Answer:
5
Step-by-step explanation:
t(1) = [tex]1^{2} + 4 = 5[/tex]
I need help pls someone:(
Answer:
7/30
Step-by-step explanation:
A man driving a car leaves a point A drives up to 32.5 km in a direction of 070. A cyclist leaves the same point in a direction 130 travelling. After some few hours both drivers are 80 km apart. Use this information to answer 3 questions. (1). What is the distance covered by the cyclist at this time in 2 d.p. (2). Find the bearing of Cyclist from the Car. correct to 1 d.p. (3). Find the shortest distance between the car and the line of path of the cyclist, in 2 d.p.
Answer: No 1 is 91.14 km who else could help with the rest of the solution for number 1, 2 & 3.
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is the number of 3-point questions and y is the number of 5-point questions, the system shown represents this situation.
x + y = 24
3x + 5y = 100
What does the solution of this system indicate about the questions on the test?
The test contains 4 three-point questions and 20 five-point questions.
The test contains 10 three-point questions and 14 five-point questions.
The test contains 14 three-point questions and 10 five-point questions.
The test contains 20 three-point questions and 8 five-point questions.
PLS HELP ME 10PTS
An artist creates a cone-shaped sculpture for an art exhibit. If the sculpture is 7 feet tall and has a base with a circumference of 27.632 feet, what is the volume of the sculpture?
Answer: The volume of the sculpture is 141.84 cubic-feet
Step-by-step explanation: Please see the attachments below
In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the probability that more than half of them have Type A blood?
The probability that more than half of the 8 randomly chosen blood donors have Type A blood is approximately 0.2533 or 25.33%.
To calculate the probability that more than half of the 8 randomly chosen blood donors have Type A blood, we can use the binomial probability formula:
[tex]\mathrm{P(X > n/2) = \sum [ P(X = k) ]}[/tex]
where the sum is taken from k = (n/2 + 1) to k = n
In this case, n represents the number of trials (8 blood donors) and p is the probability that a single blood donor has Type A blood (0.40).
P(X = k) is the probability of getting exactly k donors with Type A blood, and it is given by the binomial probability formula:
[tex]\mathrm {P(X = k) = (n, k) \times p^k \times (1 - p)^{(n - k)}}[/tex]
where (n choose k) represents the number of combinations of n items taken k at a time, and it is given by:
[tex]\mathrm {(n, k) = \frac{n!}{(k! \times (n - k)!)}}[/tex]
Now, let's calculate the probability that more than half (i.e., 5 or more) of the donors have Type A blood:
[tex]\mathrm{P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)}[/tex]
[tex]\mathrm {P(X = k) = (8, k) \times 0.40^k \times (1 - 0.40)^{(8 - k)}}[/tex]
[tex]\mathrm{P(X = 5)} = (8, 5) \times 0.40^5 \times (1 - 0.40)^{(8 - 5)}\\\\= 56 \times 0.01024 \times 0.343\\\\= 0.1961984[/tex]
[tex]\mathrm{P(X = 6)} = (8, 6) \times 0.40^6 \times (1 - 0.40)^{(8 - 6)}\\\\= 28 \times 0.004096 \times 0.36\\\\= 0.0516608[/tex]
[tex]\mathrm {P(X = 7)} = (8, 7) \times 0.40^7 \times (1 - 0.40)^{(8 - 7)}\\\\= 8 \times 0.0016384 \times 0.4\\\\= 0.0052224[/tex]
[tex]\mathrm {P(X = 8)} = (8, 8) \times 0.40^8 \times (1 - 0.40)^{(8 - 8)}\\\\= 1 \times 0.00065536 \times 0.4\\\\= 0.000262144[/tex]
Now, add all these probabilities together to get the final result:
[tex]\mathrm {P(X > 4)} = 0.1961984 + 0.0516608 + 0.0052224 + 0.000262144\\\\= 0.253343344[/tex]
Therefore, the probability that more than half of the 8 randomly chosen blood donors have Type A blood is approximately 0.2533 or 25.33%.
Learn more about probability click;
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A government agency has 6000 employees. As an alternative to the traditional five-day work week, employees were asked whether they preferred a four-day work week (10 hours per day) or flexible hours. The accompanying segmented bar chart is based on the data collected. Which of the following statements is true about work week preferences and age category? A. Preferences appear to be independent of age. B. The distribution of preferences is the same across different age groups. C. A greater percentage of employees who prefer flex hors are in the over 45 age category compared to those who prefer 4-day work week. D. A greater percentage of employees who prefer a 4-day work week are in the over 45 age category compared to those who prefer flax hours.
Complete Question
The complete question is shown on the first uploaded image
Answer:
Option D is the correct answer
Step-by-step explanation:
Now looking at the bar chart we see that a greater number of employee over the age of 45 preferred the 4-day work week compared to the number of employee between 30- 45 who preferred to have a flexible work hour and employee below 30 who' s preference are the same for both type of work hours
Pls help I really need help
Answer:
7. [tex]x \leq 5[/tex]
8. [tex]x\geq 4[/tex]
9. x < 5
10. x < -7
11. x < 45
12. [tex]x\geq -10[/tex]
13. x < -7
14. x < 45
15. [tex]x\leq 50[/tex]
16. [tex]w\geq 16[/tex]
18. q > 4
Step-by-step explanation:
El precio de un ordenador portátil ha aumentado un 25% y posteriormente fue rebajado un cierto porcentaje.Calcule que porcentaje de descuento habría que aplicar para que quede al precio original de antes del aumento. Porfa responder!!!
Answer:
Se requiere un 20 por ciento de descuento.
Step-by-step explanation:
(This exercise has been presented in Spanish and for that reason explanation will be held in the same language)
Sea [tex]p_{o}[/tex] el precio original del computador portatil, el nuevo precio es:
[tex]p_{1} =\left(\frac{100\,\% + 25\,\%}{100\,\%} \right)\cdot p_{o}[/tex]
[tex]p_{1} = 1.25\cdot p_{o}[/tex]
Si [tex]p_{2} = p_{o}[/tex], entonces el porcentaje requerido para recuperar el precio original es:
[tex]r = \left(1-\frac{p_{2}}{p_{1}} \right)\times 100\,\%[/tex]
[tex]r = \left(1-\frac{p_{o}}{1.25\cdot p_{o}} \right)\times 100\,\%[/tex]
[tex]r = \left(1-\frac{1}{1.25} \right)\times 100\,\%[/tex]
[tex]r = 20\,\%[/tex]
Se requiere un 20 por ciento de descuento.
A bird of species? A, when? diving, can travel six times as fast as a bird of species B top speed. If the total speeds for these two birds is 224 miles per hour
Answer:
Maximum speed of bird A is [tex]192\,\,\frac{mi}{h}[/tex]
Maximum speed of bird B is [tex]32\,\,\frac{mi}{h}[/tex]
Step-by-step explanation:
This is a problem with two unknowns: Max speed of bird A (we name that "A"), and max speed of bird B (we call that "B"). Now we can create two equations with these two unknowns, based on the info provided:
Equation 1): based on the phrase "bird A can travel six times as fast as bird B" we write:
[tex]A=6\,*\, B\\A=6B[/tex]
Equation 2): based on the phrase; "the total speeds for these two birds is 224 miles per hour", we write:
[tex]A+B=224\,\,\frac{mi}{h}[/tex]
Now, we use the first equation to substitute A in the second equation, ad then solve for the unknown B:
[tex]A+B=224\,\,\frac{mi}{h}\\(6B)+B=224\,\,\frac{mi}{h}\\7B=224\,\,\frac{mi}{h}\\B=\frac{224}{7} \,\,\frac{mi}{h}\\B=32\,\,\frac{mi}{h}[/tex]
Now we can solve for the other unknown "A" using the substitution equation and the value of B we just found:
[tex]A=6B\\A=6\,(32\,\,\frac{mi}{h})\\A=192\,\,\frac{mi}{h}[/tex]
Suppose ARB Bank is reviewing its service charges and interest payment policies on current accounts. Suppose further that ARB has found that the average daily balance on personal current accounts is GH¢350.00, with a standard deviation of GH¢160.00. In addition, the average daily balances have been found to follow a normal distribution;
What percentage of customers carries a balance of GH¢100 or lower?
What percentage of customers carries a balance of GH¢500 or lower?
What percentage of current account customers carries average daily balances exactly equal to GH¢500?
What percentage of customers maintains account balance between GH¢100 and GH¢500?
Answer:
5.94% of customers carries a balance of GH¢100 or lower.
82.64% of customers carries a balance of GH¢500 or lower.
0% of current account customers carries average daily balances exactly equal to GH¢500.
76.7% of customers maintains account balance between GH¢100 and GH¢500
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 350, \sigma = 160[/tex]
What percentage of customers carries a balance of GH¢100 or lower?
This is the pvalue of Z when X = 100. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 350}{160}[/tex]
[tex]Z = -1.56[/tex]
[tex]Z = -1.56[/tex] has a pvalue of 0.0594
5.94% of customers carries a balance of GH¢100 or lower.
What percentage of customers carries a balance of GH¢500 or lower?
This is the pvalue of Z when X = 500.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{500 - 350}{160}[/tex]
[tex]Z = 0.94[/tex]
[tex]Z = 0.94[/tex] has a pvalue of 0.8264
82.64% of customers carries a balance of GH¢500 or lower.
What percentage of current account customers carries average daily balances exactly equal to GH¢500?
In the normal distribution, the probability of finding a value exactly equal to X is 0. So
0% of current account customers carries average daily balances exactly equal to GH¢500.
What percentage of customers maintains account balance between GH¢100 and GH¢500?
This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 100.
From b), when X = 500, Z = 0.94 has a pvalue of 0.8264
From a), when X = 100, Z = -1.56 has a pvalue of 0.0594
0.8264 - 0.0594 = 0.767
76.7% of customers maintains account balance between GH¢100 and GH¢500
here it is ill mark you as brainliest if the answer is correct.
Answer:
A = 1168.67 cm²
Step-by-step explanation:
[tex]A=2\pi rh+2\pi r^{2}[/tex] Use this equation to find the surface area
[tex]A=2\pi (6)(25)+2\pi (6)^{2}[/tex] Multiply
[tex]A=2\pi (150)+2\pi (36)[/tex] Multiply
A = 942.48 + 226.19 Add
A = 1168.67 cm²
Answer:
1169.14cm2
Step-by-step explanation:
The surface area is that area which you can feel. Now there are two circles one at the top and one at the bottom.
These areas are expressed as;
π×r2 { remember area of a circle}.
Therefore for the two areas we have twice the area of once since they are the same. Hence we have:
2×π×r2.
Secondly, there is still another area we haven't talked about yet. It's the area you feel at the side and this area curls into a circular fashion.
Now let's assume the two circles are the top and bottom are knocked off , we would have a shape that looks like a rectangle.
Now area of a rectangle is the multiplication of both sides. In this case the side would be the height,h and the circumference of the circle since the rectangle forms into a circle when she try to join both edges together.
Hence the area of this Shape would be;
2πr{circumference} × h=2πrh
Hence the total surface area would be;
2πr2 + 2πrh.
Substituting the giving values we have;
Note: to obtain raduis,r ; we divide the diameter by 2.
2 × 22/7 × 6^2 + 2 × 22/7 × 6× 25
2×22/7(36+150)
44/7(186)= 8184/7
=1169.1429cm2
=1169.14cm2{ to 2 decimal place}
What three-digit number with units digit 2 and hundreds digit 4 is divisible by 9?
Answer:
Dear user,
Answer to your query is provided below
A number is divisible by 9, if the sum is a multiple of 9 or if the sum of its digits is divisible by 9.
Step-by-step explanation:
Here , It is given that the number is three digit in which units digit is 2 and hundreds digit is 4.
As per rule, the sum of its digits should've divisible by 9. So, Let the unknown digit be X .
Therefore, 2+X+4 =9
This implies, X = 9-2-4 = 3
So, the three digit number will be 432.
Verify - 432/9 = 48
Hence proved
The function V(r) = four-thirds pi r cubed can be used to find the volume of air inside a basketball given its radius. What does V(r) represent?
Answer:
V(r) is the volume of basketball when the radius is r.
Answer:
B. the volume of the basketball when the radius is r
Step-by-step explanation:
Write the expressions "Four times the difference of a number and 1 is equal to six times the sum of the number and three. Find the number
Answer:
4(x - 1) = 6(x + 3)
x = -11
Step-by-step explanation:
x represents “the number” so we would substitute this with a variable.
(I hope this helps! Have a great day AND STAN BTS)
2.In a large university 13.5% of the students take economics, 24.7% of the students take statistics and 11.7% take economics and statistics. The probability that a randomly selected student didn’t take economics but did take statistics is close toالقارئ الشامل (2/2 نقط
Answer:
The probability that a randomly selected student didn’t take economics but did take statistics is 13%.
Step-by-step explanation:
Let the event that a student offers Economics be E.
The event that a student does NOT offer Economics is E'.
Let the event that a student offers Statistics be S.
The event that a student does NOT offer Statistics be S'.
P(E) = 13.5% = 0.135
P(S) = 24.7% = 0.247
P(E n S) = 11.7% = 0.117
Find the probability that a randomly selected student didn’t take economics but did take statistics
This probability = P(E' n S)
Since E and E' are mutually exclusive events,
P(S) = P(E' n S) + P(E n S)
P(E' n S) = P(S) - P(E n S)
P(E' n S) = 0.247 - 0.117 = 0.13 = 13%
Hope this Helps!!!
Wyoming fisheries contend that the mean number of cutthroat trout caught during a full day of fly-fishing on the Snake, Buffalo, and other rivers and streams in the Jackson Hole area is 4.0. To make their yearly update, the fishery personal asked a sample of fly-fishermen to keep a count of the number caught during the day. The numbers were: 4, 4, 3, 2, 6, 8, 7, 1,9, 3, 1, and 6. At the 0.05 significance level, can we conclude that the mean number caught is greater than 4.0?
Answer:
[tex]t=\frac{4.5-4}{\frac{2.680}{\sqrt{10}}}=0.59[/tex]
The degrees of freedom are given by:
[tex] df =n-1= 12-1=11[/tex]
And the p value would be:
[tex]p_v =2*P(t_{11}>0.59)=0.567[/tex]
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean area is not significantly different from 4
Step-by-step explanation:
We have the following data given:
4, 4, 3, 2, 6, 8, 7, 1,9, 3, 1, and 6
The sample mean and deviation from these data are:
[tex]\bar X=4.5[/tex] represent the sample mean
[tex]s=2.680[/tex] represent the sample deviation
[tex]n=10[/tex] sample size
[tex]\mu_o =4[/tex] represent the value to verify
[tex]\alpha=0.05[/tex] represent the significance level
t would represent the statistic
[tex]p_v[/tex] represent the p value
Hypothesis to verify
We want to verify if the true mean is equal to 4, the system of hypothesis would be:
Null hypothesis:[tex]\mu =4[/tex]
Alternative hypothesis:[tex]\mu \neq 4[/tex]
The statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
Replacing the the info we got:
[tex]t=\frac{4.5-4}{\frac{2.680}{\sqrt{10}}}=0.59[/tex]
The degrees of freedom are given by:
[tex] df =n-1= 12-1=11[/tex]
And the p value would be:
[tex]p_v =2*P(t_{11}>0.59)=0.567[/tex]
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean area is not significantly different from 4
An object travels along a horizontal path at a constant rate.the object travels 1/20 of the length of the path in 3/4 second.at that rate,how many seconds does it take the object to travel the entire length of the path?
Answer:
The onject 1/8 of the length of the path 3/4 in second.
Using the ratio and proportion to find the total time does it take the object to travel the entire length of the path as following
Length:time
X:(total time )
Total time x.(3/4)/(1/8x)=(3/4)/(1/8) = 6 seconds
According to the Mortgage Bankers Association, 21% of U.S. mortgages were delinquent last year. A delinquent mortgage is one that has missed at least one payment but has not yet gone to foreclosure. A random sample of seven mortgages was selected. What is the standard deviation of this distribution
Answer:
The standard deviation for the number of delinquent mortgages in the sample is 1.08.
Step-by-step explanation:
For each mortgage, there are only two possible outcomes. Either it is delinquent, or it is not. The probability of a mortgage being delinquent is independent of other mortgages. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
21% of U.S. mortgages were delinquent last year.
This means that [tex]p = 0.21[/tex]
A random sample of seven mortgages was selected.
This means that [tex]n = 7[/tex]
What is the standard deviation of this distribution
[tex]\sqrt{V(X)} = \sqrt{7*0.21*0.79} = 1.08[/tex]
The standard deviation for the number of delinquent mortgages in the sample is 1.08.
What is the area of triangle ABC?
3 square units
0 7 square units
11 square units
15 square units
[tex]the \: answer \: is \: 7 \: square \: units \\ please \: see \: the \: attached \: picture \: for \: full \: solution \\ hope \: it \: helps[/tex]
To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette yielded mean nicotine content of 25.325.3 milligrams and standard deviation of 2.72.7 milligrams for a sample of n equals 9n=9 cigarettes. Construct a 9090% confidence interval for the mean nicotine content of this brand of cigarette.
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Please help! Will give Brainliest!
Steps 1-4 in attachment (#4 below)
Step 4: Use the equation you wrote in Step 3. Write the equation for the graph of g(x) that has also been shifted right 1 unit.
Answer:
g(x) = 2|x|g(x) = -2|x|g(x) = -2|x| -3g(x) = -2|x-1| -3Step-by-step explanation:
1) Vertical stretch is accomplished by multiplying the function value by the stretch factor. When |x| is stretched by a factor of 2, the stretched function is ...
g(x) = 2|x|
__
2) Reflection over the x-axis means each y-value is replaced by its opposite. This is accomplished by multiplying the function value by -1.
g(x) = -2|x|
__
3) As you know from when you plot a point on a graph, shifting it down 3 units subtracts 3 from the y-value.
g(x) = -2|x| -3
__
4) A right-shift by k units means the argument of the function is replaced by x-k. We want a right shift of 1 unit, so ...
g(x) = -2|x -1| -3
What is the square root of -1 ?
Answer:
i
Step-by-step explanation:
For a super soaker water gun, a pump handle is moved back and forth to build up pressure in the water reservoir. The water is released by pulling a trigger and shooting the water a significant distance. Assuming that you can create an absolute pressure of 8 atm in the reservoir:
a) What is the velocity at which the water leaves the gun?
b) If the water exits the gun through a hole with a radius of 1-mm, what is the volume rate of flow in m3/s?
c) If the water gun is fired horizontally and held 1.2 meters above the ground, where does the water hit the ground? Pressure 8 cm water
Answer:
a) The velocity at which the water leaves the gun = 37.66 m/s
b) The volume rate of flow = (1.183 × 10⁻⁴) m³/s
c) The water hits the ground 18.64 m from the point where the water gun was shot.
Step-by-step explanation:
a) Using Bernoulli's equation, an equation that is based on the conservation of energy.
P₁ + ½ρv₁² + ρgh₁ = P₂ + ½ρv₂² + ρgh₂
The two levels we are considering is just inside the water reservoir and just outside it.
ρgh is an extension of potential energy and since the two levels are at the same height,
ρgh₁ = ρgh₂
Bernoulli's equation becomes
P₁ + ½ρv₁² = P₂ + ½ρv₂²
P₁ = Pressure inside the water reservoir = 8 atm = 8 × 101325 = 810,600 Pa
ρ = density of water = 1000 kg/m³
v₁ = velocity iof f water in the reservoir = 0 m/s
P₂ = Pressure outside the water reservoir = atmospheric pressure = 1 atm = 1 × 101325 = 101,325 Pa
v₂ = velocity outside the reservoir = ?
810,600 + 0 = 101,325 + 0.5×1000×v₂²
500v₂² = 810,600 - 101,325 = 709,275
v₂² = (709,275/500) = 1,418.55
v₂ = √(1418.55) = 37.66 m/s
b) Volumetric flowrate is given as
Q = Av
A = Cross sectional Area of the channel of flow = πr² = π×(0.001)² = 0.0000031416 m²
v = velocity = 37.66 m/s
Q = 0.0000031416 × 37.66 = 0.0001183123 m³/s = (1.183 × 10⁻⁴) m³/s
c) If the height of gun above the ground is 1.2 m. Where does the water hit the ground?
The range of trajectory motion is given as
R = vT
v = horizontal component of the velocity = 37.66 m/s
T = time of flight = ?
But time of flight is given as
T = √(2H/g) (Since the initial vertical component of the velocity = 0 m/s
H = 1.2 m
g = acceleration due to gravity = 9.8 m/s²
T = √(2×1.2/9.8) = 0.495 s
Range = vT = 37.66 × 0.495 = 18.64 m
Hope this Helps!!!
Please answer this correctly
Answer:
the second oneStep-by-step explanation:
so much for bein a college student.
17)Let f(x) = -2x + 5 and g(x) = 9x2 + 4. Find f(8) + g(8) . A)565 B)569 C)564 D)560
Answer:
answer B [tex]\boxed{ \ 569 \ }\\[/tex]
Step-by-step explanation:
f(8)=-2*8+5=-11
g(8)=9*8*8+4=580
f(8)+g(8)= -11+580=569
a kangaroo and a wallaby are in a race. They have to get to a flagbole that is 100 meters away and back. For every 2 hops the kangaroo does, the wallaby does three but the kangaroo's jumps are 3 meters while the wallaby's are 2. Who gets there and back first (hint: it isnt a draw)
Answer:
im going to say a wallaby because they are smaller and lighter and if you think of the weight then less power is needed for a wallaby
idk lol XD
Step-by-step explanation:
Some of the stock in a winery has been found to be infected by Brettanomyces. You independently sample 80 barrels from the winery, and find that 28 of them are infected. Carry out a hypothesis test to evaluate the claim that half of the wine barrels are infected. What is closest to the p-value that you obtain
Answer:
Step-by-step explanation:
If half of the wine barrels are infected, it means that the proportion of infected wine is 0.5
We would set up the hypothesis test.
For the null hypothesis,
p = 0.5
For the alternative hypothesis,
p < 0.5
Considering the population proportion, probability of success, p = 0.5
q = probability of failure = 1 - p
q = 1 - 0.5 = 0.5
Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 28
n = number of samples = 80
P = 28/80 = 0.35
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.35 - 0.5)/√(0.5 × 0.5)/80 = - 2.68
From the normal distribution table, the area below the test z score in the left tail 0.0037
Therefore,
p value = 0.0037
Assuming a significance level of 0.05, therefore,
Since alpha, 0.05 > than the p value, 0.0037, then we would reject the null hypothesis.
At a gas station, 50% of the customers use regular gas, 30% use mid-grade gas and 20% use premium gas. Of those customers using regular gas, only 30% fill their tanks. Of those customers using mid-grade gas, 60% fill their tanks, whereas of those using premium, 50% fill their tanks. What is the probability that the next customer will request mid-grade gas and fill the tank
Answer:
The probability that the next customer will request mid-grade gas and fill the tank is 0.1800
Step-by-step explanation:
In order to calculate the probability that the next customer will request mid-grade gas and fill the tank we would have to make the following calculation:
probability that the next customer will request mid-grade gas and fill the tank= percentage of the people using mid-grade gas* percentage of the people using mid-grade gas that fill their tanks
probability that the next customer will request mid-grade gas and fill the tank= 30%*60%
probability that the next customer will request mid-grade gas and fill the tank= 0.1800
The probability that the next customer will request mid-grade gas and fill the tank is 0.1800
Outline the procedure for finding probabilities of any given compound events.
Answer:
Explained below.
Step-by-step explanation:
A compound event is an event in which has possible outcomes more than one.
To determine the probability of compound events on has to compute the sum of the probabilities of all the individual events and, if required, remove any coinciding probabilities.
Examples of compound events are:
The events of roll a five using a 6-sided die .The number of favorable outcome is rolling a 5, is 1.
The total number of outcomes of rolling a die is 6.
Then the probability of rolling a 5 is 1/6.
The events of pulling a heart out of a standard deck of cardsThe number of favorable outcome of pulling a heart is 13.
The total number of outcomes is 52.
The probability of pulling a heart from a standard deck is 13/52 or 1/4.
Thus, the procedure is to compute the sum of the probabilities of all the individual events and, if required, remove any coinciding probabilities.
The iron cube of side 42 com has a hole of diameter 14cm
drilled out. Calculate the volume of iron in the cube
and the total Surface area
of the Cube
Answer:
Step-by-step explanation:
Total surface of the cube = 6a²
= 6 * 42 * 42
= 10584 cm²
Hole that is drilled out, will make a cylinder shape in the middle of the cube
Volume of iron in the cube = Volume of cube - volume of cylinder
Volume of cube = a³
= 42 * 42 * 42
= 74088 cm³
Cylinder:
r = 14/2 = 7 cm
h = sideof the cube = 42 cm
Volume = πr²h
[tex]=\frac{22}{7}*7*7*42\\\\=22*7*7*6[/tex]
= 6468 cm³
Volume of iron in the cube = Volume of cube - volume of cylinder
= 74088 - 6468
= 67620 cm³