Answer:
441
Stepbystep explanation:
Where you see X, substitute with 300
30098 + 300÷2
291 + 150
= 441
Answer:
352
Stepbystep explanation:
important info:
x = 300
Solution/Explanation:
30098+300 ÷ 2=
202+150=
352
Hence, the Answer is 352.
evaluate –3(–5)(–1)(3)
Answer:
45
Stepbystep explanation:
I think one way you could do it is:
1. –3(–5) = 15
2. (–1)(3) = 3
3. (15) (3) = 45
I used a calculator pls let me know if im incorrect
Keith has $500 in a savings account at the beginning of the summer. He wants to have at least $200 in his account by the end of the summer. If there are 10 weeks in the summer, how much can Keith spend each week to have at least $200 in his account? Let x represent how much he can spend each week.
options:
x>30
x>70
x≤70
x≤30
Answer:
x≤30
Stepbystep explanation:
he can spend no more than $30 a week
this is the next question
Solve: 1/2÷0.2
Answer:
2.5
Stepbystep explanation:
Hey y’all, please help me
3. Allison bought some shirts for her clothing store for $15 each. She received $50 off her entire purchase and spent a total of $400. How many shirts did Allison purchase for her store?
Answer:
30
Stepbystep explanation:
15x30 = 450
Answer:
She purchased 30 shirts.
Stepbystep explanation:
She paid only $400 Dollars, because she got a discount of $50.
So the total before getting the discount was $450.
If you divide $450 by $15 (the price for 1 shirt) you come up with 30.
450/15 = 30
Chose the justification for each step in the solution to the given equation stop application subtraction property of equality multiplication property of equality division property of equality addition property of equality
Answer:
Stepbystep explanation:
1) If
[tex] \frac{1}{a + 1} + \frac{1}{b + 1} + \frac{1}{c + 1} = 2[/tex]
[tex]then \: {a}^{2} + {b}^{2} + {c}^{2} is[/tex]
Option :
[tex]a) \frac{3}{4} [/tex]
[tex]b) \frac{1}{3} [/tex]
[tex]c) \frac{27}{16} [/tex]
[tex]d) \frac{4}{3} [/tex]
● NEED GENUINE ANSWER
●DON'T SPAM OTHERWISE ANSWER WILL BE REPORT
The sum of the square of the constants is 3/4
Given the equation [tex]\frac{1}{a+1} +\frac{1}{b+1} +\frac{1}{c+1} =2[/tex]
The partial form of the equation is given as:
[tex]\frac{1}{a +1} = 2\\[/tex]Solve for the constant "a"
[tex]\frac{1}{a +1} = 2\\a+1 = \frac{1}{2} \\a = \frac{1}{2}  1\\a =\frac{1}{2}[/tex]
Hence [tex]a=b=c=\frac{1}{2} \\[/tex]
Taking the square of the constant, we will have:
[tex]a^2 + b^2 + c^2 =(1/2)^2 +(1/2)^2+(1/2)^2\\a^2 + b^2 + c^2 =1/4 + 1/4 + 1/4\\a^2 + b^2 + c^2 =3/4[/tex]
Hence the sum of the square of the constants is 3/4
Learn more on partial fraction here: https://brainly.com/question/24594390
Answer the sum of the square of the consonants is 3/4
Solve for x
3x+7=28
Answer:
X=7
Stepbystep explanation:
Answer:
x = 7Stepbystep explanation:
3x + 7 = 28=> 3x = 28  7=> 3x = 21=> x = 7Conclusion:
Therefore
x = 7.Hoped this helped.
[tex]GeniusUser[/tex]
What is the area of this figure?
Answer:
84mm
Stepbystep explanation:
square = LxW = 6x6 =36
triangle = bxh/2 = 6x8/2 =24
add together 24x2+36=84
Jake drew a scale drawing of a house. He used the scale 10 inches = 6 feet. What is the scale factor of the drawing?
Simplify your answer and write it as a fraction.
Answer:
5:36
Stepbystep explanation:
12 inches = 1 foot, so 6 feet = 72 inches
10:72, reduces to 5:36
What percent is equivalent to 24/50?
24%
48%
50%
52%
Answer:
48%
Stepbystep explanation:
24 is almost 25 which is half of 50 you it would be 48%, hope this helps!:)
Which expression can be used to find the product of 57 x 44?
Answer:2508
Stepbystep explanation:
A gaming computer system and additional equipment was purchased for $2,000. The system and equipment depreciate in value by 10% each year.
After how many years will the computer have a value less than $1,000?
A. 1
B. 3
C. 7
D. 8
2000200 = 1800
1800180 = 1620
1620  162 = 1458
1458 148.8 = 1309
1309  130.9 = 1178
1178 117.8 = 1060.2
1060  106 = 954
= 7 years
The value of the car is $956.5938 after 7 years and this can be determined by using arithmetic operations.
Given :
A gaming computer system and additional equipment was purchased for $2,000. The system and equipment depreciate in value by 10% each year.The following steps can be used in order to determine the total number of years will the computer have a value of less than $1,000:
Step 1  The 10% of $2000 is $200. So, the value of the car after 1 year is $1800.
Step 2  The 10% of $1800 is $180. So, the value of the car after 2 years is $1620.
Step 3  The 10% of $1620 is $162. So, the value of the car after 3 years is $1458.
Step 4  The 10% of $1458 is $145.8. So, the value of the car after 4 years is $1312.2.
Step 5  The 10% of $1312.2 is $131.22. So, the value of the car after 5 years is $1180.98.
Step 6  The 10% of $1180.98 is $118.098. So, the value of the car after 6 years is $1062.882.
Step 7  The 10% of $1062.882 is $106.2882. So, the value of the car after 7 years is $956.5938.
Therefore, the correct option is C).
For more information, refer to the link given below:
https://brainly.com/question/25834626
y = {x5?
Which equation describes a line parallel to the line described by y
Your answer:
o y=2x
o y=3x+1
oy

Oy  2x  5
Clear answer
Back
NEW
Answer:
The third option, 1/2..
Could someone help please
Stepbystep explanation:
1. x/32=6
x6=18
x=18+6
x=24
2. x/5+1=5
x+5=25
x=255
x=20
Answer:
x = 24 , x = 20
Stepbystep explanation:
(a)
[tex]\frac{x}{3}[/tex]  2 = 6 ( add 2 to both sides )
[tex]\frac{x}{3}[/tex] = 8 ( multiply both sides by 3 to clear the fraction )
x = 24
(b)
[tex]\frac{x}{5}[/tex] + 1 = 5 ( subtract 1 from both sides )
[tex]\frac{x}{5}[/tex] = 4 ( multiply both sides by 5 to clear the fraction )
x = 20
Cory has $24 more than twice as much as Stan. Together they have $150. How much money does each have?
Stan has $50 and Cory has $74
Stan has $42 and Cory has $108
Stan has $63 and Cory has $87
Stan has $108 and Cory has $42
Answer: B Stan has $42 and Cory has $108.
Stepbystep explanation:
The awnser is Stan has $42 and Cory has $108 and $108 + $42 = $150.
CAN YOU PLEASE MARK ME BRAINLY.
x= [ ? ]°
104°
1170
1249
100°
Answer:
okkkkkkkkkkkkkkkkkkkkkkkkkkk
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Sum of angles of a pentagon is ~ 540°
Therefore,
[tex] \sf104 + 117 + 100 + 124 + x = 540 [/tex][tex] \sf445 + x = 540[/tex][tex] \sf x = 540  445[/tex][tex] \sf x = 95 \degree[/tex]Value of x = 95°
Please help me evaluate f(x)=52
Answer:
Axis interception points of 52 :
Y intercepts : (0,52 )
Select the correct answer. Evaluate the following expression when x = 4 and y = 4. A. B. C. D.
The value of given expression when x=4 and y=4 is 1250.
The expression is missing in the question which is [tex]\dfrac{x^6x}{4y}[/tex].
We have to solve it for x= 4 and y = 4.
Now putting the value of x and y we get,
[tex]\dfrac{x^6x}{4y}=\dfrac{(4)^6(4)}{4}[/tex]
[tex]\dfrac{x^6x}{4y}=\dfrac{4096+4}{4}[/tex]
[tex]\dfrac{x^6x}{4y}=1250[/tex]
Hence the value of given expression when x=4 and y=4 is 1250.
For more details follow the link:
https://brainly.com/question/11897796
i need the answr for 3+x=10 please explain as well
Answer:
7
Stepbystep explanation:
basically just subtract 103=7 then to check 3+7=10
Answer:
x = 7
Stepbystep explanation:
3 + x = 10
3 3
x = 7
you subtract by 3 on both sides (because the opposite property of addition is subtraction) to cancel it out and isolate the x.
The sum of three consecutive odd numbers is 153 find the number
Answer:
Divide the no. by three
Stepbystep explanation:
153÷3 = 51
so, 51+51+51 = 153
Answer:
an odd number can be expressed as 2n+1 (2n would be even, add 1 = odd)
first number = 2n+1
second number = 2n+3 > skip + 2 because it would make it even
third number = 2n+5
2n+1+2n+3+2n+5=153
6n+9=153
6n=144
n=24
24*2+1=48+1=49
24*2+3=48+3=51
24*2+5=48+5=53
the numbers are 49, 51, and 53.
WHAT IS 62729287937927497393884x0
I NEED HELP!!!!!!!!!
PLEASEEEEEE
Answer:your mom
Stepbystep explanation:
[tex]\huge \bf༆ Answer ༄[/tex]
Any value multiplied by Zero gives Zero, therefore ~
[tex] \sf62729287937927497393884 \times 0 = 0[/tex]Hey! Please help me ASAP.
I think its the third one but im not completly sure
Answer:
t5>1.5
Stepbystep explanation:
Just ask.
Hope this helps! :)
How is 25:5 and 10:2 equivalent
Answer: yes !!
Stepbystep explanation:
first we have to simplify
25:5 = 5:1
10:2 = 5:1
yes, they are
When two ratios are in proportion the ratios are said to be equivalent.
The ratios 25:5 and 10:2 are equivalent because they are in proportion.
What is a ratio?It is the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.
We have,
25:5 and 10:2
The ratio must be in proportion to be equivalent.
25:5 = 25/5 = 5 / 1
10:2 = 10/2 = 5/1
25:5 = 10:2
25/5 = 10/2
(5x5) / 5 = (5x2) / 2
5/1 = 5/1
We see that the ratio is equivalent.
Thus,
The ratios 25:5 and 10:2 are equivalent because they are in proportion.
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#SPJ2
Help ???????????? ?????
Answer:
A
Stepbystep explanation:
Answer:
the answer is BStepbystep explanation:
What is the approximate value of q in the equation below? q log Subscript 2 Baseline 6 = 2 q 2 â€""1. 613 â€""1. 522 0. 585 3. 79.
The approximate value of q in the equation is [tex]0.774[/tex]
The equation is given as:
[tex]q\log_2(6) = 2[/tex]
Divide both sides of the equation by [tex]\log_2(6)[/tex].
So, we have:
[tex]q= \frac{2}{\log_2(6) }[/tex]
Determine log(6) base 2
[tex]q= \frac{2}{2.585}[/tex]
Divide 2 by 2.585
[tex]q= 0.774[/tex]
Hence, the approximate value of q in the equation is [tex]0.774[/tex]
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p²÷4m; use m=3, and p=4
2. A small university is trying to monitor its electricity usage. For a random sample of
30 weekend days (Saturdays and Sundays), the student center used an average of 94.26 kilowatt hours (kWh) with standard deviation 43.29. For a random sample of 60 weekdays, (Monday  Friday), the student center used an average of 112.63 kWh with standard deviation 32.07.(Please show work)
a) Test, at the 5% level, if significantly more electricity is used at the student center, on average, on weekdays than weekend days. Remember to check the conditions, identify the hypotheses, define your parameter, find the test statistic, find the pvalue, and give a conclusion in context.
b) Construct a 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days. Use two decimal places in your margin of error.
Using the tdistribution, it is found that:
a) Since the test statistic is greater than the critical value for the righttailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.
b) The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).
Item a:
At the null hypothesis, it is tested if there is no difference, that is, the subtraction is at most 0, hence:
[tex]H_0: \mu_1  \mu_2 \leq 0[/tex]
At the alternative hypothesis, it is tested if there is difference, that is, the subtraction is positive, hence:
[tex]H_1: \mu_1  \mu_2 > 0[/tex]
The standard errors are given by:
[tex]s_1 = \frac{32.07}{\sqrt{60}} = 4.14[/tex]
[tex]s_2 = \frac{43.29}{\sqrt{30}} = 7.9[/tex]
The distribution of the difference has mean and standard deviation given by:
[tex]\overline{x} = \mu_1  \mu_2 = 112.63  94.26 = 18.37[/tex]
[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{4.14^2 + 7.9^2} = 8.92[/tex]
The standard deviation are given for the samples, hence, the tdistribution is used.
The test statistic is given by:
[tex]t = \frac{\overline{x}  \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the hypothesis.
Hence:
[tex]t = \frac{\overline{x}  \mu}{s}[/tex]
[tex]t = \frac{18.37  0}{8.92}[/tex]
[tex]t = 2.06[/tex]
The critical value for a righttailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 30 + 60  2 = 88 df is [tex]t^{\ast} = 1.66[/tex]
Since the test statistic is greater than the critical value for the righttailed test, it is found that there is enough evidence to conclude that significantly more electricity is used at the student center, on average, on weekdays than weekend days.
Item b:
The interval is:
[tex]\overline{x} \pm t^{\ast}s[/tex]
Hence:
[tex]\overline{x}  t^{\ast}s = 18.37  1.66(8.92) = 3.56[/tex]
[tex]\overline{x} + t^{\ast}s = 18.37 + 1.66(8.92) = 33.18[/tex]
The 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days is (3.56, 33.18).
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Write 110 as a product of primes
Answer:
The prime factorization of 110 is: 2 x 5 x 11.
Please someone help me with this question
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