Answer:
it is b
Explanation:
because i took the thing
evidence and reasning on when puppies are going to be born
Answer:
Keep a close eye on her in case she starts giving birth to the next pup at the same time. A greenish/brown discharge may suggest a placenta has separated. If you see this, a puppy should be born within the next 2-4 hours.
Consider the two gaseous equilibria: The values of the equilibrium constants K 1 and K 2 are related by
The question is missing parts. The complete question is as follows.
Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:
[tex]SO_{2}_{(g)} + \frac{1}{2}O_{2}[/tex] ⇔ [tex]SO_{3}_{(g)}[/tex]; [tex]K_{1}[/tex]
[tex]2SO_{3}_{(g)}[/tex] ⇔ [tex]2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}[/tex]
The values of the equilibrium constants are related by:
a) [tex]K_{1}[/tex] = [tex]K_{2}[/tex]
b) [tex]K_{2} = K_{1}^{2}[/tex]
c) [tex]K_{2} = \frac{1}{K_{1}^{2}}[/tex]
d) [tex]K_{2}=\frac{1}{K_{1}}[/tex]
Answer: c) [tex]K_{2} = \frac{1}{K_{1}^{2}}[/tex]
Explanation: Equilibrium constant is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:
[tex]K=\frac{[products]^{n}}{[reagents]^{m}}[/tex]
The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.
The equilibrium constants of each reaction are:
[tex]SO_{2}_{(g)} + \frac{1}{2}O_{2}[/tex] ⇔ [tex]SO_{3}_{(g)}[/tex]
[tex]K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}[/tex]
[tex]2SO_{3}_{(g)}[/tex] ⇔ [tex]2SO_{2}_{(g)}+O_{2}_{(g)}[/tex]
[tex]K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}[/tex]
Now, analysing each constant, it is easy to see that [tex]K_{1}[/tex] is the inverse of [tex]K_{2}[/tex].
If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:
[tex]K_{2}=\frac{1}{K_{1}^{2}}[/tex]
For a chemical reaction to be spontaneous at all temperatures, which of the following conditions must be met?
A. ?S° > 0, ?H° > 0.
B. ?S° > 0, ?H° < 0.
C. ?G° > 0.
D. ?S° < 0, ?H° > 0.
E. ?S° < 0, ?H° < 0.
Answer:
B. S° > 0, ?H° < 0.
Explanation:
Expression for change in free energy is
ΔG = ΔH - TΔS
For a reaction to be spontaneous , ΔG should be negative . When we watch the relation above , we find that for ΔG will be negative at any temperature , if ΔH is negative and ΔS is positive . Then both the terms on the right hand side will be negative and then ΔG will become negative.
So option B is correct .
what is 8.000 mol / 2.00 L
Answer:
[tex]M=4.00\frac{mol}{L}=4M[/tex]
Explanation:
Hello.
In this case, we should remember that a molar concentration is defined in terms of the moles and volume in liters as shown below:
[tex]M=\frac{mol}{L}[/tex]
Thus, for the given information we obtain:
[tex]M=\frac{8.000mol}{2.00L}\\ \\M=4.00\frac{mol}{L}=4M[/tex]
Best regards.
Rhodium has an atomic radius of 0.1345 nm and density of 12.41 gm/cm3 . Determine whether it has an FCC or BCC crystal structure.
Answer:
FCC.
Explanation:
Hello,
In this case, since the density is defined as:
[tex]\rho =\frac{n*M}{Vc*N_A}[/tex]
Whereas n accounts for the number of atoms per units cell (2 for BCC and 4 for FCC), M the atomic mass of the element, Vc the volume of the cell and NA the Avogadro's number. Thus, for both BCC and FCC, the volume of the cell is:
[tex]Vc_{BCC}=(\frac{4r}{\sqrt{3} } )^3=(\frac{4*0.1345x10^{-7}cm}{\sqrt{3} } )^3=2.997x10^{-23}cm^3\\\\Vc_{FCC}=(2\sqrt{2}r)^{3} =(2\sqrt{2} *0.1345x10^{-7}cm)^3=5.506x10^{-23}cm^3[/tex]
Hence, we compute the density for each crystal structure:
[tex]\rho _{BCC}=\frac{n_{BCC}*M}{Vc_{BCC}*N_A}=\frac{2*102.9g/mol}{2.337x10^{-23}cm^3*6.022x10^{23}/mol} =14.62g/cm^3\\\\\rho _{FCC}=\frac{n_{FCC}*M}{Vc_{FCC}*N_A}=\frac{4*102.9g/mol}{5.506x10^{-23}cm^3*6.022x10^{23}/mol} =12.41g/cm^3[/tex]
Therefore, since the density computed as a FCC crystal structure matches with the actual density, we conclude rhodium has a FCC crystal structure.
Regards.
Which of the changes are chemical changes?
Sugar is dissolved in water.
A warm soda bottle fizzes when opened.
The copper roof turns green over time.
Baking soda is dissolved in vinegar and bubbles form.
A fog appears on the windshield in cold weather.
Answer:
two of them are chemical changes
Explanation:
1.) the copper roof turns green over time: it forms a new substance which is the green deposit known as verdigris .
2.) baking soda is dissolved in vinegar and bubbles form: it forms a new substance which is carbon dioxide gas.
I hope it helps:)
An aluminum plate is 78 cm wide and 35 cm long. The mass of the plate is 44,226 g. Determine its thickness. [The density of lead is 2.70g/cm^3]
Answer:
i try to solve it for you, and i aplode a similer question for you
Explanation:
You are the manager of a chemical stockroom, and find a bottle containing approximately one liter of a clear and colorless solution of unknown identity and concentration. Your only clue to its identity is that it was found between bottles of silver fluoride and sodium fluoride, so it is likely an aqueous solution of one of those two compounds. You will need to develop a procedure to determine the following: a) The identity of the unknown solution b) The concentration of the unknown solution
Answer:
Explanation:
Given that for Part A,
the arrangement can be either AgF or NaF.
On the off chance that the arrangement is AgF ,
For this situation AgF conc. can be controlled by titration with standard choride arrangement with potassium chromate as marker.
Get ready 1 M NaCl standard arrangement by dissolving 58.5 gm of NaCl in one liter refined water. Take 25 mL of 1 N NaCl arrangement in a funnel shaped carafe include hardly any drops of potassium chromate marker.
Take the example in the burette and titrate until a perpetual ruddy earthy colored hasten is seen.
[AgF responds with NaCl as follows
AgF + NaCl \small \rightarrow AgCl ( white precipitate)+ NaF
For whatever length of time that CaCl is available in the arrangement Ag structures AgCl hasten as above. When all the chloride particles expelled this way, the overabundance silver structures Ag2CrO4 ( rosy earthy colored encourage ) with the marker.
The dissolvability of AgCl is a lot of lower than the solvency of Ag2CrO4. Consequently the later won't hasten until all chloride particles exhausted.]
Let V2 be the volume of test utilized. At that point grouping of AgF in the example is given by
C2 = V1C1/V2 = 25 x 1/V2.
Rehash the titration by making legitimate weakening if any required.
On the off chance that the arrangement is NaF (Indirect strategy)
Here the Fluoride particle in a referred to volume of test is hastened as leadchlorofluoride with NaCl and PbNO3.
NaF + NaCl + Pb(NO3)2 \small \rightarrow PbClF (hasten) + 2 NaNO3
The above hasten is separated and washed and the washed encourage is taken in a measuring utencil and re-broke up in nitric corrosive to deliver the chloride particles.
PbClF + 2 HNO3 \small \rightarrow Pb(NO3)2 + HCl + HF
Presently include a known abundance of Silver nitrate answer for the above blend to encourage the chloride as silver chloride. Channel wash and evacuate the AgCl encourage.. The Filtrate contains the overabundance silver nitrate is to be dictated by titration with Standard chloride arrangement as in the past technique.
From the first amount of silver nitrate taken and the overabundance silver nitrate decided from the titration, we can decide the amount of silver nitrate responded.
The moles of silver nitrate responded = the moles of Cl delivered = the moles of F in the example.
In this way the convergence of sodium fluoride in the obscure example might be resolved.
What is the density of an object that has a volume of 26 mL and a mass of 52 g?
Answer:
Density = 2 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]Density = \frac{mass}{volume} [/tex]
From the question
mass = 52 g
volume = 26 mL
Substitute the values into the above formula and solve for the density
That's
[tex]Density = \frac{52}{26} [/tex]
We have the final answer as
Density = 2 g/mLHope this helps you
calculate the ph of the solution resulting from the addition of 20 ml of 0.100 m naoh to 30 ml of 0.100 m hno 3
Answer:1.6989
Explanation:
The pH of the solution prepared by mixing NaOH and [tex]\rm HNO_3[/tex] has been 1.69.
The moles of NaOH can be given by:
Moles = Molarity × Volume (L)
Moles of NaOH = 0.1 M × 0.02 LMoles of NaOH = 0.002 mol
Moles of [tex]\rm HNO_3[/tex] = 0.1 M × 0.03 L
Moles of [tex]\rm HNO_3[/tex] = 0.003 mol
Since, [tex]\rm HNO_3[/tex] has been remaining in the solution after neutralization, the moles of [tex]\rm HNO_3[/tex] has been :
[tex]\rm HNO_3[/tex] = 0.003 - 0.002 mol
[tex]\rm HNO_3[/tex] = 0.001 mol.
The moles of [tex]\rm HNO_3[/tex] has been equivalent to the moles of hydrogen ion.
The hydrogen ion has been 0.001 mol.
The concentration of Hydrogen ions can be given by:
Hydrogen ion concentration = [tex]\rm \dfrac{Moles}{Volume(L)}[/tex]
Hydrogen ion concentration = [tex]\rm \dfrac{0.001}{0.03\;+\;0.02}[/tex]
Hydrogen ion concentration = 0.02 M.
pH can be defined as the negative log of the hydrogen ion concentration.
pH = - log ([tex]\rm H^+[/tex])
pH = - log (0.02)
pH = 1.69
The pH of the solution prepared by mixing NaOH and [tex]\rm HNO_3[/tex] has been 1.69.
For more information about the pH of the solution, refer to the link:
https://brainly.com/question/4975103
How much energy has your body used, in joules, if your health indicates the 450 Calories were burned during your workout? How many Calories are in a dinner containing 3.5 x 106 joules?
Answer:
107.55 J, 88.67 cal
Explanation:
1 Joule = 0.239 Calories
450 cal x 0.239 = 107.55 J
3.5 x 106 = 371
371 J = 371 x 0.239 cal
371 J = 88.67 cal
Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).
Answer:
Explanation:
Hello,
In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:
[tex]\rho=1.24*1g/mL=1.24g/mL[/tex]
In such a way, since the given solution of nitric acid is 64 % by mass, we've got:
[tex]\frac{64gHNO_3}{100g\ solution}[/tex]
Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:
[tex]M=\frac{(100g-64g)HA}{100g\ solution}*\frac{1.24g\ solution }{1mL \ solution}*\frac{1000mL\ solution}{1L\ solution}*\frac{1molHA}{90.2gHA} \\\\M=4.95M[/tex]
Regards.
100 billion in scientific notation?
Answer: 1×10^11
Explanation:
concept to know: scientific notation must be written in the form of a × 10^b
where 0<a<10.
100 billion= 100,000,000,000
there are 11 zeros after 1
1 × 10^11
Hope this helps!! :)
What intermolecular forces are present among molecules in dimethyl ether, CH3OCH3?
a) London forces only
b) hydrogen bonding only
c) both London dispersion forces and hydrogen bonding
d) both London dispersion forces and dipole-dipole forces
Answer:
London forces only
Explanation:
Dimethyl ether is a nonpolar organic compound. Remember that for nonpolar organic substances, London forces are the primary intermolecular forces present.
Since dimethyl ether is a nonpolar organic compound, then it has London forces as its major intermolecular force. Intermolecular forces hold molecules of a substance together in a given state of matter.
9.44 x 10^3 In standard form
A 50 ml graduated cylinder is filled with 23.0 mL of water. Water is then added to the cyl- inder dropwise until 36.0 mL of water are in the cylinder. If it took 265 drops to increase the volume in the cylinder to 36.0 mL. How many drops are in 1 ml?
Answer:
20 drops
Explanation:
Step 1: Given data
Initial volume of water: 23.0 mLFinal volume of water: 36.0 mLDrops of water added: 265 dropsStep 2: Calculate the volume of water added
We calculate the volume of water added by subtracting the initial volume to the final volume.
36.0 mL - 23.0 mL = 13.0 mL
Step 3: Calculate the number of drops in 1 mL
We will divide the number of drops of water added by the volume they represent.
265 drops / 13.0 mL = 20.4 drops/1 mL ≈ 20 drops/1 mL
The following reaction is investigated: 2N2O(g) N2H4(g) <---> 3N2(g) 2H2O(g) Initially there are 0.100 mol of N2O and 0.25 mol of N2H4, in a 10.0-L container. If there are 0.059 mol of N2O at equilibrium, how many moles of N2 are present at equilibrium
Answer:
6.2 × 10^-2
Explanation:
Given the reaction:
------------2N2O(g) N2H4(g) <---> 3N2(g) 2H2O(g)
Initial: N2O = 0.1, N2H4 = 0.25-- 0 - - - - - 0
Then: N20 = -2x, N2H4= - x - - - +3x, +2x
Equ : 0.1 - 2x ; 0.25 - x ; +3x ; +2x
At equilibrium :
Add both:
N2O = 0.1 - 2x ;
N2H4 = 0.25 - x;
3N2 = 3x
2H2O = 2x
Moles of N2O at equilibrium = 0.059
Then;
0.1 - 2x = 0.059
-2x = 0.059 - 0.1
-2x = - 0.041
x = 0.041 / 2
x = 0.0205
Moles of N2 present at equilibrium ;
3N2 = 3x
3N2 = 3(0.0205)
= 0.0615
= 0.062 = 6.2 × 10^-2
Janey loves this time of year because she loves eating marshmallow Peeps. One day, she eats ten peeps; 8 of them have a mass of 100 g, 1 of them has a mass of 150 g, and 1 of them has a mass of 200 g. What is the average mass of all the People that Jany ate? Show your work.
Answer:
115g
Explanation:
100*8=800
800+150+200=1150
1150/10=115
Is HCL a pure substance? Look at me already asking chemistry questions! //!roll eyes emoji/2#/
Answer:
yes it is as it has a chemical formula which cannot be changed
Please Help Me What is chromatography? Question 2 options: A) A picture taken with a chrome camera. B) The stationary phase. C) The separation of substances in a mixture by differences in their attraction to a substance over which they are passed.
Explanation:
Chromatography = It is a method in which a drop of mixture is spot is spotted at one of the end of the paper. After some time whenever it gets dried, it is then dipped into solvent without toushing the spot. As a result the mixtures gets separated.
Hence, the correct option is (c) "The separation of substances in a mixture by differences in their attraction to a substance over which they are passed"
Significant Figures
Tell me what's wrong. When adding and subtracting, you line up decimal and look for the least decimal places.
0.87
4.061
+10.4
--------------
15.331
My answer is 15 but teacher said I'm wrong
Thank You
Determine the pH of the following solutions, given their hydrogen ion concentration. a. [H+] = 10^-5 M
Answer:
pH = 5Explanation:
The pH of the solution can be found by using the formula
pH = - log [H+]
From the question
[H+] = 10^-5 M
Substitute the value into the above formula and solve for the pH
That's
[tex]pH = - log( {10}^{ - 5} ) [/tex]
We have the final answer as
pH = 5
Hope this helps you
A solution of sulfuric acid contains 35.2% by mass of H2SO4 and has a density of 1.27 g/mL. What is the molarity of H2SO4 in this solution?
Answer:
[H₂SO₄] = 4.56 M
Explanation:
35.2 % by mass of H₂SO₄ means that in 100 g of solution, we have 35.2 grams of solute.
We convert the mass of solute to moles.
35.2 g / 98 g/mol = 0.359 moles
These moles are contained in 100 g of solution, so we use density to determine the volume.
1.27 g/mL = 100 g / volume
Volume = 100 g / 1.27 g/mL = 78.74 mL
Molarity is mmol /mL (either we can say, moles in 1L of solution).
We convert the moles to mmoles → 0.359 mol . 1000 = 359 mmoles
M = 359 mmoles/74.74 mL = 4.56 M
Which measurement represents the largest quantity?
A) 47.3 mg
B)
4.73 x
x 10-6 kg
C)
4.73 x 103 ug
D) 4730 ng
E)
4.73 x
x 10-4 g
Answer:
A
Explanation:
The measurement represents the largest quantity among the given options is 47.3 mg Hence, Option (A) is correct.
What is conversion factor ?
An arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
Therefore comparing all the four options it can be concluded that,The measurement represents the largest quantity among the given options is 47.3 mg Hence, Option (A) is correct.
Learn more about measurement here ;
https://brainly.com/question/18147632
#SPJ2
What is the PH of sebacic acid ?
Answer:
Sebacic acid is a naturally occurring dicarboxylic acid with the formula (CH2)8(CO2H)2. It is a white flake or powdered solid. Sebaceus is Latin for tallow candle, sebum is Latin for tallow, and refers to its use in the manufacture of candles.
Explanation:
pls mark as brainliest!!!!!
In your own words, describe the concept of specific heat capacity and the effects that it has on temperature changes. Give an example of specific heat capacity that you see in your everyday life. Why did you select this example
Answer:
The specific heat capacity is the heat that a body or a system needs to administer so that it can increase its internal temperature.
Explanation:
The calorific capacity is measured in several units, it varies a lot between products, reactants or the same systems since each one is independent in its composition and this conditions it.
As for its mathematical calculation, it is the quotient, that is, the division between the dose of energy transferred to a body and the change in temperature that it experiences.
Speed of light is 3.0x108 m/s. Convert speed of light unit into miles per hour (mi/s). 3.0x108 m/s =
mi/s
Report your answer in the format with correct sig figs:
5x1013
Given:
1 mile = 1.61 km
1 km = 1000 m
Explanation:
1 mile = 1.61 km and 1 km = 1000 m
The speed of light is [tex]3\times 10^8\ m/s[/tex]. We need to convert it into miles per hour.
1 m = (1/1000) km
[tex]3\times 10^8\ m=\dfrac{3\times 10^8}{1000}\\\\=3\times 10^5\ km[/tex]
1 km = (1/1.61) miles
[tex]3\times 10^5\ km =\dfrac{3\times 10^5}{1.61}\\\\=1.86\times 10^5\ \text{miles}[/tex]
So, [tex]v=1.86\times 10^5\ \text{miles/s}[/tex]
Hence, this is the required solution.
What does the aufbau principle suggest about electron configuration?
Electrons within the same atomic orbital have different spins.
Electrons occupy orbitals with the lowest energy first.
No more than two electrons can occupy the same atomic orbital.
Filled sublevels are more stable than partially filled sublevels.
Answer:
Electrons occupy orbitals with the lowest energy first.
Explanation:
The Aufbau Principle states that electrons will fill the atomic orbitals with the lowest energy levels first, before occupying others with higher energy levels.
For example, electrons will fill the 1s orbital before filling the 2s orbital.
Answer:
It is Filled sublevels are more stable than partially filled sublevels.
Explanation:
Just took the test and this was right.
Based on the bond energies for the reaction below, what is the enthalpy of the reaction?HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O (g)
Answer:
1219.5 kj/mol
Explanation:
To reach this result, you must use the formula:
ΔHºrxn = Σn * (BE reactant) - Σn * (BE product)
ΔHºrxn = [1 * (BE C = C) + 2 * (BE C-H) + 5/2 * (BE O = O)] - [4 * (BE C = O) + 2 * (BE O-H).
The BE values are:
BE C = C: 839 kj / mol
BE C-H: 413 Kj / mol
BE O = O: 495 kj / mol
BE C = O = 799 Kj / mol
BE O-H = 463 kj / mol
Now you must replace the values in the above equation, the result of which will be:
ΔHºrxn = [1 * 839 + 2 * (413) + 5/2 * (495)] - [4 * (799) + 2 * (463) = 1219.5 kj/mol
Based on the bond energies, the reaction
HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g) has a standard enthalpy of reaction of - 1222 kJ/mol.
The given reaction is: HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g)
The bond energies (E) of the reactions can help to calculate the standard enthalpy of the reaction (ΔH°rxn) using the following expression.
[tex]\triangle H_ \degrees {rxn} = \sum E_{reactants} - \sum E_{products}[/tex]
The broken bonds are: HC≡CH 1 triple C-C bond 2 single C-H bonds O₂ 5/2 double O-O bonds The formed bonds are: CO₂ 4 double C-O bonds H₂O 2 single O-H bondsSolution:
bond energies in the formula:
[tex]\triangle H_ \degrees {rxn} = 835+ 2(411) + 2.5(494) - 4(799) - 2(459)[/tex]
= 1222 kJ/mol
Thus, Based on the bond energies, the reaction:
HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g) has a standard enthalpy of reaction of -1222 kJ/mol.
Learn more: brainly.com/question/24857760
What is the percent yield in a reaction between 42.6 g O2 and 49.2 g Al if 72.4 g of Al2O3 is produced?
Answer:
229%
Explanation:
The equation of the reaction is;
4Al(s) + 3O2(g) ----> 2Al2O3(s)
We must first determine the limiting reactant;
Number of moles of Al2O3 produced = mass/molar mass = 72.4g/101.96 g/mol = 0.71 moles
For Al
Number of moles reacted = mass/molar mass = 49.2g/27 g/mol = 1.8 moles
If 4 moles of Al yields 0.71 moles of Al2O3
1.8 moles of Al will yield 1.8 × 0.71/4 = 0.32 moles of Al2O3
For O2
Number of moles reacted = mass/molar mass = 42.6g/32g/mol = 1.33 moles
If 3 moles of O2 yields 0.71 moles of Al2O3
1.33 moles of O2 will yield 1.33 × 0.71/3 = 0.31 moles of Al2O3
Oxygen is the limiting reactant.
% yield = actual yield/ theoretical yield × 100/1
% yield = 0.71 moles/0.31 moles × 100
% yield = 229%