Answers
Answer:
Position X.
Explanation:
To know the correct answer to the question, it is important that we know the definition of potential energy.
Potential energy can be defined as the energy possessed by an object in relation to its position. Mathematically it can be expressed as:
PE = mgh
Where
PE => is the potential energy.
m => is the mass of the object.
g => is the acceleration due to gravity.
h => is the height to which the object is located.
Considering the formula for potential energy (i.e PE = mgh), we can see clearly that the potential energy (PE) is directly proportional to the height (h). This implies that the greater the height, the greater the potential energy and the smaller the height, the smaller the potential energy.
Considering the diagram given above, we can see that the greatest height attained by the ball is at position X. Thus, the ball will have the greatest potential energy at position X.
Related Questions
How many boron atoms are there in 5 molecules of BF3? Hint: The symbol for boron is B. Submit
Answers
Answer:
5 atoms of Boron
Explanation:
Boron makes up approximately 15.944% of the mass and the rest of the 84.056% is Fluorine. There is 5 Atoms because Boron atomic mass is 10.811 in 1 molecule of BF3 and you wanted 5 Molecules.
To see the number of atoms of an element in a given molecule we need to multiply stoichiometry to the number that is written on the foot of the element that is stoichiometry. Therefore, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
What is atom?Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit.
In the nucleus, proton and neutron are present. Electron has -1 charge while proton has +1 charge. Neutron is neutral that is it has no charge. So overall the charge of nucleus is due to only proton, not by neutron.
In one molecule of BF[tex]_3[/tex], the number of boron atoms is 1. So, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
Therefore, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
To know more about atom, here:
https://brainly.com/question/13518322
#SPJ2
An ideal spring is lying horizontally on a frictionless surface. One end of the spring is attached to a wall. The other end is attached to a moveable block that has a mass of 5 kg. The block is pulled so that the spring stretches from its equilibrium position by 0.65 m. Then the block is released (from rest), and as a result the system oscillates with a frequency of 0.40 Hz (that's 0.40 rev/sec) Find:
a) the acceleratiuon of the block when the spring is stretched by 0.28 m.
b) the maximum force magnitude exerted by the spring on the block.
c) the oscillation frequency of a 2.5 kg blcok under the same circumstances (i.e. with the same spring and initial displacement).
Answers
Answer:
a) a = - 1.76 m / s², b) F = 20.5 N, c) w = 3.55 rad / s
Explanation:
a) a simple harmonic motion is described by the expression
x = A cos (wt + Ф)
in this case they give us the frequency
w = 2π f
w = 2π 0.40
w = 2.51 rad / s
as the maximum elongation is 0.65 m this corresponds to the amplitude of the movement
A = 0.65 m
to find the phase constant (Ф) we use the initial condition that for t = 0 v = 0 and x = A, we substitute
A = A cos (0+ Ф)
cos Ф = 1
Ф = 0
the resulting equation is
x = 0.65 cos (2.51 t)
Let's find the time it takes to get to x = 0.28 m
0.28 = 0.65 cos 2.51 t
2.51 t = cos-1 (0.28 / 0.65)
remember angles are in radians
t = 1.1254 / 2.51
t = 0.448 s
the acceleration is
[tex]a = \frac{dv}{dt} = \frac{d^2x}{dt^2}[/tex]
a = -A w² cos wt
we subtitle
a = - 0.65 2.51² cos (2.51 0.448)
a = - 1.76 m / s²
b) the maximum acceleration occurs when the cosine is ±1
a = A w²
a = 0.65 2.51²
a = 4.10 m / s²
Let's use Newton's second law
F = m a
F = 5 4.1
F = 20.5 N
c) The angular velocity is given by
w² = k / m
let's find the spring constant
k = m w²
k = 5 2.51²
k = 31.5 N / m
therefore if the block is exchanged for another with mass m'= 2.5 kg
w = √(31.5 / 2.5)
w = 3.55 rad / s
In reaching her destination, a backpacker walks with an average velocity of 1.19 m/s, due west. This average velocity results because she hikes for 5.96 km with an average velocity of 3.10 m/s, due west, turns around, and hikes with an average velocity of 0.744 m/s, due east. How far east did she walk
Answers
Answer:
x₂ = 4.455 m
Explanation:
The average speed is defined as the displacement traveled between the time interval
v_average = [tex]\frac{\Delta x}{\Delta t}[/tex]
in this case we have a first stop walking west at speed v = 3.10 m / s a distance of x = 5.96 km = 5.96 10³ m
Let's find the time it takes on this tour
v = x / t
t = x / v
t₁ = 5.96 10³ / 3.10
t₁ = 1.9226 10³ s
in a second to walk east at a speed of v₂ = 0.744 m / s
v₂ = x₂ / t₂
t₂ = x₂ / v₂
for full movement
let's assume that the eastward movement is positive
v =[tex]\frac{- x_1 + x_2}{t_1 +t_2}[/tex]
v = [tex]\frac{-x_1 +x_2}{t_1 + \frac{x_2}{t_2} }[/tex]
the only unknown term is the distance to the east. We replace and resolve
1.19 = [tex]\frac{-5.96 \ 10^3 + x_2}{1.92 \ 10^3 + \frac{x_2}{0.744} }[/tex]
1.19 (1.92 10³ + [tex]\frac{x_2}{0.744}[/tex]) = x₂ 1.92 10³ - 5.96 10³
2.2848 10³ + 1.599 x₂ = 1.92 10³ x₂ - 5.96 10³
x₂ (1.92 10³ - 1.599) = 2.2848 10³ + 5.96 10³
x₂ = 8.5448 10³ / 1.918 10³
x₂ = 4.455 m
6. A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at
30.00°C). The final temperature of the system is 40.22°C. Find the specific heat of iron.
90
Answers
Answer:
[tex]c=0.45\ J/g^{\circ} C[/tex]
Explanation:
Given that,
A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at 30.00°C). The final temperature of the system is 40.22°C.
We need to find the specific heat of iron.
It can be calculated as:
Cooler water gains = hot metal loses
mc∆T = - mc∆T
Put all the values,
[tex]200g(4.184\ J/g^{\circ} C)(T_f-T_i) = -25g(c)(T_f-T_i) \\\\200g(4.184 )( 40.22-30.00) = -25\times (c)\times (40.22-800.00)\\\\8552.096 = 18994.5c\\\\c=\dfrac{8552.096 }{18994.5}\\\\c=0.45\ J/g^{\circ} C[/tex]
So, the specific heat of iron is [tex]0.45\ J/g^{\circ} C[/tex]
What would cause surface ocean water to have a higher salt content?
A.
Surface ocean water will have a higher salt content from the melting of sea ice
B.
Surface ocean water will have a higher salt content from low rates of evaporation and high rates of precipitation.
C.
Surface ocean water will have a higher salt content from water flowing out of a river into the ocean
D.
Surface ocean water will have a higher salt content from high rates of evaporation and low rates of precipitation
Answers
Answer:
d I think? not sure I don't know much abt the ocean
A ball is projected at an angle of 53º. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was
launched?
OA. 31 meters/second
OB. 38 meters/second
OC
44 meters/second
OD
55 meters/second
Answers
Answer: B
Explanation:
The vertical component of a vector such as velocity is the magnitude of the vector multiplied by the sine of the angle.
[tex]V_y=48*sin(53)=38.3m/s[/tex]
Calculate the displacement and velocity at times of (a) 0.500, (b) 1.00, (c) 1.50, (d) 2.00, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70.0 m above the water
Answers
Answer:
See explanation below
Explanation:
This is a typical exercise of free falling. In this case a rock thrown straight down from the bridge, and we are asked to determine the final velocity of the rock and it's displacement at those given times.
First, just for this problem, as the rock is going straight down, we'll say that the downward direction is positive, therefore, the following expressions to calculate velocity and speed will be:
V = V₀ + gt (1)
X = V₀t + gt²/2 (2)
In this case, g = 9.8 m/s²
Now, let's see the displacement and velocity for each given time:
a) For t = 0.5 s
V = 14 + (9.8)*0.5
V = 18.9 m/s
X = (14*0.5) + (9.8)(0.5)²/2
X = 7 + 1.225
X = 8.225 m
b) For t = 1.00 s
V = 14 + (9.8)*1
V = 23.8 m/s
X = (14*1) + (9.8)(1)²/2
X = 14 + 4.9
X = 18.9 m
c) For t = 1.5 s
V = 14 + (9.8)*1.5
V = 28.7 m/s
X = (14*1.5) + (9.8)(1.5)²/2
X = 21 + 11.025
X = 32.025 m
d) For t = 2 s
V = 14 + (9.8)*2
V = 33.6 m/s
X = (14*2) + (9.8)(2)²/2
X = 28 + 19.6
X = 47.6 m
e) For t = 2.50 s
V = 14 + (9.8)*2.5
V = 38.5 m/s
X = (14*2.5) + (9.8)(2.5)²/2
X = 35 + 30.625
X = 65.625 m
Hope this helps
A 7.80-g bullet moving at 600 m/s strikes the hand of a superhero, causing the hand to move 5.90 cm in the direction of the bullet's velocity before stopping. (a) Use work and energy considerations to find the average force that stops the bullet. N (b) Assuming the force is constant, determine how much time elapses between the moment the bullet strikes the hand and the moment it stops moving. s
Answers
Answer:
a) F = 2.3797 10⁴ N, b) t = 1.97 10⁻⁴ s
Explanation:
a) For this exercise let's use the relationship between work and scientific energy
W = ΔK
W = F .d
ΔK = ½ m v² - ½ m v₀²
the bold are vectors. in this case the force of the bullet on the hand and the displacement of the bullet has the opposite direction, therefore the angle between the two is 180. The velocity when the bullet stops is zero.
We substitute
-F x = - ½ m vo2
F = [tex]\frac{m v_o^2}{2 x}[/tex]
let's calculate
F = [tex]\frac{7.80 \ 10^{-3} 600^{2} }{2 \ 5.90 \ 10^{-2} }[/tex]
F = 2.3797 10⁴ N
b) let's find the acceleration
F = ma
a = F / m
a = 2.3797 10⁴ / 7.80 10⁻³
a = 3.05 10⁶ m / s²
now we can use the kinematics relations
v = v₀ - a t
the final velocity is zero v = 0
t = v₀ / a
t = 600 / 3.05 10⁶
t = 1.97 10⁻⁴ s
When you jump, you push down on the earth and it pushes back up against you. The earth pushing up against you is what causes you to go into the air. Why doesn’t your push cause the earth to go down if your push on the earth is equal and opposite of the earth's push on you?
Answers
That's a great question !
The answer is: It does !
A push on an object causes the object to accelerate in the direction of the force.
The less mass the object has, the more the force accelerates it.
Now, when you jump, the forces on you and on the Earth are equal forces.
The up force on you causes you to accelerate up by some amount.
The down force on the Earth causes the Earth to accelerate down by some amount.
The Earth's mass is something like 5,972,000,000,000,000,000,000,000 kg, while your mass is something like 50 kg.
The Earth has something like 119,400,000,000,000,000,000,000 times as much mass as you have.
So your acceleration is something like 119,400,000,000,000,000,000,000 times as great as the Earth's acceleration.
==> The Earth's downward acceleration, caused by your jump, is there. It's just too small to notice.
BUT . . . That's the reason why seismometers (instruments to detect and measure the vibrations from distant earthquakes) have to be located as far as possible from cities and busy roads.
In places that are too close to cities and roads, the Earth's surface is always vibrating, wiggling, jiggling, heaving and weaving, in reaction to the forces of people walking around, cars and trucks driving around, even rain falling down. And kids jumping up and down !
In such places, these people-motions are louder and stronger than the vibrations coming from distant earthquakes. Seismometers wouldn't work there.
compare and contrast speed and velocity.
Answers
Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.
Heeeeeeeeelp please
Answers
OK please your picture not perfect please try again
What is the speed of a sailboat traveling 100m in 140s?
Answers
Answer:
Explanation:
d = rt only works for calculating average speeds.
100 = r(140)
r = 0.714 m/s
Answer: 0.71m/s
Explanation:
Formula: Speed = Distance/time
Speed = 100m/140s
Speed = 100/140 / 20/20
Speed = 5/7 or 0.71m/s
When the moving sidewalk at the airport is broken, as it often seems to be, it takes you 41 ss to walk from your gate to baggage claim. When it is working and you stand on the moving sidewalk the entire way, without walking, it takes 80 ss to travel the same distance. How long will it take you to travel from the gate to baggage claim if you walk while riding on the moving sidewalk?
Answers
Answer:
41
Explanation:
Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds
Answers
Answer:
[tex]120\ \text{ms}[/tex]
Explanation:
Distance between the satellite and Earth = [tex]36000\ \text{km}[/tex]
Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]
Propagation delay is given by distance by the speed of light
[tex]\dfrac{36000\times 10^3}{3\times 10^8}[/tex]
[tex]=0.12\ \text{s}\times 10^3[/tex]
[tex]=120\ \text{ms}[/tex]
The uplink propagation delay of the link is [tex]120\ \text{ms}[/tex].
The cart is given an initial push up the ramp. After this push, as the car moves up the ramp, the direction of the acceleration of the cart is ________ the ramp. After the reaches its highest point, turns around, and begins moving down the ramp, the direction of the acceleration of the cart is ________ the ramp. At the highest point the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is _______.
Answers
Answer:
Explanation:
The only force acting on the cart is a component of its weight parallel to ramp downwards . No other force acts parallel to the ramp .
Even when the cart is moving up after the initial push , its weight is acting downwards so acceleration is acting downwards .
When the cart is stationary at the top position , its weight is acting downwards so acceleration is downwards at that moment also . When the cart is going downwards , still its weight is acting down so acceleration is acting downwards .
After this push, as the car moves up the ramp, the direction of the acceleration of the cart is _down _______ the ramp. After the reaches its highest point, turns around, and begins moving down the ramp, the direction of the acceleration of the cart is _down ________ the ramp. At the highest point the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is _downwards ______.
1.0 kg clay ball traveling straight down at -10 m/s hits the floor and and sticks on it
Answers
Answer:
What am I suppose to solve
Explanation:
when air mass is caught between two cold fronts the result is a _______ front.
Answer choices
A.occluded
B.warm
C.cold
D.stationary
Answers
Explanation- At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front.
what is the angle between 3i-2j-3k and the negative x axis
Answers
Answer:
Um its the vbuck card on the 3 thrid level
Explanation:
Bc its a vbuck card you know sihdg;aig
Ang larong Latin at Sisiw ay________________________.
Answers
larong pinoy
Explanation:
ito ay larong Pinoy
Two charged bees land simultaneously on flowers that are separated by a finite distance. For a few moments, the charged bees rest on the flowers. The charged bees both generate an electric field, and while the charged bees are resting on the flowers, the net electric field at some distance between them is zero.
(a) Do the bees have the same or opposite signs of charge?
Same � the electric fields point in opposite directions and therefore cancel at some midpoint.
Same � the electric fields multiply together to equal zero.
Opposite � the electric fields point in the same direction summing to zero.
Opposite � the net electric field due to the two bees points in a direction perpendicular to the direction from one bee to the other.
(b) Suppose the net electric field is zero at a distance that is closer to bee 1. Does bee 1 have a magnitude of charge greater than or less than that of bee 2?
greater than
less than
Answers
Answer:
a. Same � the electric fields point in opposite directions and therefore cancel at some midpoint.
b. bee 1 has a magnitude of charge less than bee 2
Explanation:
a. Do the bees have the same or opposite signs of charge?
They have the same charge. This is because since same charges would produce electric fields in opposite directions, that is the only way they can cancel out at some point. So, the charges are the same and the electric fields point in opposite directions and therefore cancel at some midpoint.
b. Suppose the net electric field is zero at a distance that is closer to bee 1. Does bee 1 have a magnitude of charge greater than or less than that of bee 2?
Let q be the charge on bee 1 and r its distance from the neutral electric field point. So, it electric field E = kq/r².
Also, let q' be the charge on bee 2 and d its distance from the neutral electric field point. So, it electric field E' = kq'/d².
Since E = E' at the neutral point.
kq/r² = kq'/d²
q/q' = r²/d² = (r/d)²
Given that r < d, so r/d < 1 and (r/d)² < 1
So, q/q' < 1
q < q'
So, the charge on bee 1 is less than that on bee 2
The equilibrant is the equal to the resultant magnitude but opposite in direction.
True
False
Answer and I will give you brainiliest
Answers
Answer:
The answer is False......
Answer:
true
it is equal but opposite
Which statement applies only to magnetic force instead of both electric and magnetic forces? O A. It acts between a north pole and a south pole. O B. It can push objects apart. O C. It can pull objects together. D. It acts between objects that do not touch.
Answers
Answer:
the answer would be A. electricity don't specify the direction of any cardinal points the flow of charges moves.
Answer:
A
Explanation:
I did the test on ap3x
In a crash test, a car with a mass of 1600 kg is initially moving at a speed of 20 m/s just before it collides with a barrier. The final speed of the car after the collision is zero. The original length of the car is 4.50 m , but after the collision, the smashed car is only 3.60 m long.
Required:
a. What is the average speed Of the car during the period from first contact with the barrier to the moment the car comes to a stop? You may assume the force that the barrier exerts on the car is constant during this period.
b. How much time elapses between the moment the car makes first contact with the barrier and the moment it comes to a stop?
c. Making the very rough approximation that the large force that the barrier exerts on the car is approximately constant during contact, determine the approximate magnitude of this force?
Answers
Answer:
The answer to the given points can be defined as follows:
Explanation:
In point 1:
[tex]\bold{v_f^2= v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\[/tex]
[tex]=0.9 \ m \\[/tex]
put the value in the above formula:
[tex]\to 0= 20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \ \frac{m}{s^2}[/tex]
[tex]\bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to 222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}[/tex]
for point 2:
[tex]t= 0.0900 \ s -\text{found above}[/tex]
for point 3:
[tex]\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\[/tex]
[tex]=1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N[/tex]
True or false it is impossible to determine weather you are moving unless you can touch another object
Answers
Answer: false
Explanation:
Answer:
false
Explanation:
According to Newton's First Law of motion, an object remains in the same state of motion unless a resultant force acts on it.
High-voltage power lines are a familiar sight throughout the country. The aluminum wire used for some of these lines has a cross-sectional area of 4.8 x 10-4 m2. What is the resistance of 14 kilometers of this wire
Answers
Answer:
Explanation:
For resistance of a wire , the formula is as follows
R = ρ L / S
where ρ is specific resistance , L is length and S is cross sectional area
Given L = 14 000 m ,
S = 4.8 x 10⁻⁴ m²
specific resistance of aluminum = 2.8 x 10⁻⁸ ohm-meter
Putting the values in the formula
R = 2.8 x 10⁻⁸ x 14 x 10³ / (4.8 x 10⁻⁴ )
R = 0.8167 ohm .
= .82 ohm .
Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 3.05 m/sm/s . Her husband Bruce suddenly realizes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 40.8 mm above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 7.00 ss after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance.
Required:
a. With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground?
b. Where is Henrietta when she catches the bagels?
Answers
Answer:
v = 10.46 m/s
x = 30.134 m from house
Explanation:
given data
speed = 3.05 m/s
time = 7 s
height = 40.8 mm
solution
we get here first time required to fall that is t
t = [tex]\sqrt{\frac{2\times 40.8}{9.8}}[/tex] ..................1
t = 2.88 s
now we take here initial speed that is v
so v × t = 3.05 × ( t+ 7)
v = [tex]\frac{3.05\times (2.88 + 7)}{2.88}[/tex]
v = 10.46 m/s
and
when she catch the bagel henrietta was at
x = 3.05 × ( 2.88 + 7)
x = 30.134 m from house
Two white rabbits produce a brown rabbit. How is this possible? Explain
Answers
Answer:
If one of the parents is white and the other is brown, their offspring will be either white or brown with equal probabilities. Rabbits in this population mate randomly; thus, the probability of mating two white rabbits is the same as the probability of mating between two brown rabbits.
Explanation:
What is the main cause of tides on Earth? *
1. Sun's gravity
2. Moon's gravity
Answers
Explanation: water is connected to the moon the ocean rivers all that is connected to the mood:)
Which hormone do ovaries release?
A. estrogen
B. glucagon
C. insulin
D. testosterone
Answers
Answer:
A. estrogen
Explanation:
This is released in the female reproductive organ.
A point charge of -11 [Coulombs] is placed inside a spherical conducting shell with net charge of 5 [Coulombs]. Calculate the net charge on the outer surface of the conducting shell. Enter your answer without units (example 100 for 100 [Coulombs] or -100 for -100 [Coulombs] ).
Answers
Answer:
20 C
Explanation:
To do this, is pretty easy, we just need to do a little reasoning of what is happening.
When any charge called q is placed inside this metallic shell which is spheric, all the opposite and even equal charges are induced on the inner and outer surface of the shell. Hence, we can say that if in the inner shell we have +q, in the outer will be -q.
Now, here we have the shell with 5 C, and when the charge of -11 C is placed inside the shell we can have the following changes on the inner surface and the outer surface:
Inner surface: +11 C
Outer surface: 9 + 11 = 20 C
Net charge on the outer surface: 20 CHope this helps