Answer:
$60,000
Step-by-step explanation:
$2500*6=15000
45000+15000=60000
A poll shows that 41% of voters in a city favor of a $0.0.1 tax increase. If 25 voters are selected at random, what is that exactly 15 of them will vote in favor of the initiative?
Answer:
The probability is 0.026 to 3 d.p
Step-by-step explanation:
To calculate this , we shall be using the Bernoulli approximation.
let P = percentage of voters supporting the increase = 41% = 41/100 = 0.41
q = percentage of voters not supporting = 100-41% = 59% = 59/100 = 0.59
Now we want to calculate that exactly 15 out of 25 will vote in favor
Mathematically that would be ;
25C15 p^15 q^10
= 25C15 0.41^15 0.59^10
= 0.025981307443 or simply 0.026 to 3 decimal places
Determine whether the following statement is true or false. If it is false, rewrite it as a true statement. A double-blind experiment is used to increase the placebo effect. Choose the correct answer below. A. The statement is false. Double blinding has no effect on the placebo effect. B. The statement is false. Double blinding is used to increase the randomization. C. The statement is true. D. The statement is false. Double blinding is used to decrease the placebo effect.
Answer:
D. The statement is false. Double blinding is used to decrease the placebo effect.
Step-by-step explanation:
In a double blind study, neither researchers nor the participants know which group is receiving the placebo. If the researchers do not know which group took the medication, they cannot influence the behavior of this group, knowingly or nor, by suggesting how they should behave.
Therefore, a double-blind experiment is used to decrease the placebo effect.
A formal hypothesis test is to be conducted using the claim that the mean AC thermostat setting in restaurants is equal to 74degrees°F. What is the null hypothesis and how is it denoted?
Answer:
[tex]A. H_o: \mu = 74 ^{\circ} F[/tex]
Step-by-step explanation:
A null hypothesis refers to the hypothesis in which there is no important difference taken place and it is used in statistics and it also does not have any relation between the two measured events or variables or group association
It can be denoted by
[tex]A. H_o: \mu = 74 ^{\circ} F[/tex]
Therefore the above null hypothesis is the correct answer
The graph of an absolute value function has a vertex of (2,3) and crosses the x-axis at (−1,0) and (5,0). What is the equation for this absolute value function when y=0? A 0=|x+2|+3 B 0=|x−2|+3 C 0=−|x+2|+3 D 0=−|x−2|+3
Answer:
Option D.
Step-by-step explanation:
The vertex form of an absolute function is
[tex]y=a|x-h|+k[/tex]
where, a is a constant, (h,k) is vertex.
It is given that, vertex of an absolute function is (2,3). So, h=2 and k=3.
[tex]y=a|x-2|+3[/tex] ...(1)
It crosses the x-axis at (5,0). So put x=5 and y=0 to find the value of a.
[tex]0=a|5-2|+3[/tex]
[tex]-3=3a[/tex]
[tex]-1=a[/tex]
Put a=-1 in (1).
[tex]y=(-1)|x-2|+3[/tex]
[tex]y=-|x-2|+3[/tex]
Now, put y=0, to find the equation for this absolute value function when y=0.
[tex]0=-|x-2|+3[/tex]
Therefore, the correct option is D.
Answer:
I got this question on my test and I answered D cause if you look up the graph it matches the question
Step-by-step explanation:
D 0=−|x−2|+3
ghvhhhhcycycugvuviggggggvvvggfgffgfggyg
Answer:
fortnite
Step-by-step explanation:
winwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwinwin
Answer:
Yes
Step-by-step explanation:
Yes
Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)
Answer:
There are two or zero positive solutions and zero negative roots (zeros).
Step-by-step explanation:
Use Descartes' Rule of Signs to determine the number of real zeros of [tex]f(x)=2x^6-3x^3+1-2x^5[/tex]
[tex]f(x)=2x^6-2x^5-3x^3+1\\[/tex]
Find the 50th term of the following arithmetic sequence.
6, 13, 20, 27, ...
Answer:
349
Step-by-step explanation:
We know that a₁ (the first term) is 6 and d (the common difference) is 13 - 6 = 7.
Explicit formula: aₙ = a₁ + (n - 1)d = 13 + (n - 1) * 7 = 7n - 1
Therefore, a₅₀ = 7(50) - 1 = 349
Simplify the expression using the order of operations. 2[16-5⋅2]÷4
Answer:
3.
Step-by-step explanation:
Solve in the order of pemdas.
Answer:
[tex]\boxed{\sf 3}[/tex]
Step-by-step explanation:
Solve brackets first.
[tex]2[16-5 \cdot 2]\div4[/tex]
Multiply the terms in the brackets.
[tex]2[16-10]\div4[/tex]
Subtract the terms in the brackets.
[tex]2[6]\div4[/tex]
Divide the numbers.
[tex]2(\frac{6}{4} )[/tex]
Multiply.
[tex]\frac{12}{4} =3[/tex]
What is the value of x?
Answer:
13=x
Step-by-step explanation:
Since BE is a bisector
ABE = EBC
2x+20 = 4x-6
Subtract 2x from each side
2x+20-2x =4x-6-2x
20 = 2x-6
Add 6 from each side
20+6 = 2x-6+6
26 = 2x
Divide each side by 2
26/2 = 2x/2
13=x
Answer:
x = 13
Step-by-step explanation:
The angle bisector theorem means that m<ABE = m<EBC. Now that we know they are equal, we can set the equations to each other and solve for x.
2x + 20 = 4x - 6
26 = 2x
13 = x
So the value of x is 13.
Cheers.
Which one doesn’t belong? Why? Explain.
Answer:
IT IS (M-4)(M+1)
Step-by-step explanation:
BECAUSE ALL THE OTHER QUESTION HAVE THE VARIABLE AS X
AND THIS ONE IS M
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
Use the minimum and maximum data entries and the number of classes to find the class width, the lower class limits, and the upper class limits. min = 14, max = 121, 8 classes
Answer:
The class width is [tex]C_w \approx 13[/tex]
Step-by-step explanation:
From the question we are told that
The upper class limits is [tex]max = 121[/tex]
The lower class limits is [tex]min = 14[/tex]
The number of classes is [tex]n = 8 \ classes[/tex]
The class width is mathematically represented as
[tex]C_w = \frac{max - min}{n }[/tex]
substituting values
[tex]C_w = \frac{121 - 14}{8 }[/tex]
[tex]C_w = 13.38[/tex]
[tex]C_w \approx 13[/tex]
Since
If f (x) = -9x - 9 and g (x) = Vx - 9, what is (f ° g) (10)?
Answer: [tex](f \circ g) (10)= -18\ .[/tex]
Step-by-step explanation:
Given: [tex]f (x) = -9x - 9[/tex] and [tex]g (x) = \sqrt{x - 9}[/tex]
To find : (f o g) (10)
For this we first find (f o g) (x)= [tex]f(g(x))[/tex]
[tex]=f(\sqrt{x-9})\\\\=-9(\sqrt{x-9})-9[/tex]
Now,
[tex](f \circ g) (10)=-9(\sqrt{10-9})-9\\\\=-9\sqrt{1}-9\\\\=-9-9=-18[/tex]
Hence, the value of [tex](f \circ g) (10)= -18\ .[/tex]
A record club has found that the marginal profit, Upper P prime (x ), in cents, is given by Upper P prime (x )equals negative 0.0008 x cubed plus 0.35 x squared plus 45.5 x for x less than or equals 400, where x is the number of members currently enrolled in the club. Approximate the total profit when 240 members are enrolled by computing the sum
Answer:
The total profit when 240 members are enrolled is:
3,587,212.8 cents
Step-by-step explanation:
First of all, the total profit function is gotten by integrating the marginal profit function.
Integrate thus:
Total Profit = P(x) = [-0.0008x^4 ÷ 4] + [0.35x^3 ÷ 3] + [45.5x^2 ÷ 2]
P(x) = 0.0002x^4 + 0.1167x^3 + 22.75x^2
Next, substitute 240 for x, in the total profit function.
P(x) = 0.0002[240]^4 + 0.1167[240]^3 + 22.75[240]^2
P(x) = 663552 + 1613260.8 + 1310400
P(x) = 3,587,212.8 cents
Equivalent to $35,872.128
The smaller of two numbers is one-half the larger, and their sum is 27. Find the numbers. Answer: The numbers are ___ ___ ___
Answer:
the smaller is 9 while the digger is 18
How many different isosceles triangles have integer side lengths and perimeter 23?
Answer:
6 different isosceles triangles.
Step-by-step explanation:
This is a AMC 8 2005 question. (You can search up their solution)
There are 6 triangles:
6, 6, 11
7, 7, 9
8, 8, 7
9, 9, 5
10, 10, 3
11, 11, 1
There are only 6 because if there was an isosceles triangle with side lengths such as 5, 5, 13 the triangle would be impossible since the two smaller side lengths must sum up to be greater than the longest side length.
The number of isosceles triangles has integer side lengths and a perimeter of 23 is 6.
What is the isosceles triangle?In an isosceles triangle, two sides and angles are equal. The sum of the angle of the triangle is 180 degrees.
Given
Isosceles triangles have integer side lengths and a perimeter of 23.
Let x be the isosceles side and y be the other side. Then
[tex]\rm 2x + y = 23[/tex] ...1
And we know that the sum of the two sides of the triangle must be greater than the third side. Then
[tex]\rm 2x >y[/tex] ...2
From equations 1 and 2, we have
x > 5.75
But the value of x is an integer then x will be 6. Then
All possibilities are
[tex]6 + 6 > 11\\\\7 + 7 > 9\\\\8+8>7\\\\9+9>5\\\\10+10>3\\\\11+11>1[/tex]
Thus, the number of isosceles triangles has integer side lengths and a perimeter of 23 is 6.
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Hommie Delicacies produces two products (Orapine and Banango) from a joint process. The joint cost of production is GH¢80,000. Five thousand units of Orapine can be sold at split-off for GH¢20 per unit or processed further at an additional cost of GH¢20,000 and sold for GH¢25 per unit. Ten thousand units of Banango can be sold at split-off for GH¢15 per unit or processed further at an additional cost of GH¢20,000 and sold for GH¢16 per unit. Advise Hommie on further processing each of the products?
Answer:
Orapine: do additional processingBanango: no additional processingStep-by-step explanation:
The processing cost of split-off Orapine units is ...
GH¢20,000/(5000 units) = GH¢4/unit
The increase in revenue from the further processing is ...
GH¢25 -GH¢20 = GH¢5
The increased processing cost is less than the increased revenue, so there is additional profit from further processing 5000 units.
__
The processing cost of split-off Banango units is ...
GH¢20,000/(10000 units) = GH¢2/unit
The increase in revenue from the further processing is ...
GH¢16 -GH¢15 = GH¢1
The increased processing cost is more than the increased revenue, so the company takes a loss from further processing 10000 units. No additional processing of Banango units should be undertaken.
The half-life of a radioactive isotope is the time it takes for a quantity of the Isotope to be reduced to half its initial mass. Starting with 210 grams of a
radioactive isotope, how much will be left after 6 half-lives?
Round your answer to the nearest gram
Answer:
after 6 half lives: 210(1/2)^6= 3.28125
Step-by-step explanation:
isotope to be reduced to half its initial mass at first:
210(1/2)=105 half it is original weight
after second life: 210(1/2)^2=105(1/2)=52.5
after third : 210(1/2)^3=52.5/2=26.25
after fourth : 26.25/2=12.125
after fifth : 13.125/2
after 6 half lives: 210(1/2)^6= 3.28125
Which value for x makes the sentence true?
3/4x+ 4 = 7
1)4
2) 44/3
3) -3
4) 8
Answer:
x=4
Step-by-step explanation:
3/4x+ 4 = 7
Subtract 4 from each side
3/4x+ 4-4 = 7-4
3/4x = 3
Multiply each side by 4/3
4/3 * 3/4 x = 3 * 4/3
x = 4
If the triangle on the grid below is translated by using the rule (x, y) right-arrow (x + 5, y minus 2), what will be the coordinates of B prime?
Answer:
Option (2)
Step-by-step explanation:
If a point having coordinates (x, y) is translated by 'h' units right and 'k' units down,
New coordinates of the point will be,
(x, y) → [(x + h), (y - k)]
Coordinates of the vertices of the given triangle ABC are,
A(-1, 0), B(-5, 0) and C(-1, 2)
If this triangle is shifted 5 units right and 2 units down then the coordinates of point B will be,
B(-5, 0) → B'[(-5 + 5), (0 -2)]
→ B'(0, -2)
Therefore, coordinates of vertex B' will be (0, -2).
Option (2) will be the answer.
Answer:
(0,-2) is Correct
Have a Blessed day!
An article in the Journal of Aircraft (Vol. 23, 1986, pp. 859-864) described a new equivalent plate analysis method formulation that is capable of modeling aircraft structures such as cranked wing boxes and that produces results similar to the more computationally intensive finite element analysis method. Natural vibration frequencies for the cranked wing box structure are calculated using both methods, and results for the first seven natural frequencies follow:
Frequency Finite Element Equivalent Plate
1 14.48 14.79
2 48.45 49.08
3 97.13 99.98
4 113.97 117.43
5 174.75 181.18
6 212.54 220.06
7 277.40 294.79
(a) Do the data suggest that the two methods provide the same mean value for natural vibration frequency? Use
α = 0.05.
(b) Find a 95% confidence interval on the mean difference between the two methods. Round your answers to three decimal places (e.g. 98.765).
Answer: (a) No, the data suggests it is possible to reject the hypothesis which states that the 2 methods provide same mean value.
(b) (-10.957,-0.063)
Step-by-step explanation:
(a) Hypotheses for this data are:
[tex]H_{0}[/tex]: [tex]\mu_{1} = \mu_{2}[/tex]
[tex]H_{a}: \mu_{1} \neq \mu_{2}[/tex]
First find the differences in values:
1 => -0.31
2 => -0.63
3 => -2.85
4 => -3.46
5 => -6.43
6 => -7.52
7 => -17.39
Now, find the mean and standard deviation of the differences:
mean = [tex]\frac{-0.31+(-0.63)+...+(-17.39)}{7}[/tex] = - 5.51
sd = [tex]\sqrt{\frac{(-0.31-(-5.51))^{2}+...+(-17.39-(-5.51))^{2}}{7-1} }[/tex] = 5.89
The value of test statistics is:
t = [tex]\frac{mean}{\frac{s}{\sqrt{n} } }[/tex] = [tex]\frac{-5.51}{\frac{5.89}{\sqrt{7} } }[/tex] = - 2.4750
Analysing Student's T distribution, at a df = 7-1 = 6:
p-value = 0.025*2 = 0.05
To reject the null hypothesis, p-value must be less or equal than α. Since they are equal, reject the null hypothesis, i.e., reject the claim suggesting the 2 methods provide the same mean value for natural vibration frequency.
(b) For a CI = 95%:
t-score for α = 0.025 and df = 6 is 2.447.
mean ± [tex]t.\frac{s}{\sqrt{n} }[/tex]
-5.51 ± 2.447.[tex]\frac{5.89}{\sqrt{7} }[/tex]
-5.51 ± 5.4471
lower limit: -5.51 - 5.4471 = - 10.957
upper limit: -5.51 + 5.4471 = - 0.063
The interval on the mean difference is (-10.957,-0.063)
A rectangular vegetable garden will have a width that is 4 feet less than the length and an area of 140 square feet if x represents the length then the length can be found by solving the equation:
If x represents the length, then the length can be found by solving the equation: x(x-4)=140
Answer: x(x-4) = 140 This equation can be solve to find the length.
Step-by-step explanation:
If the width of the rectangle will be 4 less than the length and the length is represented by x then we could have the equation w=x - 4 for the width and the length is just x. And to find the area of a rectangle we multiply the length by the with so multiply x-4 by x for it to equal 140 because 140 is the area.
x(x-4) = 140 solve for x
[tex]x^{2}[/tex] - 4x = 140 subtract 140 from both sides
x^2 - 4x - 140 = 0 find a number that the product is 140 and the sum is -4
-14 and 10 works out.
[tex]x^{2}[/tex] - 14x + 10x - 140 = 0 factor by grouping
x(x -14) 10(x-14) = 0 factor out x-14
(x-14) ( x+10) = 0 set them both equal zero.
x-14= 0 or x+10 = 0
x = 14 or x= -10
Since -10 can't represent a distance, the answer is 14.
Check.
In this case the length is 14 and if the width is 4 less than the length then we will subtract 4 from 14.
14- 4 = 10 so the width is 10.
14 * 10 = 140
Emma words in a coffee shop where she is paid at the same hourly rate each day. She was paid $71.25 for working 7.5 hours on Monday. If she worked 6 hours on Tuesday, how much was she paid on Tuesday
Answer:
$57
Since $71.25 was paid for working 7.5 hours.
That means he was being paid $9.5 per hour.
Which is 71.25÷7.5.
And on tuesday that's 9.5×6 which is $57
The half-life of a radioactive isotope is the time it takes for a quantity of the Isotope to be reduced to half its initial mass. Starting with 210 grams of a
radioactive isotope, how much will be left after 6 half-lives?
Round your answer to the nearest gram
Answer:
3 grams will be left after 6 half-lives
Step-by-step explanation:
Half-live:
Time it takes for the substance to be reduced by hall.
After n half lives:
The amount remaing is:
[tex]A(n) = A(0)(0.5)^{n}[/tex]
In which A(0) is the initial amount and n is the number of half-lives.
Starting with 210 grams of a radioactive isotope, how much will be left after 6 half-lives?
This is A(6) when A(0) = 210. So
[tex]A(n) = A(0)(0.5)^{n}[/tex]
[tex]A(6) = 210(0.5)^{6} = 3.3[/tex]
Rounding to the nearest gram
3 grams will be left after 6 half-lives
Find the area of the shaded region if the dimensions of the unshaded region are 14ft x 18ft . Use 3.14 for π as necessary. Answer Asap Please! That would be greatly appreciated! PLEASE HELP ME ON THIS ASAP FIRST ANSWER GETS BRAINLIEST
Answer:
867.44 ft²
Step-by-step explanation:
The area of the shaded region is A = 196π + 252.
We have the dimensions of the unshaded region are 14ft x 18ft.
We have to find the area of shaded region.
What is the area of a Rectangle and a Circle?The area of a rectangle is -
A(R) = Length x Breadth = L x B
and the area of Circle is -
A(C) = [tex]\pi r^{2}[/tex]
According to the question -
Dimensions of the unshaded region -
L = 18ft
B = 14ft
Area of the shaded region (A) = Total Area - Area of Rectangle
Total Area = Area of 2 semicircles of radius (7 + 7) 14ft + Area of rectangle of length 18ft and breadth 28ft.
Total Area = ( [tex]2\times \frac{1}{2}\times \pi \times14 \times 14[/tex] ) + ( 18 x 28)
Total Area = 196π + 504
Area of the shaded region (A) = 196π + 504 - 252 = 196π + 252
Hence, the area of the shaded region is A = 196π + 252.
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If you are given the graph of g(x)=log2x, how could you graph f(x)=log2x+5
Answer:
The plus 5 is a vertical translation. It would move g(x) up 5 units at all points. So just take g(x) and move the curve up 5 units.
A pretzel company calculated that there is a mean of 75.4 broken pretzels in each production run with a standard deviation of 5.2. If the distribution is approximately normal, find the probability that there will be fewer than 66 broken pretzels in a run.
Answer:
P [ Z < 66 ] = 35,15 %
Step-by-step explanation:
Normal Distribution
Population mean μ₀ = 75,4
Standard deviation σ = 5,2
Then:
P [ Z < 66 ] = ( 66 - 75,4 ) / 5,2
P [ Z < 66 ] = - 9,4 / 5,2
P [ Z < 66 ] = - 1,81
In z-table we look for the reciprocate area for that z score and find
P [ Z < 66 ] = 0,3515
P [ Z < 66 ] = 35,15 %
kamau is now 2 years older than Jane if James age is y now what will be the total age in 10 years
Answer:
(2y + 22) years
Step-by-step explanation:
kamau is now 2 years older than Jane if Janes age is y now what will be the total age in 10 years.
Answer: If Jane is y years old now and Kamau is 2 years older than Jane, therefore the age of Kamau now would be 2 + y years.
In ten years time Jane age would be y + 10 years while the age of Kamau would be y + 2 + 10 = y + 12 years.
To get their total age we just have to add their individual age. Therefore the total age in 10 years = Age of Kamau in ten years + age of Jane in ten years = (y + 12) + (y + 10) = y + 12 + y + 10 = y + y + 12 + 10 = 2y + 22 years
Given: AD = BC and AD || BC
Prove: ABCD is a parallelogram.
Angles Segments Triangles Statements Reasons
ZBCA
DAC
A
Statements
Reasons
00
D
с
Assemble the proof by dragging tiles to
the Statements and Reasons columns.
Answer:
See below
Step-by-step explanation:
Proof:
Statements | Reasons
AD ≅ BC | Given
AD ║ BC | Given
AC ≅ AC | Reflexive Property
∠DAC ≅ ∠ACB | If 2 || lines are cut by a trans., the | alternate interior ∠s are congruent.
ΔADC ≅ ΔBCA | S.A.S Postulate
BA ≅ DC | Corresponding sides of congruent Δs
So, quad. ABCD is a ║gm | If a quad. has its opposite sides
| congruent, the quad. is a parallelogram.
It is prove that given quadrilateral is a parallelogram.
Given that,AD ≅ BC and AD ║ BC
By reflexive property,AC ≅ AC
If two parallel lines are cut by a transversal. Then, alternate interior angles are congruent.So that, ∠DAC ≅ ∠ACB
By Side - angle - Side congruency rule,ΔADC ≅ ΔBCA
Since, the Corresponding sides of congruent triangles are congruent.So that, BA ≅ DC
Hence, opposite sides of given quadrilateral are equal. Therefore, given quadrilateral are parallelogram.
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What is the current value of a zero-coupon bond that pays a face value of $1,000 at maturity in 6 years if the appropriate discount rate is 4%.
Answer:4
Step-by-step explanation:
A zero-coupon bond doesn’t make any payments. Instead, investors purchase the zero-coupon bond for less than its face value, and when the bond matures, they receive the face value.
To figure the price you should pay for a zero-coupon bond, you'll follow these steps:
Divide your required rate of return by 100 to convert it to a decimal.
Add 1 to the required rate of return as a decimal.
Raise the result to the power of the number of years until the bond matures.
Divide the face value of the bond to calculate the price to pay for the zero-coupon bond to achieve your desired rate of return.
First, divide 4 percent by 100 to get 0.04. Second, add 1 to 0.04 to get 1.04. Third, raise 1.04 to the sixth power to get 1.2653. Lastly, divide the face value of $1,000 by 1.2653 to find that the price to pay for the zero-coupon bond is $790,32.
HELLPPPPPPPPPPPPP Solve x2 - 16x + 60 = -12 by completing the steps. First, subtract 60 from each side of the equation. Next, add 64 to each side of the equation to complete the square. Now, write x² - 16x + 64 = -8 as ✔ (x - 8)² = -8
Answer:
x = 8 ± 2i[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Given
x² - 16x + 60 = - 12 ( subtract 60 from both sides )
x² - 16x = - 72
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 8)x + 64 = - 72 + 64, thus
(x - 8)² = - 8 ( take the square root of both sides )
x - 8 = ± [tex]\sqrt{-8}[/tex] = ± 2i[tex]\sqrt{2}[/tex] ( add 8 to both sides )
x = 8 ± 2i[tex]\sqrt{2}[/tex]
The solution of the given expression is ±2√2i+8
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given that
x² - 16x + 60 = - 12
Then subtract 60 from both sides;
x² - 16x = - 72
To complete the square then add ( half the coefficient of the x- term )² to both sides
x² + 2(- 8)x + 64 = - 72 + 64,
(x - 8)² = - 8 ( take the square root of both sides )
x = ±2√2i+8
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