You are given an array of arrays a. Your task is to group the arrays a[i] by their mean values, so that arrays with equal mean values are in the same group, and arrays with different mean values are in different groups. Each group should contain a set of indices (i, j, etc), such that the corresponding arrays (a[i], a[j], etc) all have the same mean. Return the set of groups as an array of arrays, where the indices within each group are sorted in ascending order, and the groups are sorted in ascending order of their minimum element.

Example

For
a = [[3, 3, 4, 2],
[4, 4],
[4, 0, 3, 3],
[2, 3],
[3, 3, 3]]
the output should be

meanGroups(a) = [[0, 4],

[1],

[2, 3]]

mean(a[0]) = (3 + 3 + 4 + 2) / 4 = 3;
mean(a[1]) = (4 + 4) / 2 = 4;
mean(a[2]) = (4 + 0 + 3 + 3) / 4 = 2.5;
mean(a[3]) = (2 + 3) / 2 = 2.5;
mean(a[4]) = (3 + 3 + 3) / 3 = 3.
There are three groups of means: those with mean 2.5, 3, and 4. And they form the following groups:

Arrays with indices 0and 4 form a group with mean 3;
Array with index 1 forms a group with mean 4;
Arrays with indices 2and 3 form a group with mean 2.5.
Note that neither

meanGroups(a) = [[0, 4],

[2, 3],

[1]]

nor

meanGroups(a) = [[0, 4],

[1],

[3, 2]]

will be considered as a correct answer:

In the first case, the minimal element in the array at index 2 is 1, and it is less then the minimal element in the array at index 1, which is 2.
In the second case, the array at index 2 is not sorted in ascending order.
For
a = [[-5, 2, 3],
[0, 0],
[0],
[-100, 100]]
the output should be

meanGroups(a) = [[0, 1, 2, 3]]

The mean values of all of the arrays are 0, so all of them are in the same group.

Input/Output

Answer:

import numpy as np  

a = [[3, 3, 4, 2], [4, 4], [4, 0, 3, 3], [2, 3], [3, 3, 3]]

mean_holder = [np.array(i).mean() for i in a]

mean_groups= [[i for i,x in enumerate(mean_holder) if x==v] for v in mean_holder]

mean_g = []

for i in mean_groups:

   if i not in mean_g:

       mean_g.append(i)

print(mean_holder)

print(mean_g)

Explanation:

The python's Numpy package is used to convert the lists in the a-list into arrays and the means are taken and grouped by index

pharmaceutical company is using blockchain to manage their supply chain. Some of their drugs must be stored at a lower temperature throughout transport so they installed RFID chips to record the temperature of the container. Which other technology combined with blockchain would help the company in this situation?

Assume in the for loop header, the range function has the three arguments: range (1, 10, 3), if you were to print out the value of the variable
in the for loop header, what will be printed out? List the values and separate them with a comma.

User ideas for ro blox? I prefer no numbers or underscores.

For this exercise, you are going to complete the printScope() method in the Scope class. Then you will create a Scope object in the ScopeTester and call the printScope.
The method will print the name of each variable in the Scope class, as well as its corresponding value. There are 5 total variables in the Scope class, some of which can be accessed directly as instance variable, others of which need to be accessed via their getter methods.
For any variable that can be accessed directly, use the variable name. Otherwise, use the getter method.
Sample Output:
The output of the printScope method should look like this:
a = 5
b = 10
c = 15
d = 20
e = 25
public class ScopeTester
{
public static void main(String[] args)
{
// Start here!
}
}
public class Scope
{
private int a;
private int b;
private int c;
public Scope(){
a = 5;
b = 10;
c = 15;
}
public void printScope(){
//Start here
}
public int getA() {
return a;
}
public int getB() {
return b;
}
public int getC() {
return c;
}
public int getD(){
int d = a + c;
return d;
}
public int getE() {
int e = b + c;
return e;
}
}