Find each measure below.
arc SR=
Answer:
Measure of arc SR = 62°
Step-by-step explanation:
By using the property,
"Measure of an arc of the circle is double of the measure of the angle subtended by the arch."
m∠SUR = [tex]\frac{1}{2}m(\text{arc SR})[/tex]
m(arc SR) = 2m∠SUR
= 2(31°)
= 62°
Q9 A gardener wants to build this greenhouse in the top right hand corner of her garden.
This is a sketch plan of her garden.
2.5m
5.5m
greenhouse
2m
here
5.5m
2.5m
She will leave a 50cm space between the greenhouse and the edge of the garden.
She wants a scaled plan of the garden showing the position of the greenhouse.
Draw a scale plan. Put the scale you use on the plan.
Answer:
See attachment for drawing
Step-by-step explanation:
Given
See attachment for sketch of plan
Required
Draw a scaled plan
From the question, the garden has the following dimensions.
5.5m, 5.5m, 4m and 2.5m
Using a scale of 1m : 50 cm units, the above measurements will be represented as:
[tex]5.5m \to \frac{5.5m}{50cm} \to \frac{5.5m}{0.5m} \to 11cm[/tex]
[tex]4m \to \frac{4m}{50cm} \to \frac{4m}{0.5m} \to 8cm[/tex]
[tex]2.5m \to \frac{2.5m}{50cm} \to \frac{2.5m}{0.5m} \to 5cm[/tex]
From the question, we understand that there will be 50cm space between the greenhouse and the edge.
On the scale drawing, this will be represented as:
[tex]50cm \to \frac{50cm}{50cm} \to 1cm[/tex]
From the question, the green house has the following dimensions.
2m, 2.5m
On the scale drawing, this will be represented as:
[tex]2m \to \frac{2m}{50cm} \to \frac{2m}{0.5m} \to 4m[/tex]
[tex]2.5m \to \frac{2.5m}{50cm} \to \frac{2.5m}{0.5m} \to 5m[/tex]
See attachment 2 for scale drawing
What is the area and perimeter?
Answer:
Perimeter: 26 units
Area: 24 units²
Step-by-step explanation:
12 + 9 + 5 = 26
A = 1/2BH
A = 1/2 12(4)
A = 1/2 48
A = 24
Avery is currently making $14 per hour at her job. Her boss gives her a 15% raise for showing good work ethic.
If she works 40 hours per week, how much more will Avery be making than before her 15% raise?
A.$15.00
B.$280.00
C.$84.00
D.$116.00
Answer:
C) $84
Step-by-step explanation:
40 x 14 = 560
she made $560 prior to raise
14 x 1.15 = 16.10
her new hourly rate is $16.10
40 x 16.1 = 644
she now earns $644 per week
644 - 560 = 84
x^2 + y^2 =-6x-14-6y
Answer:
x=−3+√(−y−1)(y+5)
Step-by-step explanation:
thats if your solving for x if not to math w l ay
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4. Using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 51 and 55
Answer:
percentage of lightbulb replacement requests = 34.15 %
Step-by-step explanation:
According to Empirical Rule
interval %
μ ± σ 55 ± 4 ( 51 ; 59 ) 68.3
As the question is a percentage between 55 and 51
or between 51 and μ - σ by symmetry is 68.3/2
% of lightbulb replacement requests = 34.15 %
Help!!!!!!!!!!!!!!!
If f(x) = -(24 – 32) – x, find f(-2).
SOMEONE ANSWER QUICK!!
Steven bought 4 pizzas to share with his family. Together, they ate 2 7/12 pizzas on Friday and another 2/3 of a pizza on Saturday. How much pizza is left??
Answer:
3/4 of a pizza leftover.
Step-by-step explanation:
2 7/12 + 2/3 = 3 1/4
4 - 3 1/4 = 3/4
so 3/4 of 1 pizza is left.
Find all the missing elements:
B
14
15
70°
A
b
с
Answer:
[tex]B=48.7\\[/tex]
[tex]c=61.3[/tex]
[tex]b=12[/tex]
Step-by-step explanation:
Using sines law for triangles,
[tex]\frac{15}{sinA} =\frac{14}{sinc} =\frac{b}{sinB} \\\\A= 70[/tex]
⇒ [tex]\frac{15}{sin70} =\frac{14}{sinC} =\frac{b}{sinB}[/tex]
⇒ [tex]\frac{15}{0.9397} =\frac{14}{sinC}=\frac{b}{sinB}[/tex]
⇒ [tex]15.9625=\frac{14}{sinC}[/tex]
⇒ [tex]SinC=\frac{14}{15.9625}=0.8771[/tex]
⇒ [tex]C=Sin^{-1}(0.8771)=61.29[/tex]
⇒ [tex]C=61 ~ or ~ 61.30[/tex]
[tex]\frac{b}{Sin B}=15.9625[/tex]
Now sum of angles a Δ is 180°
A+B+C=180°
[tex]70+B+61=180[/tex]
[tex]B=180-131=49~ or ~ 48.7[/tex]
[tex]b=sin(48.70)(15.9625)=(0.7547)*(15.9625)= 12.0[/tex]
╔════ ∘◦ ☆ ◦∘ ══════╗
hope it helps..
have a great day!!
╚═════ ∘◦ ❉ ◦∘ ═════╝
the answer? wowisoososksks
Answer:
1/6
Hope that this helps!
Which of these is a two-step equation? Ax + 9 = 21incorrect answer Bx = 11 + 2incorrect answer C2x + 9 = 21incorrect answer Dx/3 = 9
Answer:
2x + 9 = 21
Step-by-step explanation:
Looking at option C;
2x + 9 = 21
Step 1: Subtract 9 from both sides
2x+9 - 9 = 21 - 9
2x = 12
Step 2: divide both sides by 2
2x/2 = 12/2
x = 6
Hence the expression which is a two-step equation is 2x + 9 = 21 since we arrived at the solution in two steps
The population of Bengal tigers in a region of India can be modeled by the function P = 450(0.85), where P is the
population and I is the number of years since 2000.
What is the Bengal tiger population in 2000?
and by what percent does the tiger population decrease each year?
Answer:
(a) The population in 2000 is 450
(b) 15% decreases each year
Step-by-step explanation:
Given
[tex]P = 450(0.85)^t[/tex] --- since 2000
[tex]P \to Population[/tex]
[tex]t \to years[/tex]
Solving (a): The population in 2000
First calculate t
[tex]t = 2000 - 2000[/tex] --- years since 200
[tex]t = 0[/tex]
So, we have:
[tex]P = 450(0.85)^t[/tex]
[tex]P = 450 * 0.85^0[/tex]
[tex]P = 450 * 1[/tex]
[tex]P = 450[/tex]
Solving (b): Rate of population decrease
A function that decreases is represented as:
[tex]P(t) = a(1 - r)^t[/tex]
Where
[tex]r \to[/tex] rate of decrement
Compare [tex]P(t) = a(1 - r)^t[/tex] and [tex]P = 450(0.85)^t[/tex]
[tex]1- r = 0.85[/tex]
Collect like terms
[tex]r = 1 - 0.85[/tex]
[tex]r = 0.15[/tex]
Express as percentage
[tex]r = 15\%[/tex]
find a
polynomial P(x) of 2nd degree if P(1)=0
P (2) 3
P(-3)=0
Given:
P(x) is a 2nd degree polynomial.
[tex]P(1)=0,\ P(2)=3,\ P(-3)=0[/tex]
To find:
The polynomial P(x).
Solution:
If P(x) is a polynomial and P(c)=0, then c is a zero of the polynomial and (x-c) is a factor of polynomial P(x).
We have, [tex]P(1)=0,\ P(-3)=0[/tex]. It means 1 and -3 are two zeros of the polynomial P(x) and (x-1) and (x+3) are two factors of the polynomial P(x).
So, the required polynomial is defined as:
[tex]P(x)=a(x-1)(x+3)[/tex] ...(i)
Where, a is a constant.
We have, [tex]P(2)=3[/tex]. So, substituting [tex]x=2,\ P(x)=3[/tex] in (i), we get
[tex]3=a(2-1)(2+3)[/tex]
[tex]3=a(1)(5)[/tex]
[tex]3=5a[/tex]
[tex]\dfrac{3}{5}=a[/tex]
Putting [tex]a=\dfrac{3}{5}[/tex] in (i), we get
[tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex]
Therefore, the required polynomial is [tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex].
help me out please ill give you 5 star, brainlist
Answer:
H
Step-by-step explanation:
you can see that it's increasing by 50 for each line
4*50=200
What is the slope of the line that passes through the points listed in the table?
x | y
4 | 3
7 | 9
A. -2
B. 2
C. 3
D. 6
Answer:
B. 2
Step-by-step explanation:
(4, 3) (7, 9) M = Slope
M = [tex]\frac{y^2-y^1}{x^2-x^1}[/tex] Slope formula
[tex]M=\frac{9-3}{7-4}[/tex] Using the slope formula, plot both x and y intercepts
[tex]M=\frac{6}{3}[/tex] Slope needs to be simplified into a whole number
[tex]M=2[/tex]
I need correct answer please!:)
Answer:
G. Angle NKL is congruent to angle ZWX is the answer
Step-by-step explanation:
Hope it helps you:)
Write the equation of a line that goes through the points (2, -2) and (1, -8)
show work i will appreciate it
Answer:
y=6x-14
Step-by-step explanation:
m=-8-(-2)/1-2
m=-8+2/1-2
m=-6/-1
m=6
y-y1=m(x-x1)
y-(-2)=6(x-2)
y+2=6x-12
y=6x-2-12
y=6x-14
Help pleaseeeeeeeeeee
Answer:
Step-by-step explanation:
-3,5 to find it first go over then go up and you have your answer
Answer:
The answer is (5, -3)
Hope this helps!
Mark me brainliest if I'm right :)
can someone please help
question: An airplane is flying at an elevation of 1500 feet. What is the airplane's angle of elevation from the runway when it is 5000 feet from the runway?
Answer:
Angle of elevation of the airplane = 17.46 degrees
Step-by-step explanation:
From the picture attached,
An airplane is flying at an altitude of 1500 ft at point A.
Runway starts from point B from which distance of the airplane is 5000 ft.
Now we apply sine rule in the given triangle ABC to measure the angle θ.
sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
sinθ = [tex]\frac{AC}{AB}[/tex]
= [tex]\frac{1500}{5000}[/tex]
[tex]\theta=\text{sin}^{-1}(\frac{3}{10})[/tex]
[tex]\theta=17.46[/tex] degrees
Evaluate the expression.
3 + (50- 5^2)
5. (08.01) Line M is represented by the following equation: x + y = -1 What is most likely the equation for line P so the set of equations has infinitely many solutions?
O 2x + 2y = 2
O 2x + 2y = 4
O 2x + 2y = -2
O x - y = 1
Answer:
2x + 2y = -2
Step-by-step explanation:
you can divide a 2 from all three terms in 2x + 2y = -2 to get x + y = -1 which overlaps the original equation to provide an infinite number of solutions
Which of these are the constant?
4y+1+9x
Answer:
1 is the constant
Step-by-step explanation:
Dan walks around the block. The block is 200 feet wide and 800 feet long. How many feet did he walk?
Answer:
2000 feet
Step-by-step explanation:
200*2=400
800*2=1600
400+1600=2000
Square contains 4cm. find the area of the shape.
Answer:
Step-by-step explanation:
'Area of a square' formula is A = s^2, where s in the length of one side.
Here, with s = 4 cm, A = 16 cm^2
4 Students is___% of 20 students.
Answer:
20%
Step-by-step explanation:
4 / 20 = 0.2 = 20%
Hope this helps :)
Answer:
4 Students is 20% of 20 students.
Step-by-step explanation:
[tex] \frac{4}{20} \times 100[/tex]
= 4 × 5 %
= 20%
The third-degree Taylor polynomial about x = 0 of In(1 - x) is
Answer:
[tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Derivative Rule [Quotient Rule]: [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
MacLaurin/Taylor Polynomials
Approximating Transcendental and Elementary functionsMacLaurin Polynomial: [tex]\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n[/tex]Taylor Polynomial: [tex]\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n[/tex]Step-by-step explanation:
*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.
Step 1: Define
Identify
f(x) = ln(1 - x)
Center: x = 0
n = 3
Step 2: Differentiate
[Function] 1st Derivative: [tex]\displaystyle f'(x) = \frac{1}{x - 1}[/tex][Function] 2nd Derivative: [tex]\displaystyle f''(x) = \frac{-1}{(x - 1)^2}[/tex][Function] 3rd Derivative: [tex]\displaystyle f'''(x) = \frac{2}{(x - 1)^3}[/tex]Step 3: Evaluate Functions
Substitute in center x [Function]: [tex]\displaystyle f(0) = ln(1 - 0)[/tex]Simplify: [tex]\displaystyle f(0) = 0[/tex]Substitute in center x [1st Derivative]: [tex]\displaystyle f'(0) = \frac{1}{0 - 1}[/tex]Simplify: [tex]\displaystyle f'(0) = -1[/tex]Substitute in center x [2nd Derivative]: [tex]\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}[/tex]Simplify: [tex]\displaystyle f''(0) = -1[/tex]Substitute in center x [3rd Derivative]: [tex]\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}[/tex]Simplify: [tex]\displaystyle f'''(0) = -2[/tex]Step 4: Write Taylor Polynomial
Substitute in derivative function values [MacLaurin Polynomial]: [tex]\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3[/tex]Simplify: [tex]\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}[/tex]Topic: AP Calculus BC (Calculus I/II)
Unit: Taylor Polynomials and Approximations
Book: College Calculus 10e
Evaluate the expression 4x^2 + 3y for x = 5 and = 6.
Answer: 118
Step-by-step explanation:
PLEASE HELP ASAP!!!
Given that PQ/ST = QR/TU = RS/US , select the postulate or theroem that you can use to conclude that the triangle are similar.
○ ASA similarly postulate
○ SAS similarly theorem
○ AA similarly postulate
○ SSS similarly theorem
I need help with this ASAP!!!!
Answer:
B) 81.96°
Step-by-step explanation:
40.67 - (-41.29)
40.67 + 41.29 = 81.96
If the simple interest earned on $6000 for 9 years is $2,160. Then what is the interest rate?
Answer:
4 %
Step-by-step explanation:
1 year interest =2160÷9
= £240
Interest rate=240/6000 ×100
=4%