Write the equation of the line that passes through the points (-9,9) and (8, -2).
Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal
line.

the first one is (B) i think

the second one is (B)

the third one is (B)

the fourth one is (A)

the fifth one is (A)

Answer:

x<5   or  x<3/2

Step-by-step explanation:

2[tex]x^{2}[/tex]-13x+15<0

2[tex]x^{2}[/tex]-10x-3x+15<0

2x(x-5)-3(x-5)<0

(x-5)(2x-3)<0

x-5<0  or 2x-3<0

x<5  or  x<3/2

Answer:

x^2-3x-y+16?

Step-by-step explanation:

simplest form already, but can be converted into a proper polynomial.

x^2-3x-y+16

Answer:

Its C (Third Multiple Choice Answer)

Step-by-step explanation:

The reason being that x + 1 / 2 (6x - 4) = 6 is the way it is instead of the first step being x + 6x / 2 - 4 / 2 = 6 is because it is using legal manipulation by multiplying the 1 / 2 out.

Math:

First

2 * (x + 1 / 2 (6x - 4) = 6 * 2 [In this case the x gets multiplied by 2 and multiplies 2 to the other side as well. The reason why it isn't a Distributive Property in the first place is because we are using multiplication only and the equation is not 1 / 2 (6x - 4).

Then

2x + 6x - 4 = 12 will then equal to 8x - 4 = 12 which is adding like terms

Thirdly

(+ 4) + 8x - 4 = 12 (+ 4) [The parenthesis is to identify that the 4 is positive]

will then turn into 8x = 16

Finally

By dividing 8 on both sides of the previous equation

8x / 8 = 16 / 8 equaling x = 2.

Answer:

2/3 ​sandwich.

Step-by-step explanation:

No Explanation

Answer:

2%

Step-by-step explanation:

Answer:

Step-by-step explanation:

After creating an equilateral triangle using 3 toothpicks, I require 3 more toothpicks to create more 3 equilateral triangles ie.4 triangles it toto.

First place 3 toothpicks end to end on a Horizontal plane to create an equilateral triangle.

THEN erect 3 toothpicks on each corner of the triangles making other ends joined up together in space above the Horizontal plane so as to create another same THREE equilateral triangles. (I am unable to provide a pictorial presentation due to inadequacy of signs & symbols on the keyboard. )

I suppose, you must have visualised the superstructure.

Thanks.

Step-by-step explanation:

breath=7

lenghth=3(7)

=21

perimeter of rect=2(l+b)

=2(21+7)

=56

Answer:

y= 4/1x +1

Step-by-step explanation:

the number on the y axis is the b and you do rise over run to find m you rise (so you go up or down) 4 times and run( go to the sides) once.

rise 4

-------- = -----

run 1

Answer:

y = 3x + 1

Step-by-step explanation:

Slope: As it rises 3, it runs 1

Slope = Change in y/change in x

Slope = 3/1

y - intercept = 1 ,the point of intersection

Equation : y = mx + b

m = slope

b = y-intercept

Equation : y = 3x + 1

-Chetan K

Answer 5-5.190 =-945 -2=-947 2-2=0+3 =3+7=-935

Step-by-step explanation:

Answer: They are all divisible by 2.

Step-by-step explanation: They all have 2 in common. If you divide them by 2, they all work. Also, if you simplify all to the lowest number, they equal 2 except 2 itself which equals 1.

Answer:

divisible by 2 luv

Step-by-step explanation:

Answer:

71

Step-by-step explanation:

25+2+2+2+2+1=34

28+2+2+2+2+1=37

sum=34+37

71

Answer:

3+2+2=7 year back

28-7=21

25-7=18

years old pls mark me as brainlist

Answer:

Step-by-step explanation:

How do you find the answer for 30=6x+20?

30 = 6x + 20

10 = 6x

x = 10/6

5/4

------------------ check

30 = 6 * 10/6 + 20

30 = 10 + 20

30 = 30

the answer is good

The circle that passes through the vertices of triangle ΔABC (A, B, C) is the

circumscribing circle of triangle ΔABC.

The area of the circle that passes through vertices A, B, and C, is (C) 26·π

Reasons:

The given parameters are;

Side length of isosceles triangle ΔABC; [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex] = 3·√6

Radius of circle tangent to [tex]\overline{AB}[/tex] at B and [tex]\overline{AC}[/tex] at C = 5·√2

Required:

Area of the circle that passes through vertices A, B, and C

Solution:

Angle ∠BAO is given as follows;

[tex]\angle BAO = arctan\left(\dfrac{5 \cdot \sqrt{2} }{3 \cdot \sqrt{6}} \right) = \mathbf{arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)}[/tex]

Therefore;

[tex]\angle BOA = 90^{\circ} - arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)[/tex]

[tex]\overline{BC} = 2 \times 5 \cdot \sqrt{2} \times sin\left(90^{\circ} - arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right) = 15\cdot \sqrt{\dfrac{6}{13} }[/tex]

∠ABO' = ∠BAO' (Base angles of isosceles triangle ΔABO')

[tex]\angle BAO' = \angle BAO = \mathbf{arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)}[/tex]

Therefore;

[tex]\angle BO'A = 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)[/tex]

From sine rule, we have;

[tex]\dfrac{\overline{AB}}{sin \left(\angle BO'A \right)} = \mathbf{\dfrac{\overline{BO'}}{sin \left(\angle BAO' \right) \right)}}[/tex]

Which gives;

[tex]\mathbf{\dfrac{3 \cdot \sqrt{6} }{sin \left( 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right)}} = \dfrac{\overline{BO'}}{sin \left(arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right) \right)}[/tex]

Using a graphing calculator, we get;

[tex]\overline{BO'} = \dfrac{3 \cdot \sqrt{6} }{sin \left( 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right)} \times sin \left(arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right) \right) = \sqrt{26}[/tex]

The radius of the circumscribing circle [tex]\overline{BO'}[/tex] = √(26)

Therefore, area of the circumscribing circle, [tex]A_{O'}[/tex] = π·(√(26))² = 26·π

The area of the circle that passes through vertices A, B, and C, is (C) 26·π

Learn more here:

https://brainly.com/question/17147358

The possible question options obtained from a similar question online are;

(A) 24·π (B) 25·π (C) 26·π (D) 27·π (E) 28·π

Answer:

Step-by-step explanation:

(-4,-5) and (6,4)

Slope: (4 - - 5) / ( 6 - - 4) = 9/10

y-intercept= - 5 - (9/10)(-4)

= - 5 + 36/10 = -7/5

y = 9/10x - 7/5

The equation of the line is x + 10y -19 = 0.

We are given that;

The points of line segment= (6,4) and (-4,5)

Now,

To find the equation of a line given two points, we can use the two-point form formula:

y − y 1 = y 2 − y 1 x 2 − x 1 ( x − x 1)

where (x 1, y 1) and (x 2, y 2) are the two given points and (x, y) is any point on the line.

We have:

(x 1, y 1) = (6,4)

(x 2, y 2) = (-4,5)

Substituting these values into the formula, we get:

y − 4 = 5 − 4 -4 − 6 ( x − 6)

Simplifying and rearranging, we get:

y = -1/10 x + 19/10

This is the equation of the line in slope-intercept form. We can also write it in standard form by multiplying both sides by 10 and moving all terms to one side:

x + 10y -19 = 0

Therefore, by equation the answer will be x + 10y -19 = 0.

Learn more about equation;

https://brainly.com/question/10413253

#SPJ2

Answer:

Step-by-step explanation:

The ratio of corresponding sides is same for similar triangles:

Correct choice is D

Answer:

i tink its a

Step-by-step explanation:

Answer:

34800, 350000, 300000

Step-by-step explanation:

5>=5

34800

7>=5

350000

4<=5

300000

Answer: 4914

Step-by-step explanation:

multiply 15 and 20 to make 300

multiply 24 and 27 to make 648

set up proportion

[tex]\frac{300}{648}[/tex] × [tex]\frac{2275}{x}[/tex]

cross multiply

300x = 648(2275)

300x = 1474200

x = 4914

Answer:

1) B 0.5

2) C 2

Step-by-step explanation:

point A (-2, 2) (0.5) = (-1, 1) A'

point B (-2, -1) (0.5) = (-1, -0.5) B'

point C (3, -1) (0.5) = (1.5, -0.5) B'

point A (-2, 2) (2) = (-4, 4) A'

point B (-2, -1) (2) = (-4, -2) B'

point C (3, -1) (2) = (6, -2) B'

Answer: [tex]\frac{9}{x-1}[/tex]

Step-by-step explanation:

Since the denominators are the same, we can subtract the numerators.

[tex]\frac{x+1}{x-1}-\frac{x-8}{x-1}=\frac{(x+1)-(x-8)}{x-1}=\boxed{\frac{9}{x-1}}[/tex]

Answer:

Pregnant women have the option of being scanned for Cystic Fibrosis risks in their unborn babies. If a mother or a father have a certain recessive gene, the baby is at risk for Cystic Fibrosis.

Given the three events, which of the following statements is true?  

Select all that apply.

Event A: The mother or father carries the recessive gene.

Event B: The father carries the recessive gene.

Event C: The baby is at risk for Cystic Fibrosis.

Select all that apply:

Event A and Event B are mutually exclusive.

Event B and Event C are mutually exclusive.

Event A and Event C are not mutually exclusive.

Event A and Event C are mutually exclusive.

Event A and Event C are not mutually exclusive.

Remember that in general, A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes and P(A AND B)=0.

In this question, note that if the mother or father carries the recessive gene for cystic fibrosis, the baby is at risk. So here, A and C are not mutually exclusive, and B and C are not mutually exclusive.

A and B are not mutually exclusive because they share an outcome: the father carrying the recessive gene.

Step-by-step explanation:

Using the t-distribution, it is found that since the absolute value of the test statistic is less than the critical value for the two-tailed test, you cannot conclude that the mean sales differ between the two programs.

At the null hypothesis, it is tested if the mean sales do not differ between the two programs, that is, the subtraction of the means is 0, hence:

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

At the alternative hypothesis, it is tested if they differ, that is:

[tex]H_1: \mu_1 - \mu_2 \neq 0[/tex]

The mean and the standard errors for each sample are:

[tex]\mu_1 = 42, s_1 = 5.9675[/tex]

[tex]\mu_2 = 44.56, s_2 = 5.6177[/tex]

The distribution of the difference has mean and standard deviation given by:

[tex]\overline{x} = \mu_2 - \mu_1 = 44.56 - 42 = 2.56[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{5.9675^2 + 5.6177^2} = 8.1957[/tex]

The test statistic is:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.

Then:

[tex]t = \frac{2.56 - 0}{8.1957}[/tex]

[tex]t = 0.31[/tex]

The critical value for a two-tailed test, as we are testing if the mean is different of a value, with 9 + 9 - 2 = 16 df and a significance level of 0.05 is [tex]|t^{\ast}| = 2.12[/tex]

Since the absolute value of the test statistic is less than the critical value for the two-tailed test, you cannot conclude that the mean sales differ between the two programs.

A similar problem is given at https://brainly.com/question/13873630

Answer:

x>8

Step-by-step explanation:

[tex]- 6x+ 30 < - 18 \\ - 6x < - 18 - 30 \\ - 6x < - 48 \\ \frac{ - 6x}{ - 6} < \frac{ - 48}{ - 6} \\ x > 8[/tex]

9514 1404 393

Answer:

  5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

  ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is  ...

  b^2 -4ac

so the discriminant of your equation is ...

  10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

  100 +4ac = 0

  25 +ac = 0

  ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

  5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

Additional comment

Your problem statement does not require that 'a' be non-zero. If a=0, then the equation will have one real solution for any value of c.

If you restrict the solutions to integers, then possibilities include ...

  (a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

Answer:

The equation is 5x+10x=-5

Step-by-step explanation:

Answer:

ratio of long-sleeved shirts to short-sleeved shirts is 1:2 this is my answer that I thought of if you don't feel comfortable believing me just wait for another person to answer and see what they say.

Step-by-step explanation:

Answer:

85%

Step-by-step explanation: