Answer:
The answer is 109.76 gExplanation:
In order to find out the mass of KOH to be used we use the formula
m = c × M × vwhere
m is the mass
c is the concentration in mol/dm³
M is the molar mass
v is the volume in dm³
From the question
c = 2.8 M
v = 700 mL = 0.7 dm³
Mr( K) = 39 , Mr(O) = 16 , Mr(H) = 1
we have
Molar mass of KOH = 39 + 16 + 1
= 56 g/mol
So we have
m = 2.8 × 56 × 0.7
We have the final answer as
109.76 gHope this helps you
Item 4
Which statement is one of the three parts of cell theory?
Cell organelles can be membrane-bound or not membrane-bound.
Cells make up tissues, tissues make up organs, organs make up systems, systems make up organisms.
The smallest living things are single cells, and cells are the functional units of multicellular organisms.
There are three types of cells, prokaryotic, eukaryotic plant, and eukaryotic animal.
What is the mass in grams of 2.4 x 10-2 mol K2SO4
Consider the balanced equation below. Upper P Upper C l Subscript 3 Baseline + Upper C l Subscript 2 Baseline right arrow Upper P Upper C l Subscript 5. What is the mole ratio of PCl3 to PCl5? 1:1 2:1 3:5 5:3
Answer : The mole ratio of [tex]PCl_3[/tex] to [tex]PCl_5[/tex] is 1 : 1.
Explanation :
Balanced chemical reaction : It is a chemical reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.
The balanced chemical reaction is:
[tex]PCl_3+Cl_2\rightarrow PCl_5[/tex]
By the stoichiometry of the reaction we can say that 1 mole of [tex]PCl_3[/tex] reacts with 1 mole of [tex]Cl_2[/tex] to give 1 mole of [tex]PCl_5[/tex].
From this we conclude that the mole ratio of [tex]PCl_3[/tex] to [tex]PCl_5[/tex] is 1 : 1.
Hence, the mole ratio of [tex]PCl_3[/tex] to [tex]PCl_5[/tex] is 1 : 1.
Answer:
A
Explanation:
Given the mass of carbon on the periodic table (12.01 amu), which isotope do you think is the most abundant? Explain WHY in complete sentences. *
Answer:
Carbon-12
Explanation:
Carbon-12 is a carbon with 6 protons and 6 neutrons. Since the AMU for an element is calculated by averaging all naturally occurring isotopes, we can see that 12 in the most abundant. (Since 12.01 is very close to 12, the only reason it is not exactly 12 is because there are other isotopes like carbon-13 or carbon-14 but in low amounts)
find the frequency factor at 273 k for the decomposition of nitrogen dioxide, which has the reaction: 2no2(g) → 2no(g) + o2(g) the activation energy of the reaction is 111 kj/mol and the rate constant is 1.0 x 10-22 s-1. round to two decimal places.
Answer:
0.17 s⁻¹
Explanation:
Step 1: Given data
Temperature of the reaction (T): 273 KActivation energy (Ea): 111 kJ/molRate constant (k): 1.0 × 10⁻²² s⁻¹Ideal gas constant (R): 8.314 × 10⁻³ kJ/mol.KFrequency factor (A): ?Step 2: Calculate the frequency factor
We will use the Arrhenius equation.
ln k = lnA - (Ea/R).(1/T)
lnA = ln k + (Ea/R).(1/T)
lnA = ln 1.0 × 10⁻²² s⁻¹ + [(111 kJ/mol)/(8.314 × 10⁻³ kJ/mol.K)].(1/273K)
A = 0.17 s⁻¹
What is the density of a block of gold that occupies 1000 ml and has a mass of 3.5 kg? Show your work
Answer:
Density of block of gold is 3.5 g/cm³.
Explanation:
Given data:
Volume of block = 1000 mL
Mass of block = 3.5 kg (3.5×1000 = 3500 g)
Density of block = ?
Solution:
Density of substance is calculated by dividing the mass of substance over its volume.
Formula:
d = m/v
d = 3500 g/ 1000 mL
d = 3.5 g/mL
or
d = 3.5 g/cm³ (1ml = 1cm³)
Please help me!!!:)))
Answer:
blocks 1 and 2 the rhdh huff hgfhh5
1
An atom of element Q contains 19 electrons, 19 protons and 20 neutrons.
What is Q?
A calcium
B potassium
С
strontium
D
yttrium
Answer:
b)Potassium is the right answerAnswer:
B. Potassium
Explanation:
The element with 19 electrons, 19 protons, and 20 neutrons is potassium
where are electrons found in an atom
Answer:
The electrons are found on the outer shell of the atom.
Explanation:
If the density of aluminum is 2.7g/ml, what is the volume of 12.0g?
Answer:
The answer is 4.44 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\ [/tex]
From the question we have
[tex]volume = \frac{12}{2.7} \\ = 4.4444444....[/tex]
We have the final answer as
4.44 mLHope this helps you
What is the mass in grams of 5.9 mol c8 h18
Answer:
mass = density × volume = 0.67 × 1.00 = 0.67 kg = 670 g. The molar mass of octane, C8H18, is 8 × 12.01 (C) + 18 × 1.008 (H) = 114.224.
Explanation:
20
How do you determine the number of barium atoms in the formula below?
4Ba(OH)2
F
# of Ba atoms = coefficient 4 + subscript 1 = 5
G
# of Ba atoms = coefficient 4 X subscript 1 = 4
H
# of Ba atoms = subscript 4 X coefficient 2 = 6
# of Ba atoms coefficient 1 + subscript 1 = 2
J
Answer:
G is correct option:
# of Ba atoms = coefficient 4 × subscript 1= 4
Explanation:
Formula:
4Ba(OH)₂
G is correct option:
# of Ba atoms = coefficient 4 × subscript 1= 4
Because there are only 4 atoms of Ba in given formula.
Ba(OH)₂ contain one atom of Ba while in question there are 4 moles of Ba(OH)₂ present thus total 4×1 = 4 atoms of Ba present.
Other options are incorrect. Because,
F:
# of Ba atoms = coefficient 4 + subscript 1 = 5
This shows given formula contain 5 Ba atoms. So it is incorrect.
H:
# of Ba atoms = subscript 4 × coefficient 2 = 6
This shows that subscript is 4 which is incorrect because coefficient is 4 and subscript is 1.
j:
# of Ba atoms = subscript 1 + coefficient 1 = 2
This option shows that subscript is one which is correct but coefficient is incorrect. The coefficient of Ba is 4 and coefficient is always multiply with subscript not added. So this option is also incorrect.
You are given 3 liquid samples – A, B, C and told that one is water, one is ethanol, and one is ether (d=0.700 g/mL). Each sample is 10.0 mL. the masses are as follows: A = 10.0 g, B= 7.00 g, C = 8.00 g. Identify each of the substances using density problems.
Answer:
im just trying to get work done i will help u if i knew it
Which is denser a liquid or solid why?
Answer:
Liquids are usually less dense than solids but more dense than air. Temperature can change a liquid's density. For example, increasing the temperature of water causes the molecules to spread farther apart. The farther apart the molecules are, the less dense the water is.
Answer:
Solids are usually much more dense than liquids and gases, but not always.
Explanation:
Mercury, a metallic element that is a liquid at room temperature, is denser than many solids. Aerogel, a very unusual human-made solid, is about 500 times less dense than wate
How many moles would be in 24.23 grams of SrSO4?
Use two digits past the decimal for all values.
Answer:
about 0.13 mol
Explanation:
To find number of mols when given grams you first have to find the molar mass of the compound. This is done by adding up the atomic masses of the element in the compound. So Sr= 88 g/mol S=32 g/mol and O=16 g/mol. Then 88+32+(16x4)=184. Then using this you can convert from grams to mols by dividing the grams by the molar mass. So, 24.23/184 equals about 0.13 mol.
80.20%, 11.01 amu
19.80%, 10.81 amu
What is the Average Atomic Mass?
A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 50.1 g of the compound is burned, 91.8 g of carbon dioxide and 25.1 g of water are collected. In order to determine the moles of carbon in the compound, first determine the moles of carbon dioxide that were produced from the combustion.
Answer:
[tex]C_{3}H_4O_2[/tex]
Explanation:
Hello,
In this case, since the carbon of the initial compound is present in the carbon dioxide product, we can compute the mass and moles of carbon in the compound:
[tex]n_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =2.09molC\\\\m_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2}*\frac{12gC}{1molC} =25.0gC[/tex]
Next, the mass and moles of hydrogen in the compound, is contained in the yielded amount of water, thus, we compute the mass and moles of hydrogen in the compound:
[tex]n_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =2.79molH\\\\m_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} *\frac{1gH}{1molH} =2.79gH[/tex]
In such a way, the mass of oxygen comes from the mass of the compound minus the mass of carbon and oxygen:
[tex]m_O=50.1g-25.0g-2.79g=22.31gO[/tex]
And the moles:
[tex]n_O=22.31gO*\frac{1molO}{16gO}=1.39molO[/tex]
Then, we compute the subscripts by diving the moles of C, H and O by the moles of oxygen as the smallest moles:
[tex]C:\frac{2.09}{1.39}=1.5 \\\\H:\frac{2.79}{1.39}=2\\ \\O:\frac{1.39}{1.39} =1[/tex]
After that, we write:
[tex]C_{1.5}H_2O[/tex]
Which must be shown in whole number only, thereby we multiply the subscripts by 2, so the empirical formula turns out:
[tex]C_{3}H_4O_2[/tex]
Best regards.
PLEASE HELP!!!
what was the volume of air that has a volume of 6.00L at 120870 Pa, if the original pressure was 250020 Pa?
Answer:
The answer is 2.90 LExplanation:
In order to find the original pressure , we use the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the original volume
[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]
From the question
P1 = 250020 Pa
P2 = 120870 Pa
V2 = 6 L
We have
[tex]V_1 = \frac{120870 \times 6}{250020} = \frac{725220}{250020} \\ = 2.90064794...[/tex]
We have the final answer as
2.90 LHope this helps you
2NH.
N2 + 3H2
Reactants
Product
On the balanced equation above, how many
atoms of each element are in the reactant?
N =
H =
Answer:
N=2
H=6
Explanation:
1.Balance a chemical equation in terms of moles.
2.Use the balanced equation to construct conversion factors in terms of moles.
3.Calculate moles of one substance from moles of another substance using a balanced chemical equation.
The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.
(P.s it could also be where you have to solve it in which you have to simplify it first then solve it.) like adding them all up.
Hope this is the answer. :)
Which of the following characteristics will not help which of the following characteristics WILL NOT help you tell whether two solids are the same or are different substances?
A. Color
B. Hardness
C. Shape
D. Melting point
g Calculate the mass percent of sodium bicarbonate in the solution that has 7.00 g of solution and 0.052 Kg of water.
Answer:
11.86%
Explanation:
First, we convert both solvent and solute to the same unit, say, kg. We have.
Mass of Sodium Bicarbonate = 7g = 7/1000 kg = 0.007 kg
Mass of water = 0.052 kg.
Formula for the mass percent is
% of sodium bicarbonate = [(mass of sodium bicarbonate) / (mass of total solution) * 100%]
Total mass of solution = 0.007 + 0.052 Total mass of solution = 0.059
% of sodium bicarbonate = 0.007 / 0.059 * 100%
% of sodium bicarbonate = 11.86%
Therefore, the mass percent of sodium bicarbonate I'm the solution is 11.86%
A chemist prepares a solution of silver(II) oxide by measuring out 0.0013 of silver(II) oxide into a 100 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's silver(II) oxide solution. Be sure your answer has the correct number of significant digits.
Answer:
1.3x10⁻⁸ mol/L
Explanation:
0.0013μmol, Calculate concentration in mol/L
To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:
Moles silver(II) oxide:
0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles
Liters solution:
100mL * (1L / 1000mL) = 0.1L
That means concentration in mol/L is:
1.3x10⁻⁹ moles / 0.1L =
1.3x10⁻⁸ mol/LKc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium concentration (in M to 4 decimal places) of NO?
Answer:
The equilibrium concentration of NO is 0.02124 M.
Explanation:
Given that,
Initial concentration of NOBr = 0.878 M
[tex]k_{c}=3.07\times10^{-4}[/tex]
Temperature = 24°C
We know that,
The balance equation is
[tex]2NOBr\Rightarrow 2NO+Br_{2}[/tex]
Initial concentration is,
[tex]0.878\Rightarrow 0+0[/tex]
Concentration is,
[tex]-2x\Rightarrow 2x+x[/tex]
Equilibrium concentration
[tex]0.878-2x\Rightarrow 2x+x[/tex]
We need to calculate the value of x
Using formula of concentration
[tex]k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}[/tex]
Put the value into the formula
[tex]3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}[/tex]
[tex]2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}[/tex]
[tex]2x^2=0.0002367+0.001228x^2-0.0010536x[/tex]
[tex]2x^2-0.001228x^2+0.0010536x-0.0002367=0[/tex]
[tex]1.998772x^2+0.0010536x-0.0002367=0[/tex]
[tex]x=0, 0.01062[/tex]
We need to calculate the equilibrium concentration of NO
Using formula of concentration of NO
[tex]concentration\ of\ NO=2x[/tex]
Put the value of x
[tex]concentration\ of\ NO=2\times0.01062[/tex]
[tex]concentration\ of\ NO=0.02124[/tex]
Hence, The equilibrium concentration of NO is 0.02124 M.
What is the atomic number of arsenic (As)?
O A. 33
O B. 15
C. 75
D. 4
SUB
Answer:
33
Explanation:
HELP PLEASE, IM ON A TIMER ⏱
Which describes an attribute of nonrenewable resources?
A.) exist in fixed amounts
B.) are unlimited
C.) can often be replaced in a short time
D.) are replaced faster than they are used
Answer:
A. exist in fixed amounts or available in limited supplies
Explanation:
Answer:
A
Explanation:
Balance the equations by inserting coefficients as needed.
equation 1:
CaCO3 + HCl -> CaCl2 + CO2 + H2O
CaCO3+HCl⟶CaCl2+CO2+H2O
equation 2:
C6H12O2 + O2 -> CO2 + H2O
C6H12O2+O2⟶CO2+H2O
Answer:
1. CaCO3 + 2HCl → CaCl2 + H2O + CO2
2. C6H12O2 + 8O2 → 6CO2 + 6H2O
Explanation:
The balanced chemical equation is (i) CaCO3+2HCl⟶CaCl2+CO2+H2O
(ii) C6H12O2+ 8O2⟶CO2+6H2O
What is balanced chemical equation?An equation with equal amounts of every atom of an element on both endpoints of the arrow was called a balanced equation.
Given chemical equation is:
(i) CaCO3+HCl⟶CaCl2+CO2+H2O
It can be seen that in left side of the chemical equation count of chlorine atom is one while right side of the chemical equation it is two. So, by multiplying 2 as a coefficient in the right side of the equation. Balanced chemical equation will be
CaCO3+2HCl⟶CaCl2+CO2+H2O
(ii) C6H12O2+O2⟶CO2+H2O
It can be seen that, there are 12 hydrogen in the left side of the reaction while it is two hydrogen in the right side of the reaction. By multiplying 6 as a coefficient of hydrogen. Hence, the balanced chemical equation will be
C6H12O2+ 8O2⟶CO2+6H2O
The balanced chemical equation is
(i) CaCO3+2HCl⟶CaCl2+CO2+H2O
(ii) C6H12O2+ 8O2⟶CO2+6H2O
To know more about balanced chemical equation
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How many of the 7 traits of living things have
Answer:
What do you mean by this?
Explanation:
informative essay on bohrs Thomson's and rutherford model of the atom
Ok
A plant part that contains a tiny new plant, or embryo
seed
spore
root
flower
2. What is the purpose of subscripts?
3. What is the difference between monatomic and polyatomic ions?
4. How do the names of monatomic anions end?
5. When are Roman numerals used in cation names ?
2. Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.
3. The main difference between monatomic and polyatomic ions is that monatomic ions are composed of single atoms whereas polyatomic ions are composed of two or more atoms per ion.
4. These are nonmetal elements which have accepted extra electrons. These ions are relatively few in number and are listed below. Monatomic anions are named by taking the root of the element name and applying an -ide ending. Other important simple anions.
5. This is indicated by assigning a Roman numeral after the metal. The Roman numeral denotes the charge and the oxidation state of the transition metal ion. For example, iron can form two common ions, Fe2+ and Fe3+. To distinguish the difference, Fe2+ would be named iron (II) and Fe3+ would be named iron (III).