you went to the restaurant and you paid $28 for food. you decide to tip the waiter 15% and pay tax 10%. what was the final bill after tip and tax?

Answer:

70.83 ft³

Step-by-step explanation:

The volume of a pyramid is:

[tex]\frac{bh}{3}[/tex], where b is the base area and h is the height.

Let's first find the area of the base.

[tex]17\cdot5=85\\85\div2=42.5[/tex]

Multiplying this by 5:

[tex]42.5\cdot5=212.5[/tex]

Dividing by 3:

[tex]212.5\div3=70.83[/tex].

Hope this helped!

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle [tex]\triangle PQR[/tex] where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And [tex]\angle Q \neq 90^\circ[/tex]

Given that:

PQ = 44 ft

PR = 51 ft

[tex]\angle R = 58^\circ[/tex]

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

[tex]\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]

Where  

a is the side opposite to [tex]\angle A[/tex]

b is the side opposite to [tex]\angle B[/tex]

c is the side opposite to [tex]\angle C[/tex]

[tex]\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ[/tex]

Now,

[tex]\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ[/tex]

Let us use the Sine rule again:

[tex]\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft[/tex]

So, the answer is 35.11 ft.

Answer:

I used to know this not anymore sry g

Answer:

80 m

Step-by-step explanation:

Given :-

One side of rhombus = 20 m.

[ as one of the property of rhombus = all sides are equal ]

So, perimeter of rhombus = sum of all sides

= 20+20+20+20 = 80 m

...........................OR............................

Perimeter of rhombus = 4 × side

= 4 × 20 = 80 m

Hence, the perimeter of the rhombus is 80m.

Answer:

The perimeter is 80 meters

Step-by-step explanation:

The geometric characteristic of a rhombus is that it has 4 equal sides, then if one side measures 20 m, then each of the other sides measure also 20 m.Then its perimeter (addition of all the sides must render: 4 * 20 m = 80 m

Answer:

D) 9

Step-by-step explanation:

These angles are equal to each other because they’re alternate interior angles so:

9x + 8 = 15x - 46

9x - 15x = -46 - 8

-6x = -54

x = 9

=================================================

Explanation:

The graph goes on forever to the left and right. This means any real number x can be plugged into the function to get some output y. The domain is the set of all real numbers. In interval notation, we would say [tex](-\infty, \infty)[/tex] which is another way of saying [tex]-\infty < x < \infty[/tex]

The range is y > -100 because the exponential graph steadily approaches this horizontal asymptote. Think of it like an electric fence you cannot touch. Since we never actually get to this y value, this means y = -100 is not part of the range. Your teacher made a typo when they wrote [tex]y \ge -100[/tex] and instead they should have written [tex]y > -100[/tex]. So basically y can be anything larger than -100. The graph may look like it eventually reaches y = -100 itself, but it's actually just getting closer and closer to this y value. To write the range in interval notation, we would say [tex](-100, \infty)[/tex]

This function is exponential because it has the general shape all exponential growth functions do. We have a fairly flat part with very slow growth at first, but then as time goes on, the growth rate increases dramatically resulting in the very steep curve.

Quartic polynomials are 4th degree polynomials. They have the same end behavior as quadratic functions do, since both are even degree polynomials. We don't have a quartic here because the left end behavior isn't going off to positive infinity as the right end behavior is.

Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

F1 and F2 are the focii of the hyperbola.

Point P(x, y) is x units distant from F1 and y units distant from the other focus F2.

By the definition of a hyperbola,

"Difference between the distances of a point from the focii is always constant and equals to the measure of transverse axis."

Difference in the distances of point P from focii F1 and F2 = (x - y) units

This distance is equal to the length of the transverse axis = (x - y) units

Therefore, Option (B) will be the answer.

Answer:

x-y

Step-by-step explanation:

Answers:

=====================================================

Explanation:

The domain is the set of allowed x input values, aka the set of all allowed x coordinates of the points. We see that [tex]-4 < x \le 3[/tex]. It might help to draw vertical lines through the endpoints until you reach the x axis. Note the open hole at x = -4 to indicate we do not include this as part of the domain (hence the lack of "or equal to" for the first inequality sign).

The interval [tex]-4 < x \le 3[/tex] then can be condensed into the shorthand form (-4, 3] which is the domain in interval notation.

It says: x is between -4 and 3. It can't equal -4 but it can equal 3.

So the use of parenthesis versus square brackets tells the reader which endpoint is included or not.

--------------------------------------------------

The range describes all possible y outputs. We see that y = 5 is the largest it gets and y = -5 is the lower bound. It might help to draw horizontal lines through the endpoints until you reach the y axis. The open hole means -5 is not part of the range.

The range as a compound inequality is [tex]-5 < y \le 5[/tex]. This condenses into the shorthand of (-5, 5] which is the range in interval notation.

Verbally, the range is the set of y values such that y is between -5 and 5. It can't equal -5 but it can equal 5.

Answer:

Hello,

Step-by-step explanation:

Domain(f)= ]-4;3]={x€R | -4<x≤3}

Rang(f)=]-5;5]={y€R | -5< y ≤5}

Answer:

The answer to this question is (D)

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

[tex]\mathbf{\dfrac{(a+b+c+d)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(a+1+2+3)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(6+a)}{4} =9}[/tex]

By cross multiplying;

6+a = 9 × 4

6+a = 36

a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

https://brainly.com/question/15276410?referrer=searchResults

The greatest value for one of the four positive integers is 30.

To find the largest positive integer, you have to minimize the other three positive integers.

Find the average of the four positive integers and equate it to the given value of the average.

[tex]\frac{6 + y}{4} = 9\\\\6+ y = 36\\\\y = 36-6\\\\y = 30[/tex]

Thus, the greatest value for one of the positive integers is 30

learn more here: https://brainly.com/question/20118982

Answer: $120

First, create a function

[tex]\left \{ {{5a+b=45} \atop {12a+b=80}} \right.\\\\(5-12)a+(1-1)b=45-80\\\\-7a=-35\\\\a=\frac{-35}{-7} =5\\\\5a+b=45\\\\5(5)+b=45\\\\b=45-25=20[/tex]

Therefore, the function is y = 5x + 20

To find the amount of money at week 20, set x = 20 and solve:

[tex]y=5(20)+20=100+20=120[/tex]

Therefore, the answer is $120.

Answer:

Evaluate each expression inside both grouping symbols, then multiply the result.

Step-by-step explanation:

[tex]\displaystyle (3 - 1)(4 + 2) = (2)(6) = 12[/tex]

G - Grouping Symbols

E - Exponents

M\D - Division & Multiplication [left to right]

S\A - Subtraction & Addition [right to left OR vice versa]

I am joyous to assist you at any time.

Answer:

-9

Step-by-step explanation:

Hey there!

Well, to simplify,

5 - 2(3 + 4)

Wel need to use PEMDAS,

3+4=7

7 * -2 = -14

5 - 14 = -9

Hope this helps :)

Answer:

-9

Step-by-step explanation:

[tex]5 - 2(3+4)\\5 - 2(7)\\5 - 14\\-9[/tex]

Answer:

where m= slope m= -7/3

Step-by-step explanation:

Answer:

82 degrees

Step-by-step explanation:

Measure of arc ABC = 86*2 = 172 degrees.

Measure of arc DC = 360 - (145+172) = 360-317 = 43 degrees.

Measure of arc BCD = 121+43 = 164 degrees.

Measure of angle A = 164/2 = 82 degrees

Hey there! I'm happy to help!

PART A

Let's look at our two equations.

y=3x-5

y=6x-8

We will solve this with substitution because we have two different values for y, so it will be be very easy to substitute.

We know that y is equal to 6x-8. This means that we can replace the y in the first equation with 6x-8 and then solve for x.

6x-8=3x-5

We add 8 to both sides.

6x=3x+3

We subtract 3x from both sides.

3x=3

We divide both sides by 3.

x=1

We can plug this x-value into either of our equations to figure out what y is.

y=6(1)-8

y=6-8

y=-2

Therefore, our solution is x=1 and y= -2.

PART B

When graphing the two equations in a systems of equation, the point where they intersect is the solution. We already have our solution, so now we will just write it as a point, which is (1,-2).

Have a wonderful day! :D

Answer:

see below

Step-by-step explanation:

y = 3x − 5

y = 6x − 8

I will use substitution by substituting for y in the first equation

y = 3x − 5

6x -8 = 3x-5

Subtract 3x from each side

6x-3x -8 = 3x-5-3x

3x-8 = -5

Add 8 to each side

3x-8+8 = -5+8

3x =3

Divide by 3

3x/3= 3/3

x =1

Now find y

y = 3x − 5

  = 3(1) -5

  =3-5

  = -2

( 1,-2)

The two lines will intersect at ( 1,-2)

The solution to the two equations is where the lines intersect.

[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]

[tex]\\ \sf \longmapsto 1+6+(-8)[/tex]

[tex]\\ \sf \longmapsto 1+6-8[/tex]

[tex]\\ \sf \longmapsto 7-8[/tex]

[tex]\\ \sf \longmapsto -1[/tex]

option c is correct

Answer:

Lets start with the top row.

First, add the two values.

5+14=19

Now, divide each value by the total.

5/19=0.26315789473

Round the decimal to the nearest hundredth.

5/19=0.26

14/19=0.73684210526

Round it to the nearest hundredth.

14/19=0.74

Now, The second row.

Add the two values.

16+7=23

Divide the first value by the total.

16/23=0.69565217391

Round it to the nearest hundredth.

16/23=0.70

Divide the second value by the total.

7/23=0.30434782608

Round to the nearest hundredth.

7/23=0.30

Done!

Answer:

Row 1: 0.26 0.74

Row 2: 0.70 0.30

Step-by-step explanation:

Khan

Answer:

Domain: all real numbers/ (-inf,inf)/ -inf<x<inf

Range: all real numbers greater than -4/  [-4,inf)/ -4≤y<inf

Step-by-step explanation:

the graphs/equations of ALL quadratics (parabolas) have a domain of all real numbers

The vertex of the parabola is at y=-4 so the range cannot be any less than that, and then both ends point up, so they will continue on for infinity.  

Hope i could help!

Answer:

11

Step-by-step explanation:

The sum of the shortest two sides must be greater than the longest side.

If n is the longest side:

6 + 8 > n

14 > n

If 8 is the longest side:

6 + n > 8

n > 2

So n must be an integer greater than 2 and less than 14.

n can be 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, or 13.

There are 11 possible integers.

[tex] \LARGE{ \boxed{ \rm{ \purple{Answer}}}}[/tex]

We know,

Sum of two sides of a triangle > Third side

Then,

⇛ 6 + 8 > n

⇛ 14 > n

Nextly,

Difference of two sides of a triangle < Third side

Then,

⇛ 8 - 6 < n

⇛ 2 < n

Then, Range of third side:

☃️ 2 < n < 14

Possible measures of 3rd sides = 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 or 13.

There are 11 possible values of 3rd side. Out of them, any measure is the length of 3rd side.

━━━━━━━━━━━━━━━━━━━━

Answer:

x = -1.29 and -2.71

Step-by-step explanation:

Use the quadratic formula, which is [tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]x=\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{-8+\sqrt{8^2-4(2)(7)} }{2(2)}[/tex] and [tex]\frac{-8-\sqrt{8^2-4(2)(7)} }{2(2)}[/tex]

[tex]\frac{-8+\sqrt{8} }{4}[/tex] and [tex]\frac{-8-\sqrt{8} }{4}[/tex]

Further reduced down to:

[tex]\frac{-8+2\sqrt{2} }{4}[/tex] and [tex]\frac{-8-2\sqrt{2} }{4}[/tex]

In decimal form, to the hundredths place, both of these are:

-1.29 and -2.71

Answer:

the firsts third and last one

Step-by-step explanation:

hope this helped

Answer:

D because even though the flat fee is 150 paying 5$ a hour it will cost less

Complete question:

All of Ralph's ranch land was divided equally among his 6 children. His daughter Lynn's portion of the ranch land was divided equally among her 4 children. How much of Ralph's ranch land was inherited by 1 of Lynn's children?

Answer:

1 / 24

Step-by-step explanation:

Number of Ralph's children = 6

Number of Lynn's children = 4

If Ralph's land were divided equally among his six children, the fraction each child gets equals

Proportion of land / number of children

= 1 / 6

Therefore, Lynn who is also Ralph's daughter gets 1/6 portion.

If 1/6 is shared equally between her four children, then ;

Her portion ÷ 4

(1/6) ÷ 4

(1/6) × (4/1)

= 1/ 24

Each of Lynn's children gets 1 / 24

Answer:

It seems like you misunderstood the instructions, though I don't blame you because they wrote it strangely. I believe that you're supposed to draw your own conclusion and then explain how you go there, rather than analyze a conclusion that was already drawn for you. If a long drive=a large fare, and you've been told that the driver has a long drive, you can draw the conclusion that "The fare will be large."

Answer:

first number after the decimal point

Step-by-step explanation:

after the decimal point is the tenths, hundredths, and thousandths place.

0.1 - tenths

0.09 - hundredths

0.006 - thousandths

Answer:

5 inches on the drawing = 32 actual inches

Step-by-step explanation:

195 inches

104 x 12 = 1248 inches

1/39

Answer:

she used a scale of 5 inches to represent 32 inches actual length

Step-by-step explanation:

We are told that helen made the gym to be 195 inches long in the drawing.

Now, we are told that the actual length of the gym is 104 ft long.

Thus, converting to inches,

1ft = 12 inches

So, 104ft = 104 × 12 = 1248 inches

Which means that 194 inches represented 1248 inches.

So the scale is:

195:1248

Dividing both by a common factor of 39 to give a scale of (195/39):(1248/39)

This gives;

5:32

So she used a scale of 5 inches to represent 32 inches actual length

Answer:

B) 3

Step-by-step explanation:

Traveling at a rate of 70 miles per hour, a car travels 26 miles per gallon of gasoline.

In 300 miles journey the gallon of gasoline consumed will be

300/26= 11.54 gallons

Traveling at a rate of 45 miles per hour, the same car travels 36 miles per gallon of gasoline.

In 300 miles journey the gallon of gasoline consumed will be

300/36= 8.33 gallons

The amount of gasoline saved= 11.54-8.33

The amount of gasoline saved= 3.21

approximately 3 gallons of gasoline

Using Pythagorean theorem

[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]

[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]

[tex]\\ \sf\longmapsto P^2=121-81[/tex]

[tex]\\ \sf\longmapsto P^2=40[/tex]

[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]

[tex]\\ \sf\longmapsto P=6.2cm[/tex]

Step-by-step explanation:

Given,

Hypotenuse = 11 cm

Base (One of the given leg) = 9 cm

Therefore,

According to Pythagoras Theorem,

[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]

[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]

[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]

[tex] = > {height}^{2} = 121 - 81[/tex]

[tex] = > {height}^{2} = 4 0[/tex]

[tex] = > height = \sqrt{40} [/tex]

=> height = 6.3245553203

When rounded to nearest tenth,

=> height = 6.3

Hence,

Required length of other leg is 6.3 (Ans)

Answer: A

Step-by-step explanation: