. you have requested helicopter transportation of a critical burn patient. the remote nature of the accident will force the helicopter to land on an incline. from which direction should you approach the helicopter?

The stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.

Vsg = Vsw + Vwg

Vsg = Relative velocity of stick figure wrt ground

Vsw = Relative velocity of stick figure wrt walkway

Vwg = Relative velocity of walkway wrt ground

Let the stick figure that is walking to the west be A and the stick figure that is walking to the east be B.

For A,

Vsw = - 1 m / s

Vwg = - 0.5 m / s

Vsg = - 1 - 0.5

Vsg = - 1.5 m / s

For B,

Vsw = 1 m / s

Vwg = - 0.5 m / s

Vsg = 1 - 0.5

Vsg = 0.5 m / s

The negative symbol indicates direction. So Vsg for A > Vsg for B

Therefore, the stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.

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The time taken for the train of mass 1.4 107 kg to reach the speed of 60 km/h is  362.39 seconds

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of the train = 1.4 × 10⁷ kg

constant force F = 6.5  × 10⁵ N

Using Newton's second law

F = ma

a = F/m

  = 6.5  × 10⁵ N /1.4 × 10⁷ kg

  =  0.046 m/s²

This acceleration accelerates from

initial velocity u = 0

Final velocity v = 60 km/hr = 16.67 m/s

Using,

V = U + at

t = V - U/a

 = 16.67 / 0.046

 =  362.39 seconds

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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According to the idea behind active galactic nuclei, heated plasma in an accretion disc that revolves around the black hole is principally responsible for the active galactic nucleus' high luminosity.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum. Is called active galactic nucleus.

A light-emitting object's radiant power, which is measured in absolute terms as luminosity, is the electromagnetic power that it radiates out over time. The total quantity of electromagnetic energy released by a star, galaxy, or other celestial object in a given amount of time is measured as luminosity in astronomy.

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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Yes, a spectrophotometer can be used to measure the absorption of a particular wavelength of light that is not visible to the human eye.

A spectrophotometer is an instrument used to measure the intensity of electromagnetic radiation at different wavelengths.

Spectrophotometry is a standard biological technique used to measure light absorption or the amount of chemicals in a solution. This technique uses a light beam which passes through the sample, and each compound in the solution absorbs or transmits light over a certain wavelength.

Spectrophotometry is the quantitative analysis of electromagnetic spectra by use of a spectrophotometer; especially in order to determine the structure or quantity of a substance.

Using the spectrophotometer, absorption of light can be measured, even if we cannot observe it unaided.

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Answer:

Radius 20 m.

Explanation:

Given:

aₙ = 1.4 m/s²

V = 5.3 m/s

___________

R - ?

Centripetal acceleration:

aₙ = V² / R

Radius:

R = V² / aₙ

R = 5.3² / 1.4 ≈ 20 m

The heated (brown) air is separated from the cold (blue) air bubble on the left. A(n) is the term used to describe

"Fronts" are the borders that are formed when air masses converge. Cold front in three dimensions. Temperature changes caused by a front's motion can be used to identify it. A cold front causes a warmer air mass to be replaced by a colder one. Another name for it is a "dryline" or "dry front." a line or zone between two air masses that have different densities and, as a result, are typically at different temperatures. A moving front is given a name based on the air mass that is advancing; for example, a cold front if colder air is going forward. The front is the line separating two air masses. A front typically has overcast, stormy weather. Four separate fronts exist: the Cold, Warm, Stationary, and Occluded fronts. A cold front arises when two cold air masses collide with warm air masses.

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The total resistance of the circuit is 25 ohms.

In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.

The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.

[tex]R_{total}[/tex] = 100/4 = 25ohms

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The average acceleration of the dragster during this time interval is 44.57 m/s² and the average net force on the dragster during this time is 38915N.

The initial speed U of the dragster is zero while the final speed V of the dragster is 26.3m/s. The director runs for a total of time t of 0.59 seconds.

According to the equation of motion,

V = U+at

Putting values,

26.3 = 0.59a

a = 44.57 m/s².

So, the acceleration of the dragster is 44.57 m/s².

The force on the director is given by,

F = ma

m mass of the dragster and a is the acceleration of the dragster.

F = 873×44.57

F = 38915N.

So, the net average force on the dragster during this time is 38915 Newton.

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The law that explains after energy conversions, the total amount of energy has the same amount as the original amount of energy is the Law of conservation of energy.

The state law of conservation of energy is that energy cannot be created, the energy cannot be destroyed, and the energy can be converted from one form of energy to another form of energy. Examples like mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy.

If an apple fell from a branch of a tree

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The value of the spring constant of the ideal spring is 106.9 N/m.

The mass suspended by the student is 0.3 kg from the ideal soring and the equilibrium displacement is 5.5 cm or 0.055 cm.

The work done by the gravity will be equal to the work done by the spring,

Mgx = 1/2Kx²

Where,

x is the equilibrium displacement,

K is the spring constant,

M is the mass,

g is acceleration due to gravity,

Putting values,

0.3 x 9.8 x 0.055 = 0.5 x K x 0.055 x 0.055

K = 106.9 N/m.

The spring constant is 106.9 N/m.

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The wool becomes positively charged because it gives up electrons to the rubber rod whereas wool is rubbed against a Nylon strip so the wool will steal electrons from the Nylon and form a negative charge.

When the woolen cloth is stroke against the plastic, both wood and plastic get electrified due to friction built while rubbing. So, plastic has greater electron affinity (ability to attract electrons) in a contrast to wool, therefore, plastic acquires a negative charge and wool obtains a positive charge. When you rub a balloon with a cloth made of wool, the balloon captures electrons from the wool, leaving the balloon with a negative charge and the wool with a positive charge. If both balloons are pat with wool, they will both have the same charge (negative) and therefore will repel each other.

So we can conclude that Wool is a conductive material, which means it readily gives away its electrons. accordingly, when you rub a balloon on wool.

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Yes, a spectrophotometer could be used to measure the absorption of a particular wavelength of light that is not visible to a normal human eye.

Although we cannot directly observe the absorption of this light, it is quantifiable. A spectrophotometer, which measures the absorption of light at certain wavelengths (whether visible or not) by a solution, may be used to compute the concentration. The popular and accessible technique of spectrophotometry may be used to determine the concentration of compounds in a solution or the degree of light absorption.

 When a light beam is focused through the sample, each component either absorbs or transmits light of a certain wavelength. They are combined with quantifiable and visible colored byproducts. Another is that, as observed by a spectrophotometer, colorless substances generally absorb light from the region of the spectrum that is imperceptible to the human eye.

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Explanation:

Major activity injuries include:

Ansver:

All of the above

The magnitude of its acceleration is a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] )

The length of the vector is all there is to an acceleration's magnitude. To put it another way, writing the magnitude of acceleration indicates how quickly velocity varies. In the standard international (SI) system, the acceleration is measured in units of meters per second square.

Let T be the rope's tension, assuming it has no mass.

T =( 2[tex]W_{A}[/tex])a/g ------- 1

([tex]W_{B}[/tex]) - T = ([tex]W_{B}\\[/tex])a/g ------- 2

Add 1 and 2

[tex]W_{B}[/tex] =(a/g)( 2[tex]W_{A}[/tex]+ [tex]W_{B}[/tex])

a= g ([tex]W_{B}[/tex])/( 2[tex]W_{A}[/tex] +[tex]W_{B}[/tex] ).

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The initial speed of the projectile launched at an angle of 30 above the horizontal from the top of a 10m high cliff is 34.2 m / s

According to equations of motion,

s = u t + 1 / 2 at²

s = Displacement

u = Initial velocity

t = Time

a = Acceleration

H = 10 m

t = 4 s

θ = 30°

g = 9.8 m / s²

Here the object is launched art an angle from a height. So,

s = - H = - 10 m

u = uy

While considering vertical motion,

a = - g = - 9.8 m / s²

- H = uy t - 1 / 2 g t²

- 10 = 4 uy - 1 / 2 * 9.8 * 4²

4 uy = 68.4

uy = 17.1 m / s

sin θ = uy / u

u = 17.1 / sin 30°

u = 34.2 m / s

Therefore, the initial speed of the projectile is 34.2 m / s

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The average acceleration vector of the ball is - 9.78 m/s².

When you throw a ball upward with an initial speed, it will go up until reaching its highest peak then it will go down. So the ball doing non-uniform motion. The formula for non-uniform motion including initial speed, and final speed with time is

v = u+at

v-u = at

[tex]a = \frac{v - u}{t}[/tex]

[tex]a = \frac{- 4.5 - 4.5}{0.92}[/tex]

[tex]a = \frac{- 9.0}{0.92}[/tex]

a = 9.78 m/s²

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Answer:

Explanation:

Refraction of a light ray may be defined as:

D. changing direction while crossing a boundary ​

To find the collision rate, known the magnitude.

What is magnitude?

Magnitude typically refers to size or distance. By comparing the size and motion speed of the thing, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.

What is mean by collision rate?

The frequency of collisions between a single particle of radius m and particles with masses ranging from (m1, m1 + m1) to (m, m1) is proportional to their concentration, n(m1) m1, where (m, m1) is the rate constant for collisions between the two particles of masses m and m1 and depends on the process. 

u=140kmph

t=7.oms

v=0

E=M(V-U)/t

⇒m(0-140)/0.007×5/18m/s

⇒5555.55 (m) N

E=(5555.55) (mass) N

Therefore, the collision lasts is 5555.55(m) N.

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The force would have to work on the block till a distance of 15.66m farther to have 56 joules of kinetic energy.

The work done is given by the product of the force applied and the distance covered along the direction of force.

So we can write,

W = F.s

Where w is the work done if is the force and S is the distance covered.

According to work energy theorem, the work done is equal to the change in kinetic energy.

The force applied in this case is 3 Newton and the body has no till a distance of 3m. Let us assume that the block is moved till a distance x in order to achieve a kinetic energy of 56 joules.

So, it can be written,

3(3+x) = 56

Solving,

9+3x = 56

3x = 47

x = 15.66 m.

So, it is required to move the body by a distance of 15.66 m.

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The greater amount of energy is transferred during the first case and the difference in energies is: 84 × 10³ J

Internal energy refers to all energy within a particular system, including the kinetic energy of molecules and the energy stored in chemical bonds between molecules. The interaction of heat, work, and internal energy involves the transfer and conversion of energy whenever a change is made to the system.

The amount of heat (Q) gained or lost from the sample can be calculated using the formula Q = mcΔT. where m is the mass, c is the specific heat, and ΔT is the temperature change.

For the first case:

Q = mcΔT

Q = mc(T₁ - T₂)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 10 °C

T₂ = -15 °C

Q₁ = 1000 × 4.2 × (10 -(-15))

Q₁ = 105 × 10³ J

For the second case:

Q = mcΔT

Q = mc(T₂ - T₁)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 60 °C

T₂ = 65 °C

Q₂ = 1000 × 4.2 × (65 - 60)

Q₂ = 21 × 10³ J

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Work done by the system is calculated to  - 456.863 J, when pressure and volume change is given.

For a gas, work is the product of the pressure and the volume during a volume change. Relationship between pressure and volume can be found out by Boyle's Law. As the pressure on a gas increases then the volume of the gas decreases because the gas particles are forced closer together.

W= -p ΔV

p is pressure and ΔV is volume change

Given that volume changes from 0.160 liters to 0.570 liters

ΔV = 0.570 - 0.160

= 0.41 L

Given p = 11 atm

Now, W = -11 * 0.41

As 1 atm L = 101.3 J

Hence W=  -11 * 0.41 * 101.3

Work = - 456.863 J (work done by system)

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The submerged fraction of a person when floating gently in fresh water is 0.989. The fraction of a person is submerged when floating gently in salt water with a density of 1027 kg/m³ is 0.963

fs = ρo / ρf

fs = Submerged fraction

ρo = Density of object

ρf = Density of fluid.

a ) For fresh water,

ρo = ρp = 989 kg / m³

ρf = ρw = 1000 kg / m³

fs = 989 / 1000

fs = 0.989

b ) For salt water,

ρo = ρp = 989 kg / m³

ρf = ρs = 1027 kg / m³

fs = 989 / 1027

fs = 0.963

Therefore,

a ) In fresh water, the submerged fraction is 0.989

b ) In salt water, the submerged fraction is 0.963

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More force is exerted by the table against her finger than she exerts against the surface.

Active power is the force behind motion or change that is exerted or brought to bear. the elements of nature

The term "force" has a clear definition in science. It is quite acceptable to refer to a force of this level as a push or a pull. An object does not "have in it" or "contain" a force. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.

The newton  is the SI unit of force. As they relate to force, the base units are: The symbol for the length measurement known as the meter is m. The symbol for the kilogram, a unit of mass the sign s represents the second, a unit of time.

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Mv is equal to m - 2.5 log(d/10)2. There is a minus sign in the expression because stars distant than 10 pc have Mv that is more negative than m. Make careful you provide the star's given distance in parsecs (1 pc = 3.26 ly = 206265 AU) if you use this formula.

The moon can appear to be nearly -13 magnitude bright, the moon can appear to be -6 magnitude bright, and stars can get as bright as nearly -1.5 magnitude.

The star's actual magnitude is determined by subtracting its apparent magnitude by five times the trigonometric parallax of its distance from the star.

First-magnitude stars have apparent magnitudes less than +1.50, making them the brightest stars in the night sky. In the first century B.C., Hipparchus invented the magnitude scale. He assigned first magnitude to the 20 brightest stars and sixth magnitude to the stars that are faint enough to be seen with the unaided eye.

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Answer:

[tex]\textsf{a)} \quad x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]

[tex]\textsf{b)} \quad V=379037.8082\; \sf mm^3[/tex]

Explanation:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Volume of a rectangular prism}\\\\$V=w\:l\:h$\\\\where:\\ \phantom{ww}$\bullet$ $w$ is the width of the base. \\ \phantom{ww}$\bullet$ $l$ is the length of the base. \\ \phantom{ww}$\bullet$ $h$ is the height.\\\end{minipage}}[/tex]

Given:

The dimensions of the rectangular prism in terms of x are:

Substitute these values into the formula for volume to create an equation in terms of x:

[tex]\begin{aligned}\implies V&=(150-2x)(200-2x)x\\&=(30000-700x+4x^2)x\\&=4x^3-700x^2+30000x\end{aligned}[/tex]

To find the value of x that will give the maximum volume, differentiate the equation for volume.

[tex]\begin{aligned}\implies \dfrac{\text{d}V}{\text{d}x}&=3 \cdot 4x^{3-1}-2 \cdot 700x^{2-1}+30000x^{1-1}\\&=12x^2-1400x+30000\end{aligned}[/tex]

Set the derivative to zero and solve for x using the quadratic formula:

[tex]\implies x=\dfrac{-(-1400) \pm \sqrt{(-1400)^2-4(12)(30000)}}{2(12)}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{520000}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{40000 \cdot 13}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm \sqrt{40000}\sqrt{13}}{24}[/tex]

[tex]\implies x=\dfrac{1400 \pm 200\sqrt{13}}{24}[/tex]

[tex]\implies x=\dfrac{175\pm 25\sqrt{13}}{3}[/tex]

[tex]\implies x=\dfrac{25(7\pm\sqrt{13})}{3}[/tex]

To determine which value of x will give the maximum volume, differentiate again:

[tex]\begin{aligned}\implies \dfrac{\text{d}^2V}{\text{d}x^2}&=2 \cdot12x^{2-1}-1400x^{1-1}+0\\&=24x-1400\end{aligned}[/tex]

Substitute both values of x into the second derivative:

[tex]x=\dfrac{25(7+\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=721.1102551 > 0\implies \sf minimum[/tex]

[tex]x=\dfrac{25(7-\sqrt{13})}{3} \implies \dfrac{\text{d}^2V}{\text{d}x^2}=-721.1102551 < 0\implies \sf maximum[/tex]

Therefore, the value of x which will give the maximum volume is:

[tex]x=\dfrac{25(7-\sqrt{13})}{3}=28.2870727\; \sf mm[/tex]

To find the maximum volume of the box, substitute the found value of x into the equation for volume:

[tex]\begin{aligned}\implies V_{\sf max}&=4\left(\dfrac{25(7-\sqrt{13})}{3}\right)^3-700 \left(\dfrac{25(7-\sqrt{13})}{3}\right)^2+30000 \left (\dfrac{25(7-\sqrt{13})}{3}\right)\\\\&=379037.8082\; \sf mm^3\end{aligned}[/tex]

The dimensions of the box with maximum possible volume will be:

The two measurements, which are needed in order to calculate the speed of an object in motion, be: amount of distance travelled at a particular time interval and the time interval.

Speed is characterised as the rate at which an object's position changes in any direction.

The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. SI unit of speed be meter/second.

The equation provides the speed formula: s = d/t

Where,

the speed in m.s^-1 is s.

The distance in m is represented by d.

The time interval in s is t.

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