Write a method called min that takes three integers as parameters and returns the smallest of the three values, such that a call of min(3, -2, 7) would return -2, and a call of min(19, 27, 6) would return 6. Use Math.min to write your solution.

Answer:

public class Main

{

public static void main(String[] args) {

 System.out.println(min(3, -2, 7));

}

public static int min(int n1, int n2, int n3){

    int smallest = Math.min(Math.min(n1, n2), n3);

    return smallest;

}

}

Explanation:

*The code is in Java.

Create a method named min that takes three parameters, n1, n2, and n3

Inside the method:

Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.

In the main:

Call the method with parameters given in the example and print the result

Methods are named program statements that are executed when called/invoked.

The method in Python, where comments are used to explain each line is as follows:

#This defines the method

def mmin(a,b,c):

   #This calculates the smallest of the three values using math.min

   minNum = min(a,b,c)

   #This prints the smallest value

   return minNum

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