Answer:
y = mx + b
m =(-2--4)/(-6--7)
m = 2
-2 = 2(-6) +b
b = 10
y= 2x + 10
A teacher is comparing the quarter grades between two of her classes. She takes a random sample of 8 students from each class and lists the grades as shown. Find the mean for Class A.
Class A: 80, 83, 74, 91, 76, 87, 93, 72
Class B: 90, 75, 82, 86, 73, 85, 79, 94
Last Question Plz Help
Answer:
this is good looking nice photo but li can't give you answer of that sorry.
Step-by-step e this https://www.commonlit.org/en/students/student_lesson_activities
Need help with it I don’t know how to do it
factorize (2u+3u)(u+v)-2u+3v
Answer:
Step-by-step explanation:
(2u+3u)(u+v)-2u+3v
=2u(u+v)+3u(u+v)-2u+3v
=2u^2+2uv+3u^2+3uv-2u+3v
=5u^2+5uv-2u+3v
Which choice is equivalent to the product below when x is greater than or equal to 0
Answer: I believe it is C.
Step-by-step explanation: Because if you take 4 x 20 = 80
If I am wrong sorry.
Help please just right the ratio for all
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Answer:
1/18
Step-by-step explanation:
[tex]\frac{1}{9}[/tex]÷2
make 2 a fraction
[tex]\frac{1}{9}[/tex]÷[tex]\frac{2}{1}[/tex]
cross multiply
1*1
9*2
[tex]\frac{1*1}{9*2}[/tex]
[tex]\frac{1}{18}[/tex]
Answer:
Step-by-step explanation:
You always invert the second number in a division question and then multiply. This one is a little different. It has three levels. What do you do about that?
[tex]\frac{\frac{1}{9} }{\frac{2}{1} }[/tex]
Now you have a four level question which is handled the same way as all four level question.
Invert the bottom and multiply. Invert means turn upside down. So you turn the 2/1 upside down and you get 1/2
[tex]\frac{1}{9}*\frac{1}{2}[/tex]
What you get is 1/18 The green box with the question mark is a 1.
please help asap!!!!
Answer:
Hello! answer: 585
Step-by-step explanation:
This polygon can be split into 6 triangles so all you have to do is find the area of 1 then multiply by 6 to get the whole things area so...
15 × 13 = 195 195 ÷ 2 = 97.5 97.5 × 6 = 585 therefore the area is 585 hope that helps you!
solve the following equation 4 x + 10 = 66
-> 4x= 66-10
-> 4x= 56
-> x= 56/4
-> x= 14
mark me brainliestttt plsss :)))
Answer:
x = 14.
Step-by-step explanation:
4x + 10 = 66
4x + 10 - 10 = 66 - 10
4x = 56
x = 56/4 = 14.
The area of Sophie‘s herb garden is 1/8 The area of her vegetable garden. The area of her herb garden is 6 square feet. What is the area of her vegetable garden
Answer:
see below
Step-by-step explanation: 5 25 14 02
herb garden is 1/8 The area of her vegetable garden
herb garden is 6 square feet
vegetable garden = ???
herb garden / vegetable garden = 1/8 solve for vegetable garden
herb garden × 8 = vegetable garden
6 ft² × 8 = __________ ft²
2.75 Cards are dealt, one at a time, from a standard 52-card deck. a If the first 2 cards are both spades, what is the probability that the next 3 cards are also spades
Answer:
The answer is "0.00842".
Step-by-step explanation:
Due to these cards, a conventional 52-card set is dealt one at a time.
While the first two cards are spades, then it would be expected that we could find the next three cards tents, too.
Let A draw 2 spade cards out of 52 cards. Let B become the occasion to draw 3 spade cards the remaining 50 end cards [tex](A \cap B)[/tex] was its case where a 52 card spade is chosen [tex](2+3)=5[/tex].
The number of plots drawn first from 13 regular 52-cerd decks equals number of,[tex]n(A)=\binom{13}{2}[/tex] probability of event [tex]A, PA =\frac{\binom{13}{2}}{\binom{52}{2}}[/tex]
Furthermore, the multitude of possibilities we can pull from of the remaining 11 spades of the previous 3 cards is 50-card decks standard, [tex]n (B) = \binom{11}{3}[/tex] then, the probability of event, [tex]B, P(B)=\frac{\binom{11}{3}}{\binom{50}{3}}[/tex]
The chances of five cards being drawn (three spades and two spades),
[tex]P(B \cap A)=\frac{\binom{13}{5}}{\binom{52}{5}}[/tex]
Then there is the chance that the next three cards will be picked if the first two are both pads, [tex]P(\frac{B}{A})[/tex]
[tex]\to P(\frac{B}{A}) \\\\ =\frac{P(B\cap A )}{P(A)}\\\\=\frac{\frac{\frac{13}{5}}{\frac{52}{2}}}{\frac{\frac{13}{2}}{\frac{52}{2}}}\\\\= 0.00842[/tex]
In a small metropolitan area, annual losses due to storm, fire, andtheft are assumed to be independent, exponentially distributed random variableswith respective means 1.0, 1.5, 2.4. Determine the probability that the maximumof these losses exceeds 3.
Answer:
[tex]0.4138[/tex]
Step-by-step explanation:
Given
[tex]x \to storm[/tex]
[tex]\mu_x = 1.0[/tex]
[tex]y \to fire[/tex]
[tex]\mu_y = 1.5[/tex]
[tex]z \to theft[/tex]
[tex]\mu_z = 2.4[/tex]
Let the event that the above three factors is greater than 3 be represented as:
[tex]P(A > 3)[/tex]
Using complement rule, we have:
[tex]P(A > 3) = 1 - P(A \le 3)[/tex]
This gives:
[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]
-----------------------------------------------------------------------------------------------------------
The exponential distribution formula of each is:
[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]
So, we have:
[tex]k = 3; \mu_x = 1[/tex]
[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]
[tex]k=3; \mu_y = 1.5[/tex]
[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]
[tex]k = 3; \mu_z = 2.4[/tex]
[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]
-----------------------------------------------------------------------------------------------------------
[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]
[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]
[tex]P(A > 3) = 1 - 0.5862[/tex]
[tex]P(A > 3) = 0.4138[/tex]
help please for my math!!!!!!!!!!!
Answer:
perimeter for rectangle: (x-2+x+2)×2=4x
perimeter for triangle : 2x-8+2x-8+x+6
=5x-10
The question said both geometry has same perimeter,so we have equation :
4x=5x-10
=>x= 10
put x in triangle's perimeter: 2×10-8+2×10-8+10+6
= 40
Step-by-step explanation:
the answer is C, hope you understand it
Find the area of each figure. Round to the nearest tenth if necessary.
Answer:
Solution given:
1.
diameter(d)=6mm
base(b)=8mm
height (h)=5mm
Area of figure=area of parallelogram +area of semi circle
base*height+½π(d/2)²8*5+½*π×(6/2)²40+14.1454.4mm²Area :54.14mm²2.
for triangle
base[b]=6ft
height(h)=9ft
for square
length[l]=9ft
Area of figure=area of square +area of triangle
=l²+½*b*h=9²+½*6*9=81+27=108ft²Area: 108ft²What are the main properties of a parallelogram?
use the parallelogram (ABEF) to help you
Answer:
It must be number 2.
1 and 3 number is wrong as parallelogram don't need have right angle
Please help ;-;im stuck
Answer:
999
Step-by-step explanation:
223 → 200 + 20 + 3
374 → 300 + 70 + 4
402 → 400 + 0 + 2
900 + 90 + 9
standard form = 999
URGENT!
Find the value of x for which ABCD must be a parallelogram.
3
9
1
41
Answer and Step-by-step explanation:
To find the value of x, set the sides BC and AD equal to each other (we can do this because we are told that the figure is a parallelogram, and those sides are congruent as stated in the properties of a parallelogram).
16x - 15 = 30 + 11x
Subtract 11x from both sides of the equation.
5x - 15 = 30
Add 15 to both sides of the equation.
5x = 45
Divide both sides of the equation by 5.
x = 9
So, the answer is 9, which is equal to x.
#teamtrees #PAW (Plant And Water)
Answer:
x = 1.67
Step-by-step explanation:
We know that in a parallel, opposite sides are parallel and congruent, therefore we can solve for x, by:
(BC) = (AD)
16x - 15 = 30 - 11x
(+11x) + 16x - 15 = 30
27x - 15 = 30
27x = 45
x = 45/27
x = 1.67
Therefore, x = 1.67
Hope this helps!
simply the expression below
Answer:
A
Step-by-step explanation:
Answer:
D. (w-3)/(w-7)
Step-by-step explanation:
(w+3)(w-3)/(w-7)(w+3)
Hence, removing (w+3),
(w-3)/(w-7)
Feel free to mark this as brainliest :D
Which of the following CANNOT be true for a triangle?
A. A triangle can be equilateral and obtuse at the same time.
B. A triangle can be equilateral and equiangular at the same time.
C. A triangle can be isosceles and right at the same time.
D. A triangle can be scalene and obtuse at the same time.
Answer:
A. A triangle can be equilateral and obtuse at the same time
Step-by-step explanation:
All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°
ellus
Find the surface area of the composite figure.
2 cm
7 cm
2 cm
12 cm
12 cm
7 cm
7 cm
SA = [?] cm2
Answer:
SA = 484 cm²
Step-by-step explanation:
Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)
✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)
L = 7 cm
W = 7 cm
H = 12 cm
S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²
✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)
L = 7 cm
W = 2 cm
H = 2 cm
S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²
✔️Base area of the smaller rectangular prism = L*W
L = 7 cm
W = 2 cm
Area = 7*2 = 14 cm²
✅Surface area of the composite figure = 434 + (64 - 14)
= 434 + 50
= 484 cm²
3x+y=15 create a word problem
Answer:
---
Step-by-step explanation:
3 adults and 1 child go to a park. The admission fee for adults is x, and the fee for children is y. They spent a total of 15 dollars. Solve for x and y.
---
hope it helps
sorry if it doesn't. I'm the person who solves the problems, not creates them
what is the value of side EC ?
Answer:
EC = 28'
Step-by-step explanation:
Since ∆KAR ~ ∆ENC, therefore, their corresponding side lengths will be proportional to each other.
By implication, we have:
EN/KA = EC/KR
EN = 96'
KA = 24'
EC = ?
KR = 7'
Thus:
96/24 = EC/7
Cross multiply
EC*24 = 7*96
EC*24 = 672
Divide both sides by 24
EC = 672/24
EC = 28'
Mr. Poplin asked his students to write the following expression: "Two to the fifth power plus seven squared" Which answer choice shows this expression? A 52 - 27 B (2-5) + (7.2) © 25-74 D 2572
Answer:
B
Step-by-step explanation:
they rest The two by five and separate the square
convert 4/5 into percent
What is another way to describe the following expression?
5−(x+y)tothepowerof3
2) Use the law of sines to find the length of SR
sin(A)/a=sin(B)/b=sin(C)/c
Answer:
take 28 degree as reference angle
using sine angle
sin28=p/h
0.46=10/h
0.46h=10
h=10/0.46
h=21.73
therefore hypotenuse =21.73
again using sine rule
take 25 degree as reference angle
sin 25=p/h
0.42=SR/21.73
0.42*21.73=SR
9.12=SR
9.1=SR
Step-by-step explanation:
In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association and independence should be performed. What is the expected frequency of West Campus and failed
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
Answer:
57.5
Step-by-step explanation:
Got it right on the test.
Se desea construir un vaso de papel en forma de cono circular recto que tenga un volumen de 25πcm3
. Determine las dimensiones del vaso que requiere menos papel. Cuales deben ser si el volumen
es de 1 litro?
Answer:
Para un vaso de [tex]V = 25\pi\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 2.321\,cm[/tex] y [tex]h \approx 4.642\,cm[/tex].
Para un vaso de [tex]V = 1000\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 5.419\,cm[/tex] y [tex]h \approx 10.839\,cm[/tex].
Step-by-step explanation:
El vaso se puede modelar como un cilindro recto. El enunciado pregunta por las dimensiones del vaso tal que su área superficial ([tex]A_{s}[/tex]), en centímetros cuadrados, sea mínima para el volumen dado ([tex]V[/tex]), en centímetros cúbicos. Las ecuaciones de volumen y área superficial son, respectivamente:
[tex]V = \pi\cdot r^{2}\cdot h[/tex] (1)
[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r\cdot h[/tex] (2)
De (1):
[tex]h = \frac{V}{\pi\cdot r^{2}}[/tex]
En (2):
[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot \left(\frac{V}{\pi\cdot r} \right)[/tex]
[tex]A_{s} = 2\cdot \left(\pi\cdot r^{2}+V\cdot r^{-1} \right)[/tex]
Asumamos que [tex]V[/tex] es constante, la primera y segunda derivadas de la función son, respectivamente:
[tex]A'_{s} = 2\cdot (2\pi\cdot r -V\cdot r^{-2})[/tex]
[tex]A'_{s} = 4\pi\cdot r - 2\cdot V\cdot r^{-2}[/tex] (3)
[tex]A''_{s} = 4\pi + 4\cdot V \cdot r^{-3}[/tex] (4)
Si igualamos [tex]A'_{s}[/tex] a cero, entonces hallamos los siguientes puntos críticos:
[tex]4\pi\cdot r - 2\cdot V\cdot r^{-2} = 0[/tex]
[tex]4\pi\cdot r = 2\cdot V\cdot r^{-2}[/tex]
[tex]4\pi\cdot r^{3} = 2\cdot V[/tex]
[tex]r^{3} = \frac{V}{2\pi}[/tex]
[tex]r = \sqrt[3]{\frac{V}{2\pi} }[/tex] (5)
Ahora, si aplicamos este valor a (4), tenemos que:
[tex]A_{s}'' = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }[/tex]
[tex]A''_{s} = 4\pi + 8\pi[/tex]
[tex]A_{s}'' = 12\pi[/tex] (6)
De acuerdo con este resultado, el valor crítico está asociado al área superficial mínima. Ahora, la altura se calcula a partir de (5) y (1):
[tex]h = \frac{V}{\pi\cdot \left(\frac{V}{2\pi} \right)^{2/3} }[/tex]
[tex]h = \frac{2^{2/3}\cdot \pi^{2/3}\cdot V}{\pi\cdot V^{2/3}}[/tex]
[tex]h = \frac{2^{2/3}\cdot V^{1/3}}{\pi^{1/3}}[/tex]
Si [tex]V = 25\pi\,cm^{3}[/tex], entonces las dimensiones del vaso son:
[tex]r = \sqrt[3]{\frac{25\pi\,cm^{3}}{2\pi} }[/tex]
[tex]r \approx 2.321\,cm[/tex]
[tex]h = \frac{2^{2/3}\cdot (25\pi\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]
[tex]h \approx 4.642\,cm[/tex]
Un litro equivale a 1000 centímetros cúbicos, las dimensiones del vaso son:
[tex]r = \sqrt[3]{\frac{1000\,cm^{3}}{2\pi} }[/tex]
[tex]r \approx 5.419\,cm[/tex]
[tex]h = \frac{2^{2/3}\cdot (1000\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]
[tex]h \approx 10.839\,cm[/tex]
Plz help me well mark brainliest if correct
all of the above which is e
PLEASE HELP AS SOON AS POSSIBLE
Answer:
FALSE
TRUE
TRUE
Step-by-step explanation:
For median,
Arrange your numbers in numerical order.
Count how many numbers you have.
If you have an odd number, divide by 2 and round up to get the position of the median number.
If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.
Source: https://www.verywellmind.com/how-to-identify-and-calculate-the-mean-median-or-mode-2795785
So for April median: 2.5, 3, 3.5, 3.5 (since we have 4 numbers we divide by 2 and we count by 2 places from left. Since we have even number data, we average 3 with the next higher position to get the median so (3+3.5)/2 = 3.25
For May apply same concept and you get median to be 2.25.
Median difference is 3.25-2.25 = 1
Therefore, statement 1 is false and statement 2 is true.
For average in May, add all numbers and divide by the number of data points so May= (2.5+3+3.5+3.5)/ 4 = 3.13
Apply same concept you for April and you get 2.38 as mean.
Mean difference is 3.13-2.38 = 0.75
Therefore, statement 3 is correct (true)