Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint: use Mod). Displays the sum.
Answers
Answer:
Following are the code to this question:
#include <iostream>//defining header file
using namespace std;
int main()//defining main method
{
int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value
int i,sum=0;//defining integer variable
for(i=0;i<10;i++)//defining loop for count value
{
if(x[i]%2==1)//defining if block to check odd value
{
sum=sum+x[i];//add value in sum variable
}
}
cout<<sum;//print sum
return 0;
}
Output:
31
Explanation:
In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.
In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.
The code is in Java.
It uses for loop, if-else structure, and mod to calculate the sum of odd numbers in a list.
Comments are used to explain each line of code.
You may see the output in the attachment.
//Main.java
import java.util.*;
public class Main
{
public static void main(String[] args) {
//create a list with some numbers
List<Integer> lotsOfNumbers = Arrays.asList(7, 20, 1002, 55, 406, 99);
//initialize the sum as 0
int sumOfOdds = 0;
//create a for each loop to iterate over the lotsOfNumbers list
//check each number, if it is odd or not using the mod
//if it is odd, add the number to the sum (cumulative sum)
for (int number : lotsOfNumbers){
if(number % 2 == 1)
sumOfOdds += number;
}
//print the sum
System.out.println("The sum of odd numbers: " + sumOfOdds);
}
}
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Answers
Answer:
The answer to this question is given below in the explanation section.
Explanation:
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city library website
online in-store website
Sequential website structure:
single product website
computer-based training module
Matrix website structure:
Company website.
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Bookstore website: Webbed
Single-product website: Linear
County library website: Webbed
Online gift store website: Linear
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Answer:
The answer to this question is given below in the explanation section.
Explanation:
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Answer:
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A
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B
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C
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D
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Answers
Answer:
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Explanation:
C was wrong for me :(
Introduction:
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Explanation:
The data is sometimes recorded manually and is in analog form which is converted in to digital form.
Conclusion:
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I've written the working code. You added a break statement which right under a print function, which only printed the value of n1 and by looking at your variables, n1 = 0. That's why it was only printing 0.
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Answers
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Answer:
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Explanation:
can i have brainliest
This is using python.
Assuming all the variables are non-zero.
Which lines of code will assign the discriminant the value b2−4ac? Select 2 options.
discriminant = bb - 4ac
discriminant = b * b - 4 * a * c
discriminant = b ^ 2 - 4ac
discriminant = b ** 2 - 4 * a * c
discriminant = b ^ 2 - 4 * a * c
Answers
Answer:
discriminant = b * b - 4 * a * c
discriminant = b ** 2 - 4 * a * c
Explanation:
The operands are correct and in the right order (for python).
** is the operand for squaring something.
* is the operand for multiplying something.
- is the operand for subtracting something.
Let's take a look at these examples individually.
discriminant = bb - 4ac. You have to use the * sign so the computer understands that you're trying to multiply two objects together.
discriminant = b * b - 4 * a * c. This example works because it's using the * where it's appropriate.
discriminant = b ^ 2 - 4ac. In python we don't use the ^ sign. To use exponents, we use **. Also, there is no * sign in between 4, a, and c.
discriminant = b ** 2 - 4 * a * c. This example works because it uses the ** and * sign where appropriate.
discriminant = b ^ 2 - 4 * a * c. This example uses the ^ sign and python does not support it.