Write the perimeter of the triangle as a simplified expression

Write The Perimeter Of The Triangle As A Simplified Expression

Answers

Answer 1

Answer: 10y + 1

Step-by-step explanation:

The perimeter is the total distance round the figure.

Now, in this case it is going to be

Perimeter = 3y + 5 + 6y + y - 4

= 3y + 6y + y + 5 - 4

= 10y + 1

Answer 2

The perimeter of the given triangle is 10y + 1 units.

What is a triangle ?

A triangle is formed by 3 non co-linear points it has three sides and three vertices.

A triangle is also a polygon with three sides.The sum of all the interior angles of a triangle is 180°.

In the given question

Equations of all the sides of the lengths of the triangle is given.

We know that the perimeter of a triangle is the sum of the lengths of all the sides.

∴ Perimeter of the given triangle

= (3y + 5) + (y - 4) + 6y

= 10y + 1 units.

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Related Questions

An 14-meter-tall cylindrical tank with a 2-meter radius holds water and is half full. Find the work (in mega-joules) needed to pump all of the water to the top of the tank. (The mass density of water is 1000 kg/m3. Let g = 9.8 m/s2. Round your answer to two decimal places.)

Answers

Answer:

to two decimal places

= 6.04 mega joules

Step-by-step explanation:

The volume of the half tank

= πr²h

r= 2 m

h= 14/2= 7 m

Volume= 22/7 *2² *7

Volume= 88 m³

work (in mega-joules) needed to pump all of the water to the top of the tank

= Volume*mass density *acceleration*distance

= 88*1000*9.8*7

= 6036800 joules

In mega joules

= 6.036800 mega Joules

to two decimal places

= 6.04 mega joules

The work needed to pump all of the water to the top of the tank is 6.03 MJ

What is work?

Work is said to be done whenever a force move a body through a certain distance.

To calculate the work needed to pump the water to the tank, first we need to find the volume of the water in the tank half full.

Formula:

V = πr²h/2................ Equation 1

Where:

V = Volume of half full water in the tankh = height of the tankr = radius of the base of the tankπ = pie

From the question,

Given:

r = 2 mh = 14 mπ = 3.14

Substitute these values into equation 1

V = 3.14(2²)(14)/2V = 87.92 m³.

Finally, to get the work needed to pump all the water to the top of the tank, we use the formula below.

W = ρVhg/2................. Equation 2

Where:

W = Work needed to pump all the water to the of the tankρ = Density of the tankh = height of the tankV = Volume of halfull water in the tankg = acceleration due to gravity

From the question.

Given:

ρ = 1000 kg/m³h = 14g = 9.8 m/s²V = 87.92 m³

Substitute these values into equation 2

W = 1000(14)(9.8)(87.92)/2W = 6031312 JW = 6.03 MJ.

Hence, The work needed to pump all of the water to the top of the tank is 6.03 MJ.

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if you have driven 225 miles in 3 hours, then how long would it take you to drive 300 miles?

Answers

Answer:How many miles can a car be driven in 3 hours at 50 miles per hour? Under normal circumstances and the generally assumed conditions, the answer is of course (3 hours) * (50 miles / hour) = 150 miles.

3.5 hours

It will take you 3.5 hours to go 280 miles at 80 miles an hour.It travels at constant speed for the remaining time. Let x be the time traveled at the unknown constant speed. The total itme for the trip was 6 hours so: 6 = time traveled at 50 mph + time traveled at 60 mph + time traveled at x mph.

Step-by-step explanation:So you drive 25 miles / hour. then 25 miles/ 1 hour = 225 miles / nb of hours.2 minutes

However, traveling at 30 MPH for 1 mile (1 lap) takes 2 minutes, which means that your average will never be 60MPH.approximately 0.6818 miles per hour.

If m/_a is 155º, what is m/_c?
Pls help ASAP

Answers

According to the Vertical Angles Theorem, the opposite angles of lines intersecting each other are congruent. Therefore vertical angles are always congruent. If m

What is the constant of proportionality

Answers

Answer:

The equation for constant of proportionality is:

y = kx

K = Constant of proportionality

An example:

4y = 8x

=> 4y/4 = 8x/4

=> y = 2x

In the answer, y = 2x;   2 is the constant of proportionality

Answer:

it is ratio of the amount s y and x:k = y/x. put another way: y = Kx.

Example:- you are paid 20 rupaye an hour the constant of proportionality is 20

because pay = 20 hours worked

Solve 3x – 1.1 = 0.7

Answers

Answer:

x = 0.6

Step-by-step explanation:

3x - 1.1 = 0.7

3x = 1.8

x = 0.6

Answer:

x = .6

Step-by-step explanation:

3x – 1.1 = 0.7

Add 1.1 to each side

3x – 1.1+1.1 = 0.7+1.1

3x = 1.8

Divide each side by 3

3x/3 = 1.8/3

x = .6

Use the drop-down menus to identify the GCF of each pair of numbers.

The GCF of 12 and 16 is

The GCF of 15 and 60 is

The GCF of 24 and 30 is

The GCF of 18 and 72 is​

Answers

Answer:

4, 15, 6, 18.

Step-by-step explanation:

12 = 1, 2, 3, 4, 6, 12 16 = 1, 2, 4, 8, 16 The GCF of 12 and 16 is 4 because when you compare the numbers that go into 12 and 16, 4 is the highest number that they both are multiples of.

Try the others by yourself and if you have any questions ask me in the comments

Angle Terminology with Equations

Answers

Answer:

∠ B = 54°

Step-by-step explanation:

Supplementary angles sum to 180°.

Sum A and B  and equate to 180, that is

7x + 14 + 5x - 26 = 180, that is

12x - 12 = 180 ( add 12 to both sides )

12x = 192 ( divide both sides by 12 )

x = 16

Thus

∠ B = 5x - 26 = 5(16) - 26 = 80 - 26 = 54°

The last digit of the heights of 39 statistics students were obtained as part of an experiment conducted for a class. Use the frequency distribution below to construct a histogram. Choose the correct histogram below. Answer

Answers

Answer: 32

Step-by-step explanation:

The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 33 mm and standard deviation 7.9 mm. (a) What is the probability that defect length is at most 20 mm

Answers

Answer:

0.49926

Step-by-step explanation:

We solve for this using z score formula

z-score is

z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation

The probability that defect length is at most 20 mm is calculated as:

x = 20mm, μ = 33 mm, σ = 7.9mm

z = 20 - 33/7.9

= -13/7.9

= -1.64557

Obtaining the Probability value from Z-Table:

Probability (At most 20mm) = P(x ≤ 20mm) P(z = -1.64557)

P(x ≤ 20) = 0.049926

Therefore, the probability that defect length is at most 20 mm is 0.049926

Answer:

The probability that defect length is at most 20 mm is 0.0495.

Step-by-step explanation:

We are given that the defect length of a corrosion defect in a pressurized steel pipe is normally distributed with a mean value of 33 mm and a standard deviation of 7.9 mm.

Let X = the defect length of a corrosion defect in a pressurized steel pipe

The z-score probability distribution for the normal distribution is given by;

                             Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean defect length = 33 mm

           [tex]\sigma[/tex] = standard deviation = 7.9 mm

So, X ~ Normal([tex]\mu=33 \text{ mm}, \sigma^{2} = 7.9^{2} \text{ mm}[/tex])

Now, the probability that defect length is at most 20 mm is given by = P(X [tex]\leq[/tex] 20 mm)

        P(X [tex]\leq[/tex] 20 mm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{20-33}{7.9}[/tex] ) = P(Z [tex]\leq[/tex] -1.65) = 1 - P(Z < 1.65)

                                                             = 1 - 0.9505 = 0.0495              

The above probability is calculated by looking at the value of x = 1.65 in the z table which has an area of 0.9505.

What is the solution of the equation below ?

Answers

Answer:

d = ±7i

Step-by-step explanation:

d^2 -1 = -50

Add 1 to each side

d^2 -1 = -50

d^2 = -49

Take the square root of each side

sqrt(d^2) = sqrt(-49)

d = sqrt(-1) sqrt(49)

d = i( ±7)

d = ±7i

Answer:

A.

Step-by-step explanation:

d^2-1= -50

First, add 1 to both sides.

d^2= -49

Take the square root of both sides:

d=√-49

Since i^2=-1

d=i√49

d= ±7i

Hope this helps!

A dilation by a factor of 7/8 maps triangle ABC to triangle XYZ. Segment BC has a length of 4 cm.
What is the length of segment YZ?
3.5 cm
7.8 cm
4.5 cm
0.5 cm
HELP ASAPPPPP

Answers

I believe the answer should be 3 and 1/2 which is 3.5 because I did the factor 7/8 times 4 and I got 3 and 1/2 I’m not sure

find sum of series: 1+2+3+...+n ​

Answers

Answer:

the sum of the this series is Sn = [n(n+1)] / 2

5/8 + 7/12

A 1/2
B 5/24
C 1 5/24

Answers

Step-by-step explanation:

The answer is not in the option.

The answer is 29/24.

The answer is actually 116/96

What is 4.56 x 105in standard form? a.0.00000456 b.0.0000456 c.0.000456 d.456,000

Answers

Answer:

the answer is b

Step-by-step explanation:

The within-subjects F is the non-independent groups equivalent of the one-way ANOVA. True or False?

Answers

Answer:

Step-by-step explanation:

True

Express the set x≥2x≥2 using interval notation. Use "oo" (two lower case o's) for ∞∞.​

Answers

Answer: [x/2 , 1]

Step-by-step explanation: Convert the inequality to interval notation.

The union consists of all of the elements that are contained in each interval. There is No Solution.

I hope this helps you out. If not, my apologizes.

-Leif Jonsi-

Un guardia forestal divisa, desde un punto de observación A, un incendio en la dirección N27° 10’ E. Otro guardia, que se encuentra en el punto de observación B, a 6 millas al este de A, ve el mismo fuego en la dirección N52° 40’ W. Calcula, al décimo de milla más cercano la distancia de cada uno de los puntos de observación al incendio

Answers

Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

[tex]\dfrac{sin \ F}{f} = \dfrac{sin \ A }{a}[/tex]

[tex]\dfrac{sIn \ 79}{6} = \dfrac{sin \ 63}{a}[/tex]

a sin 79 = 6 sin 63

[tex]a =\dfrac{6 \times sin \ 63}{sin \ 79}[/tex]

[tex]a =\dfrac{6 \times 0.8910}{0.9816}[/tex]

a = 5.446 millas

la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)

[tex]\dfrac{sin \ F}{f} = \dfrac{sin \ B}{b}[/tex]

[tex]\dfrac{sin \ 79}{6} = \dfrac{sin \ 38}{b}[/tex]

b sin 79 = 6 sin 38

[tex]b = \dfrac{6 \times sin \ 38}{sin \ 79}[/tex]

[tex]b = \dfrac{6 \times0.6157 }{0.9816}[/tex]

b = 3.7635 millas

la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

A publisher sells either digital copies of their new book, paperback copies or hardback copies. For every 4 digital sales they make, they make 5 paperback sales and 1 hardback sale. In the first week of sales, the company sells 308 more paperback copies of the book than hardback copies.

Answers

Answer:

This means in the first week the number sells of digital copies is 308, paperback sells was 385 copies and hardback sell was 77 copies

Step-by-step explanation:

Let the number of digital copies be x, the number of paperback copies be y and the number of hardback copies be z.

4 digital sales is equal to 5 paperback sales and 1 hardback sale.

5x = 4y, x = 4z, y = 5z

The company sells 308 more paperback copies of the book than hardback copies

y = 308 + z

But y = 5z

5z = 308 + z

4z = 308

z = 77

y = 5z = 5(77) = 385

x = 4z = 4(77) = 308

This means in the first week the number sells of digital copies is 308, paperback sells was 385 copies and hardback sell was 77 copies

Simplify ten to the eighth divided by ten to the negative third.

Answers

Answer:

[tex]10^{11}[/tex]

Step-by-step explanation:

A statement is given i.e. "ten to the eighth divided by ten to the negative third."

It means that 10 to power 8 divided by 10 to the power -3.

Mathematically,

[tex]\dfrac{10^8}{10^{-3}}[/tex]

We know that, [tex]\dfrac{x^a}{x^b}=x^{a-b}[/tex]

Here, x = 10, a = 8 and b = -3

So,

[tex]\dfrac{10^8}{10^{-3}}=10^{8-(-3)}\\\\=10^{8+3}\\\\=10^{11}[/tex]

So, the answer is [tex]10^{11}[/tex]

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. for any minutes over 200, andrew is charged $0.39 per minute. which of the following piece-wise functions represents charges based on andrews cell phone plan?

Answers

Answer:

f (x) = { 19 + 0.39(x - 300), x > 300

Step-by-step explanation:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan. If  then If  then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore Hence, { 19 + 0.39(x - 300), x > 300

Hoped I helped

What is the probability of rolling a 2 and then a 4? Answer choices are in the form of a percentage, rounded to the nearest whole number.

Answers

Question:

Carl throws a single die twice in a row. For the first throw, Carl rolled a 2; for the second throw he rolled a 4. What is the probability of rolling a 2 and then a 4? Answer choices are in the form of a percentage, rounded to the nearest whole number. O 22% 36% O 3% O 33%

Answer:

The probability of rolling a 2 then 4 is 3%

Step-by-step explanation:

Given

A die rolled twice

Required

Probability of rolling a 2 then 4; i.e. P(2 n 4)

First, we need to list out the sample space

[tex]S = \{1,2,3,4,5,6\}[/tex]

[tex]n(S) = 6[/tex]

Next, is to calculate P(2)

[tex]P(2) = \frac{n(2)}{n(S)}[/tex]

[tex]P(2) = \frac{1}{6}[/tex]

Next, is to calculate P(4)

[tex]P(4) = \frac{n(4)}{n(S)}[/tex]

[tex]P(4) = \frac{1}{6}[/tex]

Next,is to calculate the required probability using the following formula

[tex]P(2\ n\ 4) = P(2) * P(4)[/tex]

[tex]P(2\ n\ 4) = \frac{1}{6} * \frac{1}{6}[/tex]

[tex]P(2\ n\ 4) = \frac{1}{36}[/tex]

[tex]P(2\ n\ 4) = 0.02777777777[/tex]

Convert to Percentage

[tex]P(2\ n\ 4) = 2.777777777\%[/tex]

Approximate

[tex]P(2\ n\ 4) = 3\%[/tex]

Hence, the probability of rolling a 2 then 4 is 3%

Answer:

3%

Step-by-step explanation:

Find the sum of -6x^2-1−6x 2 −1 and x+9x+9.

Answers

Answer:-6x^2+10x-5.

Step-by-step explanation: -6x^2-1−6x 2−1+x+9x+9                                                          -6x^2-1−6x 2−1+10x+9                                                                                                -6x^2-1-12−1+10x+9                                                                                                         -6x^2+10x-1-12-1+9                                                                                                                 6x^2+10x-5

The sum of the two expressions are -6x²+22x+9

What are like and unlike terms in an expression?

In Algebra, the like terms are defined as the terms that contain the same variable which is raised to the same power. In algebraic like terms, only the numerical coefficients can vary. We can combine the like terms to simplify the algebraic expressions.

Given here the expressions here as -6x²+1+6x ×2-1, x+9x+9

The sum is -6x²+1+6x ×2-1 +x+9x+9=-6x²+22x+9

Hence, The sum of the two expressions are -6x²+22x+9

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can y’all help me i keep posting this question and people keep guessing and i keep getting it wrong :/

Answers

Answer:

C

Step-by-step explanation:

So we have:

[tex]\frac{6^{\frac{3}{10}}}{6^\frac{1}{5}}[/tex]

To simplify, we can use the quotient rule of exponents, which says that if we have:

[tex]\frac{x^a}{x^b}[/tex]

Then this equals:

[tex]=x^{a-b}[/tex]

So, our equation will be:

[tex]\frac{6^{\frac{3}{10}}}{6^\frac{1}{5}}\\=6^{\frac{3}{10}-\frac{1}{5}}[/tex]

Subtract the exponents. Turn 1/5 into 2/10 by multiplying both layers be 2. Thus:

[tex]6^{\frac{3}{10}-\frac{1}{5}}\\=6^{\frac{3}{10}-\frac{2}{10}}[/tex]

Subtract in the exponent:

[tex]=6^{\frac{1}{10}}[/tex]

So, our answer is C :)

Round each number to three significant figures.a. 3.14159 b. 6.12356c. 4.56787

Answers

Answer:

The round off values are- 3.14, 6.12, and 4.57 respectively.

Step-by-step explanation:

The given value to which we have to round off is a. 3.14159 b. 6.12356 c. 4.56787

In order to round off the number we must keep in mind that there should be three digits in total and we will increase the value by one if the right-hand side value is more than 5.  

Thus round off figure of 3.14159 is 3.14.

The round off figure of 6.12356 is 6.12.

The round off figure of 4.56787 is 4.57.

math help on this question!

Answers

Answer:

none

Step-by-step explanation:

110 + 60 = 170

but 170 is obviously not 180 sooo none will be 60 degrees

Calculate the perimeter of the segment of a circle of radius 8cm. If chord subtemds angle 98 degree at the center

Answers

Answer:

If radius = 8 cm and we needed perimeter of complete circle then

circumference (or perimeter) = 2*PI * 8 = 50.2654824574  cm

or 50.27 cm (rounded)

Step-by-step explanation:

please help me in this question!

Answers

Answer:

n = 5

Step-by-step explanation:

All of the other choices are true except for n = 5, which is a counterexample. [tex]4^{5}[/tex] = 1024, which is greater than the other side as the other side is:

and [tex]4^{2}[/tex] = 16, 16 + 250 = 266

1024 < 266 is definitely false.

Therefore, the counterexample is n = 5.

True or false? For any two integers x and y, |x+y| = |x| + |y|

Answers

Answer:

False

Step-by-step explanation:

|x+y| = |x| + |y|

To show this is false, all we have to do is find one example where it is false

Let x = -1 and y = 4

|-1+4| = |-1| + |4|

|3| = |1| + |4|

3 = 5

This is false so we have a set of integers where the statement is not true

(6^2)^x =1 I need to now ASAP

Answers

Answer:

x =0

Step-by-step explanation:

[tex]\left(6^2\right)^x=1\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}\\\left(6^2\right)^x=6^{2x}\\\\6^{2x}=1\\\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)\\\ln \left(6^{2x}\right)=\ln \left(1\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\ln \left(6^{2x}\right)=2x\ln \left(6\right)\\2x\ln \left(6\right)=\ln \left(1\right)\\[/tex]

[tex]\mathrm{Solve\:}\:2x\ln \left(6\right)=\ln \left(1\right):\\\quad x=0[/tex]

Write an inequality for the graph shown below.
Use x for your variable.

Answers

Answer:

x ≤ 3

Step-by-step explanation:

In the graph given, values of variable x is represented.

From the plot, we note that a small circle is at point 3 on the numberline. This small "o" is shaded, which indicates that the values of x includes 3.

The arrow which starts at 3 on the numberline, points towards our left. This means that the values of x are less than or equal to 3. No value of x is greater than 3.

Therefore, the following inequality can be written for the graph:

x ≤ 3

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