Answer:
.6 hours
Explanation:
to find time you divide distance by speed
HELP FAST
How did the lab activities help you answer the lesson question, "How do atmospheric conditions influence weather patterns?" What did you learn from conducting this lab?
Answer:
not enough
Explanation:
information given
Answer:
Sample Response: In the lab, I discovered the air pressure, air temperature, and relative humidity conditions that create snow, rain, thunderstorms, fog, and clear skies. I learned that low-pressure areas usually experience snowy, rainy, and stormy weather, and that high-pressure areas usually experience either foggy or sunny weather. Knowing how these atmospheric conditions influence weather help weather forecasters predict weather patterns through maps and other information.
(Sorry this was not fast enough )
26. How many covalent bonds does water have?
a.1 b.2 c.3 d.4 e.5
Answer:
(b) 2
Explanation:
A bat with a mass of 0.35 kg travels at a rate of 15 m/s. What is the animal's momentum?
Answer:
momentum= mass x velocity = 0.35x15= 5.25kgm/s
A 500 kg car traveling at 20 m/s rear ends another car of 600 kg at rest. The collision is great enough that the two cars stick together after they collide. How fast will both cars be going after the collision?
Answer: its 50
Explanation:
im waffling does anybody have syrup
please help me out on this...
Only dogs
Only reptiles
Both cats and dogs
Both amphibians and reptiles
HELP YALL!!
Which nucleus completes the following equation?
Answer:
B
Explanation:
Chlorine institute
16+1=17
CI has 17 in the bottom.
Answer:C
Explanation:
Un automóvil viaja a la velocidad de 10 m/s. Se acelera Durante 12s y aumenta su velocidad hasta 70 m/s ¿Que aceleración experimenta el automóvil?
Answer:
Aceleracion = 5 m/s²
Explanation:
Dados los siguientes datos;
Velocidad inicial = 10 m/s
Velocidad final = 70 m/s
Tiempo, t = 12 segundos
Para encontrar la aceleración;
Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.
Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.
Por lo tanto, si restamos la velocidad inicial de la velocidad final y la dividimos por el tiempo, podemos calcular la aceleración de un objeto. Matemáticamente, la aceleración viene dada por la fórmula;
[tex] Aceleracion = \frac{final \; velocidad - inicial \; velocidad}{tiempo}[/tex]
Sustituyendo en la fórmula, tenemos;
[tex] Aceleracion = \frac{70 - 10}{12}[/tex]
[tex] Aceleracion = \frac{60}{12}[/tex]
Aceleracion = 5 m/s²
A hot iron ball of mass 200 g is cooled to a temperature of 22°C from 100°C. How much heat was
lost in the process?
(Ciron = 0.444 J/g°C)
Q =mcAT
Answer:
Q= -6900 J
Explanation:
use the formula Q=mC(T_2 - T_1) and sub in givens
Q=mC(T_2 - T_1)
Q= (200 g)(0.444 J/g°C)(22-100)
Q= -6900 J
The negative sign means heat is lost, which agrees with the decrease in temperature
How does a physicist define work? a force applied for a certain length of time a force applied over a distance power applied for a certain length of time power applied to something over a distance
Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.
Explanation:
Definition of work in physics
A measure of energy expended in moving an object; most commonly, force times distance is work.A circus stuntman holds himself straight out by his arms from a vertical pole. If the stuntman's center of gravity is located 0.75 m away from the pole and he weights 650 N, how much force do is arms have to apply if they exert their force upwards at 0.10 m away from the pole? [4875 N]
Answer: 4875 N
Explanation:
Given
Stuntman weight is [tex]W=650\ N[/tex]
His center of gravity is located at [tex]x=0.75\ m[/tex] away from pole
If he applies an upwards force at 0.10 m away from the pole
Suppose F is the applied force
To remain vertical, the torque of weight must be canceled by the vertical force
[tex]\Rightarrow 650\times 0.75-F\times 0.10=0\\\\\Rightarrow 650\times 0.75=F\times 0.10\\\\\Rightarrow F=\dfrac{487.5}{0.10}=4875\ N[/tex]
Please help me, I beg you
Answer:
40g
Explanation:
Solubility of Copper sulfate at 90°=60g
Solubility of potassium bromide at 90°=100g
100g-60g=40g
A new piece of exercise equipment has been added to your gym, and you try it out. To use this machine, you lie horizontal on a mat with your feet against a platform perpendicular to the mat. The platform is held by a stiff spring that is compressed when the platform moves. Your workout invovles compressing the spring by pushing on the platform with your feet. After testing compressions of the equipment, you determine that you must do 85.0 J of work to compress the spring a distance 0.170 m from its uncompressed length.What magnitude of force must you apply to hold the platform stationary at the final distance given above
Answer:
500 N
Explanation:
Since the work done on the spring W = Fx where F = force applied and x = compression length = 0.170 m (since the spring will be compressed its full length when the force is applied)
Since W = 85.0 J and we need to find F,
F = W/x
= 85.0 J/0.170 m
= 500 N
So, the magnitude of force must you apply to hold the platform stationary at the final distance given above is 500 N.
An arrow is shot at an angle of 35° and a velocity of 50 m/s. How long does it take to return to its original starting height?
Answer:
4.02 s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 35°
Initial velocity (u) = 50 m/s
Acceleration due to gravity (g) = 10 m/s²
Time of flight (T) =?
The time of flight of the arrow can be obtained as follow:
T = 2uSineθ / g
T = 2 × 35 × Sine 35 / 10
T = 70 × 0.5736 / 10
T = 7 × 0.5736
T = 4.02 s
Therefore, the time taken for the arrow to return is 4.02 s
5. A cable is attached 32.0 m from the base of a flagpole that is about to
be raised. The raising of the pole is temporarily halted when the pole is
at an angle of 60.0° with respect to the ground. If the cable exerts a ver-
tical force of 1.233 x 104 N downward and a horizontal force of 1.233 x
104 N to the left, what is the length of the flagpole?
Answer:
The length of the flagpole is approximately 87.43 m
Explanation:
The given parameters of the cable attached to the flagpole are;
The point along the flagpole at which the cable is attached = 32.0 m
The angle with respect to the ground at which the raising of the flagpole is halted = 60.0°
The downward force exerted by the cable, [tex]F_v[/tex] = 1.233 × 10⁴ N
The force exerted by the cable to the left = 1.233 × 10⁴ N
Let 'W' represent the weight of the flagpole, at equilibrium, we have;
The sum of vertical forces = 0
Therefore;
[tex]F_v[/tex] + W - R = 0
W - R = -1.233 × 10⁴ N
Taking moment about the support at the base of the pole, we get;
1.233 × 10⁴ × d × cos(60.0°) - 1.233 × 10⁴ ×d× sin(60.0°) + W × d/2 ×cos(60.0°) = 0
∴ W × d/2 ×cos(60.0°) ≈ 4513.093·d
W = 2 × 4513.093/(cos(60.0°)) ≈ 18,052.373 N
R = 18,052.373 + 1.233 × 10⁴ ≈ 30,382.373
R ≈ 30,382.373 N
Taking moment about the point of attachment of the cable to the ground, we have;
W × ((d/2) × cos(60.0°) + 32) = R × 32
∴ (d/2) = ((30,382.373 × 32/18,052.373) - 32)/(cos(60.0°)) ≈ 43.71281
d = 2 × 43.71281 ≈ 87.43
The length of the flagpole, d ≈ 87.43 m
An isloated point charge produce an electric field with magnitude E at a point 2 m away. At a point 1 m from the charge magnitude of the charge is .. A. E B. 2E C. 4E D. E/2
Answer:
the correct answer is C, E’= 4E
Explanation:
In this exercise you are asked to calculate the electric field at a given point
E = [tex]k \frac{q}{r^2}[/tex]
indicates that the field is E for r = 2m
E = [tex]\frac{ k q}{4}[/tex] (1)
the field is requested for a distance r = 1 m
E ’= k \frac{q}{r'^2}
E ’= k q / 1
from equation 1
4E = k q
we substitute
E’= 4E
so the correct answer is C
Which are parts of the middle ear? Check all that apply.
a) anvil
b) ear canal
c) eardrum
d) hammer
e) stirrup
f) auricle
Answer:
middle ear has three bones! the hammer, anvil, stirrup, and ear drum
Explanation:
Pls help I want to give more points to people this is for 100. yes 100 points
Who is number 15 on the Kansas City Chiefs
Answer:Patrick Mahomes
Explanation:
Answer:
Patrick Lavon Mahomes II
Explanation:
In which circuit will the bulb or bulbs glow brightest?
a-A simple circuit with one bulb and one battery
b-A simple circuit with one bulb and two batteries
C-A simple circuit with two bulbs and one battery
Answer:
B - a simple circuit with one bulb and two batteries.
The circuit that would glow brightest is b - A simple circuit with one bulb and two batteries
Electric circuitThis is the path for transmitting current. It usually consists of an electrical energy source and an electrical load.
In any circuit, the electrical power available is determined by the number of batteries available (energy source) and thus the current.
Ohm's lawSince we know according to Ohm's law V = iR where
V = voltage, i = current and R = load.So, making i subject of the formula, we have i = V/R .
So, i ∝ 1/R this shows that the current is inversely proportional to the load.
Circuit that would glow brightesta simple circuit with more current and less load would glow brightest. So, having a simple circuit with two batteries increases the current in the circuit and having only one bulb means that there is less load in the circuit. Thus, the circuit with one bulb and two batteries will glow brightest.So, the circuit that would glow brightest is b - A simple circuit with one bulb and two batteries
Learn more about electric circuit here:
https://brainly.com/question/19651288
Brainliest for correct answer :)
What part of the atom takes up most of the atoms space?
The atom
The electron cloud
The nucleus
The bottom part
Answer:
The electrons
Explanation:
Which describes the innermost layer of Earth?
Answer and Explanation:Option A->The innermost layer of the earth is known as the core. It is divided into inner core and outer core. It comprises of a high concentration of nickel and iron.
The diagram shows a skydiver at different points of her jump. At what point would her
acceleration be greatest?
A.
B.
C.
D.
Read the article Watering Livestock with Renewable Energy.
Why does it make sense for ranchers to use renewable energy to pump water?
Animals do not need water during the summer.
In most of the United States, there is not enough wind to run pumping systems.
Solar energy is strongest in the winter, when water is needed for animals and crops.
Wind and solar energy help save money and reduce air pollution.
Answer:
D. Wind and solar energy help save money and reduce air pollution.
Explanation:
Answer:
d
Explanation:
edge 2021
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determine how
the cars perform based on which scenario?
O on racetracks
O in real-world conditions
O in flooded environments
O on closed courses
Next
Submit
Save and Exit
return
Answer:
B on EDGE
Explanation:
If a force of 3000 N can move a crate at an acceleration of 9.2 m/s2, what is the mass of the object?
Answer:
326 kg
Explanation:
m=f/a
3000/9.2=326 kg
When humans pollute lakes, rivers, and streams,
Answer:
when waterways are polluted it affects all forms of life in the area - including us
expression:
for example when Lakes streams and ponds are polluted it can kill or harsh fish and other Wildlife that lives there!
hope that helps !
Observe: Click Reset. Turn on Show velocity vector and Show velocity components. Set vinitial to 50 m/s and set θ to 45.0 degrees. Click Play. Focus on the blue and red arrows that represent the vertical and horizontal components of the golf ball’s velocity. As the ball flies through the air, what do you notice about the blue (vertical) arrow?
Answer:
v_y = v_{oy} - g t
where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses
Explanation:
In this exercise you are asked to observe the change in velocity in a projectile launch.
If we assume that the friction force is small, the velocity in the x-axis must be constant
vₓ = v₀ₓ
Therefore, the arrow (red) that represents this movement must not change in magnitude.
In the direction of the y axis, the acceleration of gravity is acting, so the magnitude of the velocity in this axis changes
v_y = v_{oy} - g t
where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses
6. Calculate the pressure exerted on an elevator floor which has an
area of 6 m², if 20 people whose combined force is 1500 N are
standing on it.
Answer:
Hope this helps you out if you could please leave 5 stars or brainiest thank you
A car drives 30 m north in 1.5 seconds and drives 60 east in 2 seconds. What is the average velocity
Answer:
19.2 m/s
Explanation:
From the question,
Velocity = displacement/time = d/t
V = d/t.................................. Equation 1
Average velocity = Total displacement/ total time
Total dispalcement = √(30²+60²) = √4500 = 67.08 m
Total time = 1.5+2 = 3.5 s.
Substitute these value into equation 1
V = 67.08/3.5
V = 19.2 m/s.
Hence the average velocity is 19.2 m/s
The parameter given for the car during transit is 30 m north in 1.5 seconds and drives 60 east in 2 seconds, we want to find the average velocity.
average velocity is 19.2 m/s
Solution
The expression for Average velocity is
Average velocity = Total Displacement/ Total time Taken...............Eqn 1
Total Displacement = √(30²+60²) = √4500 = 67.08 m
Total time = 1.5+2 = 3.5 s.
From the Equation 1
Average Velocity = 67.08/3.5
V = 19.2 m/s.
Therefore, the average velocity is 19.2 m/s
Learn more about average velocity :
https://brainly.com/question/24739297
What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original
magnitude?
Answer:
F' = 64 F
Explanation:
The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Where
q₁ and q₂ are charges
r is the distance between charges
When each charge is doubled and the distance between them is 1/4 its original magnitude such that,
q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)
New force,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]
Apply new values,
[tex]F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F[/tex]
So, the new force becomes 64 times the initial force.