Answer:
Hey there here is your ans
Explanation:
Specular Reflection- bathroom mirror , glare on a pair of eyeglasses
Diffuse Reflection- reflection are the reading of a notebook
Tq
Specular reflection: glare on a pair of eyeglasses, bathroom mirror.
Diffuse reflection involves reading a notepad.
What is reflection?The direction in which a wavefront travels at an interface between two distinct media changes during the process of reflection. This allows the wavefront to go back into the medium in which it was first generated. Light, music, and water waves are all examples of common phenomena that may be reflected.
The following is a list of the three most common forms of reflection:
Regular Reflection.Reflection that is DiffusedMultiple ReflectionGlare on a pair of eyeglasses or the mirror in the bathroom is an example of specular reflection. Reading from a notebook is an example of diffuse reflection.
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Which of the following wavelengths have the highest frequency? Group of answer choices a.infrared waves b. radio waves c.microwaves d.visible light
b...radio waves answer
How will dropping a can from a higher or a lower elevation affect the impact it has on a clay ball?
Dropping a can from a higher elevation affects greater impact compare to dropping a can from a lower elevation.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.
If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Potential energy is a system attribute, not a property of a single body or particle.
The potential energy of the can on higher elevation is greater than the potential energy of the can on lower elevation. That is why, dropping a can from a higher elevation affects greater impact compare to dropping a can from a lower elevation.
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Ultraviolet rays from the sun are dangerous because they can damage skin. Why do ultraviolet rays cause damage?
Answer:
Skin damage
Explanation:
exposure can lead to sunburn, and long term exposure can lead to aged skin and much more
A negative charge of 0.198 C exerts an attractive force of 83,506 N on a second charge that is 3,004 m away. What is the magnitude of the second charge? ( solve for one of the charges)
Answer:
-606.73C
Explanation:
According to coulombs law
F = kq1q2/r^2
Substitute the given value
83,506 = 9*10^9(-0.198)q2/(3004)^2
83,506 = -1.242*10^9q2/9,024,016
-1.242*10^9q2 = 7.54*10^11
q2 = -7.54*10^11/1.242*10^9
q2 = -606.73C
hence the magnitude of the other charge is -606.73C
Suppose 2 C of positive charge is distributed evenly throughout a sphere of 1.27 cm radius. (a) What is the charge per unit volume for this situation? C/m3 (b) Is the sphere insulating or conducting? How do you know? The sphere is conducting. If it were insulating, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is insulating. If it were conducting, none of the charge would be in the interior of the sphere; it would only be on the surface. The sphere is conducting. If it were insulating, all of the charge would be in the interior of the sphere; not on the surface. The sphere is insulating. If it were conducting, all of the charge would be in the interior of the sphere; not on the surface.
Answer:
a) ρ = 2.33 10⁵ C / m³, b) INSULATING
Explanation:
a) For this exercise we use the important concept of density
ρ = Q / V
The volume of a sphere is
V = 4/3 πr3
V = 4/3 π (1.27 10⁻²)³
V = 8.58 10⁻⁶ m³
let's calculate
ρ = 2 / 8.58 10⁻⁶
ρ = 2.33 10⁵ C / m³
b) in a conductor the charges are mobile, therefore due to electoral repulsion all the charges must concentrate on the surface.
In an insulator the charges are fixed, therefore they are distributed throughout the volume
Consequently the sphere must be INSULATING
How does the energy from the person's hand get to the last domino?
Answer:
woh its really exist?
Explanation:
cakra
KIIS FM broadcasts at 102.7 MHz, what is the wavelength of that radio wave?
Answer:
2.92 m
Explanation:
As we know, frequency × Wavelength = Speed of light
so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..
So Lambda (wavelength) = 3×10⁸/ 102.7 × 10⁶ which gives 2.92 metres or 2.92 × 10¹⁰ Å
Sound moves through the air at a speed of 340 m/s. How long would it take to hear your echo in a canyon which is 50 meters away? Show all of your work with an explanation of your answer.
Answer: 5/17 seconds or roughly .3 seconds
Explanation:
We will hear our echo once it has traversed the canyon to reach the end, bounce off, then return back to our ears.
To find how long it travels in one direction:
[tex]\frac{50m}{340 \frac{m}{s}} = \frac{5}{34} s[/tex] (or about .14 seconds)
For it to return back to us we double that time.
The time for it to reach our ears would be 5/17 seconds or roughly .3 seconds.
an airplane travels at 500 mph, how far will the plane travel in 2 hours?
Answer:
The answer is 1000m.
Explanation:
You have to apply distance formula, D = Speed × Time :
D = Speed × Time
D = 500 × 2
D = 1000 miles
What is the characteristic that allows an object to have kinetic energy?
7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?
Answer:
Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)
Explanation:
Let the mass of this ball be [tex]x\; \rm kg[/tex].
Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].
Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:
[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].
Therefore, right before hitting the ground, the velocity of the ball would be:
[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].
The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:
[tex]\displaystyle m = \frac{p}{v}[/tex].
Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:
[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].
Which examples best demonstrate likely tasks for Legal Services workers? Check all that apply.
Cisco inspects an office building to make sure it meets fire safety regulations.
Gina gathers information about a court case.
Saul oversees inmates at a correctional facility.
Hana interviews and advises a person who has been accused of a crime.
Pamela pursues and arrests a person suspected of a crime.
Dewayne creates the paperwork for a business contract.
Answer:
b. d. f.
Explanation:
Got it right on Edge
Answer:
2. Gina gathers information about a court case.
4. Hana interviews and advises a person who has been accused of a crime.
6. Dewayne creates the paperwork for a business contract.
Hell it’s due soon??
Explanation:
don't know don't know don't know
Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
Need help ASAP
Will mark BRAINLIST and thanks only for correct answers
1.Which property of AM frequencies allow them to travel over long distances?
-high amplitude
-high energy
-constant velocity
-long wavelength
2.what types of waves do cell phones use?
-radio waves
-gamma rays
-microwaves
How much power is developed in a car that can pull a 5000 N at a constant speed
of 20 m/s?
Answer:
YAYA MAN
Explanation:
On earth a bag of sugar weight 10N. on mars a bag of sugar weight 4N. suggest the weight of the sugar is different on earth and mars
Answer:
gravity
Explanation:
there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
We must understand that the mass of an object may differ depending on its location on the planet. This is due to the effect of gravity on the object.
Gravity is simply defined as any force which attracts an object towards the centre of the earth.
From the question given, we are told that the weight of sugar is 10N on the earth and 4N on Mars. This difference in their mass is attributed to the effect of gravity on the object.
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
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What is the difference between speed and velocity?
a.Speed is displacement and time
b.Speed is velocity/ displacement
c.velocity is speed and direction
d.velocity is displacement and distance
The answer is c.velocity is speed and direction
An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
compare the physical properties of air and gold .
Answer:
Gold is metallic, with a yellow color when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.
Formula --
Molecular Weight (lb/m o l) 28.96
Critical Temp. (°F) N/A
Critical Pressure (p s i a) N/A
Boiling Point (°F) -317.8
Melting Point (°F) N/A
Psat 70°F (p s i a) (note 1)
Explanation:
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Describe ALL of the energy transformations that are taking place in this process.
Answer:I think that is false
Explanation:
A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later
The final velocity of the bus is 9.83 m/s
The given parameters;
initial velocity of the bus, = 30 km/h
constant increase in speed, = 1.5 m/s
time of motion, t = 6.8 s
The initial velocity of the bus in m/s;
[tex]v = 30 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 8.33 \ m/s[/tex]
The acceleration of the bus;
[tex]a = \frac{\Delta v}{\Delta t} = \frac{1.5 \ m/s}{6.8 \ s } = 0.22 \ m/s^2[/tex]
The final velocity of the bus at the given time of motion;
[tex]v= u + at\\\\v = 8.33 + (0.22 \times 6.8)\\\\v = 9.83 \ m/s[/tex]
Thus, the final velocity of the bus is 9.83 m/s
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can someone do this assignment for me about
force
Answer:
Newtons 3sd law
Force = mass × acceleration
3rd photo about momentum
An object with a potential energy of 981 J is placed at a height of 2m. What is the mass of the object?
Answer:
the mass of object is 2000
A portable speaker is switched on. 600 J of energy is transferred from the chemical
store in the battery to the thermal store of surroundings; 250 J by heating and
some by radiation (sound). How much energy is transferred by radiation?
Answer:
350 J of energy is transferred by radiation.
Explanation:
Given that,
600 J of energy is transferred from the chemical store in the battery to the thermal store of surroundings.
Heat energy = 250 J
Sound energy = x
According to the conservation of energy,
600 = 250 +x
x = 600-250
x = 350 J
So, 350 J of energy is transferred by radiation.
PLS ANSWER FAST THIS IS TIME TEST AND WILL GIVE BRANINLY!!!!
Answer using mass m= F divided by a
Also use kilograms {kg}
A tiny aeroplane accelerates at 35 m/ s2 with a force of 20 N. What is the mass of the aeroplane?
Answer:
0.57 kg
Explanation:
We are given that
Force, F=20 N
Acceleration ,a =[tex]35m/s^2[/tex]
We have to find the mass of Aero-plane.
To find the value of mass we will divide the force by acceleration.
We know that
Force, F=ma
Using the formula
[tex]20=m\times 35[/tex]
[tex]\frac{20}{35}=m[/tex]
[tex]m=0.57 kg[/tex]
Hence, the mass of the aero-plane=0.57 kg
There is a current of 2.95 A in one of the copper wires for 60 seconds. Calculate the charge flow through the wire.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
convert 2kg into SI unit of force
Answer:
19.6133 newton.
...?.......
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface