You start an account with $2,500 and an annual interest rate of 6.5% compounded yearly. How much is in the account after 7 years?

I need an expression and a solution​

Answer:

2+2=4

Step-by-step explanation:

lol tell me the subject and ill research and give u n answer

Answer:

4. y = -1/2x + 5

5. y = -1/3x + 3

6. y = 1

Step-by-step explanation:

For #4:

Because these lines are parallel, we know that they will have the same slope.

To get b, or the y-intercept, I just started at the point (4,4) and used the slope to work backwards to the y-axis. This is really not the best way to do it (especially with big numbers) but it works in a pinch. Also, I forgot the better way :/

For #5:

These lines are perpendicular. That means that the slopes are reciprocals of the other and, when multiplied with each other, the answer will be -1.

The reciprocal of 3 is -1/3.

To get the y-intercept, I did the same as above.

For #6:

x = 2 is a vertical line. To make a line perpendicular to it, that is, to make a line that intersects with it at 90°, the answer line will have to be horizontal.

That means that our answer is y = ?

We know that the line passes through a very specific point (2,1), and the line provided in the question already gives us the x value of this point. All we have to do is set y equal to the y value.

So, y = 1.

I hope this helps!

Answer:

6 2/9

Step-by-step explanation:

56/9

Answer:

1.53

Step-by-step explanation:

1

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140

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1.53

Answer:

[tex]\boxed {n = 26}[/tex]

Step-by-step explanation:

Solve for [tex]n[/tex]:

[tex]-413.4 = -15.9n[/tex]

-Switch sides:

[tex]-15.9n = -413.4[/tex]

-Divide both sides by [tex]15.9[/tex] and expand by multiplying both numerator and denominator by [tex]10[/tex]:

[tex]\frac{-15.9n}{-15.9} = \frac{-413.4}{-15.9}[/tex]

[tex]n = \frac{-4134}{-159}[/tex]

-Divide [tex]-4134[/tex] and [tex]-159[/tex]:

[tex]n = \frac{-4134}{-159}[/tex]

[tex]\boxed {n = 26}[/tex]

Therefore, the value of [tex]n[/tex] is [tex]26[/tex].

Answer:

45 is 125% of 36, and 36 is 80% of 45.

Step-by-step explanation:

Answer:

ans=10

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

10(4-7) /   -(4 - 1)

10(-3)  /    -(3)

-30    /    -3 =

10

Answer:

5 units will be your width and 15 will be your length so it would look like side#1=5 side #2=15 side number3 is 5 and side number 4 is 15 assuming that side 1 and 3 are parallel.

Step-by-step explanation:

yes

Answer:

2 I think thats the answer

Step-by-step explanation:

Answer:

$1400x  + $150

Step-by-step explanation:

Let the total cost of rent used for a month be $1400 plus a $150 application fee.

This means that;

Total cost (1 month) = $1400(1) + $150 = $1550

TO calculate the cost for x months, we will simply multiply x with the cost of rent for 1 month as shown.

The cost of rent for x month = 1400x * $150

The cost of rent for x month = $1400x  + $150 (application fee are paid only once)

Answer:

true, false, and false

Step-by-step explanation:

answer

32632 answer hai bro

Answer:

30 and 8

Step-by-step explanation:

30 - 8 = 22

Answer:

So when u do (-4)-(-6) it equals 2.

But when u do (-7)*(-8) it equals 56

Therefore saying that (-7)*(-8)=56 is the greatest product.

Step-by-step explanation:

Answer:

-20,250

Step-by-step explanation:

PEMDAS

Multiply left to right

45 * -10 * 45

45* -10

-450 * 45 =

-20,250

Answer:c

Step-by-step explanation:

Answer:

The required integers are x=3 and y= -9

Step-by-step explanation:

Let one the integers be x and y

An integer is 15 more than 2 times another: x=15+2y

product of the two integers is -27: x*y=27

[tex]x=15+2y ---eq(1)\\x*y=-27----eq(2)[/tex]

Solving both equations to find values of x and y

Putting value of x from equation 1 in equation 2

[tex](15+2y)*y=-27\\15y+2y^2=-27\\Rearranging:\\2y^2+15y-27=0[/tex]

This can be solved using quadratic formula:

[tex]$y=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]

Putting values and finding factors

[tex]$y=\frac{-(15)\pm\sqrt{(15)^2-4(2)(-27)}}{2(2)}$\\$y=\frac{-(15)\pm\sqrt{225+216}}{4}$\\$y=\frac{-(15)\pm\sqrt{441}}{4}$\\$y=\frac{-(15)\pm21}{4}$\\$y=\frac{-(15)+21}{4} \ or \ y=\frac{-(15)-21}{4}$\\$y=\frac{6}{4} \ or \ y=\frac{-36}{4}$\\$y=\frac{3}{2} \ or \ y=-9$[/tex]

Since y is integer so, we consider only y= -9

The value of x will be:

[tex]x*y=-27\\x*(-9)=-27\\x=\frac{-27}{-9} \\x=3[/tex]

So, the value of x is x=3

The required integers are x=3 and y= -9

Answer:

10,323,654

Step-by-step explanation:

Answer:

2/5

Step-by-step explanation:

8/20=2/5

Answer:

y= 1/5x + 0.8

Step-by-step explanation:

Hope this helps

Answer:

I think it is 13107200

Step-by-step explanation:

I think the answer might be 2,883,623. Hopefully, this helps you! :)

Answer:

e

Step-by-step explanation:

s

Answer:

There is a value of [tex]c[/tex] in (-1, 1), [tex]c = 0.577[/tex].

Step-by-step explanation:

Let [tex]f(x) = x^{3}+2\cdot x[/tex] for [tex]x \in[-1,1][/tex], we need to prove that [tex]f(x)[/tex] is continuous and differentiable to apply the Mean Value Theorem. Given that [tex]f(x)[/tex] is a polynomical function, its domain comprises all real numbers and therefore, function is continuous.

If [tex]f(x)[/tex] is differentiable, then [tex]f'(x)[/tex] exists for all value of [tex]x[/tex]. By definition of derivative, we obtain the following expression:

[tex]f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex]

[tex]f'(x) = \lim_{h \to 0} \frac{(x+h)^{3}+2\cdot (x+h)-x^{3}-2\cdot x}{h}[/tex]

[tex]f'(x) = \lim_{h \to 0} \frac{x^{3}+3\cdot x^{2}\cdot h+3\cdot x\cdot h^{2}+h^{3}+2\cdot x+2\cdot h-x^{3}-2\cdot x}{h}[/tex]

[tex]f'(x) = \lim_{h \to 0} \frac{3\cdot x^{2}\cdot h+3\cdot x\cdot h^{2}+h^{3}+2\cdot h}{h}[/tex]

[tex]f'(x) = \lim_{h \to 0} 3\cdot x^{2}+ \lim_{h \to 0} 3\cdot x \cdot h+ \lim_{h \to 0} h^{2}+ \lim_{h \to 0} 2[/tex]

[tex]f'(x) = 3\cdot x^{2}+2[/tex] (Eq. 2)

The derivative of a cubic function is quadratic function, which is also a polynomic function. Hence, the function is differentiable at the given interval.

According to the Mean Value Theorem, the following relationship is fulfilled:

[tex]f'(c) = \frac{f(1)-f(-1)}{1-(-1)}[/tex] (Eq. 3)

If we know that [tex]f(-1) = -3[/tex], [tex]f(1) = 3[/tex] and [tex]f'(c) = 3\cdot c^{2}+2[/tex], then we expand the definition as follows:

[tex]3\cdot c^{2}+2 = 3[/tex]

[tex]3\cdot c^{2} = 1[/tex]

[tex]c = \sqrt{\frac{1}{3} }[/tex]

[tex]c \approx 0.577[/tex]

There is a value of [tex]c[/tex] in the interval (-1, 1), [tex]c = 0.577[/tex].

Answer:

Answer is C

Step-by-step explanation:

There is not enough samples.

Answer:

 Yes, the variation of the sample means is small.

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

I think it is B because x+x is two x's so it would be 2x. I hope this helped have a good day

Answer:

X-intercept: -10

Y-intercept: -45

(-10),(-45)

Step-by-step explanation:

Hop this helped, Have a Wonderful Day!!

Answer:

-0.4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

3°F

Step-by-step explanation:

36 divided by 12 is 3

Answer:

3 degrees F

Step-by-step explanation:

36/12 = 3

Answer:771-71/2= 350 hamburgers and 350 +71 cheeseburgers

Step-by-step explanation: