You are driving on a roadway with multiple lanes of travel in the same direction, and are approaching an emergency vehicle parked along the roadway. You must:a. Leave the lane closest to the emergency as soon as it is safe to do so, or slow down to a speed of 20 MPH below the posted speed limit.b. Yield to the emergency vehicle.c. If you are in the lane closest to the emergency vehicle, immediately come to a complete stop and ask if anyhelp is needed.d. All of the above.

Answer:

Hub , switch port , transmission media , hope I helped

Explanation:

Answer:

the magnitude of F_A is 752 N

the direction theta of F_A is 57.9°

Explanations:

Given that,

Resultant force = 1330 N in x direction

∑Fx = R

from the diagram of the question which i uploaded along with this answer

FB = 800 N

FAsin∅ + FBcos30 = 1330 N

FAsin∅ = 1330 - (800 × cos30)

FA = 637.18 / sin∅

Now ∑Fx = 0

FAcos∅ - FBsin30 = 0

we substitute for FA

(637.18 / sin∅)cos∅ = 800 × sin30

637.18 / 800 × sin30 = sin∅/cos∅

and we know that { sin∅/cos∅ = tan∅)

so tan∅ = 1.59295

∅ = 57.88° ≈ 57.9°

THEREFORE FROM THE EQUATION

FA = 637.18 / sin∅

we substitute ∅

so FA = 637.18 / sin57.88

FA = 752 N

The correct answer is A) Chemical

Explanation:

The abbreviations SDS means Safety Data Sheet, which refers to a very complete document about chemicals and safety related to these, including their properties and potential hazards, as well as, procedures or steps to avoid hazards and accidents.

This means the main focus of this document is chemicals; moreover, in this, there is information about the route of entry, which refers to the way chemical can enter the body and includes through inhalation, ingestion, contact with skin, among others. Also, depending on the chemical some routes of entry represent a major hazard. According to this, the correct answer is A.

Answer: Chemical!!!

Explanation:

Answer: Tech B

Explanation:

From the question above, tech B saying the automotive industry offers numerous career choices is the correct answer. Pursuing a career in automotive industry is challenging and rewarding as one works with both vehicles and technology.

Examples of career choices in the automotive industry are car detailer, tire technician, car rental agent, auto mecahnic, vehicle inspector, auto electrician, auto engineer etc.

Answer:

False

Explanation:

The spiral gearing is the application that is commonly used in any vehicle where the drive from the shaft will turn perpendicular to the drive of the wheel.

The two parallel and coplanar shafts are connected by gears having helical teeth perpendicular to the axis of the shaft.

Spiral gearing application is appropriate for any machine or vehicle with a demand of great velocity and large torque power.

When two parallel and coplanar shafts are connected by gears having teeth parallel to the axis of the shaft, the arrangement is known as spiral gearing is therefore false.

Answer:

Finding stuff you need ( D )

Explanation:

Once an idea is narrowed down and divided into categories, The next line of action would be to create smaller groups that will be brainstorm solutions towards resolving the problem/ implement the idea faced by the team.

The phase of the design process that the smaller teams created will be focused on is to model and build a prototype ( finding stuff you need ) that would help implement the ideas

Answer:

Explanation:

Here's your table of (distance, power level):

  (0 km, 250 mW), (5 km, 25 mW), (10 km, 2.5 mW),

  (15 km, 250 μW), (20 km, 25 μW)

The signal can be transmitted 20 km before being attenuated to 25 μW.

__

Reportedly, the loss in fiber optic cable is about 0.5 dB/km. This compares to 10 dB/5 km = 2 dB/km for the coaxial cable. Loss in dB/km is a factor of 4 less for fiber optic cable, so the distance for the same loss would be multiplied by 4.

Answer:

well its 31.4226804124

Explanation:

Answer:

Their purpose is to invent, design, analyze, build and test machines, complex systems, structures, gadgets and materials to fulfill functional objectives and requirements while considering the limitations imposed by practicality, regulation, safety and cost.

Answer:

To make things

Explanation:

Answer:

At the middle of the DC load

Explanation:

For the Q point of an amplifier to have the Largest linear output. the Q plant has to be biased at the middle of the DC load line, this is because when the input voltage is low the transistor will be in the cutoff region while when the input voltage is very high the transistor will be in the saturation, hence when the Q point is biased at the middle it is will be higher linearly in relation to the active region

Answer:

sometimes small air bubbles are intentionally incorporated (entrained) into the mix using admixtures; other times larger bubbles are entrapped during mixing. When the bubbles are smaller than 0.04 inch, the air is called entrained; larger, and it's called entrapped.

Explanation:

Answer:

181 °C

Explanation:

Initial pressure [tex]P_{1}[/tex] = 100 kPa

Initial temperature [tex]T_{1}[/tex] = 30 °C = 30 + 273 K = 303 K

Final pressure [tex]P_{2}[/tex] = 1200 kPa

Final temperature [tex]T_{2}[/tex] = ?

n = 1.2

For a polytropic process, we use the relationship

([tex]T_{2}[/tex]/[tex]T_{1}[/tex] ) = ([tex]P_{2}[/tex]/[tex]P_{1}[/tex])^γ

where γ = (n-1)/n

γ = (1.2-1)/1.2 = 0.1667

substituting into the equation, we have

([tex]T_{2}[/tex]/303) = (1200/100)^0.1667

[tex]T_{2}[/tex]/303 = 12^0.1667

[tex]T_{2}[/tex]/303 = 1.513

[tex]T_{2}[/tex] = 300 x 1.513 = 453.9 K

==> 453.9 - 273 = 180.9 ≅ 181 °C

The final temperature of Argon in polytropic process is T = 181°C

Given data:

The initial pressure  [tex]P_{1}=100kPa[/tex]

The final pressure  [tex]P_{2}=1200kPa[/tex]

The initial temperature  [tex]T_{1}=303K[/tex]

The value of n = 1.2

For a polytropic process:

[tex]\frac{T_{2}}{T_{1}} =\frac{P_{1}}{P_{2}}^{\beta }[/tex]

The value of  [tex]\beta = \frac{(n-1)}{n}[/tex]

So, [tex]\beta =0.1667[/tex]

Substituting the values in the equation:

[tex]\frac{T_{2}}{303} =\frac{1200}{100}^{0.1667 }[/tex]

So, the value of  [tex]T_{2}=453.9K[/tex]

The temperature in degree Celsius is  [tex]T_{2}=181C[/tex].

Hence, the final temperature is T = 181°C.

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Answer:

Option D - the moisture content at turbine exit will decrease

Explanation:

In an ideal rankine system, the phenomenon of superheating occurs at a state where the vapor state of the fluid is heated above its saturation temperature and the phase of the fluid is changed from the vapor phase to the gaseous phase.

Now, a vapour phase has two different substances at room temperature, whereas a gas phase consists of just a single substance at a defined thermodynamic range, at standard room temperature.

At the turbine exit, since it's just a single substance in gaseous phase, it means it will have less moisture content.

Thus, the correct answer is;the moisture content at turbine exit will decrease

Answer: It is power stroke

Answer:

-5.9375 (or 5.9375 depending)

Explanation:

The current gain of the amplifier is simply the output current over the input current negated.

-190 mA / 32 mA == -5.9375

So the current gain for the amplifier was -5.9375

The answer a program may be looking for may not be negative, but based on the derivation, the gain should be negative for amplifiers.

Cheers.

Answer:

The time required to reduce the diameter of solid spherical ball from 2 cm to 0.50 cm = 61.60 hours

Explanation:

Given that:

The bulk gas temperature T = 347 K

The pressure = 1.0 atm

Molecular weight of naphthalene = 128 g/mole

density of the solid = 1.145 g/cm³

diffusivity in the air of coefficient = 8.19 × 10 ⁻⁶ m²/s

vapor pressure = 5.0 Torr (666 Pa)

The shape of the ball in this given study is spherical. So, the first step we need to carry out is to state the general differential equation for the mass transfer in the system of the spherical coordinates. After that , we will make use of simplified differential expression form of Fick's Flux. From there we'll determine the surface concentration (c) of the species and finally determine the material balance equation on the naphthalene which will be used in solving the time required to reduce the diameter from 2.0 cm to 0.50cm.      

THE DETAILED EXPLANATION OF WHAT WE JUST SAID CAN BE SEEN IN THE ATTACHED IMAGES BELOW.              

Answer:

the only one that meets the requirements is option C .

Explanation:

The tolerance of a quantity is the maximum limit of variation allowed for that quantity.

To find it we must have the value of the magnitude, its closest value is the average value, this value can be given or if it is not known it is calculated with the formula

         x_average = ∑ [tex]x_{i}[/tex] / n

The tolerance or error is the current value over the mean value per 100

         Δx₁ = x₁ / x_average

         tolerance = | 100 -Δx₁  100 |

bars indicate absolute value

let's look for these values ​​for each case

a)

    x_average = (2.1700000+ 2.258571429) / 2

    x_average = 2.2142857145

fluctuation for x₁

        Δx₁ = 2.17000 / 2.2142857145

        Tolerance = 100 - 97.999999991

        Tolerance = 2.000000001%

fluctuation x₂

        Δx₂ = 2.258571429 / 2.2142857145

        Δx2 = 1.02

        tolerance = 100 - 102.000000009

        tolerance 2.000000001%

b)

    x_average = (2.2 + 2.29) / 2

    x_average = 2,245

fluctuation x₁

         Δx₁ = 2.2 / 2.245

         Δx₁ = 0.9799554

         tolerance = 100 - 97,999

         Tolerance = 2.00446%

fluctuation x₂

          Δx₂ = 2.29 / 2.245

          Δx₂ = 1.0200445

          Tolerance = 2.00445%

c)

   x_average = (2.211445 +2.3) / 2

   x_average = 2.2557225

       Δx₁ = 2.211445 / 2.2557225 = 0.9803710

       tolerance = 100 - 98.0371

       tolerance = 1.96%

       Δx₂ = 2.3 / 2.2557225 = 1.024624

       tolerance = 100 -101.962896

       tolerance = 1.96%

d)

   x_average = (2.20144927 + 2.29130435) / 2

   x_average = 2.24637681

       Δx₁ = 2.20144927 / 2.24637681 = 0.98000043

       tolerance = 100 - 98.000043

       tolerance = 2.000002%

       Δx₂ = 2.29130435 / 2.24637681 = 1.0200000017

       tolerance = 2.0000002%

e)

   x_average = (2 +2,3) / 2

   x_average = 2.15

   Δx₁ = 2 / 2.15 = 0.93023

   tolerance = 100 -93.023

   tolerance = 6.98%

   Δx₂ = 2.3 / 2.15 = 1.0698

   tolerance = 6.97%

Let's analyze these results, the result E is clearly not in the requested tolerance range, the other values ​​may be within the desired tolerance range depending on the required precision, for the high precision of this exercise the only one that meets the requirements is option C .

Based on the information given, the correct option will be C. 2.211445 A-2.30000000 A.

It should be noted that the tolerance range simply means the maximum limit of variation that can be allowed for a particular quantity.

It can be noted that the range that depicts the 2% tolerance range to the full 9 digits provided is 2.211445 A-2.30000000 A. It illustrates a high precision regarding the question.

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Answer: (D) 0.94

P(7 distinct birthdays) = 363/365 = 0.9438 (0.94)

The probability that no people in a group of seven have the same birthday is; D: 0.94

The probability that no people in a group of seven have the same birthday is;

P(no two people in a group of seven) = P(1) * P(2) * P(3) * P(4) * P(5) * P(6) *P(7)

⇒ 365/365 * 364/365 * 363/365 * 362/365 * 361/365 * 360/365 * 359/365 = 0.9438 ≈ 0.94

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Answer:

LMC wall thickness= 5.05

Explanation:

Given:

Minimum inner diameter = 25 - 0.05 = 24.95

Maximum outer diameter = 35 + 0.05 = 35.05

Find:

LMC wall thickness

Computation:

LMC wall thickness = (maximum outer diameter - minimum inner diameter) / 2

LMC wall thickness = (35.05 - 24.95) / 2

LMC wall thickness= 5.05

Answer:

D

Explanation:

Answer:

a) 4.51 lbf-s^2/ft

b) 65.8 kg

c) 645 N

d) 23.8 lb

e) 65.8 kg

Explanation:

Weight of the man on Earth = 145 lb

a) Mass in slug is...

32.174 pound = 1 slug

145 pound = [tex]x[/tex] slug

[tex]x[/tex] = 145/32.174 = 4.51 lbf-s^2/ft

b) Mass in kg is...

2.205 pounds = 1 kg

145 pounds = [tex]x[/tex] kg

[tex]x[/tex] = 145/2.205 = 65.8 kg

c) Weight in Newton = mg

where

m is mass in kg

g is acceleration due to gravity on Earth = 9.81 m/s^2

Weight in Newton = 65.8 x 9.81 = 645 N

d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,

1 m/s^2 = 3.2808 ft/s^2

[tex]x[/tex] m/s^2 = 5.30 ft/s^2

[tex]x[/tex] = 5.30/3.2808 = 1.6155 m/s^2

weight in Newton = mg = 65.8 x 1.6155 = 106

weight in pounds = 106/4.448 = 23.8 lb

e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth

mass on the moon = 65.8 kg

Answer:

The flux (volume of water per unit time) through the hoop will also double.

Explanation:

The flux = volume of water per unit time = flow rate of water through the hoop.

The Flow rate of water through the hoop is proportional to the area of the hoop, and the velocity of the water through the hoop.

This means that

Flow rate = AV

where A is the area of the hoop

V is the velocity of the water through the hoop

This flow rate = volume of water per unit time = Δv/Δt =Q

From all the above statements, we can say

Q = AV

From the equation, if we double the area, and the velocity of the stream of water through the hoop does not change, then, the volume of water per unit time will also double or we can say increases by a factor of 2

The correct answer is A. Total slack

Explanation:

Projects include multiple tasks or activities; moreover, each activity and the project itself have a specific due date. Besides this, activities can be delayed and this might affect or not the due date of the project. Indeed, some activities can have extra time without any effect on the date of the project, which is known as total slack or total float (delay in activities that does not delay the project.) Additionally, total slack is possible if activities or tasks are flexible, for example, if each task in a project should take 1 day and one of the tasks takes one day and a half, this can be compensated if another task takes less time. According to this, the correct answer is A.

Answer:

Explanation:

Small-angle grain boundaries are not as effective in interfering with the slip process as are high-angle grain boundaries because there is not as much crystallographic misalignment in the grain boundary region for small-angle, and therefore not as much change in slip direction.

Low angle grain boundaries (quasi-coherent) are formed by the dislocation network positioned along the geometric plane with small tilt angle differences between successive peers that is tilt boundary made up edge dislocations therefore it may only divert the slip direction of the incoming gliding dislocation with very little frictional stresses. And on the other hand, a high angle grain boundary region because of their disordered almost liquid like structure which acts as a strong barrier against dislocation slip motion and causes actually formation of dislocations file-up against it by arresting their motion unless that the stress concentration at the leading dislocation becomes high enough to go though the barrier.

Answer:

The atmospheric pressure from a mercury barometer equals to 99.992 kilopascals.

Explanation:

760 milimeters of mercury column is equal to 101.325 kilopascals. The atmospheric pressure is found by simple rule of three:

[tex]p_{atm} = \frac{750\,mm\,Hg\times 101.325\,kPa}{760\,mm\,Hg}[/tex]

[tex]p_{atm} = 99.992\,kPa[/tex]

The atmospheric pressure from a mercury barometer equals to 99.992 kilopascals.

Answer:

5318.346

Explanation:

From the question we have

M = 6kg/s

P = 15kpa

h1 = 3248.4kj

x = 0.9

H2 is unknown

From the steam table

hf = 225.85

hg = 2599.36

H2 = HF + x(hg -hf)

h2= 225.85+0.9(2599.36 - 225.85)

= 225.85 + 0.9(2373.51)

= 225.85 + 2136.159

= 2362.009

To find The power generated by this turbine:

We insert all the parameters into the equation below:

m(h1 - h2)

= 6(3248.4 - 2362.009)

= 6 x 886.391

= 5318.346KW

Answer:

Sound barrier.

Explanation:

Sound barrier is a sudden increase in drag and other effects when an aircraft travels faster than the speed of sound. Other undesirable effects are experienced in the transonic stage, such as relative air movement creating disruptive shock waves and turbulence. One of the adverse effect of this sound barrier in early plane designs was that at this speed, the weight of the engine required to power the aircraft would be too large for the aircraft to carry. Modern planes have designs that now combat most of these undesirable effects of the sound barrier.

Answer:

B. Manning

Explanation:

The Manning formula is an empirical formula for velocity estimation of a liquid flowing in a open channel, only used for water. The Manning formula is:

[tex]V = \frac{k}{n} \cdot R_{h}^{2/3}\cdot S^{1/2}[/tex]

Where:

[tex]V[/tex] - Cross sectional average velocity, measured in meters per second.

[tex]k[/tex] - Conversion factor, dimensionless. ([tex]k = 1[/tex] for SI units)

[tex]n[/tex] - Gauckler-Manning constant, measured in [tex]\frac{s}{m^{1/3}}[/tex].

[tex]R_{h}[/tex] - Hydraulic radius, measured in meters.

[tex]S[/tex] - Slope of the hydraulic grade line, dimensionless.

Both Darcy-Weisbach and Hazen-Williams formulas are used only for fluid flowing in pipes.

In a nutshell, the correct answer is B.

Answer:

Because it helps to speed up recovery and required recovery efficiency When recovering refrigerant from a household refrigerator who's compressor does not run

Answer:

B. with each component having an individual address

Explanation:

Data bus is a system within a computer or device, consisting of a connector or set of wires, that provides transportation for data. Data bus needs an address unique to each component in order to deliver the right data to the right place. Every memory location has a unique binary address. A microprocessor architecture is mainly composed of two main buses: The data bus and the address bus.