You (50 kg) are standing on a skateboard when your friend throws a 5 kg ball at 10 m/s towards your head. You catch the ball to save your face. Describe your motion after you catch the ball, use numbers.​

Answers

Answer 1

Answer:

v₁ = 1 [m/s].

Explanation:

This problem can be solved by using the principle of conservation of linear momentum. Where momentum is conserved before and after catching the snowball.

[tex]P=m*v[/tex]

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

[tex]P=m*v\\P=5*10\\P=50[m/s][/tex]

As the momentum is conserved, it will be the same as that received by the person who catches the snowball.

[tex]50= 50*v_{1}\\v_{1}=1[m/s][/tex]

That is, the person who catches the snowball moves backwards with a speed of 1 [m/s].


Related Questions

Calculate the work done in lifting 200 kg of water through a vertical height of 6 metres
(g = 10 m/s)
(A) 5000 J
(B) 12000 J
(C) 25000 J
(D) 15000 J​

Answers

Answer:

[tex]\bf\pink{(C)\:12000\:J}[/tex]

Explanation:

Given :-

[tex]\sf\red{Mass = 200 \ kg}[/tex][tex]\sf\orange{Gravity = 10 \ m/s}[/tex][tex]\sf\green{Height = 6 \ m}[/tex]

Need to find :-

[tex]\sf\blue{Work \ done}[/tex]

Formula required :-

[tex]\sf\purple{Work \ done = Mass \times Gravity \times Height}[/tex]

Solution :-

[tex]\to\:\:\sf\red{Work \ done = Mass \times Gravity \times Height}[/tex]

[tex]\to\:\:\sf\orange{Work \ done = 200 \times 10 \times 6}[/tex]

[tex]\to\:\:\sf\green{Work \ done = 2000 \times 6}[/tex]

[tex]\to \:\ \sf\blue{ Work \ done = {\bf{\blue{1200\:J}}}}[/tex]

Hence, [tex]\bf\green{(B)}[/tex] is the correct option.

A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
3 A, calculate the size of the resistor

Answers

Answer:

4 Ohms

Explanation:

Apply the formula:

Voltage = I (current) . Resistance

You can change it the way you want to use for your purpose.

In this case...

R = V/I

R = 12/3

R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)

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