You have a frame that holds three pictures. You pulled out your favorite five photos. How many sets of three are there?

Make a list of all the possible combinations using the numbers 1 to 5 to represent the photos.

Answer:

C(5,3)=10

Pictures 1,2,3,4,5

So the Possible sets are:

(1,2,3) (1,2,4)

(1,2,5) (1,3,4)

(1,3,5) (1,4,5)

(2,3,4) (2,3,5)

(2,4,5) (3,4,5)

The requried 10 possible sets of three photos can be selected from the group of five.

In arithmetic, combination and permutation are two different ways of grouping elements of a set into subsets. In combination, the components of the subset can be recorded in any order. In a permutation, the components of the subset are listed in a distinctive order.

Here,

The number of sets of three photos that can be selected from a group of five photos is given by the combination formula:

C(5, 3) = 5! / (3! * 2!) = (5 * 4 * 3) / (3 * 2 * 1) = 10

Therefore, there are 10 possible sets of three photos that can be selected from the group of five.

The 10 possible combinations are:

{1, 2, 3}

{1, 2, 4}

{1, 2, 5}

{1, 3, 4}

{1, 3, 5}

{1, 4, 5}

{2, 3, 4}

{2, 3, 5}

{2, 4, 5}

{3, 4, 5}

Learn more about permutations and combinations here: https://brainly.com/question/2295036
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