the number of exercises

Create a for loop that iterates number of exercises times. For each exercise;

Ask the user to enter the score earned and total score of that exercise

Add the score to the earned (cumulative sum)

Add the total_score to the total (cumulative sum)

When the loop is done, calculate the percentage, divide earned by the total and multiply the result by 100, and print it

In python:

number = input("Enter a 10-character phone number: ")

for i in number:

   if i.isalpha():

       if i == "A" or i == "B" or i == "C":

           i = "2"

       elif i == "D" or i == "E" or i == "F":

           i = "3"

       elif i == "G" or i == "H" or i == "I":

           i = "4"

       elif i == "J" or i == "K" or i == "L":

           i = "5"

       elif i == "M" or i == "N" or i == "O":

           i = "6"

       elif i == "P" or i == "Q" or i == "R" or i == "S":

           i = "7"

       elif i == "V" or i == "T" or i == "U":

           i = "8"

       elif i == "W" or i == "X" or i == "Y" or i == "Z":

           i = "9"

   print(i, end="")

I hope this helps!

Code:

def phonenumber():

alpha = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']

n =[2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9]

phone = input('Enter phone number in format of XXX-XXX-XXXX : ').upper()

index = 0

for index in range(len(phone)):

if phone[index].isalpha():

print (n[alpha.index(phone[index])], end = ' ')

else:

print (phone[index], end = ' ')

phonenumber()

Compilation output is attached below:

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Answer:

4096 VLANs

Explanation:

A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.

An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²).  This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs

A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.

But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.

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