y
∝
1
√
x
If
y
=
7
when
x
=
64
find,
x
when
y
=
8

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]

If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.

⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]

☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]

Hope I helped ! ♡

⋆ Have a wonderful day / night ! ♪

Let me know if you have any questions regarding my answer! ツ

[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

4 sq un

Step-by-step explanation:

Answer:

18 pizzas

Step-by-step explanation:

Answer:

On the dive boat deck

Step-by-step explanation:

This is above the water level and water level is considered to be 0

pls love me <3

Answer: the answer is B and D I told the test

Step-by-step explanation:

Answer:

$3.25

Step-by-step explanation:

Given that:

Mean, λ = 1.4

Strike within next minute = $3 won

Strike between one and 2 minutes = $5

Strike more than 2 minutes = $1

Probability that next strike occurs within the next minute :

Using poisson :

P(x < 1) = 1 - e^-(λx) ;

P(x < 1) = 1 - e^-(1.4*1) = 1 - e^-1.4

P(x < 1) = 1 - 0.2465969

P(x < 1) = 0.7534030

Next strike occurs between 1 and 2 minutes :

(1 < x < 2) :

P(x < 2) - P(x < 1)

P(x < 2) = 1 - e^-(λx) ;

P(x < 2) = 1 - e^-(1.4*2) = 1 - e^-2.8

P(x < 2) = 1 - 0.0608100

P(x < 2) = 0.9391899

P(x < 2) - P(x < 1)

0.9391899 - 0.7534030 = 0.1857869

P(striking after 2 minutes)

P(x > 2) = e^-(λx) ;

P(x > 2) = e^-(1.4*2) = e^-2.8

P(x > 2) = 0.0608100

Amount charged :

(0.7534030 * 3) + (0.1857869 * 5) + (0.06081 * 1)

= 3.2499

= $3.25

Answer:

10.224 < μ < 12.622 ;

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

Step-by-step explanation:

The confidence interval is given as :

Mean ± Margin of Error

margin of error = Zcritical * standard deviation /sqrt(n)

n = sample size

From the data:

12.32, 11.87, 12.34, 11.48, 12.66, 8.51, 14.13, 12.95, 9.34, 8.63

From the data:

Using calculator :

Mean, = 11.423

Standard deviation, s = 1.934

Zcritical at 95% confidence interval = 1.96

Sample size, n = 10

Margin of Error = 1.96* 1.934/sqrt(10) = 1.199

Lower boundary = 11.423 - 1.199 = 10.224

Upper boundary = 11.423 + 1.199 = 12.622

10.224 < μ < 12.622

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

Answer:

B) 60.21 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

You can‘t used mixed measurements (feet and inches), so you have to convert each length to inches

8’6”=102’

14’2”=170’

Now find the area

1/2 x 102 x 170 = 8670 in²

This is one of the answers, but the quetion asks how many quart feet you need.

So, convert it back to feet.

8670 x 0.06944444444 = 60.2083333

(You could also have converted the two lengths to feet. 8’6” = 8.5 ft.  14’2” = 14.16666666.  This way would probably have been faster.

1/2 x 8.5 x 14.166666 = 60.20833333)

Answer:

FD = 25.94

Step-by-step explanation:

13x - 16 = 4x + 11 (Tangents drawn from an external point are equal)

13x - 4x = 11 + 16

9x = 27

x = 3

substituting x in 4x + 11,

4(3) + 11

12 + 11

23

ΔFED is a right triangle,

FD² = FE² + DE²

FD² = 12² + 23²

FD² = 144 + 529

FD² = 673

FD = 25.94

Answer:

FD= +-25.94

Step-by-step explanation:

EF=CF=r(radius)=12

we know,

FD^2=EF^2+ED^2 ......(1)

and

FD^2=CF^2+CD^2 ......(2)

We Know,

area of triangle, a= 1/2xbasexHeight

a=1/2xEFxED .......(3)

and

a=1/2xCFxCD .....(4)

from equation 3 and 4

1/2xEFxED=1/2xCFxCD

=> 1/2x12xED=1/2x12xCD

=>ED=CD

=>13x-16=4x+11

13x-4x=16+11

9x=27

x=3

so

FD^2=EF^2+(ED)^2

FD^2=(12)^2+(4x3+11)^2

=>FD^2=144+529

=>FD^2=673

FD=+-25.94

I'm very bad in geometry. Sorry mom I failed geometry .

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8             -8

4x >_ 4

/4       /4

x >_ 1

Answer:

4 5/12 feet tall

Step-by-step explanation:

All you have to do is subtract 1/3 from 4 and 3/4 in order to get this answer.

Answer:

Leon is 53/12 feet or 4 & 5/12 or 4.4167 (same answer different forms)

Step-by-step explanation:

Leon older brother is 19/4 feet tall or 57/12.

Leon is 1/3 or 4/12 foot shorter than his brother.

57/12-4/12= 53/12

Answer:

it is 4.6 sorry girl

Step-by-step explanation:

Answer:

Step-by-step explanation:

4.6=4 3/5=23/5

Answer:

the answer is C.

Step-by-step explanation:

Answer:

uhm im really sorry about this but i really need points i would help but id get it wrong im bad aat math

Step-by-step explanation:

Answer:

y=9

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

this is the answer. have a great day.

Answer:

⚠️DO NOT RELY ON ME⚠️ But, just by doing It in my head i think it's 236.685, but I don't really know just my thought process and mental math

Answer:

4(9 – c)

36 – 4c

Step-by-step explanation:

An example of two equivalent expressions includes the general expression and then the one that is factored.

Answer:

yes

Step-by-step explanation:

Answer:

3 1/4 + 4 2/5 + 6 1/2 = 14.15 hours

Step-by-step explanation:

Answer:

[tex]ADC = 70[/tex]

Step-by-step explanation:

Given

[tex]BCA = 50[/tex]

[tex]DCA = 60[/tex]

See attachment for parallelogram and complete question

Required

Find ADC

From the attachment:

[tex]BCD = BCA + DCA[/tex]

[tex]BCD = 50+60[/tex]

[tex]BCD = 110[/tex]

Adjacent angles add up to 180.

So:

[tex]ADC + BCD = 180[/tex]

[tex]ADC = 180-BCD[/tex]

[tex]ADC = 180-110[/tex]

[tex]ADC = 70[/tex]

Answer:

69 estudiantes.

Step-by-step explanation:

Sabemos que el número total de estudiantes en primer grado es 184.

También sabemos que la relación entre los que usan anteojos y los que no es 3/5.

Esta relación es igual al cociente entre el número de estudiantes que usan anteojos y el número de estudiantes que no usan anteojos.

Si definimos las variables:

A = número de estudiantes que usa anteojos

B = número de estudiantes que no usa anteojos.

Tenemos la relación:

A/B = 3/5

podemos reescribir como:

A = (3/5)*B

Y también sabemos que el número total de estudiantes es 184, entonces tendríamos que:

A + B = 184.

Podemos aislar B en esta segunda ecuación para luego reemplazarlo en la primera.

Aislando B obtenemos:

B = 184 - A

Si reemplazamos esto en la otra ecuación obtenemos:

A = (3/5)*B

A = (3/5)*(184 - A)

Ahora podemos resolver esto para A.

A = (3/5)*184 - (3/5)*A

A + (3/5)*A = (3/5)*184

A*(1 + 3/5) = (3/5)*184

A*(5/5 + 3/5) = (3/5)*184

A*(8/5) = (3/5)*184

A = (5/8)*(3/5)*184

A = 69

Podemos concluir que 69 estudiantes usan anteojos.

Answer:

The percentage increase in [tex]T[/tex] is 20 %.

Step-by-step explanation:

Let be [tex]T = \frac{k\cdot x}{y}[/tex], whose initial parameters are [tex]k = k_{o}[/tex], [tex]x = x_{o}[/tex] and [tex]y = y_{o}[/tex]. If these three parameters are increased by 20 %, then initial and final values of [tex]T[/tex] are, respectively:

Initial value

[tex]T_{i} = \frac{k_{o}\cdot x_{o}}{y_{o}}[/tex] (1)

Final value

[tex]T_{ii} = \frac{(1.2\cdot k_{o})\cdot (1.2\cdot x_{o})}{1.2\cdot y_{o}}[/tex]

[tex]T_{ii} = \frac{1.2\cdot k_{o}\cdot x_{o}}{y_{o}}[/tex] (2)

(1) in (2):

[tex]T_{ii} = 1.2\cdot T_{i}[/tex]

And the percentage increase in T is:

[tex]\%T = \frac{T_{ii}-T_{i}}{T_{i}}\times 100\,\%[/tex] (3)

[tex]\%T = \frac{1.2\cdot T_{i}-T_{i}}{T_{i}}\times 100\,\%[/tex]

[tex]\%T = 20\,\%[/tex]

The percentage increase in [tex]T[/tex] is 20 %.

Answer:

Step-by-step explanation:

Lets subsitute k, x and y as  100 to make it easier for us

So k = 100, x = 100, y = 100

Step 1 :-   T = kx/y

- T = 100 * 100 / 100 = 100

Step 2 :- Increase by 20% = 100 * 20% = 20,    100 + 20 = 120

Step 3 :- Percentage Increase = Increased value OVER original calue          MULTIPLIED by 100%

SO = ( 120 - 100 ) ,,,,   20/100 * 100% = 0.2* 100 = 20%

Answer:

(11+X)/2-(9x-3)/4 x=3

subsititute 3 into all x

(11+3)/2-(9*3)-3)/4

first solve the first diviision

2-(9 times 3)-3/4

=2-(27-3)/4

=2-(24)/4

since the "2-" is there, you have to subtract it from 24 before you dividewhich would then be

22/4=5.5(in decimal form)

DON'T forget you have another bracket waiting for you since you were given 3 brackets. bring the first bracket down

2-(9x-3)/4 was solved and we got 5.5, so basically we are "substituting 5.5 into that part of the question)

11+x/5.5

11+3/5.5

14/5.5

=2.54 which is your final answer

Sorry if I went overboard lol.

Step-by-step explanation:

yes, the answer is 2.54 I believe.

The probability that a student has a dog given they do not have a cat is 0.1333.

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Total number of students = 30

[tex]n(s)=30[/tex]

Number of students have cat = 16

Number of students have dog = 15

Number of students have a cat and a dog = 11

The event is the probability that a student has a dog given they do not have a cat,

[tex]n(e)=15-11[/tex]

⇒ [tex]4[/tex]

Thus the probability that a student has a dog given they do not have a cat is

⇒ [tex]P(e)=\frac{n(e)}{n(s)}[/tex]

⇒ [tex]P(e)=\frac{4}{30}[/tex]

⇒ [tex]P(e)=0.1333[/tex]

Hence we can conclude that the probability that a student has a dog given they do not have a cat is 0.1333.

Learn more about probability here

https://brainly.com/question/16484393

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