write a net ionic equation to explain the measured pH for any two solutions that have a pH less than 6 or greater than 8

Answer:

[tex]u/n = \frac{-e^2}{4\pi \epsilon r} (ln2)[/tex]

Explanation:

given data

we will take here

sodium ions = positive charge

chloride ions = negative cgarge

solution

as when we take Na positive charge so Number of origin is

d = 0

and here pair of ions with negative charge at d = - r

and d = +r

therefore

[tex]u = \frac{-2e^2}{4\pi \epsilon r} \times \frac{1}{r} \times \sum _n {\frac{1}{n}}(-1)^{n-1}[/tex]  

we will use here Taylor series approx method

[tex]u = \frac{-e^2}{2\pi \epsilon r} (ln2)[/tex]  

and N/2 pair will contribute here

so

[tex]u = \frac{N}{2} \frac{-e^2}{2\pi \epsilon r} (ln2)[/tex]

so energy per ion will be here

[tex]u/n = \frac{-e^2}{4\pi \epsilon r} (ln2)[/tex]

Answer:

molarity of the solution = 0.548 mol/L

Note: Additional information about the question is given as follows;

One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (NaOCl) by mass

What is the molarity of this solution? (Assume a density of 1.02 g/mL .)

Explanation:

A 4.00 percentage by mass composition of sodium hypochlorite (NaOCl) solution means that 100 g of the solution contains 4.00 g NaOCl.

Thus, a 1000 g of the solution contains 40.0 g NaOCl

Density of solution = 1.02 g/mL

Therefore, the volume occupied by 1000 g solution = mass/density

volume of 1000 g solution = 1000 g/1.02 g/ml = 980.4 mL

Molar mass of NaOCl = 74.5 g/mol

Number of moles = mass/molar mass

Number of moles of NaOCl = 40.0 g/74.5 g/mol

Number of moles of NaOCl  = 0.537 mole

Therefore, molarity = number of moles / volume(L)

volume of solution in litres = 980.4/1000 = 0.9804 L

Molarity = 0.537/0.9804 = 0.548 mol/L

Therefore, molarity of the solution = 0.548 mol/L

Answer:

(2) Mg²⁺ loses 2 electrons.

Explanation:

Let's consider the following half-reaction.

Mg ⇒ Mg²⁺ + 2 e⁻

Magnesium is a metal that loses 2 electrons to fulfill the octet rule. When magnesium loses electrons, the oxidation number increases from 0 to +2. This kind of half-reaction is known as oxidation, and has to be accompanied by a reduction of another species.

Answer:

41.3kJ of heat is absorbed

Explanation:

Based in the reaction:

Fe₃O₄(s) + 4H₂(g) → 3Fe(s) + 4H₂O(g) ΔH = 151kJ

1 mole of Fe3O4 reacts with 4 moles of H₂, 151kJ are absorbed.

63.4g of Fe₃O₄ (Molar mass: 231.533g/mol) are:

63.4g Fe₃O₄ × (1mol / 231.533g) = 0.274moles of Fe₃O₄

These are the moles of Fe₃O₄ that react. As 1 mole of Fe₃O₄ in reaction absorb 151kJ, 0.274moles absorb:

0.274moles of Fe₃O₄ × (151kJ / 1 mole Fe₃O₄) =

Answer:

true

Explanation:

Because ice melts if the temperature increasese

Answer:

Gallium

Explanation:

edg 2020

Answer:

Due to an electron-pair acceptor and donor.

Explanations:

Lewis acid can be defined as an electron-pair acceptor. An example is Hydrogen ion(H+). This is because it is a proton and it distributes positive charge which means that it accepts electrons(negative charge).

Lewis base can be defined as an electron-pair donor. This is because it donates electrons to be accepted by the proton. An example is ammonia(NH3).

If a biodegradable plastic or bioplastic ends up in a landfill site it will never decompose. In landfill sites waste is essentially mummified, in a complete absence of light and oxygen. Food that has ended up in landfill will not biodegrade, so there is no hope for biodegradable plastics or even bioplastics.So it is bad.

Answer:

THE NEW VOLUME OF THE GAS IS 3.124 L

Explanation:

Initial Temperature = 27°C = 27 + 273 K = 300 K

Pressure = constant

Initial Volume = 3.3 L

Final Temperature = 11 °C = 11+ 273 K = 284 K

Final volume = unknown

Using Charles' law, at constant pressure, the volume of a given gas is directly proportional to the temperature.

Mathematically,

V1 / T1 = V2 / T2

Re-arranging the formula by making V2 the subject of the formula

V2 = V1 T2 / T1

V2 = 3.3 * 284 / 300

V2 = 3.124 L

The new volume of the gas is therefore 3.124 L at 11°C

The new volume is 3.1 L

The parameters given in the question are

T1= 27°c

convert to kelvin

= 273 + 27

= 300k

T2= 11°c

convert to kelvin

= 273+11

= 284k

Volume 1= 3.3 L

V1/T1= V2/T2

3.3/300= V2/284

Cross multiply

284×3.3= 300×V2

937.2= 300V2

V2= 937.2/300

= 3.1

Hence the new volume is 3.1 L

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Answer:

[PCl₅] = 0.5646M

[PCl₃] = 0.1174M

[Cl₂] = 0.1174M

Explanation:

In the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

K equilibrium is defined as:

K = 2.44x10⁻² = [PCl₃] [Cl₂] / [PCl₅]

The initial moles of each compound when volume is 15.3L are:

PCl₅ = 0.300mol/L×15.3L = 4.59mol

Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol

PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol

At 8.64L, the new concentrations are:

[PCl₅] = 4.59mol / 8.64L = 0.531M

[PCl₃] = 1.308mol / 8.64L = 0.151M

[Cl₂] = 1.308mol / 8.64L = 0.151M

At these conditions, reaction quotient, Q, is:

Q = [0.151M] [0.151M] / [0.531M]

Q = 4.29x10⁻²

As Q > K, the reaction will shift to the left producing more reactant, that means equilibrium concentrations are:

[PCl₅] = 0.531M + X

[PCl₃] = 0.151M - X

[Cl₂] = 0.151M - X

Where X is reaction coordinate.

Replacing in K expression:

2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]

1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²

0 = 9.84x10⁻³ - 0.3264X + X²

Solving for X:

X = 0.293 → False solution. Produce negative concentrations

X = 0.0336M → Right solution.

Replacing:

[PCl₅] = 0.531M + 0.0336

[PCl₃] = 0.151M - 0.0336

[Cl₂] = 0.151M - 0.0336

Answer:

[tex]Q =9.143x10^8[/tex]

Yes, the precipitate of magnesium hydroxide will be formed.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]2NaOH(aq)+MgCl_2(aq)\rightarrow 2NaCl(aq)+Mg(OH)_2(s)[/tex]

Whereas the precipitate is the magnesium hydroxide which is formed by:

[tex]2OH^-(aq)+Mg^{2+}(aq)\rightleftharpoons Mg(OH)_2(s)\ \ \ ; K=\frac{1}{K_{sp}}[/tex]

Take into account that the solubility product is the inverse reaction. In such a way, the equilibrium is:

[tex]\frac{1}{K_{sp}}=\frac{1}{[OH^-]^2[Mg^{2+}]}[/tex]

Thus, we know the concentration of OH⁻⁻ from the concentration of sodium hydroxide being the same (2.63x10⁻³M) since it is a strong base. Moreover, since magnesium chloride totally dissociates into magnesium and chloride ions the 1.80x10⁻³ M is also the concentration of magnesium ions.

Next, as the solutions mix, the final concentration of OH⁻⁻ is:

[tex][OH^-]=\frac{75.0mL*2.63x10^{-3}M}{75.0mL+125.0mL}=9.86x10^{-4}M[/tex]

And the final concentration of Mg²⁺ is:

[tex][Mg^{2+}]=\frac{125.0mL*1.80x10^{-3}M}{75.0mL+125.0mL}=1.125x10^{-3}M[/tex]

Finally, we compute the reaction quotient:

[tex]Q=\frac{1}{[OH^-]^2[Mg^{2+}]}=\frac{1}{(9.86x10^{-4})^2*1.125x10^{-3}} =9.143x10^8[/tex]

But the equilibrium constant:

[tex]K=\frac{1}{K_{sp}}=\frac{1}{1.2x10^{-11}}=8.333x10^{10}[/tex]

Therefore, since K>Q, we infer that the precipitate of magnesium hydroxide (consider the procedure) will be formed.

Regards.

Answer:

[tex]49.45~%[/tex]

Explanation:

In this case, we have to start with the chemical reaction:

[tex]C_6H_1_2O~->~C_6H_1_0~+~H_2O[/tex]

So, if we start with 10 mol of cyclohexanol ([tex]C_6H_1_2O[/tex]) we will obtain 10 mol of cyclohexanol ([tex]C_6H_1_0[/tex]). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:

[tex](6*12)+(10*1)=82~g/mol[/tex]

With this value we can calculate the grams:

[tex]10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0[/tex]

Now, we have as a product 500 mL of [tex]C_6H_1_0[/tex]. If we use the density value (0.811 g/mL). We can calculate the grams of product:

[tex]500~mL\frac{0.811~g}{1~mL}=405.5~g[/tex]

Finally, with these values we can calculate the yield:

[tex]%~=~\frac{405.5}{820}x100~=~49.45%[/tex]%= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

Based on the data given, the percentage yield of the student's work is 49.45 %.

The equation of the clay-catalyzed dehydration of cyclohexanol is given below:

From the equation of the reaction, 1 mole of cyclohexanol yields 1 mole of cyclohexene.

Therefore 10 moles of cyclohexanol should yield 10 moles of cyclohexene.

First we determine the mass of cyclohexene obtained.

Mass = density * volume

volume of cyclohexene = 500 mL

density = 0.811 g/mL

mass of cyclohexene = 500 * 0.811

mass of cyclohexene = 405.5 g

Number of moles of cyclohexene = mass/molar mass

molar mass of cyclohexene = 82 g

moles of cyclohexene = 405.5 g/82

moles of cyclohexene = 4.945 moles

Percentage yield = 4.945/10 * 100%

Percentage yield = 49.45%

Therefore, the percentage yield of the student's work is 49.45 %.

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Answer: molar ratio: 0.58

Explanation:

This is a buffer problem. We would use the equation [tex]pH=pKa+log(\frac{base}{acid} )[/tex]. Since we were given Ka and pH, we can find the ratio.

pKa=-log(Ka)

pKa=-log(1.8×10⁻⁵)

pKa=4.74

Now that we have pKa, we can plug in our values and find the molar ratio. Instead of writing base/acid, let's use x.

4.5=4.74+log(x)

-0.24=log(x)

10⁻⁰⁻²⁴=x

x=0.58

Answer:

The correct answer is 8.4 %

Explanation:

The mass percent of a compound in a solution is calculated as follows:

mass percent = mass of solute/mass of solution x 100

The solute is vitamin C, so its mass is:

mass of solute = 5.20 g

The solvent is water, and its mass is 55.0 g. The mass of the solution is given by the sum of solute + solvent:

mass of solution= 5.20 g + 55.0 g = 60.2 g

Finally we calculate the mass percent:

mass percent = 5.20 g/60.2 g x 100 = 8.64%

Answer:

See explanation

Explanation:

In this case, we have to check the neighbors of each carbon in the molecule. In propane, we have two types of carbons (see figure 1) (blue and red ones). The red carbons are equivalent. (Both have the same neighbors). Now, we can analyze each carbon:

Blue carbon

In the blue carbon, we have 6 hydrogens neighbors (three on each methyl). If we follow the n+1 rule, we will have:

6+1= 7

For the blue carbon, we will have a Septet.

Red carbons

In the red carbon, we have only 2 neighbors (the carbon in the middle only have 2 hydrogens). If we follow the n+1 rule, we will have:

2+1=3

For the red carbon, we will have a triplet.

See figure 2

I hope it helps!

Answer:

This is a combination reaction because Li and Br are combining.

Answer:

[tex]T_2=17.8\°C[/tex]

Explanation:

Hello,

In this case, we can solve this problem by noticing that the heat lost by the warm water is gained by the ice in order to melt it:

[tex]Q_{water}=-Q_{ice}[/tex]

In such a way, the cooling of water corresponds to specific heat and the melting of ice to sensible heat and specific heat also that could be represented as follows:

[tex]m_{water}Cp_{water}(T_2-T_{water})=-m_{ice}\Delta H_{melting,ice}-m_{ice}\Cp_{ice}(T_2-T_{ice})[/tex]

Thus, specific heat of water is 4.18 J/g°C, heat of melting is 334 J/g and specific heat of ice is 2.04 J/g°C, thus, we can compute the final temperature as shown below:

[tex]m_{water}Cp_{water}(T_2-T_{water})+m_{ice}Cp_{ice}(T_2-T_{ice})=-m_{ice}\Delta H_{melting,ice}\\\\T_2=\frac{-m_{ice}\Delta H_{melting,ice}+m_{water}Cp_{water}T_{water}+m_{ice}Cp_{ice}T_{ice}}{m_{water}Cp_{water}+m_{ice}Cp_{ice}} \\\\T_2=\frac{-50.0*334+100*4.18*67+50.0*2.04*-20.0}{100*4.18+50.0*2.04} \\\\T_2=17.8\°C[/tex]

Best regards.

Answer:

4. False

5. False.

6. (b) One mole of a substance contains 6.022 x 10²³ particles of that substance

(c) There are 6.022 x 10²³ carbon atoms in 12.00 g of carbon-12.

7.  The correct option is (A) 3H₂SO₄

8. (b) 1.71 * 10³⁷ atoms of hydrogen

Explanation:

4. 1.00 mole of Ca(NO3)2 contains the same mass of N as 1.00 mole of NaNO3 is False  because 1 mole of Ca(NO3)2 contains 2 moles (28 g) of N atoms whereas 1 mole of NaNO3 contains 1 mole (14 g) of N atoms

5. The theoretical yield of a reaction is generally less than the actual yield is False  because it is the actual yield of a reaction that is always less than the theoretical yield due to some incomplete reactions.

The actual yield is obtained from carrying out the actual reaction while the theoretical yield is calculated from the equation of the reaction.

6. A mole of a substance is defined as the amount of that substance which contains as many elementary particles as there are in 12 g of carbon-12.

From experiments, it was discovered that 12 g of carbon -12 contains 6.02 * 10²³ atoms, therefore, a mole of a substance can also be defined as the amount of that substance which contains 6.02 * 10²³ particles of that substance.

(a) One mole of a substance contains as many particles as exactly 12 amu of carbon-12 is false because 12 amu is the mass of 1 atom of carbon-12 and not a mole of carbon-12.

(b) One mole of a substance contains 6.022 x 1023 particles of that substance is true from the definitions above

(c) There are 6.022 x 1023 carbon atoms in 12.00 g of carbon-12 is true from the definitions above.

(d) Because it is heavier, a mole of iodine atoms contains more particles than a mole of bromine atoms is false because, irrespective of difference in their masses, a mole of all substances contain the same number of particles- 6.02 * 10²³.

7. The balanced chemical equation of the reaction of sulfuric acid with hematite (Fe2O3) to produce iron (III) sulfate and water is as follows: .

Fe₂O₃ + 3H₂SO₄ -----> Fe₂(SO₄)₃ + 3H2O

The correct option is (A) 3H₂SO₄

8. Mass of natural gas = 1.14 * 10¹¹ Kg.

Mass of natural gas in grams = 1.14 * 10¹¹ * 10³ g = 1.14 * 10¹⁴ g

Molar mass of CH₄ = 16g/mol

Number of moles of CH₄ in 1.14 * 10¹⁴ g = 1.14 * 10¹⁴ g/ 16 gmol⁻¹ = 7.125 * 10¹² moles

1 mole of CH₄ contains 4 moles of hydrogen atoms.

7.125 * 10¹² moles of CH₄ will contain 4 * 7.125 * 10¹² moles of hydrogen atoms = 2.85 * 10¹³ moles of hydrogen atoms

1 mole of hydrogen atoms contain 6.02 * 10²³ atoms of hydrogen

2.85 * 10¹³ moles of hydrogen atoms will  contain 2.85 * 10¹³ * 6.02 * 10²³ atoms of hydrogen = 1.71 * 10³⁷ atoms of hydrogen

Answer:

1) dispersion forces

2) ion-dipole forces

Explanation:

For the formation of a solution of the substances, CH3CH2CH2CH2CH3 and CH3CH2CH2CH2CH2CH3, dispersion forces are involved. Recall that the both are organic substances hence they are both molecular in nature. They are not only molecular, they are nonpolar molecules. This implies that only dispersion forces are the possible intermolecular forces.

For the formation of a solution of LiNO3 and H2O, the dipoles of water interacts strongly with the ions Li^+ and NO3^- thereby separating the ions in solution. The positive dipole of water interacts with NO3^- while the negative dipole of water interacts with Li^+.

Therefore, the interaction between nonpolar molecules is dispersion forces while between polar molecules is ion-dipole forces.

Dispersion Forces:

They are the weakest form of intermolecular force. The attraction between molecules is temporary.

For example- Interaction between [tex]\bold { CH_3CH_2CH_2CH_2CH_3 }[/tex] and [tex]\bold { CH_3CH_2CH_2CH_2CH_2CH_3 }[/tex]

Ion-dipole forces:

The attraction between molecules is due to the interaction between opposite ions of molecules.

For example- Interaction between [tex]\bold { LiNO_3 }[/tex] and [tex]\bold { H_2O }[/tex]

Therefore, the interaction between nonpolar molecules is dispersion forces while between polar molecules is ion- dipole forces.

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Answer:

pH = 4.4

Explanation:

pH = -log[H₃O⁺]

     = -log(4.3 × 10⁻⁵)

pH = 4.37 = 4.4

I'm actually learning this in my chemistry class right now lol. Hope this helps though. :)

Answer:

It's harder to melt sodium chloride because of its density and stability.

Explanation:

The bond between Na+ and Cl- is an ionic bond, meaning its an ionic compound. Ionic compounds have more inter molecular forces(forces involving multiple molecules). Chlorine has much less of these forces than NaCl and isn't as dense.

Answer:

It's harder to melt sodium chloride because of its density

Explanation:

Answer:

Formula for effective nuclear charge is as follows. So, for He atom value of S = 0.30 because the electrons are present in 1s orbital. Therefore, calculate the effective nuclear charge for helium as follows. Thus, we can conclude that the effective nuclear charge for helium is 1.7

Explanation:

The effective nuclear charge experienced by a 1s electron in helium is +1.70.

Answer:

C. [tex]Ca_3(PO_4)_2[/tex]  will precipitate out first

the percentage of [tex]Ca^{2+}[/tex]remaining =  12.86%

Explanation:

Given that:

A solution contains:

[tex][Ca^{2+}] = 0.0440 \ M[/tex]

[tex][Ag^+] = 0.0940 \ M[/tex]

From the list of options , Let find the dissociation of [tex]Ag_3PO_4[/tex]

[tex]Ag_3PO_4 \to Ag^{3+} + PO_4^{3-}[/tex]

where;

Solubility product constant Ksp of [tex]Ag_3PO_4[/tex] is [tex]8.89 \times 10^{-17}[/tex]

Thus;

[tex]Ksp = [Ag^+]^3[PO_4^{3-}][/tex]

replacing the known values in order to determine the unknown ; we have :

[tex]8.89 \times 10 ^{-17} = (0.0940)^3[PO_4^{3-}][/tex]

[tex]\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3} = [PO_4^{3-}][/tex]

[tex][PO_4^{3-}] =\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}[/tex]

[tex][PO_4^{3-}] =1.07 \times 10^{-13}[/tex]

The dissociation  of [tex]Ca_3(PO_4)_2[/tex]

The solubility product constant of [tex]Ca_3(PO_4)_2[/tex]  is [tex]2.07 \times 10^{-32}[/tex]

The dissociation of [tex]Ca_3(PO_4)_2[/tex]   is :

[tex]Ca_3(PO_4)_2 \to 3Ca^{2+} + 2 PO_{4}^{3-}[/tex]

Thus;

[tex]Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2[/tex]

[tex]2.07 \times 10^{-33} = (0.0440)^3 [PO_4^{3-}]^2[/tex]

[tex]\dfrac{2.07 \times 10^{-33} }{(0.0440)^3}= [PO_4^{3-}]^2[/tex]

[tex][PO_4^{3-}]^2 = \dfrac{2.07 \times 10^{-33} }{(0.0440)^3}[/tex]

[tex][PO_4^{3-}]^2 = 2.43 \times 10^{-29}[/tex]

[tex][PO_4^{3-}] = \sqrt{2.43 \times 10^{-29}[/tex]

[tex][PO_4^{3-}] =4.93 \times 10^{-15}[/tex]

Thus; the phosphate anion needed for precipitation is smaller i.e [tex]4.93 \times 10^{-15}[/tex] in [tex]Ca_3(PO_4)_2[/tex] than  in  [tex]Ag_3PO_4[/tex]  [tex]1.07 \times 10^{-13}[/tex]

Therefore:

[tex]Ca_3(PO_4)_2[/tex]  will precipitate out first

To determine the concentration of [tex][Ca^+][/tex] when  the second cation starts to precipitate ; we have :

[tex]Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2[/tex]

[tex]2.07 \times 10^{-33} = [Ca^{2+}]^3 (1.07 \times 10^{-13})^2[/tex]

[tex][Ca^{2+}]^3 = \dfrac{2.07 \times 10^{-33} }{(1.07 \times 10^{-13})^2}[/tex]

[tex][Ca^{2+}]^3 =1.808 \times 10^{-7}[/tex]

[tex][Ca^{2+}] =\sqrt[3]{1.808 \times 10^{-7}}[/tex]

[tex][Ca^{2+}] =0.00566[/tex]

This implies that when the second  cation starts to precipitate ; the  concentration of [tex][Ca^{2+}][/tex] in the solution is  0.00566

Therefore;

the percentage of [tex]Ca^{2+}[/tex]  remaining = concentration remaining/initial concentration × 100%

the percentage of [tex]Ca^{2+}[/tex] remaining = 0.00566/0.0440  × 100%

the percentage of [tex]Ca^{2+}[/tex] remaining = 0.1286 × 100%

the percentage of [tex]Ca^{2+}[/tex]remaining =  12.86%

Answer:

8 mol

Explanation:

Step 1: Given data

Moles of copper (II) sulfate: 2 mol

Chemical formula of copper (II) sulfate: CuSO₄

Step 2: Establish the molar ratio of copper (II) sulfate to oxygen

According to the chemical formula, the molar ratio of copper (II) sulfate to oxygen is 1:4.

Step 3: Calculate the moles of O in 2 mol of CuSO₄

[tex]2molCuSO_4 \times \frac{4molO}{1molCuSO_4} = 8molO[/tex]

llllllllalalalalallalalalallalallalalalalalallalalalallala pls I am really sorry for this I can't take it down

Answer:

1. stability factor

2. steric hindrance factor

Explanation:

stability of ethane is lesser to that of two tert-butyl, so ethane will be more reactive and faster.

ethane is less hindered and more reactive, while two tert-butyl is more hindered and less reactive

Answer:

(a) What is the rate equation for the reaction?

rate = k[NO]2[Br2]

Explanation:

(b) How does the reaction rate change if the concentration of Br2 is changed from 0.0022 mol/L to 0.0066 mol/L?

the rate will doubleNitrosyl bromide, NOBr, is formed from NO and Br2.

(a) Rate = [tex]k[NO]2[Br2][/tex]

(b) The rate will triple Nitrosyl bromide, NOBr, is formed from NO and Br2.

(c) The rate will triple increase by a factor of 4

(a) The reaction is second order in NO ---> [tex]rate , r = k[NO]^2[/tex]

the reaction is first order in Br2 --> rate ,[tex]r = k[Br2]^1[/tex]

Therefore, from the above two total rate equation is , rate , [tex]r = k [NO]^2[/tex][tex][Br2]^1[/tex]

--> [tex]r = k[NO]^2 [Br2][/tex]

(b)The rate law is rate , [tex]r = k[NO]^2 [Br2][/tex]

------> rate , r is directly proportional to [Br2]

----->[tex]r / r’ = [Br2] / [Br2]’[/tex]

r = initial rate

r’ = final rate

[Br2] = initial conc = 0.0022 mol/L

[Br2]’ = final conc = 0.0066 mol/L

Plug the values we get[tex]r/r’ = 0.0022 / 0.0066[/tex]

r / r’ = 0.33

----> r’ = r / 0.33 = 3r

Therefore, the rate will triple

-------------------------------------------------------------------------------

(c) The rate law is rate ,[tex]r = k[NO]^2 [Br2][/tex]

------> rate , r is directly proportional to [tex][NO]^2[/tex]

-----> r / r’ =[tex][NO]^2 / [NO]’^2[/tex]

r = initial rate[tex]r / r’ = [NO]^2 / [NO]’^2[/tex]

r’ = final rate

[NO] = initial conc = 0.0024 mol/L

[NO]’ = final conc = 0.0048 mol/L

Plug the values we get [tex]r/r’ = 0.0024 / 0.0048[/tex]

[tex]r / r’ = (0.0024^2) / (0.0048)^2[/tex]

= [tex](0.5)^2[/tex]

=[tex]0.25[/tex]

----> r’ = [tex]r / 0.25 = 4r[/tex]

Therefore, the rate will triple increase by a factor of 4

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Answer:

1- there are 16 hydrogen atoms. ( heptane  C7H16)

2- The compound is octane (C8H18)

explanation

to determine any atom in an alkane, this formula is used Cn H 2n +2, where n is the number of carbon atoms in the molecule.

to find the compound in Q2 we'll apply the numbers:

C nH₂n+2

Answer:

[tex]P_2=1.1x10^6Pa[/tex]

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

[tex]P_1V_1=P_2V_2[/tex]

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

[tex]P_2=\frac{P_1V_1}{V_2}[/tex]

Consider that the given initial pressure is also equal to Pa:

[tex]P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa[/tex]

Which stands for a pressure increase when volume decreases.

Regards.

Answer:

It depends on the weather.

Explanation:

Like rain and hail, snow comes from the water vapor that forms the clouds, but obviously its formation is different: snow forms when the temperature is low in the atmosphere. In these conditions the water vapor drops freeze and when they collide form tiny crystals that join together to form snowflakes, which fall to Earth when they are heavy enough.

Answer:

i think option a is correct answer because when there is low temperature then the kinetic enegry will be very less and the atoms moves very slowly.

Answer:

A. very, very slowly

Explanation:

A is the answer because atoms will move faster in hot gas than in cold gas.